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import java.util.Scanner;
public class Fernando {
public static void main(String[] args) {
Scanner skype = new Scanner(System.in);
System.out.print("What is your name ")?
String n = skype.nextLine(); // This is the line with the error
System.out.print("\n and how old are you?");
int y = skype.nextInt();
displayInfo(n,y);
}
public String displayInfo(String name, int age){
return name +" is "+ age+" years old.";
}
}
All it says is expected. I don't understand what's wrong at all.
Try changing
System.out.print("What is your name ")?
to:
System.out.println("What is your name?");
This should work, as you have a ? instead of a ;.
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Why is the below code not working when using "!" not equals; it gave me "while" statement has an empty body? and when I'm removing the "!" it works...
import java.util.Scanner;
public class Main {
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
String input = "";
while (!input.equals("quit")); {
System.out.print("Input : ");
input = scanner.next().toLowerCase();
System.out.println(input);
}
}
}
you have to remove the semicolon
while(!input.equals("quit")) {
...
}
Remove the ; in the loop before {
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I'm writing a simple quiz program. The code on line 19 is giving me a run time error. Could someone please advise why?
import java.util.Scanner;
public class javaQuiz {
public static void main(String[] args) {
String questionOne = "Who is the best band member of the beatles?";
String questionOneAns = "John";
String questionTwo = "what is 1 + 1?";
int questionTwoAns = 2;
String questionThree = "What continent is China a part of?";
String questionThreeAns = "Asia";
String questionFour = "Who is the Turing Test named after?";
String questionFourAns = "Alan Turing";
Scanner userI = new Scanner(System.in);
String userAns = scan.NextLine();
System.out.println(questionOne);
if(userAns == questionOneAns) {
System.out.println("Correct!");
} else {
System.out.println("Wrong answer!");
}
}
}
Isnt it because your scanner is called userI instead of scan?
Line 19 should be:
String userAns = userI.nextLine();
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Please explain the use of System.in.read() method in this example that I'm learning about from another post. As a beginner, I find it unclear when I input a number and get different one in the output, please clarify.
import java.io.IOException;
public class MainClass {
public static void main(String[] args) {
int inChar;
System.out.println("Enter a Character:");
try {
inChar = System.in.read();
System.out.print("You entered ");
System.out.println(inChar);
}
catch (IOException e){
System.out.println("Error reading from user");
}
}
System.in.read() reads values as their binary value; for example reading "a" will result in the value of "97" - the mapping of this is available here https://www.asciitable.com/.
In order to get the textual representation of this in Java you want to read this as either a Character or a String - Character is a single value, while a String is a combination of Characters one after the other. For example:
public class MainClass {
public static void main(String[] args) {
System.out.println("Enter a Character:");
Scanner scanner = new Scanner(System.in);
String input = scanner.nextLine();
System.out.print("You entered ");
System.out.println(input);
}
Have a look at the Scanner class to see other options, you can use scanner.nextInt() to get an Integer back.
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I am trying to iterate through each character in a string that is inputted and check if any letter is a.
Here is my Java code:
import java.util.Scanner;
public class Input
{
public static void main(String[] args)
{
Scanner in = new Scanner(System.in);
String input;
input = in.nextLine();
for (int i=0; i<input.length(); i++)
{
char chararcter = input.charAt(i);
String s = Character.toString(character); //the error is here
if (s.equals("a"))
{
System.out.println("You typed an A.");
}
}
}
}
For reference, here is a Python analog.
input=raw_input()
for i in range (0,len(input)):
if input[i] == "a":
print "You typed an A."
I apologize for the simplistic nature of this question; I'm very new to Java. Thank you for helping.
You've change the spelling in your declaration.
char character = input.charAt(i); // <-- not chararcter (extra rc).
You don't have to convert character to String. just simply do character comparison.
if (chararcter == 'a')
{
System.out.println("You typed an A.");
}
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The strings were parsed to integers, so the condition of the if statements are properly right set. Why are the if statements not running? Why there doesn't appear a MessageDialog with a response?
class process{
public static void whoIs(){
JFrame frame=new JFrame("The Oldest");
String a=JOptionPane.showInputDialog(frame, "Enter, please, the first name and age:", "QUIZ: Who is the Oldest", JOptionPane.QUESTION_MESSAGE);
String b=JOptionPane.showInputDialog(frame, "Enter, please, the second name and age:", "QUIZ: Who is the Oldest", JOptionPane.QUESTION_MESSAGE);
String age1=a.replaceAll("[^\\d]","");
String age2=a.replaceAll("[^\\d]","");
String name1=a.replaceAll("\\d","");
String name2=b.replaceAll("\\d","");
int age1int=Integer.parseInt(age1);
int age2int=Integer.parseInt(age2);
if (age1int>age2int){
JOptionPane.showMessageDialog(frame, name1+ " is the oldest!", "QUIZ: Who is the Oldest?", JOptionPane.INFORMATION_MESSAGE);
}
if (age2int>age1int) {
JOptionPane.showMessageDialog(frame, name2+ " is the oldest!", "QUIZ: Who is the Oldest?", JOptionPane.INFORMATION_MESSAGE);
}
}
}
Your both ages are same and your if condition will not match since you are not considering the equality. I think you missed this, Next time try with debugger then you can identify these kind of issues by your own.
String age1=a.replaceAll("[^\\d]","");
String age2=a.replaceAll("[^\\d]","");
This should change this to following.
String age1=a.replaceAll("[^\\d]","");
String age2=b.replaceAll("[^\\d]","");