I want to write a few arguments in a .txt file and I want to sort them. To do that I want to go to the next line for every groop of arguments but I dont know how to do that.I have tried the:
x.nextLine();
statement, but that is only for scanning and not for formatting.
How can I go to the next line of a file while formatting? Is there another statement for that?
This is the code I created:
try{
w = new Formatter("data.txt");
}
catch(Exception e){
JOptionPane.showMessageDialog(null, "Fatal Error, please Reboot or reinstal program", "Error", JOptionPane.PLAIN_MESSAGE);
}
w.format("%s,%s,%s,%s%n", book,code,author,editor);
w.close();
You write
w.format("%s,%s,%s,%s%n", book,code,author,editor);
and I assume you want a newline where you write %n. But newline is \n, so change your code to
w.format("%s,%s,%s,%s\n", book,code,author,editor);
Also, you may want to revise the error catching logic in the program: right now if opening the file fails, you show an error message, which is good, but after that your program continues execution and will crash and burn on the first write operation...
EDIT: every time you execute the line w.format("%s,%s,%s,%s\n", book,code,author,editor); a line terminated by a new line will be added to the file, as long as you don't close the file or restart the program, because the Javadoc for the constructor you use says:
fileName - The name of the file to use as the destination of this formatter. If the file exists then it will be truncated to zero size; otherwise, a new file will be created. The output will be written to the file and is buffered.
So, if you need a file that grows instead of being overwritten you should use one of the other available constructors, eg one accepting an Appendable as argument. This would lead to the following code:
FileWriter fstream = new FileWriter("data.txt",true);
Formatter w = new Formatter(fstream);
// do whatever your program needs to do
w.close();
Of course surrounded by the necessary exception handling.
Related
I have a.txt list trying to move the first line to the last line in Java
I've found scripts to do the following
Find "text" from input file and output to a temp file. (I could set
"text" to a string buffRead.readLine ??) and then...
delete the orig file and rename the new file to the orig?
Please for give me I am new to Java but I have done a lot of research and can't find a solution for what I thought would be a simple script.
Because this is Java and concerns file IO, this is a non-trivial setup. The algorithm itself is simple, but the symbols required to do so are not immediately evident.
BufferedReader reader = new BufferedReader(new FileReader("fileName"));
This gives you an easy way to read the contents of the file fileName.
PrintWriter writer = new PrintWriter(new FileWriter("fileName"));
This gives you a simple way to write to the file. The API to do so is the exact same as System.out when you use a PrintWriter, thus my choice to use one here.
At this point its a simple matter of reading the file and echoing it back in the correct order.
String text = reader.readLine();
This saves the first line of the file to text.
while (reader.ready()) {
writer.println(reader.readLine());
}
While reader has text remaining in it, print the lines into the writer.
writer.println(text);
Print the line that you saved at the start.
Note that if your program does anything else (and it's just a good habit anyway), you want to close your IO streams to avoid leaking resources.
reader.close();
writer.close();
Alternatively, you could also wrap the entire thing in a try-with-resources to perform the same cleanup automatically.
Scanner fileScanner = new Scanner(myFile);
fileScanner.nextLine();
This will return the first line of text from the file and discard it because you don't store it anywhere.
To overwrite your existing file:
FileWriter fileStream = new FileWriter("my/path/for/file.txt");
BufferedWriter out = new BufferedWriter(fileStream);
while(fileScanner.hasNextLine()) {
String next = fileScanner.nextLine();
if(next.equals("\n") out.newLine();
else out.write(next);
out.newLine();
}
out.close();
Note that you will have to be catching and handling some IOExceptions this way. Also, the if()... else()... statement is necessary in the while() loop to keep any line breaks present in your text file.
Add the same line to the last line of this file have a look into this link https://stackoverflow.com/a/37674446/6160431
What I am trying to do is write a record to new line in my text file. Every time someone clicks sign up on my program, I want to call a method that opens a file and adds a record. This is what I have now:
To open the file:
try {
l = new Formatter("chineses.txt");
System.out.println("Did create");
} catch (Exception e){
System.out.println("Did not create");
}
To add the record:
public void addRecord(){
l.format("%s", nameField.getText());
}
Every time I put in a name in the name field and click sign up in my GUI, it always replaces whatever is on the first line in the text file.
How can I make it write to the second line while retaining what is on the first line?
Have you thought about using RandomAccessFile? You can seek to the end, then write.
According to the javadoc a formater created with a single String argument will first empty the file (truncate to zero length) before writing to it. This is why your file is not appended to. The program first removes whatever is in the file and then writes the new content to it when you call l.format().
What you probably want to do is format your data to a String using Formatter(). Open your record file for appending and then write that string to the file. This link should have plenty of details on how you might do this. (I googled "java open and write a file" to find that resource)
I have an file, where I am writing data to it. I've tried googling, but all examples I have tried have just confused me more.
I am inputting data into a file, and this is happening correctly, where the items selected are being appended to the file. Where my issue is, is that I want to check whether the string being inputted already exists in the file, and if it does, I want to skip it.
The code I am using to input the data to the file is below, but I am not sure how to change it to check for a duplicate.
for (EventsObj p : boxAdapter.getBox()) {
if (p.box){
String result = p.name + " " + p.price;
try {
// open file for writing
OutputStreamWriter out= new OutputStreamWriter(openFileOutput("UserEvents.txt",MODE_APPEND));
// write the contents to the file
out.write(result);
out.write('\n');
// close the file
out.close();
}
catch (java.io.IOException e) {
//do something if an IOException occurs.
Toast.makeText(this, "Sorry Text could't be added", Toast.LENGTH_LONG).show();
}
}
}
It is getting the checkboxes ticked, then getting the name and price related to it and appending it to file. But I want to carry out a check that this does not already exist. Any help would be appreciated and I've exhausted google and tried many things.
So, if I understood your question correctly the file contains a number of strings delimited by newline.
What you want to do is to read the file contents line by line, and store the lines in a HashSet<String>. Then, you open the file for appending and append the additional string, but only if the file did not contain the string already. As the other answer suggested, you use the contains method. However, unlike the other answer I'm not suggesting to use a list of strings; instead, I'm suggesting the use of a HashSet as it's more efficient.
While reading the file contents line by line, you can perform some basic checks: does the file already contain duplicate rows? You may want to handle those by giving the user a warning that the file format is invalid. Or you may want to proceed nevertheless.
You should firstly read from the file and create a list of strings with all your inputs.
Then before adding to the file you can check if the list of strings contains the string you want to add (just make sure that the strings share the same format such that a match will be found). If it returns false add to the file, if yes don't add to the file.
Shouldn't be such a tremendous task. You can make use of the contains method.
You might need to keep the contents of the file in a String in your program. A little inefficient, but at the moment I do not see any other way but to keep track of things in your program instead of on the file.
So before you run the program which appends text to the file, the very first thing you should probably do is parse the file for all text:
File yourFile = new File("file-path-goes-here");
Scanner input = null;
try {
input = new Scanner (new FileInputStream(yourFile) );
}
catch (FileNotFoundException e) {;;;}
String textFromFile = "";
while (input.hasNextLine())
textFromFile += input.nextLine() + "\n";
//Now before adding to the file simply run something like this
if(textFromFile.indexOf("string-to-write-to-file") != -1)
;//do not write to file
else {
;//write to file and add to textFromFile
textFromFile += "string-you-added-to-file" + "\n";
}
Hope this answers your question. Let me know if something is not clear.
I am trying to clear the contents of a file I made in java. The file is created by a PrintWriter call. I read here that one can use RandomAccessFile to do so, and read somewhere else that this is in fact better to use than calling a new PrintWriter and immediately closing it to overwrite the file with a blank one.
However, using the RandomAccessFile is not working, and I don't understand why. Here is the basic outline of my code.
PrintWriter writer = new PrintWriter("temp","UTF-8");
while (condition) {
writer.println("Example text");
if (clearCondition) {
new RandomAccessFile("temp","rw").setLength(0);
// Although the solution in the link above did not include ',"rw"'
// My compiler would not accept without a second parameter
writer.println("Text to be written onto the first line of temp file");
}
}
writer.close();
Running the equivalent of the above code is giving my temp file the contents:(Lets imagine that the program looped twice before clearCondition was met)
Example Text
Example Text
Text to be written onto the first line of temp file
NOTE: writer needs to be able to write "Example Text" to the file again after the file is cleared. The clearCondition does not mean that the while loop gets broken.
You want to either flush the PrintWriter to make sure the changes in its buffer are written out first, before you set the RandomAccessFile's length to 0, or close it and re-open a new PrintWriter to write the last line (Text to be written...). Preferably the former:
if (clearCondition) {
writer.flush();
new RandomAccessFile("temp","rw").setLength(0);
You'll be lucky if opening the file twice at the same time works. It isn't specified to work by Java.
What you should do is close the PrintWriter and open a new one without the 'append' parameter, or with 'append' set to 'false'.
I have a program that is only meant to be terminated by pressing Ctrl + C. In this program I write to an external file using:
File logFile = new File("output.txt");
PrintWriter log_file_writer = new PrintWriter(logFile);
log_file_writer.println("TEXT");
However because I don't know when the program will be terminated, I can't close the file using:
log_file_writer.close();
I think this is resulting in no text appearing in the output file.
Would anyone have a solution for this?
Thank you for your help.
log_file_writer.flush();
will push the content to disk
As the javadoc says:
PrintWriter(File file) Creates a new PrintWriter, without automatic line flushing, with the specified file.
Therefore, you need to flush the data you want to print that is actually buffered:
log_file_writer.flush();
You did not flush the content, I always use the autoFlush argument, but it is not available with File:
PrintWriter log_file_writer = new PrintWriter(new FileOutputStream("output.txt"),true);
but you can also use log_file_writer.flush(); after each write.