How can I convert the number of days to number of months and days using Joda-Time. For example, when I have 33 days, it should display 1 month and 2 days.
public static void main(String[]args)
{
Calendar calendar = new GregorianCalendar();
int years = calendar.get(Calendar.YEAR);
int month = (calendar.get(Calendar.MONTH))+1;
int day = calendar.get(Calendar.DATE);
DateTime startDate = new DateTime(years, month, day, 0, 0, 0, 0);
DateTime endDate = new DateTime(2014, 7, 3, 0, 0, 0, 0);
Days d = Days.daysBetween(startDate, endDate);
int days = d.getDays();
int t = 1000 * 60 * 60 *24;
int days = days/t;
System.out.println(days);
}
You can use class org.joda.time.Period for this.
Example:
Period p = new Period(startDate, endDate, PeriodType.yearMonthDayTime());
System.out.println(p.getMonths());
System.out.println(p.getDays());
Trying to create a decimal fraction number to represent months makes no sense to me, as months have different numbers of days (28, 29, 30, 31).
ISO 8601
The sensible ISO 8601 standard defines a textual way to represent a span of time in terms of months and days, called Durations. Joda-Time has a class for this purpose called Period. Forgive the mismatch in terms, as there is no standard definition of date-time terminology yet.
For an example of using the Period class, see this other answer by Ilya on this question.
ISO Duration
The textual format is PnYnMnDTnHnMnS where P means "Period" and the T separates the date portion from time portion. The other parts are optional. One month and two days would be P1M2D. The Joda-Time Period class both parses and generates such strings.
Related
How to calculate the number of "full" months between two dates with joda time, dropping incomplete months?
For example, I have 2 dates
LocalDate from = new LocalDate (2018, 9, 10);
LocalDate to = new LocalDate (2018, 11, 15);
Between these dates there is one "full" month - October from 1 to 31.
So I want to get is the number "1" by dropping the "incomplete" months - September and November
I need something like this
System.out.println(Months.monthsBetween(from, to).getMonths()); // returns 2
System.out.println(Months.**completed**MonthsBetween(from, to).getMonths()); // returns 1
UPD 1.
I could achieve what I want as follows:
LocalDate from = new LocalDate (2018, 9, 10);
LocalDate to = new LocalDate (2018, 11, 15);
if (to.getDayOfMonth() != 1)
from = from.plusMonths(1).withDayOfMonth(1);
if (to.getDayOfMonth() != 1)
to = to.withDayOfMonth(1);
System.out.println(Months.monthsBetween(from, to).getMonths());
but maybe there is an out of the box method?
Wouldn't this means that you simply want to remove one month from each interval and do a difference between them?
LocalDate fromMinusOne = from.minus(Months.ONE);
LocalDate toMinusOne = to.minus(Months.ONE);
System.out.println(Months.monthsBetween(fromMinusOne, toMinusOne).getMonths());
Joda Time provides methods to extract days, months and years between two dates. Create two instances of you date.
DateTime startDate = DateTime.parse("1970-01-01", DateTimeFormat.forPattern("yyyy-MM-dd"))
DateTime endDate = DateTime.parse("2015-02-25", DateTimeFormat.forPattern("yyyy-MM-dd"))
You can create your date instances in LocalDate as well instead of DateTime.
Now, complete months between above two dates can be found easily with,
int months = Months.monthsBetween(startDate.withDayOfMonth(1), endDate.withDayOfMonth(1)).getMonths()
For days,
int days = Days.daysBetween(startDate, endDate).getDays()
Difference between two dates in months
For years,
int years = Years.yearsBetween(startDate, endDate).getYears();
This question already has answers here:
Number of days between two dates in Joda-Time
(9 answers)
Closed 7 years ago.
I need to get the difference in months between two dates, I'm using Joda Time, the problem is this:
DateTime date1 = new DateTime().withDate(2015, 2, 1);
DateTime date2 = new DateTime().withDate(2015, 1, 1);
Months m = Months.monthsBetween(date1, date2);
int monthDif = m.getMonths();//this return 0
it returns 0 because there is no month in the middle of the two dates, I need to return the difference in months not a few months in between, and add 1 would be problematic when the dates are the same.
Changing the first date to 2015-02-02, Joda correctly returns 1 month:
DateTime date1 = new DateTime().withDate(2015, 2, 2);
DateTime date2 = new DateTime().withDate(2015, 1, 1);
System.out.println(Months.monthsBetween(date2, date1).getMonths());
// Returns 1.
So my guess is that because you didn't provide a time portion, Joda cannot be precise about exactly which point in time of 2015-01-01 date2 refers to. You might have as well referred to 23:59:59, in which case a full month wouldn't have elapsed yet, technically.
If you provide a zero time portion explicitly, it works as you initially expected:
DateTime date1 = new DateTime().withDate(2015, 2, 1).withTime(0, 0, 0, 0);
DateTime date2 = new DateTime().withDate(2015, 1, 1).withTime(0, 0, 0, 0);
System.out.println(Months.monthsBetween(date2, date1).getMonths());
// Returns 1.
Therefore, I recommend you specify a 00:00:00 time portion in each date explicitly.
While other answers are correct they still mask the real problem.
it returns 0 because there is no month in the middle of the two dates
No. It returns 0 because there is time part of DateTime object. You creating two istances of DateTime filled with current moment in time (with hours, minutes, seconds and milliseconds) and then modify just date part. There is no reasons to do it if you want to compare just two dates. use LocalDate instead.
LocalDate date1 = new LocalDate(2015, 2, 1);
LocalDate date2 = new LocalDate(2015, 1, 1);
Months m = Months.monthsBetween(date1, date2);
int monthDif = Math.abs(m.getMonths());//this return 1
Also need to pay attention to the fact that despite the fact that Months docs say nothing about it, Month can contain negative value if first date is after second date. So we need to use Math.abs to really count the number of months between two dates.
The docs say:
Creates a Months representing the number of whole months between the two specified partial datetimes.
But it isn't true. It really calculates the difference in months. Not the number of months.
The way this is calculated depends on the business logic that is to be used. Each month varies in length. One option would be to, in the monthsBetween() function, get the start of the month for both date1 and date2, and compare that.
Something like:
DateTime firstOfMonthDate1 = new DateTime(date1.getYear(), date1.getMonthOfYear(), 1, 0, 0);
DateTime firstOfMonthDate2 = new DateTime(date2.getYear(), date2.getMonthOfYear(), 1, 0, 0);
Months m = Months.monthsBetween(firstOfMonthDate1, firstOfMonthDate2)
In Java, how would I go about constructing a utility that would take a range of dates (start and end date) and then would see how many times a given partial date ( the month and day-of-month) appears in that range, and will add an entry to a list for each match.
In my instance, I want to give it a range of say 5 years - starting Jan 1st 2014 and going to Dec 31st 2019. My check date is the 2nd August. I want the method to return the full information about each match of any August 2 of any year in the range. So for 2014 is will return Saturday 2nd August 2014, then Sunday 2nd August 2015 etc and so on.
I've been trying to get something working so far with Joda Time and the default date/calendar classes in Java and I'm just getting myself in a mess.
Thanks,
S
Edit: How silly of me, apologies for not adding my code :(
public static List<Date> getDaysInRange(Date startdate,
Date enddate,
Date checkDate) {
SimpleDateFormat sdf = new SimpleDateFormat("MMdd");
List<Date> dates = new ArrayList<>();
Calendar cal = new GregorianCalendar();
cal.setTime(startdate);
while (cal.getTime().before(enddate)) {
if (sdf.format(cal.getTime()).equals(sdf.format(checkDate))) {
Date result = cal.getTime();
dates.add(result);
}
cal.add(Calendar.DATE, 1);
}
return dates;
}
Date-Only
Since you want only a date without time-of-day and without time zone, use a date-only class. The old java.util.Date/.Calendar classes lack such a class. And those old classes are notoriously troublesome and flawed.
Instead use either:
Joda-Time
java.time, built into Java 8, inspired by Joda-Time.
Joda-Time
Here is some untested code using Joda-Time 2.6.
The main idea is to focus on the small set of possible year numbers rather than test every day of year. In the example below, that means six date-time values to compare rather than thousands. Besides efficiency, the purpose of the code becomes more apparent.
The arguments to your routine should be a month number and a day-of-month number, a pair of ints or Integers, rather than a Date. As seen in this examples two int variables, month and day.
LocalDate start = new LocalDate( 2011, 2, 3 );
LocalDate stop = new LocalDate( 2016, 4, 5 );
int yearStart = start.getYear();
int yearStop = stop.getYear();
int month = 11;
int day = 22;
for ( i = yearStart, i <= yearStop, i++ )
{
LocalDate x = new LocalDate( i, month, day );
boolean matchStart = ( x.isEqual( start ) || x.isAfter( start ) );
boolean matchStop = x.isBefore( stop ); // Half-Open approach where beginning of range is inclusive while ending is exclusive.
if ( matchStart && matchStop )
{
// Add to collection of LocalDate objects.
// Later you can ask each LocalDate object for its day-of-week.
{
}
java.time
The java.time package also offers a LocalDate class. The code would be similar to the above Joda-Time example.
I think using SimpleDateFormat is a bad idea. Use Calendar for comparison directly, like this
cal1.get(Calendar.MONTH) == cal2.get(Calendar.MONTH) && cal1.get(Calendar.DAY_OF_MONTH) == cal2.get(Calendar.DAY_OF_MONTH)
I have a requirement where I need to find out number of months between two dates including extra days.
example:
start date:01/01/2014
end date:21/02/2014
LocalDate startDate = new LocalDate(startDate1);
LocalDate endDate = new LocalDate(endDate1);
PeriodType monthDay =PeriodType.yearMonthDay().withYearsRemoved();
Period difference = new Period(startDate, endDate, monthDay);
int months = difference.getMonths();
int days = difference.getDays()
the out put I will get is:
months:1 days:20
but my requirement is I want get total months including that extra day.
like:1.66 months.
How to get this one in java?
In order to be able to say 1.66 months you need to define how long a month is. It's not always the same. If you assume that a month is 30 days long then you can solve this by using:
Date startDate = new SimpleDateFormat("dd/MM/yyyy").parse("01/01/2014");
Date endDate = new SimpleDateFormat("dd/MM/yyyy").parse("21/02/2014");
double result = (endDate.getTime() - startDate.getTime()) / (1000D*60*60*24*30);
This gives us 1.7 and if you divide with 31 you get 1.6451612903225807.
If you want a better (but not perfect) approximation of how long a month is you can try 365/12 which will give you 1.6767123287671233 but still this is not perfect because leap years have 366 days.
The problem though is not with the formula, but with the problem definition. Nobody in real life says "I'll be there in exactly 1.66 months" and nobody will ever ask you to convert 1.66 months in days.
This is my own answer, a variation on cherouvim's
final Date startDate = new GregorianCalendar (2014, 0, 1).getTime ();
final Date endDate = new GregorianCalendar (2014, 1, 21).getTime ();
System.out.println ((endDate.getTime () - startDate.getTime ()) / (float) (1000L * 60 * 60 * 24 * 30));
I'm not sure what I'm doing wrong, but I've got a piece of code which calculates the number of days between two dates, and which looks something like the following:
final Calendar first = new GregorianCalendar(2010, Calendar.OCTOBER, 1);
final Calendar last = new GregorianCalendar(2010, Calendar.NOVEMBER, 1);
final long difference = last.getTimeInMillis() - first.getTimeInMillis();
final long days = difference / (1000 * 60 * 60 * 24);
System.out.println("difference: " + difference);
System.out.println("days: " + days);
To summarise, the code block above calculates the number of days between 1st October 2010 and 1 November 2010. I'm expecting to see it return 31 days (seeing as there's 31 days in October)
difference: xxxx
days: 31
but instead it's showing 30 days in October!
difference: 2674800000
days: 30
I've managed to narrow it down to between the the dates 2 October 2010 and 3 October 2010, which seems to only have 82800000 milliseconds, instead of a full 86400000 milliseconds (exactly one hour missing).
Does anyone have any ideas what I'm doing wrong? Or is the 2nd October a special date which has one minute less than a regular day?
(86400000 - 82800000)/1000 = 3600, which is one hour. You're seeing daylight savings time, combined with the rounding of integer math
You could get around it by doing the calculations with floating point numbers and rounding at the end, or you could check out a library like Joda time which offers much better date math than what's built in.
You may be better off comparing the year and day or year instead of the milliseconds that pass in a day.
int lastYear= last.get(Calendar.YEAR);
int firstYear= first.get(Calendar.YEAR);
int lastDayofYear = last.get(Calendar.DAY_OF_YEAR);
int firstDayofYear = first.get(Calendar.DAY_OF_YEAR);
int nDaysElapse = lastDayofYear - firstDayofYear;
int nYearsElapse = lastYear- firstYear;
int days = (nYearsElapse*365)+nDaysElapse;
You should read this post to get a better understanding of how Calendar is interrelated with date/time stamps.
Having read that site, my initial questions were:
What do you mean by days? Do you mean '24-hour blocks' or do you mean calendar days? In the same vein, do you care if you are off slightly due to daylight savings etc?
If you mean Calendar days, your best bet is probably to:
final Calendar first = new GregorianCalendar(2010, 9, 1);
final Calendar last = new GregorianCalendar(2010, 10, 1);
Calendar difference = Calendar.getInstance();
difference.setTimeInMillis(last.getTimeInMillis() - first.getTimeInMillis());
int numDays = difference.get(Calendar.DAY_OF_YEAR) - difference.getMinimum(Calendar.DAY_OF_YEAR);
Of course, the above code will only work if the number of days < 365. You will need to create a rolling calculation e.g.
int yearDiff = last.get(Calendar.YEAR) - first.get(Calendar.YEAR);
Calendar tmp = new GregorianCalendar();
tmp.setTimeInMillis(first.getTimeInMillis());
for(int i = 0; i < yearDiff; i++) {
numDays += tmp.getActualMaximum(Calendar.DAY_OF_YEAR);
i++;
tmp.add(Calendar.YEAR, 1);
}
This should allow you to get the number of days in a correct and consistent manner, without worrying about Daylight Savings, Leap Years etc.
That said, JodaTime probably has this functionality built in.
The answer by Brad Mace is correct.
Use a Library
This question is a good example of why you should use a good date-time library wither than roll your own. For Java that means using either Joda-Time or the new java.time package in Java 8.
Joda-Time
Example code in Joda-Time.
DateTimeZone timeZone = DateTimeZone.forID( "Australia/Melbourne" );
DateTime theFirst = new DateTime( 2014, DateTimeConstants.OCTOBER, 1, 0, 0, 0, timeZone ).withTimeAtStartOfDay();
DateTime nextMonth = theFirst.plusMonths( 1 ).withTimeAtStartOfDay();
int days = Days.daysBetween( theFirst, nextMonth ).getDays();
Or if you don't care about time-of-day, use the LocalDate class.
java.time
Java 8 and later comes with a new java.time framework to supplant the old java.util.Date/.Calendar classes. Inspired by Joda-Time, defined by JSR 310, and extended by the ThreeTen-Extra project.
Example code using Java 8. Note that the enum ChronoUnit returns a 64-bit long rather than int.
LocalDate firstOfOctober = LocalDate.of( 2010 , java.time.Month.OCTOBER , 1 );
LocalDate nextMonth = firstOfOctober.plusMonths( 1 );
long daysInMonth = ChronoUnit.DAYS.between( firstOfOctober , nextMonth );
The code you put in your post is calculating the time between September 1 and October 1, not October 1 and November 1. The output is correct for the code you posted.