Develop Reference

JSon disasambly [duplicate]

I have several string each containing a JSON representation of an array of objects. Here's an example in code to illustrate, though this is not my actual code (the JSON strings are passed in):
String s1 = "[{name: "Bob", car: "Ford"},{name: "Mary", car: "Fiat"}]";
String s2 = "[{name: "Mack", car: "VW"},{name: "Steve", car: "Mercedes Benz"}]";
I need to combine those two JSON arrays into one large JSON array. I could treat this as a String manipulation problem and replace the inner end square brackets with commas but that's not particularly robust (though I am guaranteed to get valid JSON).
I'd rather treat these two Strings as JSON arrays and just add them together somehow. It's a great plan except I don't know the "somehow" part.
Does anyone know a solution in Java that doesn't require constructing Java Object representations of the JSON objects?
Thanks!

This code will take sourceArray (s2), and append it to the end of destinationArray (s1):
String s1 = "[{name: \"Bob\", car: \"Ford\"},{name: \"Mary\", car: \"Fiat\"}]";
String s2 = "[{name: \"Mack\", car: \"VW\"},{name: \"Steve\", car: \"Mercedes Benz\"}]";
JSONArray sourceArray = new JSONArray(s2);
JSONArray destinationArray = new JSONArray(s1);
for (int i = 0; i < sourceArray.length(); i++) {
destinationArray.put(sourceArray.getJSONObject(i));
}
String s3 = destinationArray.toString();

You really have only two choices: parse the JSON (which invariably would involve constructing the objects) or don't parse the JSON. Not parsing is going to be cheaper, of course.
At first glance your idea about treating it as a String-manipulation problem might sound fragile, but the more I think about it, the more it seems to make fine sense. For error detection you could easily confirm that you were really dealing with arrays by checking for the square brackets; after that, just stripping off the ending bracket, adding a comma, stripping off the beginning bracket, and adding the "tail" should work flawlessly. The only exception I can think of is if either array is empty, you should just return the other String unchanged; again, that's very easy to check for as a String.
I really don't think there's any reason to make it more complex than that.

I used this code for Combine two Json Array.
String s1 = "[{name: \"Bob\", car: \"Ford\"},{name: \"Mary\", car: \"Fiat\"}]";
String s2 = "[{name: \"Mack\", car: \"VW\"},{name: \"Steve\", car: \"Mercedes Benz\"}]";
String s3=new String("");
s1=s1.substring(s1.indexOf("[")+1, s1.lastIndexOf("]"));
s2=s2.substring(s2.indexOf("[")+1, s2.lastIndexOf("]"));
s3="["+s1+","+s2+"]";
System.out.println(s3);

And here is my solution, You may want to merge more than two arrays :
Java version:
public static JSONArray mergeMultiJsonArray(JSONArray... arrays) {
JSONArray outArray = new JSONArray();
for (JSONArray array : arrays)
for (int i = 0; i < array.length(); i++)
outArray.put(array.optJSONObject(i));
return outArray;
}
Kotlin version:
fun mergeMultiJsonArray(vararg arrays: JSONArray): JSONArray {
val outArr = JSONArray()
for (array in arrays)
for (i in 0 until array.length())
outArray.put(array.optJSONObject(i))
return outArr
}

i use this code to append all the elements of a jsonArray to a common JsonArray.
public JSONArray getMergeJsonArrays(ArrayList<JSONArray> jsonArrays) throws JSONException
{
JSONArray MergedJsonArrays= new JSONArray();
for(JSONArray tmpArray:jsonArrays)
{
for(int i=0;i<tmpArray.length();i++)
{
MergedJsonArrays.put(tmpArray.get(i));
}
}
return MergedJsonArrays;
}

This function does the magic, adding multiples arrays returning one JSONArray with all elements
public static JSONArray JoinArrays(JSONArray... jsonArrays) {
JSONArray resultJSONArray = new JSONArray();
Arrays.stream(jsonArrays).forEach(jsonArray -> IntStream.range(0, jsonArray.length()).mapToObj(jsonArray::get).forEach(resultJSONArray::put));
return resultJSONArray;
}

Use Below Method pass all JSON array in ArrayList this method will return cumulative JsonArray
public JSONArray getMergeJson(ArrayList<JSONArray> xyz){
JSONArray result=null;
JSONObject obj= new JSONObject();
obj.put("key",result);
for(JSONArray tmp:patches){
for(int i=0;i<tmp.length();i++){
obj.append("key", tmp.getJSONObject(i)); ;
}
}
return obj.getJSONArray("key");
}

Why can't read a .json?

I want to read a .json using library json-simple, my json file is:
{
"Subjects": {
"subject1": "MIS",
"subject2": "DBMS",
"subject3": "UML"
}
}
And my code is:
import java.io.*;
import java.util.*;
import org.json.simple.*;
import org.json.simple.parser.*;
public class JSONReadFromTheFileTest {
public static void main(String[] args) {
JSONParser parser = new JSONParser();
try{
Object obj = parser.parse(new FileReader("/Users/User/Desktop/course.json"));
JSONObject jsonObject = (JSONObject)obj;
JSONArray subjects = (JSONArray)jsonObject.get("Subjects");
Iterator iterator = subjects.iterator();
while (iterator.hasNext()) {
System.out.println(iterator.next());
}
}catch(Exception e){
e.printStackTrace();
}
}
}
I would like to get in console:
subject1: MIS
subject2: DBMS
subject3: UML
But instead of that, I just get the next error:
java.lang.ClassCastException: org.json.simple.JSONObject cannot be cast to org.json.simple.JSONArray
at project.Main(Main.java:11)
But I searched in internet, and I found that if I change sintaxys of the .json in the next way:
{
"Subjects": [
"subject1: MIS",
"subject2: DBMS",
"subject3: UML"
]
}
I get in console what I want:
subject1: MIS
subject2: DBMS
subject3: UML
And you may think my problem is solved, but not yet, because I want to read the json file in the first way.
I hope someone can help me. Thanks in advance.

The first example shows a Subjects key containing a single object with several properties (subject1, subject2, etc).
Consider those properties like the member variables of a class.
In order to let you better understand if the class is Person those variables could be name and surname.
What you try to achieve in your code is extracting a JSONArray from the JSON you are providing.
Going back to the example for Person the array could be - sorry for the silly example - an Array containing phone numbers.
So what you are expecting is that one of the member properties of the class is an array.
This is not possible in the first example because the first example does not contain a json array.
This line extracts the whole json object:
JSONObject jsonObject = (JSONObject)obj;
This one tries to get an array out but no array is there in the first example:
JSONArray subjects = (JSONArray)jsonObject.get("Subjects");

Square brackets represent an array, which you've casted the getter into.
The second json shown is more correct for the code you've written, however, arrays cannot hold key-value pairs, so that's why you've made second JSON have an array of strings
To parse the first file, you'd need to start with
JSONObject subjects = (JSONObject)jsonObject.get("Subjects")
If you have full control over the file, I'd suggest just storing ["MIS", "DBMS", "UML"] then write a simple loop
for (int i = 0; i < jsonArray.length; i++) {
System.out.printf("subject%d: %s%n", i+1, jsonArray.get(i));
}

To make your code work with your json, you should not use JSONArray for "Subjects" but instead JSONObject. The reason is that [ and ] indicates beginning and ending of array element in json which is represented by JSONArray. If you have { and } element then its object represented by JSONObject. zz So replace this:
JSONArray subjects = (JSONArray)jsonObject.get("Subjects");
Iterator iterator = subjects.iterator();
while (iterator.hasNext()) {
System.out.println(iterator.next());
}
with following (I have not compiled it):
JSONObject subjects = (JSONObject)jsonObject.get("Subjects");
for(Iterator iterator = subjects.keySet().iterator(); iterator.hasNext();) {
String key = (String) iterator.next();
System.out.println(key + ": " + subjects.get(key));
}

As others mentioned you should replace JSONArray with JSONObject in your code. But I would suggest to switch to different JSON library all together. I would recommend to use Json-Jackson library. Also, there is another library that provides a wrapper over Json-Jackson library. It has JsonUtils class that can simply parse your JSON in one line. Just read first your Json from file into a String jsonString and do this.
Map<String, Object> myMap = JsonUtils.readObjectFromJsonString(jsonString, Map.class);
You will get a Map with one key "Subjects" that will have a value of a Map with your 3 keys and values:
subject1: MIS
subject2: DBMS
subject3: UML
Here is the JavaDoc for the JsonUtils class. The library could be found as Maven artifact and on Github (including source code and Javadoc).

How to create json, sorted on keys, using gson?

I need to create constant json string or a json sorted on keys. What do I mean by constant json string? Please look into following code sample, which I created.
My Code 1:
public class GsonTest
{
class DataObject {
private int data1 = 100;
private String data2 = "hello";
}
public static void main(String[] args)
{
GsonTest obj=new GsonTest();
DataObject obj2 = obj.new DataObject();
Gson gson = new Gson();
String json = gson.toJson(obj2);
System.out.println(json);
}
}
Output 1:
{"data1":100,"data2":"hello"}
My Code 2:
public class GsonTest
{
class DataObject {
private String data2 = "hello";
private int data1 = 100;
}
public static void main(String[] args)
{
GsonTest obj=new GsonTest();
DataObject obj2 = obj.new DataObject();
Gson gson = new Gson();
String json = gson.toJson(obj2);
System.out.println(json);
}
}
Output 2:
{"data2":"hello","data1":100}
If you see, if I switch variables (data1 & data2 in DataObject class), I get different json. My objective to get same json, even if somebody changes position of the class variables. I get it when somebody adds new variables, json would change. But json shouldn't change when variables are moved around. So, my objective is to get standard json, possibly in sorted keys order for same class. If there is nested json, then it should be sorted in the nested structure.
Expected output on run of both the codes:
{"data1":100,"data2":"hello"} //sorted on keys!! Here keys are data1 & data2
I understand, I need to change something in String json = gson.toJson(obj2); line, but what do I have to do?
Why I need them to be order?
I need to encode the json string and then pass it to another function. If I change the order of keys, even though value remain intact, the encoded value will change. I want to avoid that.

First of all, the keys of a json object are unordered by definition, see http://json.org/.
If you merely want a json string with ordered keys, you can try deserializing your json into a sorted map, and then serialize the map in order to get the sorted-by-key json string.
GsonTest obj=new GsonTest();
DataObject obj2 = new DataObject();
Gson gson = new Gson();
String json = gson.toJson(obj2);
TreeMap<String, Object> map = gson.fromJson(json, TreeMap.class);
String sortedJson = gson.toJson(map);

Like others have mentioned that by design JSON is not supposed to have sorted keys in itself. You can also come up with a recursive solution to do it. I won't say my solution is very efficient but it does the intended job. Please have a look at the following piece of code.
private static JsonObject sortAndGet(JsonObject jsonObject) {
List<String> keySet = jsonObject.keySet().stream().sorted().collect(Collectors.toList());
JsonObject temp = new JsonObject();
for (String key : keySet) {
JsonElement ele = jsonObject.get(key);
if (ele.isJsonObject()) {
ele = sortAndGet(ele.getAsJsonObject());
temp.add(key, ele);
} else if (ele.isJsonArray()) {
temp.add(key, ele.getAsJsonArray());
} else
temp.add(key, ele.getAsJsonPrimitive());
}
return temp;
}
Input:
{"c":"dhoni","a":"mahendra","b":"singh","d":{"c":"tendulkar","b":"ramesh","a":"sachin"}}
Output:
{"a":"mahendra","b":"singh","c":"dhoni","d":{"a":"sachin","b":"ramesh","c":"tendulkar"}}

Perhaps a work around is for your class wrap a TreeMap which maintains sort order of the keys. You can add getters and setters for convenience. When you gson the TreeMap, you'll get ordered keys.

Java JSON object to read a list value

I have a JSON response something like this:
{
"id_list":["123", "456", "789"],
...
}
I was wondering what I should do if I want use the JSONObject to read such a id list and to return a List<String> of the ids for example. I did not see there's any method in JSONObject can do such thing (ref: http://www.json.org/javadoc/org/json/JSONObject.html). The most possible one might be the JSONArray, but I don't know if I use JSONArray and turn every value in the list to be an JSONObject, how can I read them without keys.
Thank you

You can iterate through the JSONArray and store each value to the list, and return that.
JSONObject jo = new JSONObject(jsonString); //
JSONArray ja = jo.getJSONArray("id_list"); // get the JSONArray
List<String> keys = new ArrayList<>();
for(int i=0;i<ja.length();i++){
keys.add(ja.getString(i)); // iterate the JSONArray and extract the keys
}
return keys; // return the list

how to parse multiple json objects with no name

im having some trouble parsing json. I have json in the format of:
{"blah":"blah","blah":"blah"}
{"blah":"blah","blah":"blah"}
{"blah":"blah","blah":"blah"}
Here is the link to the JSON: http://gerrit.aokp.co/query?format=JSON&q=status:merged&age:1d
I cant make this a jsonobject and iterate over it. I currently have it as a string.
Is there a way to iterate over this? there will be over 500.
I tried making it an array by adding square brackets around it, but it didnt work because i needed to divide them with commas. I cant manipulate this by hand because im getting it from the web. So i tried this.
jsonString = jsonString.replaceAll("}(?!,)", "},");
the reason im adding the negative comma is that sometimes i might have a jsonobject inside of of these objects so I only want to add a comma in front of the '}' without commas.
when i do the replaceall i get this error.
Error in fetching or parsing JSON: java.util.regex.PatternSyntaxException: Syntax error in regexp pattern near index 1:
}(?!,)
^
What am I doing wrong or is there an easier way to do this that im looking over?
EDIT:
Oh yes, I need to implement this in java because this is in an android app.

here is an example how you can accomplish what you want using Jackson's ObjectMapper.
ObjectMapper om = new ObjectMapper();
try {
List<Object> obj = om.readValue(yourJsonString, new TypeReference<List<Object>> () { });
} catch (IOException e1) {
e1.printStackTrace();
}
Now you will have a list of each of the individual Objects in your JSON string. To take it a step further you could create a POJO for the Object you are parsing.
Something like:
public class MyObject{
private String project;
private String branch;
}
That is just an exmple, you would need to define a property for each json property.
Then you can turn :
List<Object> obj = om.readValue(yourJsonString, new TypeReference<List<Object>> () { });
Into
List<MyObject> obj = om.readValue(yourJsonString, new TypeReference<List<MyObject>> () { });
Hope this helps!

From the link you posted, it looks like there are newlines between objects (and only between objects). If that's right, I'd approach it like this:
String[] items = dataFromWeb.split("\n");
String asJSONArrayString = Arrays.toString(items);
JSONArray jsonArray = new JSONArray(asJSONArrayString);
This splits the data at newlines, then joins it together with commas between elements and brackets around the whole thing.

JSONObject jObject = null;
mJsonString = downloadFileFromInternet(urlString);
jObject = new JSONObject(mJsonString);
This will get you json object.
This is the way to get json array from json object:
JSONArray jsonImageArray = jObject.getJSONArray("your string");