Develop Reference

Passing XML Data in an XML File

I have some XML data inside an XML file which i want to pass to another application. I have used XMLPullPaser.
<?xml version="1.0" encoding="utf-8" ?>
<node1>
<node2>dd03</node2>
<node3>,17,0,,**<xml><cell>555</cell></xml>**,</node3>
</bintextobj>
node 3 contains the data as highlighted. The xml I want to pass as data of xml file. Is there any way of achieving this?

Use CDATA to store the value. This will cause the parser to treat the value of node3 like plain text.
<node3><![CDATA[,17,0,,**<xml><cell>555</cell></xml>**,]]></node3>

write xsl to extract the <xml>..</xml> and write into the new xml file which can be passed to the other applications.

XML Parent & child Attributes reading in java?

I have the following data in my XML file.
<main>
<Team Name="Development" ID="10">
<Emp Source="Business" Total="130" Active="123" New="12" />
<Emp Source="Business" Total="131" Active="124" New="13" />
</Team>
<Team Name="Testing" ID="10">
<Emp Source="Business" Total="133" Active="125" New="14" />
</Team>
</main>
I want to read above data & store values into arrays,Can any one help on these?

Not sure why you need to convert those xml into Arrays, anyhow you can read xml and parse it by several ways. Normally we use DOM or Stax Parser and a Tutorial link is here, also here is a Java SAX Parsing Example tutorial.
Hope this can help you to achieve your goal. Update your question again if you stuck anywhere.

You can use parser in JAVA to parse the XML document. The package in java for this purpose is javax.xml.parsers . DocumentBuilder parses XML into a Document and Document is a tree structured data structure that is DOM(Document Object Model) readable file. Its nodes can be traversed/ changed/ accessed by DOM methods.
Here is a very good tutorial on XML DOM: http://www.roseindia.net/xml/dom/
and more specifically: http://www.roseindia.net/xml/dom/accessing-xml-file-java.shtml
also you can always refer to w3school for more theory on DOM!

In XSLT, how do I get the filepath of the xml file of a certain element if that xml file was included with xinclude?

I have these XML files:
master.xml (which uses XInclude to include child1.xml and child2.xml)
child1.xml
child2.xml
Both child1.xml and child2.xml contain a <section> element with some text.
In the XSLT transformation, I 'd want to add the name of the file the <section> element came from, so I get something like:
<section srcFile="child1.xml">Text from child 1.</section>
<section srcFile="child2.xml">Text from child 2.</section>
How do I retrieve the values child1.xml and child2.xml?

Unless you turn off that feature, all XInclude processors should add an #xml:base attribute
with the URL of the included file. So you don't have to do anything, it should already be:
<section xml:base="child1.xml">Text from child 1.</section>
<section xml:base="child2.xml">Text from child 2.</section>
( If you want, you can use XSLT to transform the #xml:base attr into #srcFile. )

I'm 99% sure that once xi:include has been processed, you have a single document (and single infoset) that won't let you determine which URL any given part of the document came from.
I think you will need to place that information directly in the individual included files. Having said that, you can still give document-uri a try, but I think all nodes will return the same URI.

Generate java class hierarchy from xml (plist)

Are there any tools that can automatically generate java class hierarchy from xml (plist)?
Say we have:
<blah>
<item />
<item />
</blah>
And we need to get something like:
class Blah {
Collection<Item> items;
}
...and so on and so forth

If I get it right, then the elements shall be transformed into class and field names.
This can be done with a few lines of code:
parse the xml document into a DOM
walk through the DOM tree and create a java source file in memory (StringBuilder)
write the source file to your file system
Or use XSLT to create a transformation from your xml document to a java source file.

The markup must be well-formed

First off, let me say I am a new to SAX and Java.
I am trying to read information from an XML file that is not well formed.
When I try to use the SAX or DOM Parser I get the following error in response:
The markup in the document following the root element must be well-formed.
This is how I set up my XML file:
<format type="filename" t="13241">0;W650;004;AG-Erzgeb</format>
<format type="driver" t="123412">001;023</format>
...
Can I force the SAX or DOM to parse XML files even if they are not well formed XML?
Thank you for your help. Much appreciated.
Haythem

Your best bet is to make the XML well-formed, probably by pre-processing it a bit. In this case, you can achieve that simply by putting an XML declaration on (and even that's optional) and providing a root element (which is not optional), like this:
<?xml version="1.0"?>
<wrapper>
<format type="filename" t="13241">0;W650;004;AG-Erzgeb</format>
<format type="driver" t="123412">001;023</format>
</wrapper>
There I've arbitrarily picked the name "wrapper" for the root element; it can be whatever you like.

Hint: using sax or stax you can successfully parse a not well formed xml document until the FIRST "well formed-ness" error is encountered.
(I know that this is not of too much help...)

As the DOM will scan you xml file then build a tree, the root node of the tree is like the as 1 Answer. However, if the Parser can't find the or even , it can even build the tree. So, its better to do some pre-processing the xml file before parser it by DOM or Sax.