I am new to Weblogic. And I want to enable the JMX on Weblogic 12c.
As I searched on stackoverflow, I found this:
Add the following JVM parameters to your Weblogic startup scripts:
-Dcom.sun.management.jmxremote -Dcom.sun.management.jmxremote.port=8888 -Dcom.sun.management.jmxremote.ssl=false -Dcom.sun.management.jmxremote.authenticate=false
However I couldn't find this script.
So where is it?
Thank you very much!
There are a few weblogic startup (and shutdown scripts), one for Windows (ending in "cmd") and one for Unix/Linux (ending in "sh"). The filename begins startWebLogic and it was installed in your weblogic/bin folder.
Per the documentation (linked above),
The startWebLogic script does the following:
Sets environment variables by invoking DOMAIN_NAME\bin\setDomainEnv.cmd (setDomainEnv.sh on UNIX), where DOMAIN_NAME is the directory in which you located the domain; for example, WL_HOME\user_projects\domains\DOMAIN_NAME, and where WL_HOME is the location in which you installed WebLogic Server.
Invokes the java weblogic.Server command, which starts a JVM that is configured to run a WebLogic Server instance.
Related
In our project , in ide we are providing few vm arguements in ecipse run configurations. But when we are deploying the application, we are trying to provide these arguements. But not sure how to provide through tomcat to run on server startup. Can anybody help us here. Thanks in avdance.
The proper way to set VM arguments in Tomcat is to create a file in the Tomcat bin directory called "setenv.bat" (or "setenv.sh" if you're in Linux or Mac). In that file, you can set JVM options by setting the JAVA_OPTS variable, like for instance:
set JAVA_OPTS="-Xmx2G -Xms128M -Dvariable=2"
https://docs.oracle.com/cd/E40520_01/integrator.311/integrator_install/src/cli_ldi_server_config.html
I am running Ubuntu 16.04 and I need to install and run Restcomm JSS7 stack as a JBoss AS Service.
I followed this video tutorial to install JBoss AS 7. Then I set the JBOSS_HOME environment variable to installation directory of JBoss AS 7. As a result, I was able to start the JBoss AS successfully by executing ./run.sh in the bin sub-folder of the installation directory.
Then I followed this guide to install Restcomm JSS7 stack. For that, I downloaded restcomm-jss7-7.4.1404.zip, unzipped it to /opt/ and then navigated to the ss7-jboss sub-directory and then executed ant deploy,
and the result was
...
BUILD SUCCESSFUL
which according to the guide is an indication of the service deployed successfully.
Then I am following CHAPTER 4 SECTION 4.1 of this user manual to run it as a JBoss AS Service. According to it,
All you have to do to start the Service is start the JBoss AS. This
will automatically start the SS7 Service. To start the JBoss Server
you must execute the run.sh (Unix) or run.bat (Microsoft Windows)
startup script in the /bin folder (on Unix or
Windows).
TWO PROBLEMS:
My <jboss_install_directory>/bin does NOT have a run.sh script. Because of this reason, I tried by running JBoss AS by using the regular standalone.sh script.
Next in the user manual, it is stated:
Result: If the service started properly you should see following lines
in the Unix terminal or Command Prompt depending on your environment:
(Note: I have pasted the following excerpt from user manual here, since it is too long to paste in this question.)
But I see none of those lines in my terminal. Rather, my terminal output of running ./standalone.sh is pasted here.
So I don't know how and where to proceed from here. Please help.
NOTE: This question is NOT a duplicate of my other question. Like I mentioned in the question titles, this question is about why my JBoss AS installation doesn't contain a run.sh script, and what would be its alternative. The other question is about some possible command to find out the JBoss Services started when it is running? When a beginner is starting to learn something, their entire purpose Not getting the job done. They have many confusions/questions in their mind.
The documentation documents how to start a JBoss 5.1 server but your installation uses a JBoss 7.1 server, which is why you have to use standalone.sh instead of run.sh to start the server and why the logs are different.
Since you correctly reach the JBoss AS 7.1.0.Final "Thunder" started in 3955ms line I wouldn't worry too much (except about using a documentation that is clearly outdated).
The documentation of your product only declares compatibility with JBoss 5.1.0. While it may work on later releases, you might want to check if there's a more recent version of your product. I wouldn't recommend installing JBoss AS 5.1.0 as it isn't supported anymore and will contain security breaches.
I want to change memory configuration of Tomcat. I know it can be done at
Start > Apache Tomcat > Configure Tomcat > Java Tab] as can be seen below
and specifying options like
-Xms512m
-Xmx1024m
-XX:MaxPermSize=512m
-XX:MaxHeapFreeRatio=70
there.
However this program group is created if I install Tomcat from an executable. I have installed Tomcat by simply extracting the zip which does not create Program group. So now where can I specify this information
With regards to the question of where Tomcat's memory options are saved when using the service version, on my machine at least they can be found in the Windows Registry at:
HKEY_LOCAL_MACHINE\SOFTWARE\Wow6432Node\Apache Software Foundation\Procrun 2.0\Tomcat-6\Parameters\Java
Initial memory and Maximum memory are recorded against the JvmMs and JvmMx values, while the options text is recorded against the Options value.
The Tomcat-6 portion of the address on mine is, I believe, based on the identifier I gave to the service (i.e. within the service manager Tomcat is named "Apache Tomcat 6.0 Tomcat-6"), and you may not need to go through Wow6432Node depending on whether you're using 32-bit or 64-bit Tomcat.
I'm assuming here that they haven't made any dramatic changes in where this information is stored in versions of Tomcat more recent than Tomcat 6.
Ohkay while digging inside Tomcat I found some information in one of its txt files (point 3.4) and online:
Apart from CATALINA_HOME (which is set to apache-tomcat-x.x.x directory, for e.g. C:\Program Files\Apache Software Foundation\apache-tomcat-7.0.41) and CATALINA_BASE (optional, defaults to CATALINA_HOME), all environment variables can
be specified in the setenv script. The script is placed either into
CATALINA_BASE/bin or into CATALINA_HOME/bin directory and is named
setenv.bat (on Windows) or setenv.sh (on *nix). The file has to be
readable.
By default the setenv script file is absent. If the script file is present
both in CATALINA_BASE and in CATALINA_HOME, the one in CATALINA_BASE is
preferred.
For example, to configure the JRE_HOME and CATALINA_PID variables you can
create the following script file:
On Windows, %CATALINA_BASE%\bin\setenv.bat:
set "JRE_HOME=%ProgramFiles%\Java\jre6"
exit /b 0
On *nix, $CATALINA_BASE/bin/setenv.sh:
JRE_HOME=/usr/java/latest
CATALINA_PID="$CATALINA_BASE/tomcat.pid"
To set Java options for memory allocation for web app, add something like following (as per memory requirements of your application) to the same file
set JAVA_OPTS="-Xms256m -Xmx512m"
The CATALINA_HOME and CATALINA_BASE variables cannot be configured in the
setenv script, because they are used to locate that file.
All the environment variables described here and the setenv script are
used only if you use the standard scripts to launch Tomcat. For example, if
you have installed Tomcat as a service on Windows, the service wrapper
launches Java directly and does not use the script files.
I am a newbie to Ubuntu 12.10 and moved to it from Windows.
In Windows I have configured the environment variable to include servlet-api.jar in the CLASSPATH variable so I do not have to type -cp <path to servlet-api.jar> every time I compile.
For normal Java programs, I have set the JAVA_HOME using:
export JAVA_HOME="/usr/lib/jvm/java-7-openjdk-i386" >> ~/.bashrc
With that solved, I need to set the CLASSPATH but do not know how to.
Please help on that!
Also I read on some forums that I should change the CLASSPATH manually each time I compile because changing the CLASSPATH may upset other applications.
Next, I tried this command to start Tomcat
service tomcat7 start but I got an error :
You need root privileges to run this script I do not know why. Help me solve that!
And if within the scope, please tell me how the directory structure of tomcat in Windows differs from that in Ubuntu.
Misc
I used sudo apt-get install tomcat7 to get Tomcat 7.
You don't say whether you're using an Ubuntu Tomcat package or a standalone Tomcat installation.
For a standalone Tomcat, you will be starting and stopping it using the scripts in its bin directory: startup.sh and shutdown.sh. In that case, Tomcat will use the environment variable values set at the time of invocation.
When doing this, you can set the environment variables prior to running these commands.
The same is true for the Tomcat 6 or Tomcat 7 that Ubuntu distributes as packages.
These neatly separate the $CATALINA_HOME directory (where the Tomcat 7 distribution is supposed to be) from the $CATALINA_BASE directory (where all of the changes and additions for a particular Tomcat instance are supposed to be. For the tomcat7 package, the first directory is /usr/share/tomcat7, while the second is /var/lib/tomcat7.
You can find startup.sh and shutdown.sh in /usr/share/tomcat7/bin and of course you can use them.
However, if you use the Tomcat provided with Ubuntu, you're probably going to want to run it just like any other standard system service, and the packages support this: e.g. in the case of tomcat7, you can just use
sudo service tomcat7 status
sudo service tomcat7 start
sudo service tomcat7 stop
sudo service tomcat7 restart
just like you can for any system service, and it uses the same mechanism as other system services do:
the shell script /etc/init.d/tomcat7 is used to start and stop Tomcat 7
/etc/default/tomcat7 is its configuration file, allowing a few parameters to be set
Using this method, you cannot specify additional environment variables for Tomcat to use by setting them in your shell or in /etc/default/tomcat7; they will not be passed to Tomcat.
However, there is a second method to set environment variables: if you set them in the shell script /var/lib/tomcat7/bin/setenv.sh (or, if you must, /usr/share/tomcat7/bin/setenv.sh), they will be picked up and passed to Tomcat. This method always works.
Finally, Tomcat offers finer control than just using a $CLASSPATH when it comes to specifying additional classes or JARs to be loaded on startup: in its conf/catalina.properties configuration file, you can set the common.loader, server.loader and shared.loader to a list of directories and/or JAR files to be loaded in additional to the standard ones.
All it means is that you should do that as a superuser - which translates to administrator in windows so you should try something like sudo service tomcat7 start
Try export CLASSPATH=/usr/share/tomcat7/lib/servlet-api.jar:/usr/share/tomcat7/lib/jsp-api.jar - This will depend on where your tomcat installation in located.
You can get more here
Cheers
I am running tomcat 6.0.18 as a windows service. In the service applet the jvm is configured default, i.e. it is using jvm.dll of the JRE.
I am trying to monitor this application with JConsole but cannot connect to it locally. I added the parameter -Dcom.sun.management.jmxremote (which works when starting tomcat with the start.bat script). But the jvm does not seem to pick up the parameter.
There's a nice GUI to edit the options, no need to muck around in the registry.
Open up the C:\Program Files\Apache Software Foundation\Tomcat 6.0\bin\tomcat6.exe (or just double-click on the monitor icon in the task bar). Go to the Java pane, add the following to the list of arguments, and restart Tomcat.
-Dcom.sun.management.jmxremote
-Dcom.sun.management.jmxremote.port=8086
-Dcom.sun.management.jmxremote.ssl=false
-Dcom.sun.management.jmxremote.authenticate=false
Then you can connect with JConsole or the newer VisualVM.
Here's the prescribed way for changing jvmoptions & interacting with the service:
http://tomcat.apache.org/tomcat-5.5-doc/windows-service-howto.html
I would try going into your registry at HKLM/Software/Apache Software Foundation/Procrun 2.0//Parameters/Java and editing the "Options" multi-string value directly.
If Tomcat is running as a Windows service, and you want to attach to the JVM locally, you need to run VisualVM or JConsole as the System account. You can use Sysinternals PsExec.exe to accomplish this.
psexec.exe -i -s c:\visualvm\bin\visualvm.exe
I'm posting it mainly to record this information to myself, I haven't validated it - but this is supposed to work as well:
http://mysqlandsqlserver.blogspot.com/2010/02/jconsolejmap-and-tomcat-as-windows.html
There is still a rather simple way to connect JConsole to Java process started as Windows Service using the local mode which I discovered here.
Basically it says that in order to connect to Java process launched as a Windows Service you need to launch JConsole as a Windows Service (you can do it using windows native api or using any wrapper like yajsw.)
By the way, this will free you from restarting the Java Process which was critical for me.
Add the following near the top of your catalina.bat
set JAVA_OPTS=%JAVA_OPTS% -Dcom.sun.management.jmxremote ^
-Dcom.sun.management.jmxremote.port=8086 ^
-Dcom.sun.management.jmxremote.ssl=false ^
-Dcom.sun.management.jmxremote.authenticate=false
Stop and restart tomcat (obviously)
Run jconsole.exe. If your tomcat is running as service, then run jconsole.exe as administrator.
Select Remote Process and enter localhost:8086