Check a string for consecutive repeated characters [closed] - java

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It is asked in an interview to write the code in Java to display the string which doesn't have consecutive repeated characters.
E.g.: Google, Apple, Amazon;
It should display "Amazon"
I wrote code to find continues repeating char. Is there any algorithm or efficient way to find it?

class replace
{
public static void main(String args[])
{
String arr[]=new String[3];
arr[0]="Google";
arr[1]="Apple";
arr[2]="Amazon";
for(int i=0;i<arr.length;i++)
{
int j;
for(j=1;j<arr[i].length();j++)
{
if(arr[i].charAt(j) == arr[i].charAt(j-1))
{
break;
}
}
if(j==arr[i].length())
System.out.println(arr[i]);
}
}
}
Logic : Match the characters in a String with the previous character.
If you find string[i]==string[i-1]. Break the loop. Choose the next string.
If you have reached till the end of the string with no match having continuous repeated character, then print the string.

Related

How can I output individual letters of a string? In my assignment, I have to get the W out of the word "Wetter" [closed]

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public class Main {
public static void main(String[] args) {
String satz = "Heute ist wunderbares Wetter, fahren wir doch zum Strand";
System.out.println(satz);
System.out.print(satz.substring(22));
}
}
I tried different things, but i have always errors. i am a beginner with Java, and i try to understand strings. I tried to understand them in ANSI C, but i have no clue :D
String is an Object which has build in methods such as the one you're using .substring(). Another which might be handy for you in this case is charAt() in combination with a loop.
You can read more about which methods String object has at https://docs.oracle.com/javase/7/docs/api/java/lang/String.html
//Print All Charchters
for (int i=0; i<satz.length(); i++)
{
System.out.println(satz.charAt(i));
}
//Get char In a specific Location (Index)
System.out.println(satz.charAt(22));
If you want to print out the 23rd letter you can use substring or charAt
String satz = "Heute ist wunderbares Wetter, fahren wir doch zum Strand";
System.out.println(satz);
System.out.println(satz.charAt(22));
System.out.println(satz.substring(22,23))

Parse String statement into a boolean expression [closed]

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I have a string statement String s = sb.contains("is");
I want to use this in an if condition like
if (s) {
//do something
}
How can I achieve this functionality?
Edit: Basically I get a boolean logic along with strings as an input. Ex: "Stack & over & (is | flow)". I have an array of sentences and I have to pick every sentence that follows this logic. I thought I would construct a string like "sb.contains(stack) && sb.contains(over) && (sb.contains(is) || sb.contains(flow))" and I thought I would run this boolean logic over all the sentences. Is there any other way of doing this?
The contains method returns a boolean value, so you can just simply set the type of variable 's' to a boolean.
public class Main
{
public static void main(String[] args) {
String sb = "crisis";
boolean s = sb.contains("is");
if(s){
System.out.println("S is true");
System.out.println(s);
}
}
}
https://docs.oracle.com/javase/7/docs/api/java/lang/String.html#contains(java.lang.CharSequence)

How to correct this text processing programme? [closed]

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import java.util.Scanner;
public class TextProcessing
{
public static void main(String[] args)
{
String sentence, wordToBeTargeted, wordToBeReplaced, output;
boolean wordToCheck;
Scanner myInput = new Scanner(System.in);
sentence = myInput.nextLine();
do
{
wordToCheck = true;
System.out.println("Please enter the word for replacement:");
wordToBeTargeted = myInput.nextLine;
if(sentence.toLowerCase().indexOf(wordToBeTargeted.toLowerCase()) == -1)
{
wordToCheck = false;
System.out.println("This word cannot be found in the sentence!")
}
else
{
System.out.println("Please enter the word you would like to replace with:");
wordToBeReplaced = myInput.nextLine();
}
}while(wordToCheck = false);
}
}
}
Write a file named TextProcessing.java that will replace all occurrences of a word in a string with another word
The expected outcome is like this:
I won't write the code out - you should still get something out of the exercise, but will give some direction. The first approach that comes to mind:
Split the first input on ' ' into a list
Iterate through the list, conditionally changing values based based on two input strings
As you're iterating you can either output into a new string / stringbuilder, or directly write to console depending on the requirements

How to split a string at every Nth occurrence of a character in Java [closed]

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I'm trying to split a String at every Nth occurence, but missing the last values.Here is what is expected.
Input : String str = "234-236-456-567-678-675-453-564";
Output :
234-236-456
567-678-675
453-564
Here N=3, where the str should be split at every 3rd occurence of -.
Try this.
String str = "234-236-456-567-678-675-453-564";
String[] f = str.split("(?<=\\G.*-.*-.*)-");
System.out.println(Arrays.toString(f));
result:
[234-236-456, 567-678-675, 453-564]
You can try the following with Java 8:
String str = "234-236-456-567-678-675-453-564";
Lists.partition(Lists.newArrayList(str.split("-")), 3)
.stream().map(strings -> strings.stream().collect(Collectors.joining("-")))
.forEach(System.out::println);
Output:
234-236-456
567-678-675
453-564
Maybe one of the worst way without using function available in java , but good like exercise :
public static void main(String[] args){
String s = "234-236-456-567-678-675-453-564";
int nth =0;
int cont =0;
int i=0;
for(;i<s.length();i++){
if(s.charAt(i)=='-')
nth++;
if(nth == 3 || i==s.length()-1){
if(i==s.length()-1) //with this if you preveent to cut the last number
System.out.println(s.substring(cont,i+1));
else
System.out.println(s.substring(cont,i));
nth=0;
cont =i+1;
}
}
}

valid word counter out of bounds error [closed]

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{
public static int WordCount (String cString)
{
String currentWord;
int index;
int spacePos;
int validWordCount=0;
boolean validWord;
char upClowC;
cString=cString.trim()+" ";
spacePos=cString.indexOf(" ");
validWord=true;
for(index=0;index<cString.length();index++)
{
currentWord=cString.substring(0,spacePos);
upClowC=Character.toUpperCase(currentWord.charAt(index));
if(upClowC<'A'||upClowC>'Z')
{
validWord=false;
}
}
if(validWord==true)
{
validWordCount++;
}
return validWordCount;
}
public static void main(String[] args)
{
String sentence;
System.out.println("enter a sentence:");
sentence=EasyIn.getString();
WordCount(sentence);
}
}
I'm trying to create a method which takes a sentence and picks out the valid words (i.e. no numbers or symbols), but I keep getting an out of bounds error.
I can't use an array.
Your problem is here:
currentWord = cString.substring(0, spacePos);
upClowC = Character.toUpperCase(currentWord.charAt(index));
currentWord gets shorter, but index is still running from 0 to the length of the string.
General notes:
Follow Java naming conventions and change the name of your method to begin with small letter
if(validWord) is enough when you want to compare something to true, otherwise it's like asking "is it true that the value is true" instead of simply "is the value true"
Next time post your stack trace to get better and sooner help
In your code, you are doing
spacePos = cString.indexOf(" ");
And then inside the loop:
currentWord = cString.substring(0,spacePos);
upClowC = Character.toUpperCase(currentWord.charAt(index));
Now, because of the loop, the index will take values from 0 to your string length minus 1. If your substring (currentWord) is smaller than your string - which probably is -, then currentWord.charAt(index) will try to index out of the bounds of the substring, which is why you get the error.

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