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1-D raw, sample of a .wav file [duplicate]

I want to read wav files in Java and I am going to classify them with K-means.
How can I read wav files in Java and assign them into an array or something like that(you can suggest ideas for it) to classify them?
EDIT: I want to use APIs for reading wav files and for K-means.

The official Java Sound Programmer Guide walks through reading and writing audio files.
This article by A Greensted: Reading and Writing Wav Files in java should be helpful. The WavFile class is very useful and it can be tweaked to return the entire data array instead of buffered fragments.

Equivalent to matlab's wavread function:
http://web.archive.org/web/20120531113946/http://www.builogic.com/java/javasound-read-write.html

You could read the sound files using javax sound library and FileInputStream
(found a nice example here)
and treat the wave files as a vector of bits (0,1) or bytes.. using multiple sequence alignment (Wiki) create a distance matrix between every stream of bits/bytes, and from there, the clustering should be straight forward.
The Problem is, that this method is very sensitive to noise, etc, but it is worth a shot...

Not sure if this will help someone. Java JDK already provides AudioSystem class.
I used this as part of my tests to check generated WAV properties,
AudioFileFormat audioFileFormat = AudioSystem.getAudioFileFormat(new File(response.get()));
assertEquals(1, audioFileFormat.getFormat().getChannels());
assertEquals(8000.0, audioFileFormat.getFormat().getSampleRate(), 0.0f);
assertEquals(8, audioFileFormat.getFormat().getSampleSizeInBits());

How do I convert heapbytebuffer to "File"?

I have a heapbytebuffer in a variable "myByteBuffer" that represents an audio wav that I want to playback. I see that AudioInputStream is a way to play files using AudioSystem.getAudioInputStream(soundFile). Since it accepts a "File", how can I convert the heapbytebuffer I have to a "File"?

Don't use the File overload unless you have (or want to save) a physical file. Just take your data and wrap it in an InputStream:
AudioSystem.getAudioInputStream(new ByteArrayInputStream(myByteBuffer.array()))
This assumes you're using the full buffer. If not, you can slice out the part you're using as necessary. See here for details.

Access the same file for read and write random position

Start by saying that I have not great experience in Java and I've done a lot of research. I would please ask you a specific question.
Thank you
I need to open a file for reading and writing from which I read and write a 512-byte blocks.
The file is fixed length and the information to be written will overlap with other existing.
For example, I read the first 512 bytes of the file and if it contains certain values write a block 512 to position 2048.
I tried using FileInputStream and FileOutputStream but every time I open with FileOutputStream the contents of the file are deleted.
It can be done with Java?
Roberto

Use a FileChannel; it allows random access to any part of a file, in read, write or any combination of both.
Example:
final Path path = Paths.get("path/to/the/file");
final FileChannel channel = FileChannel.open(path, relevantOptions);
Optionally, after that, you can use the .map() method.

Java 6 File Input Output Stream (same file)

I searched and looked at multiple questions like this, but my question is really different than anything I found. I've looked at Java Docs.
How do I get the equivalent of this c file open:
stream1 = fopen (out_file, "r+b");
Once I've done a partial read from the file, the first write makes the next read return EOF no matter how many bytes were in the file.
Essentially I want a file I/O stream that doesn't do that. The whole purpose of what I'm trying to do is to replace the bytes in an existing file in the current file. I don't want to do it in a copy or make a copy before I do the Read->Write.

You can use a RandomAccessFile.

As Perception mentions, you can use a RandomAccessFile. Also, in some situations, a FileChannel may work better. I've used these to handle binary file data with great success.
EDIT: you can get a FileChannel from the RandomAccessFile object using getChannel.

Change the volume of an audio file and save the file using java.sound.sampled

I want to change the volume of an audio file
and save the new file using java.sound.sampled.
I tried to use the mixer to create a source line
from the file given and a target line to the new file.
So that I can change the mixer settings to change the volume.
But the sound is being played to the system speaker.
Am I thinking along correct way or not?
Is there any other way to record a file from a line?
The code is available here
A solution I got is www.jsresources.org/examples/AmplitudeConverter.html.
But can the same be done within java.sound.sampled
without using external libraries.

To change the volume, if you don't use a "Control" (see the Java Sound Tutorials), there is the option of directly modifying the samples themselves.
In your innermost loop, convert the bytes in the innermost buffer into a sample (if it is WAV 16-bit encoding, then you need to put the two bytes together to make the single SHORT value), then multiply that value by a float that ranges from 0 to 1, where 0 is the quietest and 1 leaves the sound at full volume. Then take the result and break it back down into two bytes and pass it along.
Do you need the code to do this? There are several other posts here where folks convert from bytes to INTs or Float and back.
Hmmm. This question is pretty old. Well maybe my answer will help someone new to the same problem.