I have a jsonarray formatted like this:
String jsonArray = {"myList":[{"code":"01","price":"2,3", "date":"21/12/2014"},{"code":"02","price":"3,4", "date":"26/12/2014"}]}
Mylist class is:
public class MyList {
private String code;
private String price;
private String date;
//..getter and setter
}
My non working "deserializator" is the following:
ObjectMapper objectMapper = new ObjectMapper();
List<MyList> list = new ObjectMapper().readValue(jsonArray, new TypeReference<List<MyList>>() { });
catching the following exception:
org.codehaus.jackson.map.JsonMappingException: Can not deserialize instance of java.util.ArrayList out of START_OBJECT token
How can I solve that?
Thanks in advance!
Here's my own working solution using Gson:
String jsonArray = {"myList":[{"code":"01","price":"2,3", "date":"21/12/2014"},{"code":"02","price":"3,4", "date":"26/12/2014"}]}
Gson gson = new Gson();
JsonParser parser = new JsonParser();
List<MyList> list = new ArrayList<MyList>();
try {
JsonArray jArray = (JsonArray) parser.parse(jsonArray).getAsJsonObject().get("myList");
for (JsonElement jObj : jArray) {
MyList item = gson.fromJson( jObj , MyList.class);
list.add(item);
}
} catch (Exception e) {
e.printStackTrace();
}
Hope it will be useful for other users!
Related
I have a json as below. I want to get mobile_number from this jsonObject.
json:-
{"id": "ABCD", "report": { "data": { "phone": { "mobile_number": 9876543210, "active": "Y", "content": null } } } }
I am doing it like this and it works fine but can someone help me with any other approach for it without getting every key.
JSONObject jsonObject = new JSONObject(json);
JSONObject report = getJSONObjectFromJson(jsonObject, "report");
JSONObject data = getJSONObjectFromJson(jsonObject, "data");
JSONObject phone = getJSONObjectFromJson(data, "phone");
long mobileNumber = getLongFromJson(phone, "mobile_number");
private Long getLongFromJson(JSONObject object, String key){
return (object !=null && object.has(key)) ? object.getLong(key) : null;
}
private JSONObject getJSONObjectFromJson(JSONObject object, String key){
return (object !=null && object.has(key)) ? object.getJSONObject(key) : null;
}
I've just dealing with the similar issue and decided to use JsonPath like this:
final DocumentContext jsonContext = JsonPath.parse(jsonString);
final Object read = jsonContext.read("$['report']['data']['phone']['mobile_number']");
You can use Jackson ObjectMapper.
try {
ObjectMapper mapper = new ObjectMapper();
String jsonString = "{\"id\": \"ABCD\", \"report\": { \"data\": { \"phone\": { \"mobile_number\": 9876543210, \"active\": \"Y\", \"content\": null } } } }";
JsonNode rootNode = mapper.readTree(jsonString);
JsonNode mobileNumber = rootNode.path("report").path("data").path("phone").path("mobile_number");
System.out.println("Mobile Number: " + mobileNumber.longValue());
} catch (JsonParseException e) {
e.printStackTrace();
} catch (JsonMappingException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
So there are lot of ways to do it but everything leads eventually to traversing the tree.
So to conclude all the approaches,
1. **Convert string to JsonObject and traverse.**
JSONObject jsonObject = new JSONObject(json);
JSONObject report = getJSONObjectFromJson(jsonObject, "report");
JSONObject data = getJSONObjectFromJson(jsonObject, "data");
JSONObject phone = getJSONObjectFromJson(data, "phone");
long mobileNumber = getLongFromJson(phone, "mobile_number");
private Long getLongFromJson(JSONObject object, String key){
return (object !=null && object.has(key)) ? object.getLong(key) : null;
}
private JSONObject getJSONObjectFromJson(JSONObject object, String key){
return (object !=null && object.has(key)) ? object.getJSONObject(key) : null;
}
2. **Using jackson objectMapper to get the JsonNode and then traverse.**
ObjectMapper mapper = new ObjectMapper();
JsonNode jsonNode= mapper.readTree(json);
JsonNode mobileNumber = jsonNode.path("report").path("data").path("phone").path("mobile_number");
3. **Using gson jsonmapper to convert to map and then iterate the map.**
Gson gson = new Gson();
Map map = gson.fromJson(json, Map.class);
jsonObject.getJSONObject("x").getJSONObject("Y").getJSONObject("z");
Another route would be to leverage the ObjectMapper.
I have set response as JSON but get this
Could not write JSON: No serializer found for class org.json.JSONObject and no properties discovered to create BeanSerializer (to avoid exception, disable SerializationFeature.FAIL_ON_EMPTY_BEANS)
#RequestMapping(value = "/customerlist", method = RequestMethod.POST)
public ResponseGenerator getCustomerList() {
ResponseGenerator responseGenerator = new ResponseGenerator();
try {
responseGenerator.setCode(StatusCode.SUCCESS.code);
responseGenerator.setMessage(StatusCode.SUCCESS.message);
responseGenerator.setStatus(ResponseStatus.SUCCESS);
JSONObject data = userService.getUserList();
responseGenerator.setJSONData(data);
return responseGenerator; //error here
} catch (Exception e) {
logger.error("Error while getting Customer List : ", e);
e.printStackTrace();
responseGenerator.setCode(StatusCode.GENERAL_ERROR.code);
responseGenerator.setMessage(StatusCode.GENERAL_ERROR.message);
responseGenerator.setStatus(ResponseStatus.FAIL);
return responseGenerator;
}
}
userService.getUserList():
public JSONObject jsonResp;
public JSONObject getUserList() throws Exception{
jsonResp =new JSONObject();
//List<JSONObject> customers = new ArrayList<JSONObject>();
JSONObject jsonResponse = erpNextAPIClientService.getCustomerList();
//ObjectMapper objectMapper = new ObjectMapper();
//objectMapper.setVisibility(PropertyAccessor.FIELD, Visibility.ANY);
//JSONArray jsonArray = objectMapper.convertValue(jsonResponse.get("data"), JSONArray.class);
JSONArray jsonArray = jsonResponse.getJSONArray("data");
//JSONArray jsonArray =new Gson().fromJson(jsonResponse.get("data").toString(),JSONArray.class);
for (int i = 0; i < jsonArray.length(); i++) {
JSONObject cust = erpNextAPIClientService.getUser(jsonArray.getJSONObject(i).get("name").toString());
JSONObject custAddress =erpNextAPIClientService.getCustomerAddress(jsonArray.getJSONObject(i).get("name").toString());
JSONObject custData = new JSONObject(cust.getString("data"));
JSONObject custAddressData = new JSONObject(custAddress.getString("data"));
custData.accumulate("bill_to_address_line_one",custAddressData.get("address_line1"));
custData.accumulate("bill_to_address_line_two",custAddressData.get("address_line2"));
custData.accumulate("bill_to_city",custAddressData.get("city"));
custData.accumulate("bill_to_state",custAddressData.get("state"));
custData.accumulate("bill_to_zip",custAddressData.get("pincode"));
custData.accumulate("bill_to_country",custAddressData.get("country"));
jsonResp.put("data",custData);
System.out.println(custData.toString());
//customers.add(custData);
}
return jsonResp;
}
This will throw an error, as JSONObject does not expose default getter.
Although a workaround can be done to avoid this thing.
You need to change ResponseGenerator class to accept Map<String, Object> instead of JSONObject.
Now change this line:
responseGenerator.setJSONData(data);
to this:
responseGenerator.setJSONData(data.toMap());
I hope this should work.
P.S.: My recommendation would be to remove JSONObject conversion and instead return an Object of actual class,as internally spring uses jackson, which is more powerful JSON framework then org.json
Try with this in the entity class. It solved that issue.
#JsonIgnoreProperties({"hibernateLazyInitializer", "handler"})
I convert JSONObject in string for parse it in JsonNode with jackson but i have a List in my JSONObject and when i parse it with a ObjectMapper i get this :
["{Property1 : value1, Property2 : value2}"]
And i can't call myJsonNodeObject.get(i).get("Property1") this is my problem.
I have tried to cast my List in JSONArray in my JSONObject but don't work.
resultAsJSONObject = new JSONObject();
resultAsJSONObject.put("Label", getMetricStatisticsResult.getLabel());
resultAsJSONObject.put("Datapoints", getMetricStatisticsResult.getDatapoints());
resultAsJSONObject.put("fromDate", fromDate.getTimeInMillis());
resultAsJSONObject.put("toDate", toDate.getTimeInMillis());
resultAsJSONObject.put("error", "");
resultAsString = resultAsJSONObject.toString();
mapper.readValue(resultAsString, MetricsData.class);
Assuming that you have a JSON string which you just want to change. Then you can use Jackson to parse it as a ObjecNode and then modify it. Here is an example:
public class JacksonModifyJson {
static final String JSON = "{\"name\":\"Bob\", \"age\":13}";
public static void main(String[] args) throws IOException {
final ObjectMapper mapper = new ObjectMapper();
final ObjectNode jsonNode = mapper.readValue(JSON, ObjectNode.class);
jsonNode.put("url", "example.com");
System.out.println(mapper.writeValueAsString(jsonNode));
}
}
Output:
{"name":"Bob","age":13,"url":"example.com"}
THis method is really easy and works too
try {
JSONObject jsonObject = new JSONObject(THESTRINGHERE);
String[] names = JSONObject.getNames(jsonObject);
JSONArray jsonArray = jsonObject.toJSONArray(new JSONArray(names));
ArrayList<String> listdata = new ArrayList<String>();
JSONArray jArray = (JSONArray)jsonArray;
if (jArray != null) {
for (int i=0;i<jArray.length();i++){
listdata.add(jArray.get(i).toString());
}
}
// System.out.println(listdata);
} catch (Exception e) {
System.out.println(e.getMessage());
}
I would like to append JSON object to existing JSON array to get data structure like this.
"results":[
{
"lat":"value",
"lon":"value"
},
{
"lat":"value",
"lon":"value"
}
]
I'm trying to do it using the code in example, but unfortunately whole object is overriden everytime.
Log.i(AppHelper.APP_LOG_NAMESPACE, "POSITIONS AVAILABLE " + jsonDataString);
AppHelper helper = new AppHelper(ctx);
JSONObject mainObject = new JSONObject(jsonDataString);
JSONObject valuesObject = new JSONObject();
JSONArray list = new JSONArray();
//putv given values to the JSON
valuesObject.put("lat", lat.toString());
valuesObject.put("lon", lon.toString());
valuesObject.put("city", city);
valuesObject.put("street", street);
valuesObject.put("date", helper.getActualDateTime());
valuesObject.put("time", helper.getActualDateTime());
list.put(valuesObject);
//mainObject.put("values", list);
mainObject.accumulate("values", list);
saveJsonData(ctx, mainObject.toString(),"positions");
How it should be right?
Put and accumulate everytime rewrite all previous values, but i would like to append this object:
{
"lat":"value",
"lon":"value"
},
Into results parent.
BTW: I would like to do it without GSON.
Thanks for any help..
There isnt any problem with your code. It does append
String jsonDataString = "{\"results\":[{\"lat\":\"value\",\"lon\":\"value\" }, { \"lat\":\"value\", \"lon\":\"value\"}]}";
JSONObject mainObject = new JSONObject(jsonDataString);
JSONObject valuesObject = new JSONObject();
JSONArray list = new JSONArray();
valuesObject.put("lat", "newValue");
valuesObject.put("lon", "newValue");
valuesObject.put("city", "newValue");
valuesObject.put("street", "newValue");
valuesObject.put("date", "newValue");
valuesObject.put("time", "newValue");
list.put(valuesObject);
mainObject.accumulate("values", list);
System.out.println(mainObject);
This prints {"values":[[{"date":"newValue","city":"newValue","street":"newValue","lon":"newValue","time":"newValue","lat":"newValue"}]],"results":[{"lon":"value","lat":"value"},{"lon":"value","lat":"value"}]}.
Isnt this what you are expecting?
With gson you can do like
import com.google.gson.Gson;
import com.google.gson.JsonObject;
public class AddJson {
public static void main(String[] args) {
String json = "{\"results\":[{\"lat\":\"value\",\"lon\":\"value\" }, { \"lat\":\"value\", \"lon\":\"value\"}]}";
Gson gson = new Gson();
JsonObject inputObj = gson.fromJson(json, JsonObject.class);
JsonObject newObject = new JsonObject() ;
newObject.addProperty("lat", "newValue");
newObject.addProperty("lon", "newValue");
inputObj.get("results").getAsJsonArray().add(newObject);
System.out.println(inputObj);
}
}
Simple Approach
String jsonData = "{\"results\":[{\"lat\":\"value\",\"lon\":\"value\" }]}";
System.out.println(jsonData);
try {
JSONArray result = new JSONObject(jsonData).getJSONArray("results");
result.getJSONObject(0).put("city","Singapore");
jsonData = "{\"results\":"+result.toString()+"}";
System.out.println(jsonData);
} catch (JSONException e) {
e.printStackTrace();
}
OutPut Before Appending
{"results":[{"lat":"value","lon":"value" }]}
OutPut After Appending
{"results":[{"lon":"value","lat":"value","city":"Singapore"}]}
If you want to add new value to an Object you can try the below as well
Before:
{
"Name": "EnCoMa",
"Manager": "Abhishek Kasetty"
}
code :
JsonFactory factory = new JsonFactory();
ObjectMapper mapper = new ObjectMapper(factory);
ObjectWriter ow = new ObjectMapper().writer().withDefaultPrettyPrinter();
String json = ow.writeValueAsString(TheObjectToWhichYouWantToAddNewValue);
ObjectNode node = (ObjectNode) mapper.readTree(json);
node.putPOJO("new Key","new value")
after:
{
"Name": "EnCoMa",
"Manager": "Abhishek Kasetty",
"new Key": "new value"
}
I am making a JSON request to server using Java. Here is the following parameters.
{method:'SearchBySearchConfiguration',params:[{{SearchCriteria:'%arriva',
IsAccountSearch:true,IsContactSearch:false,SearchByName:true,SearchByAddress:false
CRMTextValues:[], CRMCurrencyValues:[]}]}
I could do this way.
JSONObject json=new JSONObject();
json.put("method", "SearchBySearchConfiguration");
How do I add the rest of params, in name-value pair to JSON object?
Thanks in advance!
One way I can think of is using the org.json library. I wrote a sample to build part of your request object:
public static void main(String[] args) throws JSONException {
JSONObject jsonObject = new JSONObject();
jsonObject.put("method", "SearchBySearchConfiguration");
JSONArray jsonArray = new JSONArray();
JSONObject innerRecord = new JSONObject();
innerRecord.put("SearchCriteria", "%arriva");
innerRecord.put("IsAccountSearch", true);
jsonArray.put(innerRecord);
jsonObject.put("params",jsonArray);
System.out.println("jsonObject :"+jsonObject);
}
The output is :
jsonObject :{"method":"SearchBySearchConfiguration","params":[{"IsAccountSearch":true,"SearchCriteria":"%arriva"}]}
Another technique would be to build Java objects that resemble your request structure. You can then convert it into json using Jackson library's ObjectMapper class.
In both cases once you get the json string, you can directly write it into the request body.
JSONObject json=new JSONObject();
json.put("method", "SearchBySearchConfiguration");
JSONArray paramsArr = new JSONArray();
JSONObject arrobj = new JSONOject();
arrobj.put("SearchCriteria","%arriva");
arrobj.put("IsAccountSearch","true");
arrobj.put("IsContactSearch","false");
arrobj.put("SearchByName","true");
arrobj.put("SearchByAddress","false");
arrobj.put("CRMTextValues",new JSONArray());
arrobj.put("CRMCurrencyValues",new JSONArray());
paramsArr.put(arrobj);
json.put("params",paramsArr);
The you can create JSONArray and put that array in JSONObject
Its Better to use gson for this.
First you need to create classs with following members :
public class TestClass{
private String method;
private ParamClass params;
}
public class ParamClass{
private String SearchCriteria;
private boolean IsAccountSearch;
private boolean IsContactSearch;
private boolean SearchByName;
private boolean SearchByAddress;
private String[] CRMTextValues;
private String[] CRMCurrencyValues;
}
Usage :
Serializing :
Gson gson = new Gson();
String jsonString = gson.toJson(testClassObject);
Deserializing :
Gson gson = new Gson();
TestClass testClassObject = gson.fromJson(jsonString , TestClass.class);
See this below example, where a JSONArray is returned and then how i am converting it in JSONObject form...
public JSONArray go() throws IOException, JSONException {
JSONArray json = readJsonFromUrl("http://www.xxxxxxxx.com/AppData.aspx");
return json;
}
JSONArray jarr;
for(int i=0 ; i<jarr.length() ; i++){
JSONObject jobj = jarr.getJSONObject(i);
String mainText = new String();
String provText = new String();
String couText = new String();
try{
mainText = jobj.getString("Overview");
System.out.println(mainText);
}catch(Exception ex){}
try{
JSONObject jProv = jobj.getJSONObject("Provider");
provText = jProv.getString("Name");
System.out.println(provText);
}catch(Exception ex){}
try{
JSONObject jCou = jobj.getJSONObject("Counterparty");
couText = jCou.getString("Value");
System.out.println(couText);
}catch(Exception ex){}
Jackson is a very efficient to do JSON Parsing
See this link:
http://jackson.codehaus.org/
Gson is provided by google which is also a good way to handle JSON.
To add params, JSONArray is used.
Inside params, we use JSONObject to add data such as SearchByAddress, IsAccountSearch ..etc.
Reference http://www.mkyong.com/java/json-simple-example-read-and-write-json/
package com.test.json;
import java.io.FileWriter;
import java.io.IOException;
import org.json.simple.JSONArray;
import org.json.simple.JSONObject;
import org.json.simple.JSONValue;
public class JsonSimpleExample {
public static void main(String[] args) {
JSONObject obj = new JSONObject();
obj.put("method", "SearchBySearchConfiguration");
JSONArray list = new JSONArray();
JSONObject innerObj = new JSONObject();
innerObj.put("SearchCriteria","%arriva" );
innerObj.put("IsAccountSearch",true);
innerObj.put("IsContactSearch",false);
innerObj.put("SearchByName",true);
innerObj.put("SearchByAddress",false);
innerObj.put("CRMTextValues",new JSONArray());
innerObj.put("CRMCurrencyValues",new JSONArray());
list.add(innerObj);
obj.put("params", list);
System.out.print(obj);
}
}