Just what the title says, if it helps in any way I have this java code (multipart consists of json object and file):
// Construct a MultiPart
MultiPart multiPart = new MultiPart();
multiPart.bodyPart(new BodyPart(inParams, MediaType.APPLICATION_JSON_TYPE));
multiPart.bodyPart(new BodyPart(fileToUpload, MediaType.APPLICATION_OCTET_STREAM_TYPE));
// POST the request
final ClientResponse clientResp = resource.type("multipart/mixed").post(ClientResponse.class, multiPart);
(using com.sun.jersey.multipart ) and I want to create the same in .NET (C#)
So far I managed to POST the json object like this:
Uri myUri = new Uri("http://srezWebServices/rest/ws0/test");
var httpWebRequest = (HttpWebRequest)WebRequest.Create(myUri);
httpWebRequest.Proxy = null;
httpWebRequest.Accept = "application/json";
httpWebRequest.ContentType = "application/json";
httpWebRequest.Method = "POST";
Console.Write("START!");
using (var streamWriter = new StreamWriter(httpWebRequest.GetRequestStream())){
string json = new JavaScriptSerializer().Serialize(new
{
wsId = "0",
accessId = "101",
accessCode = "x#ds!2"
});
streamWriter.Write(json);
streamWriter.Flush();
streamWriter.Close();
var httpResponse = (HttpWebResponse)httpWebRequest.GetResponse();
}
But I want to send the file together. The content type has to be "multipart/mixed" because that's what the web service gets. I tried to find some package that supports multiparts but I found nothing except maybe this http://www.example-code.com/csharp/mime_multipartMixed.asp (which is not free so I can't use it).
I finally managed to do it like this:
HttpContent stringStreamContent = new StringContent(json);
stringStreamContent.Headers.ContentType = new MediaTypeHeaderValue("application/json");
HttpContent fileStreamContent = new StreamContent(fileStream);
fileStreamContent.Headers.ContentType = new MediaTypeHeaderValue("application/octet-stream");
// Construct a MultiPart
// 1st : JSON Object with IN parameters
// 2nd : Octet Stream with file to upload
var content = new MultipartContent("mixed");
content.Add(stringStreamContent);
content.Add(fileStreamContent);
// POST the request as "multipart/mixed"
var result = client.PostAsync(myUrl, content).Result;
Related
I have the following Java code to send a POST request to SharePoint REST API to create a list and it returns the following authentication errors:
CloseableHttpClient httpClient = null;
try {
String user = xxx;
String password = xxx;
String domain = xxx;
String workstation = "";
CredentialsProvider credsProvider = new BasicCredentialsProvider();
credsProvider.setCredentials(new AuthScope(AuthScope.ANY),
new NTCredentials(user, password, workstation, domain));
httpClient = HttpClients.custom().setDefaultCredentialsProvider(credsProvider).build();
String digestQueryURL = "http://my_sharepoint_site/_api/contextinfo";
HttpPost httpPost = new HttpPost(digestQueryURL);
httpPost.addHeader("Accept", "application/json;odata=verbose");
CloseableHttpResponse response = httpClient.execute(httpPost);
byte[] content = EntityUtils.toByteArray(response.getEntity());
String jsonString = new String(content, "UTF-8");
ObjectMapper mapper = new ObjectMapper();
JsonNode j = mapper.readTree(jsonString);
String formDigestValue = j.get("d").get("GetContextWebInformation").get("FormDigestValue").toString();
response.close();
// now try to create the list
String url = "http://my_sharepoint_site/_api/web/lists";
HttpPost httpPost2 = new HttpPost(url);
httpPost2.addHeader("X-RequestDigest", getFormDigest(httpClient));
httpPost2.addHeader("Accept", "application/json;odata=verbose");
httpPost2.addHeader("Content-Type", "application/json;odata=verbose");
String body = "{ '__metadata': { 'type': 'SP.List' }, 'AllowContentTypes': true, 'BaseTemplate': 100, 'ContentTypesEnabled': true, 'Description': 'My list description', 'Title': 'Test' }";
StringEntity se = new StringEntity(body);
httpPost2.setEntity(se);
CloseableHttpResponse response2 = httpClient.execute(httpPost2);
StringBuilder result = new StringBuilder();
System.out.println(response2.getStatusLine().toString());
BufferedReader br = new BufferedReader(new InputStreamReader(response2.getEntity().getContent()));
String output;
while ((output = br.readLine()) != null) {
result.append(output);
}
System.out.println(result.toString());
} catch (Exception e) {
}
Console output
HTTP/1.1 403 FORBIDDEN
{"error":{"code":"-2130575251, System.Runtime.InteropServices.COMException","message":{"lang":"en-US","value":"The security validation for this page is invalid. Click Back in your Web browser, refresh the page, and try your operation again."}}}
I can use very similar code to send GET requests to the REST API to retrieve all lists, retrieve list items, perform all these read operations. However this does not work for POST requests. Am I doing something wrong? The credentials provided are for an account that has full control over the entire site collection, so we can rule out permission errors.
Alright, the problem is really very simple. This line:
String formDigestValue = j.get("d").get("GetContextWebInformation").get("FormDigestValue").toString();
Returns the formDigestValue with quotation marks enclosing it. Using asText() instead of toString() helped.
I need to convert the following code from Java to C# when I'm using restAPI in C#.
In java :
HttpGet statusGet = new HttpGet(fileUrl);
statusGet.setHeader("X-API-TOKEN", API_TOKEN);
HttpResponse response = httpClient.execute(statusGet);
// Extract exported file
ZipInputStream zs = new ZipInputStream(response.getEntity().getContent());
In C# this is what I have:
var client1 = new RestClient(fileUrl);
var request1 = new RestRequest(Method.GET);
request1.AddHeader("X-API-TOKEN", "API_TOKEN");
request1.AddHeader("content-type", "application/json");
request1.AddParameter("application/json", "{\n\t\"format\" : \"csv\",\n\t\"surveyId\" : \"_surveyId\"\n}", ParameterType.RequestBody);
IRestResponse responsedata = client1.Execute(request1);
var download=client1.DownloadData(request1);
MemoryStream stream = new MemoryStream(download);
ZipInputStream zs = new ZipInputStream(stream);
using (ZipFile zip1 = ZipFile.Read(zs))
I have no clue how to implement response.getEntity().getContent(). I believe it is getting the Stream(Containing a zip file?)
Updated: So I get the byte array from client1.DownloadData(request1), looks like it is not right to convert it to stream (has readtimeout exception). and it will not be able to read from zipfile.read
Thank you so much for your help
Are you getting any specific errors? It looks like you are implementing this using RestSharp. Have you followed their examples and read through their documentation?
I have not personally used this third-party solution, but immediately on their front page they have the following example that does exactly what you are trying to do:
var client = new RestClient("http://example.com");
// client.Authenticator = new HttpBasicAuthenticator(username, password);
var request = new RestRequest("resource/{id}", Method.POST);
request.AddParameter("name", "value"); // adds to POST or URL querystring based on Method
request.AddUrlSegment("id", "123"); // replaces matching token in request.Resource
// easily add HTTP Headers
request.AddHeader("header", "value");
// add files to upload (works with compatible verbs)
request.AddFile(path);
// execute the request
IRestResponse response = client.Execute(request);
var content = response.Content; // raw content as string
// or automatically deserialize result
// return content type is sniffed but can be explicitly set via RestClient.AddHandler();
RestResponse<Person> response2 = client.Execute<Person>(request);
var name = response2.Data.Name;
// easy async support
client.ExecuteAsync(request, response => {
Console.WriteLine(response.Content);
});
// async with deserialization
var asyncHandle = client.ExecuteAsync<Person>(request, response => {
Console.WriteLine(response.Data.Name);
});
// abort the request on demand
asyncHandle.Abort();
It looks like you would want to access the IRestResponse.Content property, or to deserialize using the RestClient.Execute<T>(RestRequest request) function.
Below is the Http post method for file upload in c#. What is the equivalent for this code in java which uses apache library. How to add contentDisposition in java and pass byte array value in it. Providing some online reference is much appreciated.
C# Code
byte[] date = //file in byte format
var fileContent = new StreamContent(new MemoryStream(data));
fileContent.Headers.ContentDisposition = new ContentDispositionHeaderValue("form-data")
{
Name = "\"files\"",
FileName = "\"" + filename + "\""
}; // the extra quotes are key here
fileContent.Headers.ContentType = new MediaTypeHeaderValue(contentType);
var content = new MultipartFormDataContent();
content.Add(fileContent);
HttpResponseMessage response = null;
HttpRequestMessage request = new HttpRequestMessage(HttpMethod.Post, _url + uri);
request.Content = content;
My Java Code
StringBody name = new StringBody("\"files\"", ContentType.MULTIPART_FORM_DATA);
StringBody file = new StringBody("\"" + filename + "\"", ContentType.MULTIPART_FORM_DATA);
HttpEntity entity = MultipartEntityBuilder.create()
.addPart("Name", name)
.addPart("FileName", file)
.addBinaryBody("file", data)
.build();
Postmethod = new HttpPost(_url + uri);
Postmethod.addHeader(useragent);
Postmethod.addHeader(Accesstoken);
Postmethod.setEntity(entity);
Postmethod.addHeader("content-type", contentType);
response = httpClient.execute(Postmethod);
The response status code is 400 .Where did I go wrong?
Thanks in Advance..
In one of my application i am cropping the image using http://fengyuanchen.github.io/cropper/
The resultant cropped image am getting in the base64 dataURL format, but i required that to be in file object format.
How to convert the dataURL to file either in client side or server side.
Use Blob instead of the deprecated BlobBuilder. The code is very clean and simple. (Manuel Di Iorio's code is deprecated.)
function dataURLtoBlob(dataurl) {
var arr = dataurl.split(','), mime = arr[0].match(/:(.*?);/)[1],
bstr = atob(arr[1]), n = bstr.length, u8arr = new Uint8Array(n);
while(n--){
u8arr[n] = bstr.charCodeAt(n);
}
return new Blob([u8arr], {type:mime});
}
//test:
//var blob = dataURLtoBlob('data:text/plain;base64,YWFhYWFhYQ==');
Data URI scheme
How to convert dataURL to file object in javascript?
function dataURItoBlob(dataURI) {
// convert base64 to raw binary data held in a string
// doesn't handle URLEncoded DataURIs - see SO answer #6850276 for code that does this
var byteString = atob(dataURI.split(',')[1]);
// separate out the mime component
var mimeString = dataURI.split(',')[0].split(':')[1].split(';')[0];
// write the bytes of the string to an ArrayBuffer
var ab = new ArrayBuffer(byteString.length);
var ia = new Uint8Array(ab);
for (var i = 0; i < byteString.length; i++) {
ia[i] = byteString.charCodeAt(i);
}
// write the ArrayBuffer to a blob, and you're done
var bb = new BlobBuilder();
bb.append(ab);
return bb.getBlob(mimeString);
}
Then just append the blob to a new FormData object and post it to your server using ajax:
var blob = dataURItoBlob(someDataUrl);
var fd = new FormData(document.forms[0]);
var xhr = new XMLHttpRequest();
fd.append("myFile", blob);
xhr.open('POST', '/', true);
xhr.send(fd);
Thats my validation for input.
$data = $_POST['thumb'];
$uriPhp = 'data://' . substr($data, 5);
if ( base64_encode(base64_decode($uriPhp))){
$_POST['thumb'] = $uriPhp;
}
for saving I am using : http://www.verot.net/php_class_upload.htm
$foo = new Upload($_POST['thumb']);
if ($foo->uploaded) {
// save uploaded image with a new name
$foo->file_new_name_body = $name;
$foo->image_convert = 'png';
$foo->Process("uploads/");
}
My Goal is to request GoogleTaskAPI for TASKLIST with specified no.of result.
It works fine, If I m passing no requestBody. But I need to pass request parameter to specific number of results to be returned. When I do that, it creates new Tasklist, Instead of listing. So how to do this?
My Code:
GoogleAccessProtectedResource access = new GoogleAccessProtectedResource(accessToken, httpTransport, jsonFactory, clientId, clientSecret, refreshToken);
HttpRequestFactory rf = httpTransport.createRequestFactory(access);
String endPointUrl = "https://www.googleapis.com/tasks/v1/users/#me/lists";
String requestBody = "{\"maxResults\":3}";
GenericUrl endPoint = new GenericUrl(endPointUrl);
ByteArrayContent content = new ByteArrayContent("application/json", requestBody.getBytes());
//Try 0: Works, But Retrieving all of my Tasklist, I need only 3
//HttpRequest request = rf.buildGetRequest(endPoint);
//-------
//Try 1: Fails to retrieve
//HttpRequest request = rf.buildGetRequest(endPoint);
//request.setContent(content);
//request.getContent().writeTo(System.out);
//-------
//Try 2: Fails to retrieve
HttpRequest request = rf.buildRequest(HttpMethod.GET, endPoint, content);
request.getContent().writeTo(System.out);
//-------
HttpResponse response = request.execute();
String str = response.parseAsString();
utils.log(str);
maxResults is a query parameter, not a request parameter, so you can just put it in the url:
String endPointUrl = "https://www.googleapis.com/tasks/v1/users/#me/lists?maxResults=3";
You should also consider using the Java client's Tasks interface for making requests; it may be a little easier since it handles the details of the url for you:
http://code.google.com/p/google-api-java-client/wiki/APIs#Tasks_API