I've got a JSONArray that I pull from a server, it is a report of the emails I send to the server. My goal is to go through it, pick the one with a specific subject and print the "recieved" number from that element of the array. The JSON looks like this:
[
{"rejections":58,"timestamp":"2014-08-08 12:46:26","subject":"2014/08/08 12:46:03.604: apitest ACTION_100_","clicks":0,"opens":28,"streams":0,"received":86,"bounces":0,"complaints":0,"unsubs":0}
{"rejections":77,"timestamp":"2014-08-11 13:54:49","subject":"2014/08/11 13:54:25.786: apitest ACTION_100_","clicks":0,"opens":14,"streams":0,"received":91,"bounces":0,"complaints":0,"unsubs":0}
]
I'm basically trying to echo the number associated with "recieved": where the subject is "2014/08/11 13:54:25.786: apitest ACTION_100_" ... I don't know how to do the if statement. I know it will look something like:
if(thisElement["subject"].equals("2014/08/11 13:54:25.786: apitest ACTION_100_")){
echo thisElement["recieved"];
}`
My code:
//json = the first code block in this post
//newSubj = the subject I mentioned above
JSONArray json = readJsonFromUrl(serverStats);
for (int i = 0; i < json.length(); i++)
{
JSONObject obj = json.getJSONObject(i);
//if(obj["subject"].equals(newSubj)) <----- ?
System.out.println(obj.toString()); // should this be obj["recieved"].toString()?
}
http://www.json.org/javadoc/org/json/JSONObject.html
if (newSubj.equals(obj.get("subject")) {
int received = obj.getInt("received");
System.out.println(received);
}
Related
Very new to JSON, this is probably very simple but I'm not sure how to access the "coordinates" in this JSON I know how to go from resourceSets to resources but get stuck at "point":
{
"resourceSets":[
{
"estimatedTotal":1,
"resources":[
{
"__type":"Location:http:\/\/schemas.microsoft.com\/search\/local\/ws\/rest\/v1",
"bbox":[
51.3223903,
-0.2634519,
51.3246386,
-0.2598541
],
"name":"name",
"point":{
"type":"Point",
"coordinates":[
51.3235145,
-0.261653
]
}
}
]
}
]
}
My code so far:
JSONParser parser = new JSONParser();
JSONObject jObj = (JSONObject)parser.parse(result);
JSONArray jsonArray = (JSONArray)jObj.get("resourceSets");
for (int i = 0; i < jsonArray.size(); i ++) {
JSONObject jObjResourceSets = (JSONObject)jsonArray.get(i);
JSONArray jsonArray2 = (JSONArray)jObjResourceSets.get("resources");
System.out.println("Coords" + jObjResourceSets.get("point"));
}
Lets analyse what you're doing (and need to be doing), step by step, in order to get the "coordinates".
First of all, JSON is a great language to transfer static data. It works like a dictionary, where you have a key and the respective value. The key should always be a String, but the value can be a String, an int/double or even an array of other JSON objects. That's what you have.
For instance, "estimatedTotal" is an element (JSONObject) from the "resourceSet" array (JSONArray).
JSONArray jsonArray = (JSONArray)jObj.get("resourceSets");
What you're saying here is straight forward: from your overall JSONObject - jObj - you want to extract the array with key "resourceSets".
Now you have direct access to "resourceSets" array elements: "estimatedTotal", "resources", etc. So, by applying the same logic, in order to access "coordinates" we need to access the "resources" array. And by that I mean to create a JSONArray object like we did before.
JSONArray jsonResourcesArray = (JSONArray)jObjResourceSets.get("resources");
I hope it's clear what's the content of jsonResourcesArray here. It's the JSON array of "__type", "bbox", "name", "point", (...). The Coordinates howevere are inside "point" JSON object. How do we access it?
JSONObject jsonPointObject = (JSONObject) jsonResourcesArray.get("point");
And you know by know that "jsonPointObject" has as its values the following JSON objects: "type" and "coordinates". Coordinates is an array of values, so do we have to use JSONArray or JSONObject?
JSONArray jsonCoordinatesArray = (JSONArray) jsonPointObject.get("coordinates");
From which we mean: from the jsonPointObject we want to extract the array that has key "coordinates". Now your array is a JSONArray with values of jsonCoordinatesArray.get(0) and jsonCoordinatesArray.get(0).
Now you have, not only the code to get those values, but the understanding of how JSON works and how Java interacts with it so you can solve any Json problem from now on.
Normally this code works for the given JSON object. However I'll put the tested formatted JSON value below the java code so you can test it as well.
Note that this code will get you all the coordinates of all the elements in your object.
public static void main(String[] args) throws Exception {
String result = getJsonString();
// Getting root object
JSONParser parser = new JSONParser();
JSONObject jObj = (JSONObject)parser.parse(result);
// Getting resourceSets Array
JSONArray jsonArray = (JSONArray)jObj.get("resourceSets");
for (int i = 0; i < jsonArray.size(); i++) {
// Getting the i object of resourceSet
JSONObject jObjResourceSets = (JSONObject) jsonArray.get(i);
// Getting resources list of the current element
JSONArray jsonArray2 = (JSONArray) jObjResourceSets.get("resources");
for (int j = 0; j < jsonArray2.size(); j++) {
// Getting the j resource of the resources array
JSONObject resource = (JSONObject) jsonArray2.get(j);
// Getting the point object of the current resource
JSONObject point = (JSONObject) resource.get("point");
// Getting the coordinates list of the point
JSONArray coordinates = (JSONArray) point.get("coordinates");
for (int k = 0; k < coordinates.size(); k++) {
System.out.println("Coordinates[" + k + "]: " + coordinates.get(k));
}
// Printing an empty line between each object's coordinates
System.out.println();
}
}
}
The tested JSON Object:
{
"resourceSets":[
{
"estimatedTotal":1,
"resources":[
{
"__type":"Location:http:\/\/schemas.microsoft.com\/search\/local\/ws\/rest\/v1",
"bbox":[
51.3223903,
-0.2634519,
51.3246386,
-0.2598541
],
"name":"name",
"point":{
"type":"Point",
"coordinates":[
51.3235145,
-0.261653
]
}
}
]
}
]
}
If it worked please mark it as the answer.
Good luck ^^
B.
You need the following piece of code to get the data.
JSONArray jsonArray2 = (JSONArray)jObjResourceSets.get("resources");
/**
* here we should note that the "resources" is only having one JSON object hence we can take it as below
* from 0th index using ((JSONObject)jsonArray2.get(0)) these piece of code and the next part is to take the point JSONObject
* from the object.
*/
JSONObject temp = (JSONObject)((JSONObject)jsonArray2.get(0)).get("point");
System.out.println("Coords"+temp.get("coordinates")); //this will give you the coordinates array
//now if you want to do further processing, traverse in the jsonArray like below
JSONArray arr= (JSONArray)temp.get("coordinates");
System.out.println("X coordinate:"+arr.get(0));
System.out.println("Y coordinate:"+arr.get(1));
For more information and further details on JSONObject and JSONArray you can go through this linkparsing-jsonarray-and-jsonobject-in-java-using-json-simple-jar
json-simple-example-read-and-write-json
I have following JSONObject (not array, which I don't mind to convert). I am trying to do two things:
get the count of genre entry as "poetry" (count = 2).
get the key value of author name and genre:
authorName = malcolm
genreName = newsarticle
authorName = keats
genreName = poetry
{ "AddressBook" :{
"Details" :{
"authorname" :{
"Author-malcolm":{
"genre" :"poetry"
}
"Author-keats":{
"genre" :"poetry"
}
}
}
}
}
Code which I tried:
public static void main(String[] args) throws Exception, IOException, ParseException {
JSONParser parser = new JSONParser();
Object obj = parser.parse(new FileReader("My path to JSON"));
JSONObject jsonObject = (JSONObject) obj;
JSONArray arrayhere = new JSONArray();
arrayhere.add(obj);
System.out.println(arrayhere);
int count = 0;
for(int i = 0; i < arrayhere.size(); i++) {
JSONObject element = arrayhere.getJSONObject(i);//The method getJSONObject(int) is undefined for the type JSONArray
String branchName = element.getString("genre");//The method getString(String) is undefined for the type JSONObject
if(branchName.equals("poetry")) {
count ++;
}
}
System.out.println("Count f0r poetry genre=" + count);
}
}
I have looked at solutions all over. There is no question similar to this at stackoverflow. I am not sure if the procedure is correct.
A few problems here.
First, I'm not sure where you got that example JSON but you can't work with that. That's not even valid JSON Formatting.
Looks like you want something like this:
{
AddressBook:
[
{
authorname: "author-malcom",
genre:"poetry"
},
{
authorname: "author-keats",
genre: "poetry"
}
]
}
That's the structure you're trying to create in JSON.
So, you're parsing this in from a file into a JSONObject that has a key called AddressBook inside of it. That key points to an array of JSONObjects representing authors. Each of those objects will have a key called genre. You're trying to access the genre key and count on a condition.
What you did above was create attempt to create a JSONObject from an invalid string, and then add the entire JSONObject itself into the JSONArray. JSONArray.add() doesn't convert an object to an array, it literally adds it onto the array.
jsonObj => {"Name":"name1","Id":1000}
jsonArray.add(jsonObj)
jsonArray => [{"Name":"name1","Id":1000}]
That's what you did in your code above. You didn't create an array from a JSONObject, you added an object to the array.
Proper use is going to look like:
Object obj = parser.parse(new FileReader("path_to_file"));
JSONObject jobj = (JSONObject) obj;
//access key AddressBook
JSONArray author_array = jobj.getJSONArray("AddressBook");
int poetry = 0;
for(int i = 0; i < author_array.length(); i++) {
JSONObject author = (JSONObject) author_array.get(i);
if(author.getString("genre").equals("poetry")) {
poetry++;
}
}
To summarize, you're problems come from a lack of understanding about JSON Formatting and how to access elements within a JSON Object.
Paste in the sample JSONObject I gave you above here. That site will let you visualize what you're working with.
I am trying to get json data from a fake api call and need to get the count of the items in it(so that in future I can call the actual restful service). I am not able to get the number of departments in the json. I am expecting the result as 4(int) here.
I am not able to get the string value(json) for the code below:
String json = client.target("file:///C:/Program%20Files%20(x86)/apache-tomcat-8.0.35/webapps/GetProducts.json").request(MediaType.TEXT_PLAIN).get(String.class);
Please find below the entire code:
String json = client.target("file:///C:/Program%20Files%20(x86)/apache-tomcat-8.0.35/webapps/GetProducts.json").request(MediaType.TEXT_PLAIN).get(String.class);
JSONObject jsnobject = new JSONObject(json);
JSONArray jsonArray = jsnobject.getJSONArray("locations");
for (int i = 0; i < jsonArray.length(); i++) {
JSONObject explrObject = jsonArray.getJSONObject(i);
}
JSON Sample:
{
"Department":
[
{"SectionId":"1","SectionName":"Childrens Wear"},
{"SectionId":"2","SectionName":"Womens Wear"},
{"SectionId":"3","SectionName":"F&A"},
{"SectionId":"1","SectionName":"Mens Wear"}
]
}
I am new to java as well as api's.
Thanks,
You are either using incorrect key in code or you posted incorrect JSON example. You used locations as the key incode however there is no value against that key in sample JSON. You need to use Department as the key.
JSONArray jsonArray = jsnobject.getJSONArray("Department");
In my android project, I have an activity in which I want to obtain data from database using a PHP script. I manage the result of the script in this line :
String result = EntityUtils.toString(entity);
I created the jsonObject :
JSONObject jsonObject = new JSONObject(result);
I print this line and get: {"id":"1"}{"id":"2"}{"id":"3"}
But when I do this:
int i;
for(i=0;i<array.length;i++)
{
array[i] = "ID : "+jsonObject.getString("id");
}
I obtain "id : 1" three times, so I think there are some errors in the cycle..
the code of script php is here :
#Get the first row of the results
while ($row = mysqli_fetch_row($data)) {
#Build the result array (Assign keys to the values)
$result_data = array(
'id' =>$row[0],
);
#Output the JSON data
echo json_encode($result_data);
change to:
int i;
for(i=0;i<array.length;i++)
{
jsonObject=array[i];
String s = "ID : "+jsonObject.getString("id");
}
{"id":"1"}{"id":"2"}{"id":"3"}
is no valid code for a single JSON object - see here: JSON syntax.
I can only guess what you try to achieve, but I would guess your intention is to have a JSON array with 3 objects, each having an "id" value. The JSON code for such a structure should look like this:
[{"id":"1"},{"id":"2"},{"id":"3"}]
If you can make "EntityUtils.toString(entity)" to return the above JSON code, the following loop should also work:
JSONArray ja = new JSONArray(result);
for (int i = 0; i < ja.length(); i++) {
JSONObject jsonObject = ja.getJSONObject(i);
System.out.println("ID : "+jsonObject.getString("id"));
}
edit
On a side note: I believe you get the result you describe, because when you call
new JSONObject(result);
where the result is a String that consists of
{"id":"1"}{"id":"2"}{"id":"3"}
then most likely JSONObject stops parsing the JSON code after the first right brace without throwing a parse exception. So it actually only parses the first JSON object and because of this you get "id : 1" three times. Personally I would consider this behavior a bug, so consider reporting it.
My PHP code is this:
$userdetails = mysqli_query($con, "SELECT *FROM aircraft_status");
#$row = mysql_fetch_row($userdetails) ;
while($rows=mysqli_fetch_array($userdetails)){
$status[]= array($rows['Aircraft']=>$rows['Status']);
}
#Output the JSON data
echo json_encode($status);
and gives this:
[{"A70_870":"1"},{"A70_871":"1"},{"A70_872":"1"},{"A70_873":"1"},{"A70_874":"1"},{"A70_875":"1"},{"A70_876":"2"},{"A70_877":"1"},{"A70_878":"2"},{"A70_879":"2"},{"A70_880":"2"},{"A70_881":"0"},{"A70_882":"0"},{"A70_883":"0"},{"A70_884":"0"},{"A70_885":"0"}]
The java code that reads it is this:
// Create a JSON object from the request response
JSONObject jsonObject = new JSONObject(result);
//Retrieve the data from the JSON object
n870 = jsonObject.getInt("A70_870");
n871 = jsonObject.getInt("A70_871");
n872 = jsonObject.getInt("A70_872");
n873 = jsonObject.getInt("A70_873");
n874 = jsonObject.getInt("A70_874");
n875 = jsonObject.getInt("A70_875");
n876 = jsonObject.getInt("A70_876");
n877 = jsonObject.getInt("A70_877");
n878 = jsonObject.getInt("A70_878");
n879 = jsonObject.getInt("A70_879");
n880 = jsonObject.getInt("A70_880");
n881 = jsonObject.getInt("A70_881");
n882 = jsonObject.getInt("A70_882");
n883 = jsonObject.getInt("A70_883");
n884 = jsonObject.getInt("A70_884");
n885 = jsonObject.getInt("A70_885");
When i run my android app I seem to keep getting the error:
"of type org.json.JSONArray cannot be converted into Json object"
However when I send the app dummy code without the square brackets, it seems to work fine! How do I get rid of those [ and ] brackets on the ends???
Alternatively is there a way to accept the json as it is and adapt the java to read it?
echo json_encode($status, JSON_FORCE_OBJECT);
Demo: http://codepad.viper-7.com/lrYKv6
or
echo json_encode((Object) $status);
Demo; http://codepad.viper-7.com/RPtchU
Instead of using JSonobject, use JSONArray
JSONArray array = new JSONArray(sourceString);
Later loop through the array and do the business logic.
http://www.json.org/javadoc/org/json/JSONArray.html
Maybe with this kind of json structure?
$status[$rows['Aircraft']]= $rows['Status'];
You get an JSONArray, Not Object, you could create an Object holding an array, or parsing the array.
Refering to this post
Solution #1 (Java)
How about a helper method like this:
private int getProp(String name, JSONArray arr) throws Exception {
for (int i = 0; i < arr.length(); ++i) {
JSONObject obj = arr.getJSONObject(i);
if (obj.has(name))
return obj.getInt(name);
}
throw new Exception("Key not found");
}
Then you could use it like:
JSONArray jsonArray = new JSONArray(result); // note the *JSONArray* vs your *JSONObject*
n870 = getProp("A70_870", jsonArray);
n871 = getProp("A70_871", jsonArray);
...
Note I haven't tested this code, so you may need to make some changes...
Alternate solution (PHP)
It's been awhile since I've worked with PHP, but you might be able to leave your Java code intact and change your PHP int the while-loop body to:
$status[$rows['Aircraft']] = $rows['Status'];