All Arrays in ArrayList get overwritten - java

Here I have a loop in a loop to fill level but when it runs through it fills each ArrayList(Integer) the same way, so in the end every row is the exact same. I just can't figure out how this is even possible, when I am filling in every single field one by one.
//... level = new ArrayList<ArrayList<Integer>>();
for(int x = 0; x < currentLevel.getLevelHeight(); x++){
for(int y = 0; y < currentLevel.getLevelWidth(); y++){
currentLevel.getLevel().get(x).set(y, Integer.parseInt(allLines.split("\\.")[x].toString().split(";")[y]));
System.out.print(currentLevel.getLevel().get(x).get(y));
}
System.out.println("");
}

You must have initialized
level = new ArrayList<ArrayList<Integer>>();
badly. There is only one object ArrayList<Integer> and it is stored repeatedly to create the List of Lists.

Related

Error with adding element to list - repeating n-time last element

Could anyone help me and point out what is wrong here? All the fields are non-static. Function shuffle returns each time different array.
List<Point[]> someArray = new ArrayList<Point[]>();
for(int i = 0; i < 4; i++) {
Point[] temporary = new Point[50];
temporary = shuffle(pointsArray.getPoints());
someArray.add(temporary);
print(someArray.get(i));
}
The result of print in the first loop is ok since they're different. Right after getting out of the loop, I want to print elements of list someArray again.
for(int i = 0; i < 4; i++) {
print(someArray.get(i));
}
The result here is 4 time of the last element.

Checking for Adjacent elements in 2d Arrays and replacing them

So, I am building a method to check a 2d array for a target value and replace each adjacent element with that target value. I have literally tried to brainstorm the solution to this for about an hour and I just want to know if anyone can help me with this, this is the code I have so far
public int[][] replaceValue(int n, int[][]y){
int [][]temp0 = new int[y.length][y[0].length];
int[]top, down ,left, right = new int[y[0].length];
for(int row = 0; row < y.length; row++){
for(int col = 0; col < y[row].length; col++){
temp0[row][col] = y[row][col];// new array so I wouldn't mess with the array passed in
}
}
for(int row = 0; row < temp0.length; row++){
for(int col = 0; col < temp0[row].length; col++){
top[row] = temp0[row-1][col];
down[row] = temp0[row+1][col];
right[row] = temp0[row][col+1];
left[row] = temp0[row] [col-1];
}
}
I got error messages such as I didn't initialize my top and left and right and down variables but I simply don't understand how the logic works for checking the adjacent elements and making sure the whole array is not replaced with the target value. Thanks
The question is a little confusing so I will try to interpret it.
What you are given is a 2-dimensional array with some integer values. Your function should scan the 2-d array, and if you find some target value,
return a 2-d array with the adjacent indices as the target value as well.
For example, if we have a 3x3 array and the target is 2...
1 1 1 1 2 1
1 2 1 ====> 2 2 2
1 1 1 1 2 1
Your problem is that you can't think of a way to change the value without changing the entire array to 2.
Solution One: You scan for the target value in the given array, but you update the values in the temporary array.
Solution Two: You scan the temporary array, and store whether or not it should be changed using a 2-d boolean array.
Solution One is much better in terms of efficiency (both memory and time), so I'll just give you my solution #2, and leave you to do Solution One on your own.
Also, please use more descriptive variable names when it matters :P (why is the input called temp??)
public static int[][] replaceValue(int target, int[][] currArray){
int[][] temp = new int[currArray.length][];
//get a boolean array of same size
//NOTE: it is initialized as false
boolean[][] needsChange = new boolean[currArray.length][currArray[0].length];
//copy the current array into temp
for(int i = 0; i < currArray.length; i++){
temp[i] = currArray[i].clone();
}
//Go through each value in the 2d array
for(int i = 0; i < temp.length; i++){
for(int j = 0; j < temp[0].length; j++){
//if it is the target value, mark it to be changed
if(temp[i][j] == target){
needsChange[i][j] = true;
}
}
}
//Go through each value in the 2d array
for(int i = 0; i < temp.length; i++){
for(int j = 0; j < temp[0].length; j++){
if(needsChange[i][j]){ //NOTE: same as "needsChange[i][j] = true;"
//Now, we will check to make sure we don't go out of bounds
//Top
if(i > 0){
temp[i-1][j] = target;
}
//Bottom
if(i + 1 < temp.length){
temp[i+1][j] = target;
}
//Left
if(j > 0){
temp[i][j-1] = target;
}
//Right
if(j + 1 < temp[0].length){
temp[i][j+1] = target;
}
}
}
}
//return the new array we made
return temp;
}
You have not initialized your local variables before first use. So you need to change your 3rd line to some thing like the below code:
int[] top = new int[temp[0].length], down = new int[temp[0].length],
left = new int[temp[0].length], right = new int[temp[0].length];
After that your code is compiled and you can check your logic.

How do I loop thorough a 2D ArrayList in Java and fill it?

I am trying to use 2D arrayLists in Java.
I have the definition:
ArrayList<ArrayList<Integer>> myList = new ArrayList<ArrayList<Integer>>();
How can I loop through it and enter in numbers starting from 1?
I know that I can access a specific index by using:
myList.get(i).get(j)
Which will get the value. But how do I add to the Matrix?
Thanks
You can use a nested for loop. The i-loop loops through the outer ArrayList and the j-loop loops through each individual ArrayList contained by myList
for (int i = 0; i < myList.size(); i++)
{
for (int j = 0; j < myList.get(i).size(); j++)
{
// do stuff
}
}
Edit: you then fill it by replacing // do stuff with
myList.get(i).add(new Integer(YOUR_VALUE)); // append YOUR_VALUE to end of list
A Note: If the myList is initially unfilled, looping using .size() will not work as you cannot use .get(SOME_INDEX) on an ArrayList containing no indices. You will need to loop from 0 to the number of values you wish to add, create a new list within the first loop, use .add(YOUR_VALUE) to append a new value on each iteration to this new list and then add this new list to myList. See Ken's answer for a perfect example.
Use for-each loop, if you are using Java prior 1.5 version.
for(ArrayList<Integer> row : myList) {
for(Integer intValue : row) {
// access "row" for inside arraylist or "intValue" for integer value.
}
}
Assuming the matrix is not initialized,
int m = 10, n = 10;
ArrayList<ArrayList<Integer>> matrix = new ArrayList<ArrayList<Integer>>();
for (int i = 0; i < m; i++) {
List<Integer> row = new ArrayList<Integer>();
for (int j = 0; j < n; j++) {
row.add(j);
}
matrix.add(row);
}

Populating ArrayList

I am trying to populate an array list, however, my array list constantly equals 0, and never initializes, despite my declaring it over main().
This is my code.
static ArrayList<Integer> array = new ArrayList<Integer>(10); //The parenthesis value changes the size of the array.
static Random randomize = new Random(); //This means do not pass 100 elements.
public static void main (String [] args)
{
int tally = 0;
int randInt = 0;
randInt = randomize.nextInt(100); //Now set the random value.
System.out.println(randInt); //Made when randomizing number didn't work.
System.out.println(array.size() + " : Array size");
for (int i = 0; i < array.size(); i++)
{
randInt = randomize.nextInt(100); //Now set the random value.
array.add(randInt);
tally = tally + array.get(i); //add element to the total in the array.
}
//System.out.println(tally);
}
Can someone tell me what is going on? I feel rather silly, I've done ArrayLists for my default arrays and I cannot figure this out to save my life!
new ArrayList<Integer>(10) creates an ArrayList with initial capacity of 10 but the size is still 0 as there are no elements in it.
ArrayList is backed by an array underneath so it does create an array of a given size (initial capacity) when constructing the object so it doesn't need to resize it every time you insert a new entry (arrays in Java are not dynamic so when you want to insert a new record and the array is full you need to create a new one and move all the items, that's an expensive operation) but even though the array is created ahead of time size() will return 0 until you actually add() something to the list.
That's why this loop:
for (int i = 0; i < array.size(); i++) {
// ...
}
Will not execute as array.size() is 0.
Change it to:
for (int i = 0; i < 10; i++)
And it should work.

When adding objects to this arraylist, they all become identical

public void fillWith(TileEntity tile){
for(int i = 0; i < this.height; i++){//for every x and y value
for(int j = 0; j < this.width; j++){
tile.x = j;
tile.y = i;
this.tiles.add(tile);
}
}
}
Okay so the above code is supposed to fill the level with a TileEntity tile. When I print out the x and y coords before the line "this.tiles.add(tile)", each tile has different coords. But when I print out the x and y coords of all of the tiles in the ArrayList "tiles", every single one is (9,9). They are all identical to the very last tile added to the arraylist. Thanks!
You keep adding the same object in your for-loop.
If you want to add different objects, you will need to create new instances using for example new TileEntity().
public void fillWith(){
TileEntity tile;
for(int i = 0; i < this.height; i++){//for every x and y value
for(int j = 0; j < this.width; j++){
tile = new TileEntity();
tile.x = j;
tile.y = i;
this.tiles.add(tile);
}
}
}
You are right that, in your code example, the values change every time you are in the loop, but because tile points to the same object every iteration, you will only change the x and y values within that object. (Java will not create a new object for you when you change x and/or y). When you add tile to the array this.tiles, it will reference the object you add - it will not make a copy of it.
All in all, tile and every object in your array will point to the same single instance of TileEntity.
You've succeeded in adding the same tile to the ArrayList 100 times. There's still only one object here, so the last update "wins": x = 9 and y = 9.
If you want different values, then you must add 100 different tile objects, each with their own distinct values.
You need to create new tile object each time in the loop,otherwise each time the existed tile pbject changes and remains with the last inserted values.
for(int j = 0; j < this.width; j++){
tile= new TileEntity();
tile.x = j;
tile.y = i;
this.tiles.add(tile);
}

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