I am using JPA and Spring for my db tasks and I need to have a join query like below in the JPA Repo class
#Query("SELECT 1 as id, COUNT(bill) as bills, ba.resource, MAX(b.updatedAt) as latestdate FROM Bill b join b.billComp ba where ba.comp.comp = ?1 group by ba.resource")
public List<BillCalc> findByBills(Long comp);
My Entity class is as below
#Entity
public class BillCalc {
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
private Integer id;
#Column(name = "latestdate", nullable = false)
private Date latestdate;
#Column(name = "bills", nullable = false)
private Long bills;
#Column(name = "resource", nullable = false)
private String resource;
I cannot create a table for this and can someone help me in getting the mapping to work? It gives me an error saying cannot cast from Object to BillCalc.
I tried #SubSelect but it does not take parameters
add a constructor to BillCalc.
BillCalc(Integer id, long bills, String resouce, Date latestdate) {...}
then use a Select new query:
SELECT new BillCalc(1, COUNT(bill), ba.resource, MAX(b.updatedAt))
FROM Bill b join b.billComp ba
WHERE ba.comp.comp = ?1 group by ba.resource")
#See Chapter 4.8.2 "Constructor Expressions in the SELECT Clause" in JSR-000220 Enterprise JavaBeans 3.0 Final Release (persistence)
Related
I'm trying to implement a custom #loader using a namedQuery on a OneToOne - Relation of an entity.
However the lastDatalog field remains null at all given times
I've tested the named query befor on a simple integration test using a repositry, the result was exactly what I intend to have in the lastDestinationStatus
(I need the last updated record from the logs for this data and IREF combination)
when I query the Datalog entity with the id of the data I get the correct result so the Datalog entity seems to be persisted
maybe good to know : curent hibernate version on the project is 4.2.11.Final
this is en extract from entity 1
#Entity
#Table(name = "data")
#NamedQueries({
#NamedQuery(name = "LastLogQuery", query = "select log from DataLog log where log.data.id= ?1 and " +
"log.IREF = (select max(log2.IREF) from DataLog log2 where log2.data = log.data ) " +
"and log.tsUpdate = (select max(log3.tsUpdate) from DataLog log3 where log3.data = log.data and log3.IREF = log.IREF)")})
public class Data{
....
#OneToOne(targetEntity = DataLog.class)
#Loader(namedQuery = "LastLogQuery")
private DataLog lastDataLog;
}
extract from entity 2
#Entity
#Table(name ="log")
public class DataLog{
.......
#ManyToOne(fetch = FetchType.EAGER)
#org.hibernate.annotations.Fetch(value = org.hibernate.annotations.FetchMode.SELECT)
#JoinColumn(name = "DTA_IDN", nullable = false)
private Data data;
/** IREF */
#Column(name = "DSE_LOG_UID_FIL_REF_COD")
private String IREF;
#Column(name = "LST_UPD_TMS", nullable = false)
#Temporal(TemporalType.TIMESTAMP)
private Date tsUpdate;
}
I have an Oracle 18.4.0 XE database that I'm trying to access from JPA 2.1, implemented by Hibernate 5.2.17.
I have a ManyToMany connection between 2 entities:
public class PermissionEntity implements Serializable {
private static final long serialVersionUID = -3862680194592486778L;
#Id
#GeneratedValue
private Long id;
#Column(unique = true)
private String permission;
#ManyToMany
private List<RoleEntity> roles;
}
public class RoleEntity implements Serializable {
private static final long serialVersionUID = 8037069621015090165L;
#Column(unique = true)
private String name;
#Id
#GeneratedValue(strategy = GenerationType.SEQUENCE)
private Long id;
#ManyToMany(fetch = FetchType.LAZY, mappedBy = "roles")
private List<PermissionEntity> permissions;
}
When trying to run the Spring Data JPA request on PermissionRepository: findAllByPermission(Iterable<String> permissions), I get the following exception:
Error : 1797, Position : 140, Sql = select permission0_.id as id1_0_, permission0_.permission as permission2_0_ from PermissionEntity permission0_ where permission0_.permission=(:1 , :2 ), OriginalSql = select permission0_.id as id1_0_, permission0_.permission as permission2_0_ from PermissionEntity permission0_ where permission0_.permission=(? , ?), Error Msg = ORA-01797: this operator must be followed by ANY or ALL
You are telling the Spring Data Jpa engine to search for Permission where permission is equal to the list. It should use the IN operator so your method name should be:
findAByPermissionIn(Iterable<String> permissions)
Use the 'in' keyword: findAllByPermissionIn(Iterable<String> permissions).
This would produce a query like this: where permission0_.permission IN (:permissions).
This is my Entity configuration
#Entity
#NamedQuery(name = "Payment.findByEmail", query = "SELECT p FROM Payment p JOIN p.additionalAuthData a " +
"WHERE KEY(a) = 'email' AND VALUE(a) = ?1 AND (p.paymentType = 4 OR p.paymentType = 10)")
public class Payment {
#Id
#GeneratedValue(strategy = GenerationType.SEQUENCE)
private Long id;
#Column(name = "payment_type")
private Integer paymentType;
/** other properties, getters and setters */
#ElementCollection
#CollectionTable(name = "additional_auth_data")
#MapKeyJoinColumn(name = "id", referencedColumnName = "id")
#MapKeyColumn(name = "field")
#Column(name = "data_value")
private Map<String, String> additionalAuthData;
}
The NamedQuery findByEmail("test#example.com") generates the following SQL
select -- all fields ...
from payment payment0_ inner join additional_auth_data additional1_ on payment0_.id=additional1_.id
where
additional1_.field='email' and (select additional1_.data_value from additional_auth_data additional1_ where payment0_.id=additional1_.id)='test#example.com' and (payment0_.payment_type=4 or payment0_.payment_type=10)
which is wrong: it may work if you have only one row but it blows up otherwise. H2 complains Scalar subquery contains more than one row and PostgreSQL more than one row returned by a subquery used as an expression. In fact, query's where condition compares a scalar value ('test#example.com') with a subquery.
The correct SQL should be:
select -- all fields
from payment payment0_ inner join additional_auth_data additional1_ on payment0_.id=additional1_.id
where additional1_.field='payerEmail' and additional1_.data_value='test#example.com' and (payment0_.payment_type=4 or payment0_.payment_type=10)
Is the HSQL correct? Is there a way to instruct Hibernate to generates a clever, better SQL? Is this a Hibernate bug?
Note: Hibernate shipped with Spring Boot Starter 1.3.7.RELEASE
Edit:
Using an #Embeddable class
#ElementCollection
#JoinTable(name = "additional_auth_data", joinColumns = #JoinColumn(name = "id"))
#MapKeyColumn(name = "field")
#Column(name = "data_value")
private Set<AdditionalData> additionalAuthData;
#Embeddable
public static class AdditionalData {
#Column(name = "field", nullable = false)
private String field;
#Column(name = "data_value")
private String dataValue;
protected AdditionalData() {
}
public AdditionalData(String field, String dataValue) {
this.field = field;
this.dataValue = dataValue;
}
/** Getters, setters; equals and hashCode on "field" */
}
#NamedQuery(name = "Payment.findByEmail", query = "SELECT p FROM Payment p JOIN p.additionalAuthData a " +
"WHERE a.field = 'email' AND a.dataValue = ?1 AND (p.paymentType = 4 OR p.paymentType = 10)")
solves the problem, and the SQL is correct, but it looks just plain wrong, like shooting a fly with a bazooka...
It generates correct SQL without value().
Use just a=?1
But I would expect is should generate it simple also with it.
I have a SQL query like this:
SELECT h.name, h.created_date, tbl.*
FROM my_table tbl
LEFT JOIN
(SELECT name, max(created_date) created_date FROM my_table GROUP BY name) h
ON tbl.name = h.name;
It returns the row from my_table (which has multiple for name="") along with the maximum created_date for that name.
Is there a way to replicate this in a JPQL query?
Here is the gist of the Entity class, it's quite simple:
#Entity
#Table(name = "MY_TABLE")
#XmlRootElement
public class MyTable implements Serializable {
private BigDecimal tableId;
private String name;
private Date createdDate;
// ...
#Id
#Basic(optional = false)
#Column(name = "TABLE_ID")
#GeneratedValue(generator = "TBL_ID_SEQ")
public BigDecimal getTableId() {
return tableId;
}
#Basic(optional = false)
#Column(name = "NAME")
public String getName() {
return name;
}
#Basic(optional = false)
#Column(name = "CREATED_DATE", insertable = false)
#Temporal(TemporalType.TIMESTAMP)
public Date getCreatedDate() {
return createdDate;
}
// ... getters/setters
}
Just reading your question I guess you do not need another entity. Entities in JPA are the same like tables in SQL. Usually there is a 1:1 relationship between entities and tables. You just have to know how to invoke a query using JPQ. You need a entity manager, which invokes your statement.
EntityManagerFactory emf = Persistence.createEntityManagerFactory("PersistenceUnit");
EntityManager em = emf.createEntityManager();
You have to define your persistence unit, i.e. in a pom file, or a config java file. So done you can go on coding something like this:
Query q = em.createQuery( "Your query in sql syntax as a string object" );
In respect to your entities and invoked query you will receive a List using
List<object> resultOfMyQuery = q.getResultList();
This is only one short example. But hopefully you got some buzzwords to look for ;)
I have two tables: Tax and TaxRule. There is one column same in both table i.e TAX_RULE_ID. But don't have any Hibernate mapping like OneToOne or OneToMany. Both table looks like-
TAX
#Id
#Column(name = "TAX_RATE_ID")
private Long taxRateId;
#Column(name = "TAX_RULE_ID")
private Long taxRuleId;
#Column(name = "TAX_TYPE")
private String taxType;
TAX_RULE
#Id
#Column(name = "TAX_RULE_ID")
private Long taxRuleId;
#Column(name = "TAX_CD")
private String TaxCode;
#Column(name = "STATE")
private String state;
I am trying to fetch data on the key i.e TAX_RULE_ID. This column is common in both table.
I have following Hibernate code in which I am joining both table on the TAX_RULE_ID column as follows:
CriteriaBuilder criteriaBuilder = entityManager.getCriteriaBuilder();
CriteriaQuery<String[]> cQuery = criteriaBuilder.createQuery(String[].class);
Root<Tax> taxRoot = cQuery.from(Tax.class);
cQuery.multiselect(taxRateRoot.get("taxType"), taxRateRoot.get("taxRate"));
List<Predicate> predicates = new ArrayList<>();
Join<Tax, TaxRule> join = taxRoot.join("taxRuleId");
.....rest of the code.
I am getting following Exception on the join point:
org.hibernate.jpa.criteria.BasicPathUsageException: Cannot join to attribute of basic type
at org.hibernate.jpa.criteria.path.AbstractFromImpl.constructJoin(AbstractFromImpl.java:270)
at org.hibernate.jpa.criteria.path.AbstractFromImpl.join(AbstractFromImpl.java:263)
at org.hibernate.jpa.criteria.path.AbstractFromImpl.join(AbstractFromImpl.java:436)
at com.iclsystems.base.dao.TaxRateDAOImpl.getTaxTypeForApplicableWorkOrderTax(TaxRateDAOImpl.java:31)
at com.iclsystems.base.businessObjects.TaxLookupBOImpl.getTaxTypeForApplicableWorkOrderTax(TaxLookupBOImpl.java:53)
at com.iclsystems.base.businessObjects.TaxLookupBOImpl.getWorkOrderTaxLookup(TaxLookupBOImpl.java:29)
at com.iclsystems.test.eventhandler.base.TaxLookupBOTest.testTaxLookupBO(TaxLookupBOTest.java:52)
You cannot use the #Join annotation for a basic property (e.g., an attribute with a simple #Column mapping). #Join is for associations:
one-to-one
one-to-many
many-to-one
many-to-many
You need to remove this line, as the taxRuleId is already fetched from the database:
Join<Tax, TaxRule> join = taxRoot.join("taxRuleId");
If you want to join the TaxRule table, you need to replace the:
#Column(name = "TAX_RULE_ID")
private Long taxRuleId;
with a many-to-one association:
#ManyToOne
#JoinColumn(name = "TAX_RULE_ID")
private TaxRule raxRule;