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access WEB-INF/jsp from html

I have a simple application to test the communication between html and jsp. My jsp is located in
WEB-INF/test.jsp
Here is the structure of my files:
ProjectA
src
irstServlet.java
Web-Content
test1.html
WEB-INF
test.jsp
Here is the code from servlet
protected void doPost(HttpServletRequest request, response) throws ServletException, IOException {
RequestDispatcher dispatcher = getServletContext().getRequestDispatcher("/WEB-INF/test.jsp");
request.setAttribute("userName", request.getParameter("userName"););
dispatcher.forward(request, response);
}
First I have deploy in tomcat start my test1.html: It take me to the servlet: FirstServlet.java and I can enter userName there.
But after i enter the values in and press enter I expect it to forward me to test.jsp which is not working. I get the error:
The origin server did not find a current representation for the target resource or is not willing to disclose that one exists.
Edited:
In my html I am trying to use it like:
<form method="POST" name="XX" action="/HelloWorldServlet">
Still not working.
Please can someone help me?

Your code does not look like it would compile at all.
Parameter response has no type - should be HttpServletResponse
There is a semicolon (;) after request.getParameter("userName")
Also I'm not sure why you're getting RequestDispatcher from servlet context rather than from the request - then again I've never checked if it makes any difference.
Anyway, I would rewrite doPost method like this:
#Override
protected void doPost(HttpServletRequest req, HttpServletResponse resp) throws ServletException, IOException {
req.setAttribute("userName", request.getParameter("userName"));
req.getRequestDispatcher("/WEB-INF/test.jsp").forward(req, resp);
}
EDIT:
I'm assuimng you have either a correct servlet mapping in your web.xml:
<servlet>
<servlet-name>HelloWorldServlet</servlet-name>
<servlet-class>FirstServlet</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>HelloWorldServlet</servlet-name>
<url-pattern>/HelloWorldServlet</url-pattern>
</servlet-mapping>
or your servlet is annotated with #WebServlet annotation:
#WebServlet("/HelloWorldServlet")
public class FirstServlet extends HttpServlet {
//your code
}
. If neither of those is true, that's your problem right there.

Output of ServletProgram created using Servlet Interface is not getting as Expected? [duplicate]

This question already has answers here:
Servlet returns "HTTP Status 404 The requested resource (/servlet) is not available"
(19 answers)
Closed 6 years ago.
I created a Servlet Program using Servlet Interface and I am just Sending my response to the Browser using response interface method getWriter() which returns PrintWriter reference and I am trying to print the following Information such as Hello and a Date on the Browser.
But,I am getting a following 404 Error.
Can anyone guide me Why?
Code for my Servlet Program.
class FirstAppUsingServlet implements Servlet
{
public void init(ServletConfig config) throws ServletException
{
}
public void destroy()
{
}
public ServletConfig getServletConfig()
{
return null;
}
public String getServletInfo()
{
return null;
}
public void service(ServletRequest request, ServletResponse response) throws ServletException, IOException
{
Date d1=new Date();
System.out.println(d1);
PrintWriter out=response.getWriter();
out.println("Hello Java");
out.println(d1);
}
}
Code for the web.xml:
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" id="WebApp_ID" version="2.5">
<display-name>FirstServletApp</display-name>
<servlet>
<description></description>
<display-name>FirstAppUsingServlet</display-name>
<servlet-name>FirstAppUsingServlet</servlet-name>
<servlet-class>FirstAppUsingServlet</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>FirstAppUsingServlet</servlet-name>
<url-pattern>/FirstAppUsingServlet</url-pattern>
</servlet-mapping>
</web-app>
And the Following error:
http://localhost:8089/FirstServletApp/WEB-INF/classes/FirstAppUsingServlet.java

Do couple of things:
First check whether TOMCAT server started properly or not. For this, check
http://localhost:8080/ from the browser. I am assumming you have started server on 8080 port.
If Server is started properly, then you will see TOMCAT home page. If it is not, then you have to check JAVA_HOME environmental variable setting.
Check if you have any error on console page of your editor.
Check if your URL is correct because you haven't pasted URL here.

Http status 404 -/the requested resource is not available [duplicate]

This question already has answers here:
Servlet returns "HTTP Status 404 The requested resource (/servlet) is not available"
(19 answers)
Closed 6 years ago.
I am new to java, I just tried to read initialization parameters from Deployment Descriptor file (web.xml), But got above error?
My web.xml and java file coding coding in snap attached.
My directrory structure is
c:\....tomcat\webapps\dd\web-inf\classes
No error in java class file.
Java file code which is compiled successfully
import java.io.*;
import java.net.*;
import javax.servlet.*;
import javax.servlet.http.*;
public class MyServlet2 extends HttpServlet {
String fileName;
public void init(ServletConfig config) throws ServletException {
super.init(config);
fileName = config.getInitParameter("logfilename");
}
protected void doGet(HttpServletRequest request,HttpServletResponse response)throws ServletException, IOException {
processRequest(request, response);
}
protected void doPost(HttpServletRequest request,HttpServletResponse response)throws ServletException, IOException {
processRequest(request, response);
}
protected void processRequest(HttpServletRequest request,HttpServletResponse
response)throws ServletException, IOException {
PrintWriter out = response.getWriter();
out.println(fileName);
out.close();
}
}
web.xml
<?xml version="1.0" encoding="ISO-8859-1"?>
<web-app>
<servlet>
<servlet-name>MyServlet2</servlet-name>
<servlet-class>MyServlet2</servlet-class>
<init-param>
<param-name>logfilename</param-name>
<param-value>value1</param-value>
</init-param>
</servlet>
<servlet-mapping>
<servlet-name>MyServlet2</servlet-name>
<url-pattern>/mc11</url-pattern>
</servlet-mapping>
</web-app>
Other detail of my directory and error page i think that my web.xml not working

There are two problems I can see at the moment...
Servlet init parameters
You currently have:
//defining param1
param1
value1
That's not how you define the parameter. You should specify a param-name element containing the name of the parameter, rather than using the name of the parameter as an XML element name.
<init-param>
<param-name>logfilename</param-name>
<param-value>...</param-value>
</init-param>
Also note that // isn't how you write comments in XML - if you wanted a comment, you should have:
<!-- Define the first parameter -->
<init-param>
<param-name>logfilename</param-name>
<param-value>...</param-value>
</init-param>
(The param-value element should have been a hint - if you could really just specify your own element, I'd have expected <logfilename>value in here</logfilename> - having the name specified as an element name, but the value specified with a fixed element name of param-value would have been an odd scheme.)
Servlet mapping
Currently your mapping is:
<servlet-name> FormServlet</servlet-name>
<url-pattern>/ss/</url-pattern>
</servlet-mapping>
I suspect that mapping won't match http://localhost:8080/dd/ss/s.html because you don't have any wildcards in there - it you may well find that it matches exactly http://localhost:8080/dd/ss/. It's not clear where the dd part comes in, but I assume that's a separate part of your configuration. You should try:
<!-- I would recommend removing the space from the servlet
- name *everywhere*. -->
<servlet-name>FormServlet</servlet-name>
<url-pattern>/ss/*</url-pattern>
</servlet-mapping>
If that doesn't work for http://localhost:8080/dd/ss/s.html, see whether it maps http://localhost:8080/ss/s.html - it may be that your engine isn't configured the way you expect elsewhere.

There is no problem with code,I try net beans tool and done assignment perfectly with the help of above code.Before that may be problem in tomcat.

Getting HTTP Status 404 error when trying to run servlet [duplicate]

This question already has answers here:
Servlet returns "HTTP Status 404 The requested resource (/servlet) is not available"
(19 answers)
Closed 6 years ago.
I have a problem with my simple servlet that I am trying to run, Hello.java. I made it in eclipse, then placed the file it in the webapps/ServletTest/WEB-INF/classes folder and compiled it, creating the file Hello.class in the same folder. I then modified my web.xml file to map the servlet and tried to run it through the following address
http://localhost:8080/ServletTest/Hello
However, this did not work, giving the following error
HTTP Status 404 -
type Status report
message
description The requested resource is not available.
Apache Tomcat/7.0.42
The mapping in the web.xml file looks like this:
<servlet>
<servlet-name>Hello</servlet-name>
<servlet-class>Main.Hello</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>Hello</servlet-name>
<url-pattern>/Hello</url-pattern>
</servlet-mapping>
The code of the servlet:
package Main;
import java.io.IOException;
import java.io.PrintWriter;
import javax.servlet.ServletException;
import javax.servlet.annotation.WebServlet;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
#WebServlet("/Hello")
public class Hello extends HttpServlet {
private static final long serialVersionUID = 1L;
public Hello() {
super();
}
protected void doGet(HttpServletRequest request, HttpServletResponse
response) throws ServletException, IOException {
PrintWriter out = response.getWriter();
response.setContentType("text/html");
String path = request.getContextPath();
String ip = request.getRemoteAddr();
out.print("<html>" +
"<title>Hello</title>" +
"Hello World"+ "<br>" +
"Your ip is: " + ip + "<br>" +
"Your path is: " + path
+ "</html>");
}
protected void doPost(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
}
}

The compiled Hello.class file should be in the folder
webapps/ServletTest/WEB-INF/classes/Main
since it's declared to be in package Main.
Also, you can see Tomcat's startup logs in /logs/catalina.out or /logs/catalina.log, depending.
Also, Suresh is right in the comments, use either a <servlet> declaration or #WebServlet. Don't use both.

Try to delete web.xml.
Annotation #WebServlet("/Hello") is enough for Tomcat 7+

If the root folder not having proper permission you will face this issue. So please check the root folder property and remove read only permission and add user to full access permission in security tab.

Error 404: The requested resource is not available using HelloWorld servlet [duplicate]

This question already has answers here:
Servlet returns "HTTP Status 404 The requested resource (/servlet) is not available"
(19 answers)
Closed 1 year ago.
I am writing a Java Servlet, and I am struggling to get a simple HelloWorld example to work properly.
The HelloWorld.java class is:
package crunch;
import java.io.*;
import javax.servlet.*;
import javax.servlet.http.*;
public class HelloWorld extends HttpServlet {
public void doGet(HttpServletRequest request,
HttpServletResponse response)
throws ServletException, IOException {
PrintWriter out = response.getWriter();
out.println("Hello World");
}
}
I am running Tomcat v7.0, and have already read similar questions, with responses referring to changing the invoker servlet-mapping section in web.xml. This section actually doesn't exist in mine, and when I added it the same problem still occurred.

Try this (if the Java EE V6)
package crunch;
import java.io.*;
import javax.servlet.*;
import javax.servlet.http.*;
#WebServlet(name="hello",urlPatterns={"/hello"}) // added this line
public class HelloWorld extends HttpServlet {
public void doGet(HttpServletRequest request,
HttpServletResponse response)
throws ServletException, IOException {
PrintWriter out = response.getWriter();
out.println("Hello World");
}
}
now reach the servlet by http://127.0.0.1:8080/yourapp/hello
where 8080 is default Tomcat port, and yourapp is the context name of your applciation

You definitely need to map your servlet onto some URL. If you use Java EE 6 (that means at least Servlet API 3.0) then you can annotate your servlet like
#WebServlet(name="helloServlet", urlPatterns={"/hello"})
public class HelloWorld extends HttpServlet {
//rest of the class
Then you can just go to the localhost:8080/yourApp/hello and the value should be displayed. In case you can't use Servlet 3.0 API than you need to register this servlet into web.xml file like
<servlet>
<servlet-name>helloServlet</servlet-name>
<servlet-class>crunch.HelloWorld</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>helloServlet</servlet-name>
<url-pattern>/hello</url-pattern>
</servlet-mapping>

Writing Java servlets is easy if you use Java EE 7
#WebServlet("/hello-world")
public class HelloWorld extends HttpServlet {
#Override
public void doGet(HttpServletRequest request,
HttpServletResponse response) {
response.setContentType("text/html");
PrintWriter out = response.getWriter();
out.println("Hello World");
out.flush();
}
}
Since servlet 3.0
The good news is the deployment descriptor is no longer required!
Read the tutorial for Java Servlets.

this is may be due to the thing that you have created your .jsp or the .html file in the WEB-INF instead of the WebContent folder.
Solution: Just replace the files that are there in the WEB-INF folder to the Webcontent folder and try executing the same - You will get the appropriate output

For those stuck with "The requested resource is not available" in Java EE 7 and dynamic web module 3.x, maybe this could help: the "Create Servlet" wizard in Eclipse (tested in Mars) doesn't create the #Path annotation for the servlet class, but I had to include it to access successfuly to the public methods exposed.

You have to user ../../projectName/Filename.jsp in your action attr. or href
../ = contains current folder simple(demo.project.filename.jsp)
Servlet can only be called with 1 slash forward to your project name..

My problem was in web.xml file. In one <servlet-mapping> there was an error inside <url-pattern>: I forgot to add / before url.