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Format specific section of String - java

I have a String: a%sb%sc%s. I need to format b before I format a or c, but I'm not sure how or even if I can specify only to format b while keeping the rest of the String unformatted.
In other words, I'm trying to do this:
String.format(foo, "test");
With the outcome:
a%sbtestc%s
Is it possible to manipulate a String like this or should I just use String.replace instead?
A little more detail. The ultimate String will look something like: aA-PARMbB-PARMcC-PARM and then used to fetch some data. a and c are much more dynamic than b, so I'm trying to format b before hand.
So, again. I'm trying to achieve the following:
String.format(foo, "B-PARM");
With the results:
a%sbB-PARMc%s
Then format the rest:
String.format(formattedFoo, "A-PARM", "C-PARM");

You could do your formatting in steps,
String aString = String.format("something %s something else", "a string");
String bString = String.format("...%s...", "test");
String cString = // ....
String completeString = String.format("a%sb%sc%s", aString, bString, cString);
but again, I have to wonder what is going on, and whether this represents an XY Problem, one that is best solved by a completely different approach. Consider giving us the details of the overall problem that you're trying to solve and perhaps not the code tactics that you're using to try to solve it.

Related

I am writing a program that takes in a file and extracts data from a single string within the file. I run into a problem when I try to separate the substrings in the way that I want. The goal is to separate the larger chunks of the line from other large chunks without separating the smaller chunks within the larger chunk (separated by commas).
An example of the file contents would be this: (Although it is slightly long, the files I have may vary from short lists like this to 50 or even to 100 blocks of item sets)
{"timeStamp":1477474644345,"itemSets":[{"mode":"any","sortrank":4999,"type":"custom","priority":false,"isGlobalForMaps":true,"uid":"LOL_D957E9EC-39E4-943E-C55E-52B63E05D99C","isGlobalForChampions":false,"associatedMaps":[],"associatedChampions":[40],"blocks":[{"type":"starting","items":[{"id":"3303","count":1},{"id":"2031","count":1},{"id":"1082","count":1},{"id":"3340","count":1},{"id":"3363","count":1},{"id":"2043","count":1},{"id":"3364","count":1}]},{"type":"Support Build Items","items":[{"id":"2049","count":1},{"id":"1001","count":1},{"id":"3165","count":1},{"id":"3117","count":1},{"id":"2301","count":1},{"id":"3089","count":1},{"id":"3135","count":1},{"id":"3504","count":1}]},{"type":"AP Build Items","items":[{"id":"3165","count":1},{"id":"3020","count":1},{"id":"3089","count":1},{"id":"3135","count":1},{"id":"3285","count":1},{"id":"3116","count":1}]},{"type":"Other Items (Situational Items)","items":[{"id":"3026","count":1},{"id":"3285","count":1},{"id":"3174","count":1},{"id":"3001","count":1},{"id":"3504","count":1}]}],"title":"Janna Items","map":"any"},{"mode":"any","sortrank":0,"type":"custom","priority":false,"isGlobalForMaps":false,"uid":"LOL_F265D25A-EA44-5B86-E37A-C91BD73ACB4F","isGlobalForChampions":true,"associatedMaps":[10],"associatedChampions":[],"blocks":[{"type":"Searching","items":[{"id":"3508","count":1},{"id":"3031","count":1},{"id":"3124","count":1},{"id":"3072","count":1},{"id":"3078","count":1},{"id":"3089","count":1}]}],"title":"TEST","map":"any"}]}
The code I have attempted to write tries to separate this into meaningful chunks, here is what I have written so far:
cutString = dataFromFile.substring(dataFromFile.indexOf("itemSets\":") + 11, dataFromFile.indexOf("},{"));
stringContinue = dataFromFile.substring(cutString.length());
while(stringContinue.contains("},{"))
{
//Do string manipulation to cut every part and re-attach it, then re-check to find if this ("},{\"id") is not there
if(stringContinue.contains("},{\"id"))
{
//if(stringContinue.equals(anObject))
cutString = cutString + stringContinue.substring(0, stringContinue.indexOf("},{\"id"));
}
else if(stringContinue.contains("},{\"count"))
{
cutString = cutString + stringContinue.substring(0, stringContinue.indexOf("},{\"count"));
}
else if(stringContinue.contains("},{"))
{
cutString = cutString + stringContinue.substring(0, stringContinue.indexOf("},{"));
}
stringContinue = stringContinue.substring(cutString.length());
//Check if we see a string pattern that is the cut off point
//if()
//System.out.println(stringContinue);
System.out.println(cutString);
}
But when I run it, I get an output like this:
{"mode":"any","sortrank":4999,"type":"custom","priority":false,"isGlobalForMaps":true,"uid":"LOL_D957E9EC-39E4-943E-C55E-52B63E05D99C","isGlobalForChampions":false,"associatedMaps":[],"associatedChampions":[40],"blocks":[{"type":"starting","items":[{"id":"3303","count":1arting","items":[{"id":"3303","count":1
The output I want to achieve is this:
{"mode":"any","sortrank":4999,"type":"custom","priority":false,"isGlobalForMaps":true,"uid":"LOL_D957E9EC-39E4-943E-C55E-52B63E05D99C","isGlobalForChampions":false,"associatedMaps":[],"associatedChampions":[40],"blocks":[{"type":"starting","items":[{"id":"3303","count":1},{"id":"2031","count":1},{"id":"1082","count":1},{"id":"3340","count":1},{"id":"3363","count":1},{"id":"2043","count":1},{"id":"3364","count":1}]},{"type":"Support Build Items","items":[{"id":"2049","count":1},{"id":"1001","count":1},{"id":"3165","count":1},{"id":"3117","count":1},{"id":"2301","count":1},{"id":"3089","count":1},{"id":"3135","count":1},{"id":"3504","count":1}]},{"type":"AP Build Items","items":[{"id":"3165","count":1},{"id":"3020","count":1},{"id":"3089","count":1},{"id":"3135","count":1},{"id":"3285","count":1},{"id":"3116","count":1}]},{"type":"Other Items (Situational Items)","items":[{"id":"3026","count":1},{"id":"3285","count":1},{"id":"3174","count":1},{"id":"3001","count":1},{"id":"3504","count":1}]}],"title":"Janna Items","map":"any"}
{"mode":"any","sortrank":0,"type":"custom","priority":false,"isGlobalForMaps":false,"uid":"LOL_F265D25A-EA44-5B86-E37A-C91BD73ACB4F","isGlobalForChampions":true,"associatedMaps":[10],"associatedChampions":[],"blocks":[{"type":"Searching","items":[{"id":"3508","count":1},{"id":"3031","count":1},{"id":"3124","count":1},{"id":"3072","count":1},{"id":"3078","count":1},{"id":"3089","count":1}]}],"title":"TEST","map":"any"}
So then my question is how do I check for the point where I can separate the blocks without getting java to detect the same pattern that it uses to separate the smaller chunks? Basically I am looking for a pattern like this ("},{"), but not this ("},{\"id:") or this ("},{\count:"). Is there any other things that the String Class can offer for functionality that is similar that i am not aware of?
Edit: Although using a json parser would make things easier and convenient for this type of problem, another one rises because it would make the program only take in json files. This question is more for string manipulation and trying to find a part of the string that can separate the large blocks of information without touching or changing (very minimally as possible) the smaller blocks that have the same way of separation. So far regex and splitting strings to be re-attached later seems to be the way to go unless there is a more clear-cut answer.

You could split the string into an array based on regex like this:
//fileString is the String you get from your file
String[] chunksIWant = fileString.split("\\},\\{");
This will return the String array chunksIWant split in the chunks you want. It does get rid of the regex itself, in this case "},{", so if you would need the symbols for some reason you will have to add them back afterwards.

You are getting this data from file in Json format.
So when you get that data on java side use JsonParser to convert data in JsonArray format.
Then you can iterate that JsonArray to get as JsonObject by using String name.
You can use value of JsonObject as required.

I am using a set of constant Strings for text anonymization. One of the strings should go something like "[Town in the state of XX]", where XX is to be replaced later with an actual state (the rest of the string remains as is).
My question is: is there a way to do this "elegantly" (in the spirit of a SQL PreparedStatement)?
Or should I just put XX and then do myString.replace("XX", "someState"), in which case, the string can no longer be a constant :(
EDIT: Just realized that String.replace returns a new String, so myString could still be a constant with this method.

If you use %s instead of XX, then you can simply use String.format.

You can use the Formatter class
And conveniently from system out
System.out.format("My name is '%s' and i am %d years old. My party will be at '%s'.", name, years, time);

Is there a way i can create code build code by using Concatenation in Android studio/eclipse?
In other words i have 2 sets of strings one for each country i am dealing with ZA and KE. They have 2 different EULA's.
So i would like to pull the string related to the respective country.
String message = mContext.getString(R.string.eula_string_za);
above is an example of the output code. is there someway i can go about "creating" that based on If statements?
String str = "mContext.getString(R.string.eula_string_";
if (something = "ZA") {
str += "za);";
} else {
str += "ke);";
}
so if the country selected is ZA then the output code should be
mContext.getString(R.string.eula_string_za);
and if its KE it should be
mContext.getString(R.string.eula_string_ke);
and then the result will then pull the correct string from strings.xml?

Java is a compiled code, not an executed one,you can't write code this way like in an interpreted language.
The best way to manage different languages in android is to use a string.xml file for each language.
Take a look at this tutorial, it will help you a lot :
Supporting different languages in android

If you want to go this route you could try to use reflection. Have a look at Class.getField(…) if you want to use reflection.
Instead of first building a code string using a if statement you can also use the same if statement to find the correct string:
String str;
if (something.equals("ZA")) {
str = mContext.getString(R.string.eula_string_za);
} else {
str = mContext.getString(R.string.eula_string_ke);
}
Note that your condition something = "ZA" does not do what you think it does: It assigns something the string "ZA" and then evaluates itself to "ZA", so this would not even compile. The correct way would be something == "ZA", but even this does not work in the general case. You need to use String.equals(…). Some even argue you should use it the other way around (i.e. "ZA".equals(something)) to avoid a NullPointerException…
Another possibility would be to first build a Map from county to the corresponding string ID for all the EULAs you have and then asking the Map to return the correct one.
But probably the cleanest solution would be to use Androids built in mechanism, as hkN suggests.

I am trying to return a string of names in a list as an integer, the names are pulled from a longer list. i have managed to get the list of names needed but cannot figure out how to convert the string into an integer. see code below:
public static void doStuff(List<Seat> uk){
for(Seat s:uk)
if (s.place.contains("Edinburgh"))
System.out.println(s.results);
This is where i get stuck does anyone have any advise on how to solve this?

You can use Integer.parseInt("123") to convert a String ("123") to an Integer (123).
What String are you trying to convert though ?
Let me know if it works (or not)
Happy coding :) -Charlie

To convert a string to an int:
String s = "5";
int i = Integer.parseInt(s);
Your question is a bit confusing, so if this isn't what you're looking for, let me know and I'll update my answer accordingly.

Hi I'm new to java so this is going to seem a bit tame. Anyway, in objC, when I want to insert a variable into a string, I would do it like this:
NSString *string = [NSString stringWithFormat:#"test%i", variable];
How do I do this in java?

There are number of ways, but the java.lang.String.format() method is an easy one:
String message = String.format("There are %d ways to leave your lover", 50);

Using the String.format() method. Take a look at the documentation for understanding all the different formatting options available.