How to Decode a xml Sent over Url in java

How to Decode a xml Sent over Url in java - java

I am firing an online xml in java to the method below:
public String WriteToServer(String xml) {
StringBuilder answer = new StringBuilder();
try {
String myurl="example.com";
URL url = new URL(myurl);
URLConnection conn = url.openConnection(Proxy.NO_PROXY);
conn.setDoOutput(true);
OutputStreamWriter writer = new OutputStreamWriter(conn.getOutputStream());
writer.write(xml);
writer.flush();
BufferedReader reader = new BufferedReader(new InputStreamReader(conn.getInputStream()));
String line;
while ((line = reader.readLine()) != null) {
answer.append(line);
}
writer.close();
reader.close();
} catch (Exception e) {
System.out.println(e);
}
return answer.toString();
}
My Problem is that the server receives an encoded xml so it can not understand and returns a 500 response to the client. How can I decode a xml to a plain text that the server can read?

Try below code just before creating OutputStreamWriter instance
String myurl="example.com";
URL url = new URL(myurl);
URLConnection conn = (HttpURLConnection)url.openConnection();
conn.setRequestMethod("POST");
conn.setRequestProperty("Content-Type", "application/x-www-form-urlencoded");
conn.setRequestProperty("Content-Language", "en-US");
conn.setUseCaches (false);
conn.setDoInput(true);
conn.setDoOutput(true);

Related

Send value of my sim card in get

I would like to recover the values of my sim card to send it as a get or post to my app php I read several topic and I try a lot of things but I am novice in java. And I dont know how to send data taken from my java application to my web site.
String IMEINumber = manager.getDeviceId();
String SIMSerialNumber = manager.getSimSerialNumber();
BtnStart = (Button) findViewById(R.id.idBtnStart);
varText = (TextView) findViewById(R.id.idTxtView);
varText.setText(info);
I try this without succes:
URL url = new URL( "http://www.example.com/erm**?data=SIMSerialNumber**");
HttpURLConnection connexion = (HttpURLConnection) url.openConnection();

Try using below code snippet: Code for Post request in java, sending request to specified URL.
HttpURLConnection connection = null;
JSONObject responseJsonObject = null;
try {
URL posturl = new URL("http://www.example.com/erm**?data=SIMSerialNumber**");
connection = (HttpURLConnection) posturl.openConnection();
connection.setRequestMethod("POST");
connection.setRequestProperty("Content-Type", "<type of your content>");
connection.setDoInput(true);
connection.setDoOutput(true);
//Send request
DataOutputStream wr = new DataOutputStream(connection.getOutputStream());
postBody -- will contain your value to be posted.
wr.write(postBody.toString().getBytes("UTF-8"));
wr.flush();
wr.close();
InputStream is = connection.getInputStream();
BufferedReader rd = new BufferedReader(new InputStreamReader(is));
String line;
StringBuffer response = new StringBuffer();
while ((line = rd.readLine()) != null) {
response.append(line);
response.append('\r');
}
rd.close();
Save your response in any format you want.I'm using Json format
responseJsonObject = new JSONObject(response.toString());
} catch (Exception e) {
e.printStackTrace();
}

Trying to get an Access Token from Dwolla restful api

Im having trouble getting an access token for the sandbox environment.
Im following this guide for authenticating: OAuth
So when i create my request, following this guide, i get the following response from the api:
{"error":"access_denied","error_description":"Invalid application credentials."}
Im using key for mf client ID and secret as my client secret as per the instructions.
Here is the code Im using:
public static void main(String[] args) {
try {
URL url = new URL("https://www.dwolla.com/oauth/v2/token");
HttpURLConnection conn = (HttpURLConnection) url.openConnection();
conn.setRequestMethod("POST");
conn.setRequestProperty("Content-Type", "application/x-www-form-urlencoded");
conn.setRequestProperty("client_id", "<Key>");
conn.setRequestProperty("client_secret", "<Secret>");
conn.setRequestProperty("grant_type", "client_credentials");
conn.setDoInput(true);
conn.setDoOutput(true);
System.out.println("Message:" + conn.getResponseMessage());
BufferedReader br = new BufferedReader(new InputStreamReader(
(conn.getInputStream())));
String output;
System.out.println("Output from Server .... \n");
while ((output = br.readLine()) != null) {
System.out.println(output);
}
conn.disconnect();
} catch (MalformedURLException ex) {
Logger.getLogger(PaymentTest.class.getName()).log(Level.SEVERE, null, ex);
} catch (IOException ex) {
Logger.getLogger(PaymentTest.class.getName()).log(Level.SEVERE, null, ex);
}
}

I was able to get an access token finally. My problem is first of all the above code uses client_id and client_secret as header params. These need to go in the body of the request.
My second problem is that I used the wrong content type for the message I was sending.
Here is the code that worked for me:
URL url = new URL("https://sandbox.dwolla.com/oauth/v2/token");
HttpURLConnection conn = (HttpURLConnection) url.openConnection();
conn.setRequestMethod("POST");
conn.setRequestProperty("Content-Type", "application/json");
conn.setDoInput(true);
conn.setDoOutput(true);
String data = "";
JSONObject jsonObj = new JSONObject();
jsonObj.put("client_id", "<Your Client ID>");
jsonObj.put("client_secret", "<Your Client Secret>");
jsonObj.put("grant_type", "client_credentials");
data = jsonObj.toString();
System.out.println("data = " + data);
byte[] outputInBytes = data.getBytes("UTF-8");
OutputStream os = conn.getOutputStream();
os.write( outputInBytes );
os.close();
System.out.println("Message:" + conn.getResponseMessage());
BufferedReader br = new BufferedReader(new InputStreamReader((conn.getInputStream())));
String output;
System.out.println("Output from Server .... \n");
while ((output = br.readLine()) != null) {
System.out.println(output);
}
conn.disconnect();

Java code to login to website which contains emailId in page and password in another page

I want to write a Java application, which can login to a website For example, www.tumblr.com/login. Basically this web page asks for an email address on the first page and then would take the user to the next page to enter the password.
Can someone please help me with a sample Java code for this problem?

You might want to look at HttpURLConnection
public static String executePost(String targetURL, String urlParameters) {
HttpURLConnection connection = null;
try {
//Create connection
URL url = new URL(targetURL);
connection = (HttpURLConnection) url.openConnection();
connection.setRequestMethod("POST");
connection.setRequestProperty("Content-Type",
"application/x-www-form-urlencoded");
connection.setRequestProperty("Content-Length",
Integer.toString(urlParameters.getBytes().length));
connection.setRequestProperty("Content-Language", "en-US");
connection.setUseCaches(false);
connection.setDoOutput(true);
//Send request
DataOutputStream wr = new DataOutputStream (
connection.getOutputStream());
wr.writeBytes(urlParameters);
wr.close();
//Get Response
InputStream is = connection.getInputStream();
BufferedReader rd = new BufferedReader(new InputStreamReader(is));
StringBuilder response = new StringBuilder(); // or StringBuffer if Java version 5+
String line;
while ((line = rd.readLine()) != null) {
response.append(line);
response.append('\r');
}
rd.close();
return response.toString();
} catch (Exception e) {
e.printStackTrace();
return null;
} finally {
if (connection != null) {
connection.disconnect();
}
}
Code example found here

Jersey post method request sending with payload

URL url = new URL("http://nvmbd1bkb150v03.rjil.ril.com/system/ws/v11/gh/search/?portalId=400100000001003&usertype=customer&$format=json");
String payload="portalId=400100000001003&Q1-1-1000000931=1000000919&usertype=customer&%24format=json";
HttpURLConnection connection = (HttpURLConnection) url.openConnection();
connection.setDoInput(true);
connection.setDoOutput(true);
connection.setRequestMethod("POST");
connection.setRequestProperty("session_id", session_id);
connection.setRequestProperty("Accept", "application/json");
connection.setRequestProperty("Content-Type", "application/json; charset=UTF-8");
OutputStreamWriter writer = new OutputStreamWriter(connection.getOutputStream(), "UTF-8");
//writer.write(payload);
writer.close();
BufferedReader br = new BufferedReader(new InputStreamReader(connection.getInputStream()));
while ((line = br.readLine()) != null) {
jsonString.append(line);
}
//br.close();
//connection.disconnect();
} catch (Exception e) {
throw new RuntimeException(e.getMessage());
}
out.println(jsonString.toString());
This is all my code. I want to read that web service but it is giving me error. Please help.

How to stream a JSON object to a HttpURLConnection POST request

I can not see what is wrong with this code:
JSONObject msg; //passed in as a parameter to this method
HttpURLConnection httpCon = (HttpURLConnection) url.openConnection();
httpCon.setDoOutput(true);
httpCon.setDoInput(true);
httpCon.setUseCaches(false);
httpCon.setRequestProperty( "Content-Type", "application/json" );
httpCon.setRequestProperty("Accept", "application/json");
httpCon.setRequestMethod("POST");
OutputStream os = httpCon.getOutputStream();
OutputStreamWriter osw = new OutputStreamWriter(os, "UTF-8");
msg.write(osw);
osw.flush();
osw.close();
os.close(); //probably overkill
On the server, I am getting no post content at all, a zero length string.

Try
...
httpCon.setRequestMethod("POST");
httpCon.connect(); // Note the connect() here
...
OutputStream os = httpCon.getOutputStream();
OutputStreamWriter osw = new OutputStreamWriter(os, "UTF-8");
...
osw.write(msg.toString());
osw.flush();
osw.close();
to send data.
to retrieve data try:
BufferedReader br = new BufferedReader(new InputStreamReader( httpCon.getInputStream(),"utf-8"));
String line = null;
while ((line = br.readLine()) != null) {
sb.append(line + "\n");
}
br.close();
System.out.println(""+sb.toString());

public String sendHTTPData(String urlpath, JSONObject json) {
HttpURLConnection connection = null;
try {
URL url=new URL(urlpath);
connection = (HttpURLConnection) url.openConnection();
connection.setDoOutput(true);
connection.setDoInput(true);
connection.setRequestMethod("POST");
connection.setRequestProperty("Content-Type", "application/json");
connection.setRequestProperty("Accept", "application/json");
OutputStreamWriter streamWriter = new OutputStreamWriter(connection.getOutputStream());
streamWriter.write(json.toString());
streamWriter.flush();
StringBuilder stringBuilder = new StringBuilder();
if (connection.getResponseCode() == HttpURLConnection.HTTP_OK){
InputStreamReader streamReader = new InputStreamReader(connection.getInputStream());
BufferedReader bufferedReader = new BufferedReader(streamReader);
String response = null;
while ((response = bufferedReader.readLine()) != null) {
stringBuilder.append(response + "\n");
}
bufferedReader.close();
Log.d("test", stringBuilder.toString());
return stringBuilder.toString();
} else {
Log.e("test", connection.getResponseMessage());
return null;
}
} catch (Exception exception){
Log.e("test", exception.toString());
return null;
} finally {
if (connection != null){
connection.disconnect();
}
}
}`
call this methopd in doitbackground in asynctask

HttpURLConnection is cumbersome to use. With DavidWebb, a tiny wrapper around HttpURLConnection, you can write it like this:
JSONObject msg; //passed in as a parameter to this method
Webb webb = Webb.create();
JSONObject result = webb.post("http://my-url/path/to/res")
.useCaches(false)
.body(msg)
.ensureSuccess()
.asJsonObject()
.getBody();
If you don't like it, there is a list of alternative libraries on the link provided.
Why should we all write the same boilerplate code every day? BTW the code above is more readable and less error-prone. HttpURLConnection has an awful interface. This has to be wrapped!

Follow this example:
public static PricesResponse getResponse(EventRequestRaw request) {
// String urlParameters = "param1=a&param2=b&param3=c";
String urlParameters = Piping.serialize(request);
HttpURLConnection conn = RestClient.getPOSTConnection(endPoint, urlParameters);
PricesResponse response = null;
try {
// POST
OutputStreamWriter writer = new OutputStreamWriter(conn.getOutputStream());
writer.write(urlParameters);
writer.flush();
// RESPONSE
BufferedReader reader = new BufferedReader(new InputStreamReader((conn.getInputStream()), StandardCharsets.UTF_8));
String json = Buffering.getString(reader);
response = (PricesResponse) Piping.deserialize(json, PricesResponse.class);
writer.close();
reader.close();
} catch (Exception e) {
e.printStackTrace();
}
conn.disconnect();
System.out.println("PricesClient: " + response.toString());
return response;
}
public static HttpURLConnection getPOSTConnection(String endPoint, String urlParameters) {
return RestClient.getConnection(endPoint, "POST", urlParameters);
}
public static HttpURLConnection getConnection(String endPoint, String method, String urlParameters) {
System.out.println("ENDPOINT " + endPoint + " METHOD " + method);
HttpURLConnection conn = null;
try {
URL url = new URL(endPoint);
conn = (HttpURLConnection) url.openConnection();
conn.setRequestMethod(method);
conn.setDoOutput(true);
conn.setRequestProperty("Content-Type", "text/plain");
} catch (IOException e) {
e.printStackTrace();
}
return conn;
}

this without json String post data to server
class PostLogin extends AsyncTask<Void, Void, String> {
#Override
protected String doInBackground(Void... params) {
String response = null;
Uri.Builder builder= new Uri.Builder().appendQueryParameter("username","amit").appendQueryParameter("password", "amit");
String parm=builder.build().getEncodedQuery();
try
{
response = postData("your url here/",parm);
}catch (Exception e)
{
e.printStackTrace();
}
Log.d("test", "response string is:" + response);
return response;
}
}
private String postData(String path, String param)throws IOException {
StringBuffer response = null;
URL url = new URL(path);
HttpURLConnection connection = (HttpURLConnection) url.openConnection();
connection.setRequestMethod("POST");
connection.setDoOutput(true);
// connection.setRequestProperty("Content-Type", "application/json");
// connection.setRequestProperty("Accept", "application/json");
OutputStream out = connection.getOutputStream();
out.write(param.getBytes());
out.flush();
out.close();
int responseCode = connection.getResponseCode();
if (responseCode == HttpURLConnection.HTTP_OK) {
BufferedReader br = new BufferedReader(new InputStreamReader(connection.getInputStream()));
String line;
response = new StringBuffer();
while ((line = br.readLine()) != null) {
response.append(line);
}
br.close();
}
return response.toString();
}

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Java is a programming language and computing platform first released by Sun Microsystems in 1995.

How to Decode a xml Sent over Url in java - java

Related

Send value of my sim card in get

Trying to get an Access Token from Dwolla restful api

Java code to login to website which contains emailId in page and password in another page

Jersey post method request sending with payload

How to stream a JSON object to a HttpURLConnection POST request

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