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How to add date in mysql database from Hibernate/Spring Jpa

I use spring boot, and I want to add 1 year to a specific column in mysql database
String queryRecherche = "UPDATE myTable t SET t.dateDebut = DATE_ADD(t.dateDebut, INTERVAL 1 YEAR) WHERE.id = 3 ";
Query query = em.createQuery(queryRecherche);;
query.executeUpdate();
But I get the folowing error :
org.hibernate.query.sqm.ParsingException: line 1:66 no viable alternative at input 'DATE_ADD(t.dateDebut,INTERVAL1'
Have you please any suggestions to do this.

You're using Hibernate 6 (I can tell by the error message), so the correct HQL syntax to use is:
UPDATE MyEntity t SET t.dateDebut = t.dateDebut + 1 year WHERE t.id = 3
You had three errors in your query:
You referred to the name of a table instead of the name of an entity class in the UPDATE clause.
You used the unportable MySQL DATE_ADD function instead of the portable HQL date/time arithmetic described here.
The syntax of your WHERE clause was garbled.
Perhaps you meant for this to be a native SQL query, in which case you called the wrong method of Session. But there's no need to use native SQL for the above query. As you can see, HQL is perfectly capable of expressing that query.

You can use SQL directly, via createNativeQuery, or register a new function as shown in this example to call it from HQL

How can I correctly implement an Hibernate SQL query starting from an SQL query that count the number of rows?

I am absolutly new in Hibernate and I have the following problem.
I have this standard SQL query:
SELECT count(*)
FROM TID003_ANAGEDIFICIO anagraficaEdificio
INNER JOIN TID002_CANDIDATURA candidatura
ON (candidatura.PRG_PAR = anagraficaEdificio.PRG_PAR AND candidatura.PRG_CAN = anagraficaEdificio.PRG_CAN)
INNER JOIN TID001_ANAGPARTECIPA anagPartecipa ON(anagPartecipa.PRG_PAR = candidatura.PRG_PAR)
INNER JOIN anagrafiche.TPG1029_PROVNUOIST provNuovIst ON (provNuovIst.COD_PRV_NIS = anagPartecipa.COD_PRV_NIS)
WHERE anagraficaEdificio.FLG_GRA = 1 AND provNuovIst.COD_REG = "SI";
This works fine and return an integer number.
The important thing to know is that in this query the only
parameter that can change (inserted by the user in the frontend of a webappplication) is the last one (this one: provNuovIst.COD_REG = "SI").
So, the application on which I am working use Hibernate and the requirement say that I have to implement this query using Hibernate Native SQL, I have found this tutorial:
http://www.tutorialspoint.com/hibernate/hibernate_native_sql.htm
that show this example:
String sql = "SELECT * FROM EMPLOYEE WHERE id = :employee_id";
SQLQuery query = session.createSQLQuery(sql);
query.addEntity(Employee.class);
query.setParameter("employee_id", 10);
List results = query.list();
that, from what I have understand (correct me if I am doing wrong assertion), involves the use of an Employee model class. So th prvious query first define the query (using the :param_name syntax for the parameter), then create an SQLQuery Hibernate object, add the class used for the result, set the previous parameter neam and finally obtain a List (that I think Hibernate create as something like an ArrayList) with the retrieved object.
My problem is that I simply I have to obtain an integer value (because I have a SELECT count(*), so I will obtain an integer value and not a set of rows).
So how can I correctly use the Hibernate Native SQL to implement my SQL query into my Hibernate repository class?

Use SQLQuery.uniqueResult to retrieve a single value from the query:
String sql = "SELECT count(*) ...";
SQLQuery query = session.createSQLQuery(sql);
// set parameters...
int count = ((Number)query.uniqueResult()).intValue();

Force ebean to not include an ID in a generated query

I'm building a select that has to get me all distinct values from a table.
The sql I would normally write would look like this: "SELECT DISTINCT ARTIST FROM MUSICLIB"
However, ebean is generating the following: "SELECT DISTINCT ID, ARTIST FROM MUSICLIB"
The finder is as such:
find.select("artist").setDistinct(true).findList();
I've found that ebean is generating this ID on every single query, no matter what options I set.
How do I accomplish what I'm looking for?

You can't do that, Ebean for objects mapping requires ID field, and if you won't include it you'll get some mysterious exceptions.
Instead you can query DB without mapping and then write your SQL statement yourself:
SqlQuery sqlQuery = Ebean.createSqlQuery("SELECT DISTINCT artist FROM musiclib");
List<SqlRow> rows = sqlQuery.findList();
for (SqlRow row : rows) {
debug("I got one: " + row.getString("artist"));
}
Of course if artist is a relation, you need to perform additional query using list of found IDs with in(...) expression.

HQL not return results but when queried directly it works

I am trying below query in HQL but I get no results. Can someone help me on why I don't get any results? I tried to query the DB directly (please see SQL below) and i get 12 records. But HQL gives me 0 records.
"cause" I input the following String - "'XXX1','YYY 2'"
DB I use is Pracle 11g.
String queryStr = "from DefectsTran t join t.defects d where d.releaseName=:rel and t.defectCause in :cause and t.latestRecord=:lastrec";
Query q = session.createQuery(queryStr);
q.setString("rel", release);
q.setString("cause", filter2);
q.setString("lastrec", "Y");
SQL query that works fine when I use in TOAD.
select count(*)
from QC10.defects_tran t
inner join QC10.defects on DEFECT_ID_FK_DT = RECORD_ID
where
DEFECT_CAUSE in ('Data Request Issue', 'Functioning as Expected', 'User Education Required', 'Test Script Incorrect', 'Test Specific')
and t.latest_record = 'Y'

Instead of q.setString("cause", filter2); use q.setParameterList("cause", filter2);. filter2 has to be of a Collection subtype. Please read more about other overloading available for setParameterList: http://docs.jboss.org/hibernate/orm/3.2/api/org/hibernate/Query.html

jpa select statement with subnets

I am trying to write query with multiple select subnets in it.But I defined a nativequery
I am giving error. Compiler specifies that "(" after "from" is not proper. How can I define
a native query in JPA 2.0
For eaxmple:
SELECT *
from (SELECT ****C) REI3 where column1 != 1
GROUP BY REI3.column2 order by REI3.column3 ASC

JPA does not have too much to do with validating SQL syntax, query is passed to JDBC driver. Likely you are trying run query such a way, that it is interpreted as JP QL. Instead try following method to execute it as
Query q = em.createNativeQuery("Your SQL here");
Other alternative is to use NamedNativeQuery Example