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I'm writing a program where I have to write back out the numbers I am given until I get the number 42.
For example:
Input:
5
6
4
42
1
0
Output
5
6
4
So far, I have tried this:
package com.logical01;
import java.util.Scanner;
public class MainProgram {
public static void main(String[] args) {
int[] array = new int[100];
Scanner in = new Scanner(System.in);
System.out.println("Enter the number of elements: ");
int n_Elements = in.nextInt();
System.out.println("Enter the values now: ");
for (int i = 0; i < n_Elements; i++) {
array[i] = in.nextInt();
}
for (int i = 0; i < n_Elements; i++) {
if (i == 42) {
break;
}
System.out.println("\n"+array[i]);
}
}
}
However, this program does not work; it writes back the same values out (rather than stopping when there's a 42).
You need to change from
if(i == 42)
to
(if array[i] == 42)
i holds the value while iterating.
You need to change the loop to this:
for(int i=0; i<n_Elements; i++){
if(array[i]==42){
break;
}
This is because you want to iterate through the array and check if the value at index i is 42,
e.g. array[4] = {1,2,42,3};
Then the loop iterates through the array and:
array[0] == 42 false
array[1] == 42 false
array[2] == 42 true therefore -> break;
Related
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I would like to write a program that reads an array of integers and finds the minimum value.
The first line contains the size of an array.
Output
An integer number representing the minimum in the input array.
Input:
5
5 1 4 2 3
My code:
import java.util.Arrays;
import java.util.Scanner;
class Main {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
int a = sc.nextInt();
int[] c = new int[a ];
for (int i = 0; i < c.length; i++) {
c[i] = sc.nextInt();
}
Arrays.sort(c);
int b= c[0] > 0 ? c[0]: c[c.length -1];
for (int i =1; i < c.length - 1; i++){
if(c[i] < 0){
if(c[i] > b){
b = c[i];
}
}
else{
if (c[i] < b){
b= c[i];
}
}
}
System.out.println(b);
}
}
My output:
3
-1 -2 -3
What is wrong with my code?
You are making it more complicated than necessary. No need to sort the array. Just set a variable to be equal to the first value in the array. Then scan through the array setting the variable to the actual array element if it is less than the present variable value.
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if Take an array of size 10 and take user inputs.how can i Traverse the array and each time you encounter '6' or '7', replace them with 60 and 70 respectively in java??
Maybe you can try this,
int[] input = {1,2,3,4,5,6,7,8,9};
for(int i = 0; i < input.length; i++)
if(input[i]==6 || input[i]==7)
input[i]*=10;
//Printing
for(int i : input)
System.out.println(i);
Here is a simplistic approach. Loop through the array and check each positions value. If it's a 6 or 7 replace as expected.
public static void main(String[] args){
int[] array = {1,2,3,4,5,6,7,8,9};
for(int i = 0; i < array.length; i++){
if(array[i] == 6){
array[i] = 60;
}
else if(array[i] == 7){
array[i] = 70;
}
}
for(int i : array){
System.out.println(i);
}
}
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import java.io.*;
import java.util.*;
public class Binary {
public static void main(String args[]) {
int i = 0, j = 0, num;
Scanner in = new Scanner(System.in);
int arr[] = new int[100];
System.out.println("enter the number");
num = in.nextInt();
while (num != 1) {
j = num % 2;
num = num / 2;
arr[i] = j;
i++;
}
for (i = i; i <= 0; i--) {
System.out.print("The binary number: " + arr[i]);
}
}
}
I wrote this programme to convert decimal input to its corresponding binary value, the programme takes the input but it does not show the output i.e. the binary value. please help
As it was already pointed out, you need to change the condition of
while (num != 1) {
to
while (num > 0) {
since your version is prone to an infinite cycle due to the possibility of num being 2.
Change the for cycle, like this:
for (i = arr.length - 1; i >= 0; i--) {
System.out.print("The binary number: " + arr[i]);
}
but to be able to do this, you need to know how many elements will you need to use, so change the declaration of arr to this
int arr[] = new int[(int)Math.ceil(Math.log(num) / Math.log(2))];
But to be able to do this, you need to initialize num before you declare arr. Code is untested, let me know if there are any typos.
condition should be while(num!=0){ //do calculations}
and change the condition of for loop into for(i=i;i>=0;i--){}
You could use the Integer class and it's static method toBinaryString(int i). This method converts an int into its binary value and returns it as a String.
If I correctly understood what you are trying to achieve, you could just write:
Scanner in = new Scanner(System.in);
System.out.println("enter the number");
int num = in.nextInt();
String binary = Integer.toBinaryString(num);
System.out.print("The binary number: " + binary);
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Here is some basic code:
public static void main(String[] args) {
String string = "Hello!";
System.out.println("First loop.");
for (int i = 0; i < string.length(); i++) {
System.out.println("g");
}
System.out.println("Second loop.");
for (int i = (string.length() - 1); i <= 0; i--) {
System.out.println("g");
}
}
For some reason, the program won't go through the second loop at all. This is somewhat strange. Can you explain this, and how to fix it?
Your second loop should be looping backwards, while the index is still greater than or equal to zero, not less than or equal to zero. With <= 0, i is greater than zero on the first evaluation and the loop never runs.
Try:
for (int i = (string.length() - 1); i >= 0; i--) {
Change the for condition,the i is initial with value greater than 0 (length-1) and there is condition i <= 0 which is true in case length is equal to 1.But the length of string is 6 so change the condition as below :
for (int i = (string.length() - 1); i >= 0; i--) {
System.out.println("g");
}
Your problem is the condition in the second for loop
i <= 0
never happens. I don't understand why you would want to check that.
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array[0] = 1;
array[1] = 2;
array[2] = 3;
array[3] = 4;
items_arr = 4;
System.out.println("The elements in the array are: ");
for (int x = 0; x < items_arr; x++)
System.out.println("Array[" + x + "]=" + array[x]);
System.out.print("\n");
Scanner insert = new Scanner(System.in);
System.out.print("Enter an Element to Insert: ");
int input = insert.nextInt();
for (s = 0; s < items_arr; s++)
if (array[s] == input)
break;
items_arr++;
for (s = 0; s < items_arr; s++)
System.out.println("Array[" + s + "]=" + array[s]);
break;
The output is. The elements are
Array [0]= 1
Array [1]= 2
Array [2]= 3
Array [3]= 4
Enter an element to Insert: 5
Array [0]= 1
Array [1]= 2
Array [2]= 3
Array [3]= 4
Array [4]= 0
when I insert 5 it posts 0
any suggestions please.. thanks!
To insert in to the array you shuould be doing follwoing operation
array[s]=input
Two notes here
Arrays are fixed length, and you should be checking the array length before inserting values in to that,other wise you will get ArrayIndexOBException. Safer to sue List/Set
As better coding practise, and to improve the readablity, you should be enclosing the conditional/loop statements (such as if or for) - see eg below
eg: 1
for (int x = 0;x<items_arr;x++) {
System.out.println("Array["+x+"]="+array[x]);
}
eg 2:
for(int s = 0; s < items_arr; s++) {
if (array[s] == input) {
break;
}
}
You have not inserted 5 in your array,
do something after items_arr++
array[ items_arr] = input;
If you do not insert any thing then by default every element is 0
You should be using a Collection type; I would recommend an ArrayList - that is -
List<Integer> al = new ArrayList<Integer>();
for (int i = 1; i < 5; i++) {
al.add(i);
}
Scanner insert = new Scanner(System.in);
System.out.print("Enter an Element to Insert: ");
int input = insert.nextInt();
al.add(input); // And so on...
You are not updating/inserting the array with the new input.
for(s = 0; s < items_arr; s++)
if (array[s] == input)
break;
items_arr++;
just replace the above code with
array[ items_arr] = input;
items_arr++;