So, I want to compare from string to array of strings
String [] string = new String [10];
string [1] = "pencil";
string [2] = "pen";
string [3] = "eraser";
how do i compare string to the array of strings from above?
A quicker way is to use this code
if(Arrays.asList(string).contains(search_string))
If I understand you correctly, Write a loop, where iterate multiple string(example array) and equals with src string.
String [] string = new String [10];
...
String src = ..;//src string
for(String string : string){
if(src.equals(string)){
//Equal
}
}
Try using this:
for (int i = 0; i < string.length; i++) {
if (ch.equals(string[i])) { // ch is the string to compare
System.out.println("equal");//or whatever your action is
}
}
EDIT:
If what you are seeking to do is to verify if the searched string appears in the string[i] you can try:
string[0] = "pentagon";
string[1] = "pencil";
string[2] = "pen";
string[3] = "eraser";
string[4] = "penny";
string[5] = "pen";
string[6] = "penguin";
string[7] = "charp";
string[8] = "charpen";
string[9] = "";
String ch = "pen";
Then test if the arrays elements contain the searched string:
for (int i = 0; i < string.length; i++) {
if (string[i].indexOf(ch) != -1) {
System.out.println(string[i]+" contains "+ch);
} else
System.out.println(string[i]+" doesn't contain "+ch);
}
EDIT 2:
int i=0;
Boolean found=false;
while(i < string.length && !found) {
if (string[i].indexOf(ch) != -1) {
found=true;
}
i++;
}
if(found){
system.out.println(ch+" is found");
}
Related
I have a string array for example:
new String[] = {"powerhouse", "p, pow, power, house, pose, poser"};
My goal is to split the first entry in the array in this case powerhouse into any two words and check them against the second entry, which serves as a dictionary of words.
Here's my implementation so far:
public static String[] convertWordsToArray(String input){
String[] wordArr = null;
wordArr = input.split(",");
return wordArr;
}
public static String splitEm(String[] strArr) {
String fw = strArr[0];
String sw = strArr[1];
String[] arrOne = convertWordsToArray(fw);
System.out.println(arrOne.length);
String[] dict = convertWordsToArray(sw);
System.out.println(dict.length);
for(int i = 0; i < dict.length - 1; i++) {
String mWord = fw.split(i, i + 1);
System.out.println(mWord);
}
// Edit Starts Here, tried to substring it but nothing prints in log
for(int i = 0; i < arrOne.length; i++) {
String mWord = fw.substring(0, i);
System.out.println(mWord);
}
return ""; // empty for now
}
I am stuck at the part where the first word has to be split. Should I use two loops, one for the first word and the other for the dictionary? I know that somehow the dictionary has to be converted to a list or array list to avail the .contains() method. How do I go about this? Thanks.
If anyone want the solution for PHP language, then you can use below code:
function ArrayChallenge($strArr) {
$dictWords = explode( ',', $strArr[1] );
$strLength = strlen($strArr[0]);
$output = 'not possible';
for( $i = 1; $i < $strLength; $i++ ){
$firstStr = substr($strArr[0], 0, $i);
$lastStr = substr($strArr[0], $i, $strLength);
if ( in_array( $firstStr, $dictWords ) && in_array( $lastStr, $dictWords ) ) {
$output = $firstStr . ',' . $lastStr;
break;
}
}
return $output;
}
Do you need something like this?
String s = "powerhouse";
List<String> list = new ArrayList<String>();
for(int i = 0; i < s.length(); i++){
for(int j = i+1; j <= s.length(); j++){
list.add(s.substring(i,j));
}
}
System.out.println(list);
I assume you need something like below:
Split second string at each , or even better using regex to trim
spaces before or after ,
check if each part of the splited entry fro above point is made of
only the chars contained in the first entry of your input
example
public static void main(String args[]) {
String[] test1 = {"powerhouse", "p, pow, power, house, pose, poser"};
String[] test2 = {"powerhouse", "p, xyz, power, house, pose, poser"};
System.out.println(check(test1));
System.out.println(check(test2));
}
static boolean check(String[] input){
String firstEntry = input[0];
String[] dictionary = input[1].split("\\s*,\\s*");
for(int i = 0; i < dictionary.length; i++){
if(!dictionary[i].matches("["+firstEntry+"]+")){
return false;
}
}
return true;
}
this will print true for the first case and false for the second as "xyz" is not a valid subpart/substring according to your discription
Try this :
public class Stack {
public static void main(String[] args) {
String[] str = {"powerhouse", "p, pow, power, house, pose, poser"};
String firstPart = str[0];
String secondPart = str[1];
boolean contain = isContain(firstPart, secondPart);
System.out.println(contain);
}
private static boolean isContain(String firstPart, String secondPart) {
for (int i = 0; i < firstPart.length(); i++) {
String firstWord = firstPart.substring(0, i);
String secondWord = firstPart.substring(i, firstPart.length());
List<String> strings = Arrays.asList(secondPart.trim().split("\\s*,\\s*"));
if (strings.contains(firstWord) && strings.contains(secondWord)) return true; if you want to check both words use this
//if (strings.contains(firstWord) || strings.contains(secondWord)) return true; if you want to check any(one) word from two words use this
}
return false;
}
}
I was working on a Java coding problem and encountered the following issue.
Input: A String -> "Code"
Output Expected: A string -> CCoCodCode
My Code snippet: (Note: In comments I have written what I expect upon passing the string)
public String stringSplosion(String str) { // string Say 'Code'
String join = "", values = "";
String gotIt = "";
int n = str.length(); // 4
int size = 0;
for (int i = n; i >= 1; i--) {
size = size + n; // 4+3+2+1=10
}
String[] result = new String[size];
for (int i = 0; i < str.length(); i++) {
values = str.substring(i, i + 1);
join = join + values;
result[i] = join;
}
for (String s : result) {
gotIt = gotIt + s;
}
return gotIt; // Expected output: CCoCodCode
}
Output I am getting:
CCoCodCodenullnullnullnullnullnullnullnullnullnullnullnull
Why is null getting stored although I have reduced the size and how can I remove it?
NOTE: I need to solve this using arrays. I know it is much easier using List.
If you want to keep the current structure of your code, get rid of the first for loop.
And create String[] array = new String[n]
public static String stringSplosion(String str) { // string Say 'Code'
String join = "", values = "";
String gotIt = "";
int n = str.length(); // 4
String[] result = new String[n]; //you want your String array to contain 4 strings
for (int i = 0; i < str.length(); i++) {
values = str.substring(i, i + 1);
join = join + values;
result[i] = join;
}
for (String s : result) {
gotIt = gotIt + s;
}
return gotIt; // Expected output: CCoCodCode
}
public class Answer {
public static String answer(String input){
StringBuilder sb = new StringBuilder(((input.length() + 1) * input.length()) / 2);
for (int i = 1; i <= input.length(); i++) {
sb.append(input.substring(0, i));
}
return sb.toString();
}
public static void main(String[] args) {
System.out.println(answer("Code"));
}
}
Below statements are not required:
int size = 0;
for (int i = n; i >= 1; i--) {
size = size + n; // 4+3+2+1=10
}
You just need to change the array size from
String[] result = new String[size];
to
String[] result = new String[n];
for your program to give the expected output.
If I understand ur problem correctly to print the pattern then u can use below code,
public String printPattern(String input){
//Holds the iteration value by index
int previous=0;
//It holds the result characters
String result=null;
StringBuilder strBuilder=new StringBuilder();
//first loop to iterate only till input string length
for(int i=0;i<input.length();i++){
//checking iteration lenght with input string length
if(previous<input.length()){
//incrementing iteration for reading characters from input string
previous++;
//main loop for previous iteration value check and iterate
for(int j=0;j<previous;j++){
//converting string to Character array
char a []=input.toCharArray();
//using string builder to build the string from characters
strBuilder.append((a[j]));
//setting the value to stringbuilder by converting it in string
result=strBuilder.toString();
}
}
}
return result;
}
Size should be the length of string. Code's length is 4. Code will produce {C, Co, Cod, Code}.
public String stringSplosion(String str) { // string Say 'Code'
String join = "", values = "";
String gotIt = "";
int n = str.length(); // 4
String[] result = new String[n];
for (int i = 0; i < str.length(); i++) {
values = str.substring(i, i + 1);
join = join + values;
result[i] = join;
}
System.out.println(Arrays.toString(result));
for (String s : result) {
gotIt = gotIt + s;
}
return gotIt; // Expected output: CCoCodCode
}
String input = "Code";
String output[] = IntStream.range(0, input.length()+1)
.mapToObj(i -> input.substring(0, i))
.toArray(String[]::new);
I have an assignment for school due at midnight today. I have finished almost all the assignment except for one question. I need to swap "r" and "q" with each other as values. So, if you enter "r" in the compiler you should get "q" if you enter "q" you get "r"(Using JOptionPane). For example, if your name is Quart, the compiler should print Ruaqt. I tried using the replace.All method, but once I can only swap "r" or "q" not both. I know I need a temporary variable, but do not know anything else...
We had to replace vowels with the letter after them so I did this:
String firstName = JOptionPane
.showInputDialog("What is your first name?");
String lastName = JOptionPane
.showInputDialog("What is your last name?");
String fullname = firstname + lastname;
String lowername = fullName.toLowerCase();
String encryptedname = lowername.replaceAll("a", "b")
.replaceAll("e", "f").replaceAll("i", "j").replaceAll("o", "p")
.replaceAll("u", "v");
Thanks
Dunno why the 2 answers using StringBuilder are both making the thing more complicated than needed.
Here is the way you can use StringBuilder to do that single character swap:
public static String swapChar(String string, char c1, char c2) {
StringBuilder sb = new StringBuilder(string);
for (int i = 0; i < sb.length(); ++i) {
if (sb.charAt(i) == c1) {
sb.setCharAt(i, c2);
} else if (sb.charAt(i) == c2) {
sb.setCharAt(i, c1);
}
}
return sb.toString();
}
Update :
Just found that what you are looking for is actually doing a bunch of replace of character at the same time. That can be cleanly done by providing a Map as parameter:
public static String replaceChars(String string, Map<Character,Character> cmap) {
StringBuilder sb = new StringBuilder(string);
for (int i = 0; i < sb.length(); ++i) {
if (cmap.containsKey(sb.charAt(i)) {
sb.setCharAt(i, cmap.get(sb.charAt(i));
}
}
return sb.toString();
}
to use it:
// or make a util method to make these even easier to create
Map<Character,Character> cmap = new HashMap<Character,Character>();
cmap.put('r','q');
cmap.put('q','r');
cmap.put('a','b');
cmap.put('e','f');
cmap.put('i','j');
cmap.put('o','p');
cmap.put('u','v');
and simply do a replace:
String result = replaceChars(inputString, cmap);
or even simpler, by making use of Apache Commons Lang:
String result = StringUtils.replaceChars(inputString, "rqaeiou", "qrbfjpv");
You can try this.
private static final char Q_STR = 'q';
private static final char R_STR = 'r';
public static String replaceString(String original, int position, char strToReplace) {
StringBuilder strBuilder = new StringBuilder(original);
if (strToReplace == Q_STR) {
strBuilder.setCharAt(position, R_STR);
} else if (strToReplace == R_STR){
strBuilder.setCharAt(position, Q_STR);
}
return strBuilder.toString();
}
public static void main(String[] args) {
String firstname = "Quart";
String lastname = " QuartLastName";
String fullname = firstname + lastname;
String lowername = fullname.toLowerCase();
//get all chars in String
char[] array = lowername.toCharArray();
//list to keep original position of Q char
List<Integer> allQPosition = new ArrayList<Integer>();
//list to keep original position of R char
List<Integer> allRPosition = new ArrayList<Integer>();
for (int i = 0; i < array.length; i++) {
if(array[i] == 'q') {
allQPosition.add(i);
} else if(array[i] == 'r') {
allRPosition.add(i);
}
}
//replace q
for (Integer integer : allQPosition) {
lowername = replaceString(lowername, integer, Q_STR);
}
//replace r
for (Integer integer : allRPosition) {
lowername = replaceString(lowername, integer, R_STR);
}
//replace others
String encryptedname = lowername.replace("a", "b")
.replace("e", "f")
.replace("i", "j")
.replace("o", "p")
.replace("u", "v");
System.out.println("Result: " + encryptedname);
}
My solution is:
Keep all position of 'q' and 'r' from original String.
Replace each of them
Replace the rest of other chars
Hope this help
public static void main(String[] args) {
String origin = "r and q";
System.out.println(newReplacement(origin, 'r', 'q'));
}
private static String newReplacement(String origin, char firstChar, char secondChar) {
StringBuffer stringBuffer = new StringBuffer(origin);
for(int i = 0; i < origin.length(); i++) {
if(origin.charAt(i) == firstChar) {
stringBuffer.replace(i, i+1, secondChar + "");
continue;
}
if(origin.charAt(i) == secondChar) {
stringBuffer.replace(i, i+1, firstChar + "");
}
}
return stringBuffer.toString();
}
Rewrite replace method with simple one.
This question already has answers here:
What is the simplest way to convert a Java string from all caps (words separated by underscores) to CamelCase (no word separators)?
(22 answers)
Closed 7 years ago.
convert string to camelCase
eg:
"user_id" to "userId"
"user_name" to "userName"
"country_province_city" to "countryProvinceCity"
how to do that in a easy way?
ps:"country_province_city" should be "countryProvinceCity" not "countryprovincecity"
I would use a loop and a StringBuilder. Something like
String[] arr = { "user_id", "user_name", "country_province_city" };
for (String str : arr) {
StringBuilder sb = new StringBuilder(str);
int pos;
while ((pos = sb.indexOf("_")) > -1) {
String ch = sb.substring(pos + 1, pos + 2);
sb.replace(pos, pos + 2, ch.toUpperCase());
}
System.out.printf("%s = %s%n", str, sb);
}
And I get the (requested)
user_id = userId
user_name = userName
country_province_city = countryProvinceCity
As Fast Snail mentions, simply use, for example, if String str = "user_id, user_name, user_id";, call str = str.replaceAll("userID", "user_id");, causing str to now have the value "userID, user_name, userID"
Alternatively, a more complete method would be as follows
public String toCamel(String str) {
String[] splits = str.split("_");
for (int i = 1; i < splits.length; i++) {
char first = Character.toUpperCase(splits.charAt(0));
if (splits[i].length() > 0)
splits[i] = first + splits[i].substring(1);
else
splits[i] = first + "";
}
String toRet = "";
for (String s : splits)
toRet += s;
return toRet;
}
This is a very simple one:
public static void main(String[] args) {
Scanner scan = new Scanner(System.in);
String result = "";
String input = scan.nextLine();
for (int i = 0; i < input.length(); i++) {
if (input.charAt(i) == '_') {
result += input.toUpperCase().charAt(i + 1);
i = i + 1;
} else {
result += input.toLowerCase().charAt(i);
}
}
System.out.println(result);
}
if you like to do it many times, I advice you to use a while loop to keep repeating the same code over and over again:
while (true) {
//the previous code
}
http://commons.apache.org/proper/commons-lang/javadocs/api-3.4/index.html
String str="country_province_city";
wordUtils.capitalize(str, '_');
str=str.replaceAll("_", "");
output: countryProvinceCity
For another point of view that the answers above you can also do it with split function and two loops, like this:
String[] strings = {"user_id","user_name","country_province_city"};
for (int i = 0; i < strings.length; i++)
{
String string = strings[i];
String totalString = "";
String[] divide = string.split("_");
for(int j = 0; j < divide.length; j++)
{
if(j != 0)
{
divide[j] = "" + divide[j].toUpperCase().charAt(0) + divide[j].substring(1,divide[j].length());
}
totalString = totalString + divide[j];
}
}
If you want to show this changed Strings by console you just have to add System.out.println after the second loop and inside the first one, like this:
for (int i = 0; i < strings.length; i++)
{
//The same code as the code that I put in the example above
for(int j = 0; j < divide.length; j++)
{
//The same code as the example above
}
System.out.println(totalString);
}
On the contrary, if your objective it's to store them into an array, you can do it like this:
String[] store;
for (int i = 0; i < strings.length; i++)
{
//The same code as the code that I put in the example above
store = new String[divide.length];
for(int j = 0; j < divide.length; j++)
{
//The same code as the example above
}
store[j] = totalString;
}
If you have any doubt about the code please let me know.
I expect it will help to you!
How do I compare 2 numbers which can have the values 202.10.200 and 202.101.30 in java. I understand the above 2 cannot be "numbers". We need to compare this keeping in mind 202.101.30 should be greater than 202.10.200.
Scanner keyboard = new Scanner(System.in);
String inputLine = keyboard.nextLine();
String[] inputArray = inputLine.split(".");
int[] numArray = null;
for(int i = 0; i < inputArray<length; i++)
{ numArray[i] = Integer.parseInt(inputArray[i]);
}
Then you just need to write another loop to compare another two input arrays with different numbers.
If you are sure that strings are syntattically identical and have the same number of elements separated by ".", you can split them into arrays, convert arrays elements into int and then compare them onw by one:
String s1 = "202.10.200";
String s2 = "202.101.30";
String sGreater = s1;
String[] strArr1 = s1.split("\\.");
String[] strArr2 = s2.split("\\.");
for (int i=0; i<strArr1.length; i++)
{
int x1 = Integer.parseInt(strArr1[i]);
int x2 = Integer.parseInt(strArr2[i]);
if (x2>x1)
{
sGreater = s2;
break;
}
}
This method can be used as an implementation of a Comparator:
public static int compareTo(String s1, String s2) {
String[] a1 = s1.split("\\.");
String[] a2 = s2.split("\\.");
for (int i = 0; i < 3; i++) {
if (!a1[i].equals(a2[i]))
return Integer.parseInt(a1[i]) - Integer.parseInt(a2[i]);
}
return 0;
}
This one works with any (but equal) number of integer groups separated by dots.
private static int compareDotNums(String str1, String str2) {
if (str1 != null && str2 != null) {
String[] split1 = str1.split("\\.");
String[] split2 = str2.split("\\.");
if (split1.length != split2.length)
throw new IllegalArgumentException("Input length mismatch.");
int result = 0;
for (int i = 0; i < split1.length; i++) {
try {
result = Integer.valueOf(split1[i]).
compareTo(Integer.valueOf(split2[i]));
} catch (NumberFormatException e) {
throw new IllegalArgumentException(
"Illegal input. Not a number.");
}
if (result != 0)
break;
}
return result;
} else
throw new IllegalArgumentException("Non-null input required.");
}
Sample Output:
System.out.println(compareDotNums("202.10.200", "202.201.30")); // -1
System.out.println(compareDotNums("202.210.200", "202.201.30")); // 0
System.out.println(compareDotNums("202.201.30", "202.201.30")); // 1
System.out.println(compareDotNums("202.201.30.110", "202.201.30.128")); // -1
System.out.println(compareDotNums("202.201.30.128", "202.201.30.128")); // 0
System.out.println(compareDotNums("202.201.30.210", "202.201.30.128")); // 1