Just as a counterpoint to this question: what is an interface in Java?
An interface is a special form of an abstract class which does not implement any methods. In Java, you create an interface like this:
interface Interface
{
void interfaceMethod();
}
Since the interface can't implement any methods, it's implied that the entire thing, including all the methods, are both public and abstract (abstract in Java terms means "not implemented by this class"). So the interface above is identical to the interface below:
public interface Interface
{
abstract public void interfaceMethod();
}
To use this interface, you simply need to implement the interface. Many classes can implement an interface, and a class can implement many interfaces:
interface InterfaceA
{
void interfaceMethodA();
}
interface InterfaceB
{
void interfaceMethodB();
}
public class ImplementingClassA
implements InterfaceA, InterfaceB
{
public void interfaceMethodA()
{
System.out.println("interfaceA, interfaceMethodA, implementation A");
}
public void interfaceMethodB()
{
System.out.println("interfaceB, interfaceMethodB, implementation A");
}
}
public class ImplementingClassB
implements InterfaceA, InterfaceB
{
public void interfaceMethodA()
{
System.out.println("interfaceA, interfaceMethodA, implementation B");
}
public void interfaceMethodB()
{
System.out.println("interfaceB, interfaceMethodB, implementation B");
}
}
Now if you wanted you could write a method like this:
public void testInterfaces()
{
ImplementingClassA u = new ImplementingClassA();
ImplementingClassB v = new ImplementingClassB();
InterfaceA w = new ImplementingClassA();
InterfaceA x = new ImplementingClassB();
InterfaceB y = new ImplementingClassA();
InterfaceB z = new ImplementingClassB();
u.interfaceMethodA();
// prints "interfaceA, interfaceMethodA, implementation A"
u.interfaceMethodB();
// prints "interfaceB, interfaceMethodB, implementation A"
v.interfaceMethodA();
// prints "interfaceA, interfaceMethodA, implementation B"
v.interfaceMethodB();
// prints "interfaceB, interfaceMethodB, implementation B"
w.interfaceMethodA();
// prints "interfaceA, interfaceMethodA, implementation A"
x.interfaceMethodA();
// prints "interfaceA, interfaceMethodA, implementation B"
y.interfaceMethodB();
// prints "interfaceB, interfaceMethodB, implementation A"
z.interfaceMethodB();
// prints "interfaceB, interfaceMethodB, implementation B"
}
However, you could never do the following:
public void testInterfaces()
{
InterfaceA y = new ImplementingClassA();
InterfaceB z = new ImplementingClassB();
y.interfaceMethodB(); // ERROR!
z.interfaceMethodA(); // ERROR!
}
The reason you can't do this is that y is of type interfaceA, and there is no interfaceMethodB() in interfaceA. Likewise, z is of type interfaceB and there is no interfaceMethodA() in interfaceB.
I mentioned earlier that interfaces are just a special form of an abstract class. To illustrate that point, look at the following code.
interface Interface
{
void abstractMethod();
}
abstract public class AbstractClass
{
abstract public void abstractMethod();
}
You would inherit from these classes almost exactly the same way:
public class InheritsFromInterface
implements Interface
{
public void abstractMethod() { System.out.println("abstractMethod()"); }
}
public class InteritsFromAbstractClass
extends AbstractClass
{
public void abstractMethod() { System.out.println("abstractMethod()"); }
}
In fact, you could even change the interface and the abstract class like this:
interface Interface
{
void abstractMethod();
}
abstract public class AbstractClass
implements Interface
{
abstract public void abstractMethod();
}
public class InheritsFromInterfaceAndAbstractClass
extends AbstractClass implements Interface
{
public void abstractMethod() { System.out.println("abstractMethod()"); }
}
However, there are two differences between interfaces and abstract classes.
The first difference is that interfaces cannot implement methods.
interface Interface
{
public void implementedMethod()
{
System.out.println("implementedMethod()");
}
}
The interface above generates a compiler error because it has an implementation for implementedMethod(). If you wanted to implement the method but not be able to instantiate the class, you would have to do it like this:
abstract public class AbstractClass
{
public void implementedMethod()
{
System.out.println("implementedMethod()");
}
}
That's not much of an abstract class because none of its members are abstract, but it is legal Java.
The other difference between interfaces and abstract classes is that a class can inherit from multiple interfaces, but can only inherit from one abstract class.
abstract public class AbstractClassA { }
abstract public class AbstractClassB { }
public class InheritsFromTwoAbstractClasses
extends AbstractClassA, AbstractClassB
{ }
The code above generates a compiler error, not because the classes are all empty, but because InheritsFromTwoAbstractClasses is trying to inherit from two abstract classes, which is illegal. The following is perfectly legal.
interface InterfaceA { }
interface InterfaceB { }
public class InheritsFromTwoInterfaces
implements InterfaceA, InterfaceB
{ }
The first difference between interfaces and abstract classes is the reason for the second difference. Take a look at the following code.
interface InterfaceA
{
void method();
}
interface InterfaceB
{
void method();
}
public class InheritsFromTwoInterfaces
implements InterfaceA, InterfaceB
{
void method() { System.out.println("method()"); }
}
There's no problem with the code above because InterfaceA and InterfaceB don't have anything to hide. It's easy to tell that a call to method will print "method()".
Now look at the following code:
abstract public class AbstractClassA
{
void method() { System.out.println("Hello"); }
}
abstract public class AbstractClassB
{
void method() { System.out.println("Goodbye"); }
}
public class InheritsFromTwoAbstractClasses
extends AbstractClassA, AbstractClassB
{ }
This is exactly the same as our other example, except that because we're allowed to implement methods in abstract classes, we did, and because we don't have to implement already-implemented methods in an inheriting class, we didn't. But you may have noticed, there's a problem. What happens when we call new InheritsFromTwoAbstractClasses().method()? Does it print "Hello" or "Goodbye"? You probably don't know, and neither does the Java compiler. Another language, C++ allowed this kind of inheritance and they resolved these issues in ways that were often very complicated. To avoid this kind of trouble, Java decided to make this "multiple inheritance" illegal.
The downside to Java's solution that the following can't be done:
abstract public class AbstractClassA
{
void hi() { System.out.println("Hello"); }
}
abstract public class AbstractClassB
{
void bye() { System.out.println("Goodbye"); }
}
public class InheritsFromTwoAbstractClasses
extends AbstractClassA, AbstractClassB
{ }
AbstractClassA and AbstractClassB are "mixins" or classes that aren't intended to be instantiated but add functionality to the classes that they are "mixed into" through inheritance. There's obviously no problem figuring out what happens if you call new InheritsFromTwoAbstractClasses().hi() or new InheritsFromTwoAbstractClasses().bye(), but you can't do that because Java doesn't allow it.
(I know this is a long post, so if there are any mistakes in it please let me know and I will correct them.)
Interface is a contract. A simple example is a Tenant and Landlord which are the two parties and the contract is the Rent Agreement. Rent Agreement contains various clause which Tenants have to follow. Likewise Interface is a contact which contains various method (Declaration) which the Party has to implement (provide method bodies).Here party one is the class which implement the interface and second party is Client and the way to use and interface is having “Reference of Interface” and “Object of Implementing class”: below are 3 components:(Explained with help of example)
Component 1] Interface : The Contract
interface myInterface{
public void myMethod();
}
Component 2] Implementing Class : Party number 1
class myClass implements myInterface {
#Override
public void myMethod() {
System.out.println("in MyMethod");
}
}
Component 3] Client code : Party number 2
Client.java
public class Client {
public static void main(String[] args) {
myInterface mi = new myClass();
// Reference of Interface = Object of Implementing Class
mi.myMethod(); // this will print in MyMethod
}
}
An interface in java is a blueprint of a class. It has static constants and abstract methods only.The interface in java is a mechanism to achieve fully abstraction. There can be only abstract methods in the java interface not method body. It is used to achieve fully abstraction and multiple inheritance in Java. An interface is a collection of abstract methods. A class implements an interface, thereby inheriting the abstract methods of the interface.
An interface is not a class. Writing an interface is similar to writing a class, but they are two different concepts. A class describes the attributes and behaviors of an object. An interface contains behaviors(Abstract Methods) that a class implements.
Unless the class that implements the interface is abstract, all the methods of the interface need to be defined in the class.Since multiple inheritance is not allowed in java so interface is only way to implement multiple inheritance.
Here is an example for understanding interface
interface Printable{
void print();
}
interface Showable{
void print();
}
class testinterface1 implements Printable,Showable{
public void print(){System.out.println("Hello");}
public static void main(String args[]){
testinterface1 obj = new testinterface1();
obj.print();
}
}
Interface : System requirement service.
Description : Suppose a client needed some functionality "i.e. JDBC API" interface and some other server Apache , Jetty , WebServer they all provide implements of this.
So it bounded requirement document which service provider provided to the user who uses data-connection with these server Apache , Jetty , WebServer .
Interface is the blueprint of an class.
There is one oop's concept called Data abstraction under that there are two categories one is abstract class and other one is interface.
Abstract class achieves only partial abstraction but interface achieves full abstraction.
In interface there is only abstract methods and final variables..you can extends any number of interface and you can implement any number of classes.
If any class is implementing the interface then the class must implements the abstract methods too
Interface cannot be instantiated.
interface A() {
void print()
}
This question is 6 years old and lot of things have changed the definition of interface over the years.
From oracle documentation page ( post Java 8 release) :
In the Java programming language, an interface is a reference type, similar to a class, that can contain only constants, method signatures, default methods, static methods, and nested types. Method bodies exist only for default methods and static methods. Interfaces cannot be instantiated—they can only be implemented by classes or extended by other interfaces.
Have a look at related SE questions for better explanation:
Is there more to an interface than having the correct methods
What is the difference between an interface and abstract class?
What it is
An interface is a reference type, just like a class is. These are the two main reference types in Java.
What it contains
An interface can contain a subset of what a normal class can contain. This includes everything that is static, both methods and variables, and non-static method declarations. It is not allowed to have non-static variables.
A declaration of a method differs from a normal method in several things; here is one as an example:
[public] [abstract] ReturnType methodName();
These declarations can be marked as public and abstract, as represented with [optional braces]. It is not necessary to do so, as it is the default. private, protected, package-private (aka. nothing) and the final modifier are not allowed and marked as a compiler error. They have not implementation, so there is a semicolon instead of curly braces.
As of Java 8, they can hold non-static methods with an implementation, these have to be marked with the default modifier. However, the same restrictions as to the other modifiers apply (adding that strictfp is now valid and abstract is no more).
What it's useful for
One of its uses is for it to be used as a face for a service. When two parties work together to form a service-requester & service-provider kind of relationship, the service provider provides the face of the service (as to what the service looks like) in the form of an interface.
One of the OOP concept is "Abstraction" which means to hide away complex working of the systems and show only what is necessary to understand the system. This helps in visualizing the working of a complex system.
This can be achieved through interface where in each module is visualized (and also implemented) to work through interface of another module
An interface is a class-like construct that contains only constants and abstract methods (Introduction to java programming, n.d.). Moreover, it can extend more than one interface for example a Superclass. Java allows only single inheritance for class extension but allows multiple extensions for
interfaces(Introduction to Java programming, n.d.) For example,
public class NewClass extends BaseClass
implements Interface1, ..., InterfaceN {
...
}
Secondly, interfaces can be used to specify the behavior of objects in a class. However, they cannot contain abstract methods. Also, an interface can inherit other interfaces using the extends keyword.
public interface NewInterface extends Interface1, ... , InterfaceN {
}
Reference
Introduction to Java Programming. Interfaces and Abstract classes (n.d). Retrieved March 10, 2017 from https://viewer.gcu.edu/7NNUKW
In general, we prefer interfaces when there are two are more implementations we have. Where Interface is acts as protocol.
Coding to interface, not implementations Coding to interface makes loosely couple.
An interface is a reference type in Java. It is similar to class. It is a collection of abstract methods. A class implements an interface, thereby inheriting the abstract methods of the interface. Along with abstract methods, an interface may also contain constants, default methods, static methods, and nested types. for more details
From the latest definition by Oracle, Interface is:
There are a number of situations in software engineering when it is
important for disparate groups of programmers to agree to a "contract"
that spells out how their software interacts. Each group should be
able to write their code without any knowledge of how the other
group's code is written. Generally speaking, interfaces are such
contracts.
For example, imagine a futuristic society where computer-controlled
robotic cars transport passengers through city streets without a human
operator. Automobile manufacturers write software (Java, of course)
that operates the automobile—stop, start, accelerate, turn left, and
so forth. Another industrial group, electronic guidance instrument
manufacturers, make computer systems that receive GPS (Global
Positioning System) position data and wireless transmission of traffic
conditions and use that information to drive the car.
The auto manufacturers must publish an industry-standard interface
that spells out in detail what methods can be invoked to make the car
move (any car, from any manufacturer). The guidance manufacturers can
then write software that invokes the methods described in the
interface to command the car. Neither industrial group needs to know
how the other group's software is implemented. In fact, each group
considers its software highly proprietary and reserves the right to
modify it at any time, as long as it continues to adhere to the
published interface.
[...] An interface is a reference type, similar to a class, that can
contain only constants, method signatures, default methods, static
methods, and nested types. Method bodies exist only for default
methods and static methods. Interfaces cannot be instantiated—they
can only be implemented by classes or extended by other interfaces.
The most popular usage of interfaces is as APIs (Application Programming Interface) which are common in commercial software products. Typically, a company sells a software package that contains complex methods that another company wants to use in its own software product.
An example could be a package of digital image processing methods that are sold to companies making end-user graphics programs.
The image processing company writes its classes to implement an interface, which it makes public to its customers. The graphics company then invokes the image processing methods using the signatures and return types defined in the interface. While the image processing company's API is made public (to its customers), its implementation of the API is kept as a closely guarded secret—in fact, it may revise the implementation at a later date as long as it continues to implement the original interface that its customers have relied on.
Check out to learn more about interfaces.
In addition to what others have mentioned and by illogical comparison
it's a frame work for wrapping methods so they can be stored in
variables.
Thus on the fly you can equate the interface variable to be equal to any method or collection of methods atleast in this sense, a good reason you would usually want to do that is to escape repetitive logic that will definitely be an enemy of progress within the half life of your code at any decaying rate, be careful with the scenario below user discretion is advised.
SCENARIO
You have a game with a drawSillyThings() method in a SoulAvenger class, that has to draw some frames or sprites. Now drawSillyThings() has a list of other methods it needs to call in other to draw a metamorphed glorified-soul-ranger after user kills the grim-reaper in level 5k, i.e. drawSillyThings() needs to call either of inviteTheGrimReaper(), drawUpperCut(), drawTotalKO(), drawVictoryAndGlorifiedRanger(), drawDefeatAndMockery(), drawFightRecap() and drawGameOver() whenever the right situations arise during the gaming experience but all these would result in unwanted logic in drawSillyThings() which might slow the game i.e.
public static class SoulAvenger{
public SoulAvenger(){
//constructor logic
}
private void loadLevel5k(){...}
private void dontAllowUserWinOnTime(){...}
private void loadGrimReaperFight(){...}
private void drawSillyThings(){
... //unaccounted game logic
while(fighting_in_level_5k){
while(soul_ranger_has_enough_lives){
if(game_state=fight)inviteTheGrimReaper();
else if(game_state=medium_blows)drawUpperCut();
else if(game_state=heavy_blows)drawTotalKO();
else if(game_state=lost)drawDefeatAndMockery();
else if(game_state=won)drawVictoryAndGlorifiedRanger();
else if(game_state=end)drawFightRecap();
}else drawGameOver();
}
}
}
The problem here is the loop-nested boolean checks that have to be performed each time while the soul-ranger is still alive where as you could just have an alternative class which makes sure drawSillyThings() doesn’t need a game_state to be checked each time in order to call the right method but to do that you ‘ld need to kinda store the right method in a variable so that subsequently you can kinda variable = new method and also kinda variable.invoke(). If that wasn’t something have a look
public static class InterfaceTest{
public interface Method{
public void invoke();
}
public static void main(String[] args){
//lets create and store a method in a variable shall we
Method method_variable=new Method(){
#Override
public void invoke(){
//do something
}
};
//lets call or invoke the method from the variable in order to do something
method_variable.invoke();
//lets change the method to do something else
method_variable=new Method(){
#Override
public void invoke(){
//do something else
}
};
//lets do something else
method_variable.invoke();
}
}
This was probably what the guys at oracle had discovered was missing from Java several years before rumors of some developers planning a massive protest surfaced on the web but back to the SoulAvenger, as the gameplay occurs you would definitely just want to kinda have a variable be equated to give the right method to be invoked in drawSillyThings() in order to run things in a silly manner therefore
public static class SoulAvenger{
private interface SillyRunner{
public void run_things();
}
...//soul avenging variables
private SillyRunner silly_runner;
public SoulAvenger(int game_state){
//logic check is performed once instead of multiple times in a nested loop
if(game_state=medium_blows){
silly_runner=new SillyRunner(){
#Override
public void run_things(){
drawUpperCut();
}
};
}else if(game_state=heavy_blows){
silly_runner=new SillyRunner(){
#Override
public void run_things(){
drawTotalKO();
}
};
}else if(game_state=lost){
silly_runner=new SillyRunner(){
#Override
public void run_things(){
drawDefeatAndMockery();
}
};
}else if(game_state=won){
silly_runner=new SillyRunner(){
#Override
public void run_things(){
drawVictoryAndGlorifiedRanger();
}
};
}else if(game_state=fight){
silly_runner=new SillyRunner(){
#Override
public void run_things(){
drawFightRecap();
}
};
}
}
private void loadLevel5k(){
//an event triggered method to change how you run things to load level 5k
silly_runner=new SillyRunner(){
#Override
public void run_things(){
//level 5k logic
}
};
}
private void dontAllowUserWinOnTime(){
//an event triggered method to help user get annoyed and addicted to the game
silly_runner=new SillyRunner(){
#Override
public void run_things(){
drawDefeatAndMockery();
}
};
}
private void loadGrimReaperFight(){
//an event triggered method to send an invitation to the nearest grim-reaper
silly_runner=new SillyRunner(){
#Override
public void run_things(){
inviteTheGrimReaper();
}
};
}
private void drawSillyThings(){
...//unaccounted game logic
while(fighting_in_level_5k){
while(soul_ranger_has_enough_lives){
silly_runner.run_things();
}
}
}
}
Now the drawSillyThings() doesn’t need to perform any if logic while drawing because as the right events gets triggered the silly_runner gets equated to have its run_things() method invoke a different method thus using a variable to store and invoke a method kinda-ish although in the real gaming world(I actually mean in a console) several threads will work asynchronously to change interface variables to run different piece of code with the same call.
An interface in java is a special type of Abstract class, the Interface provided the 100% Abstraction but since the java introduce new features in java 8 the meaning of whole Interface is change. Interfaces are used to tell what should be done. But due to new features now we give implementations of methods in Interface, that changed the meaning of Interface.
In Interface the method is public abstract by default
interface Bird{
void sound();
void eat();
}
Java doesn't provide the multiple inheritances feature mean a class doesn't have two parents, but we extend multiple Interfaces in java.
An interface is a contract between the system and the external environment. More specifically to Java - a contract for a class (for a specific behavior), implemented in a form that resembles a pure abstract class.
There is an interface Accountable which has 2 methods. There are 9 classes which implement the Accountable interface.
public interface Accountable{
boolean isAccountable();
float getWorth();
}
We have got a new requirement as follows:
Two more methods declarations to be added to the interface. But we need to minimize the effect on the existing classes.
I was told that we can use Adaptors to resolve the issue. But I am not sure how to do it.
Could anyone please help me solve the issue?
Using java 8 you can declare default implementation just in interface:
public interface Accountable{
boolean isAccountable();
float getWorth();
default int someMethod() {return 0;}
}
If you use old java the only way is to add an abstract class as a middlware, but since java don't support multiple inheritance it could be painful.
Avoid adding a method to the interface by instead creating a new interface which inherits from that first interface.Now your new class will implement new interface.So there is minimal change.
I guess the goal is to learn about Adapters. In order to use an Adapter you firstly need to create one:
public class AccountableAdapter implements Accountable{
#Override
boolean isAccountable(){ return false; }
#Override
float getWorth(){ return (float)0.0 }
}
Your classes then extend that Adapter. You see, they automatically will implement all methods of the interface inheriting the default-implementations from the Adapter.
If later the interface is added a method, you will have to add an implementation in the Adapter, only. All extending classes won't break.
Of course until here you only have Default-Implementations. Now you will override all methods that need to have a special implementation in your concrete classes.
Personally I find this is a rather bad example to learn about Adapters. A better and "real-life" example would be event handlers. For example MouseInputAdapter. It supplies you with a variety of possible callbacks from mouse-events. By using an Adapter, you can resort to implement only the Listener you really need and don't have to implement the whole interface.
I love this, most people do not know the power of interfaces and its purpose, interfaces is the best thing for the development already invented solution for your problem used design patterns
Your Interface transformed
public interface Accountable <E> {
//method commun all class
public boolean isAccountable();
public float getWorth();
//method commun all class
public int someMethod();
//method commun all class
public E getSameCommun();
}
That a generic implementation
public abstract class Generic<T extends Serializable> implements<T>{
private boolean accountable;
#Override
public boolean isAccountable(){
return
}
#Override
public int someMethod(){
System.out.println("do samethink");
}
#Override
public E getSameCommun(){
System.out.println("do samethink");
}
}
use in your class
public class Class1 extends Generic<Class1> implements Accountable<Class1>{
//that moment you bring 3 method of the Generic
// you need implement specific method of class
#Override
public float getWorth(){
//so something
}
}
//other class
public class Class2 extends Generic<Class2> implements Accountable<Class2>{
//that moment you bring 3 method of the Generic
// you need implement specific method of class
#Override
public float getWorth(){
//so something
}
}
//other class
public class Class3 extends Generic<Class3> implements Accountable<Class3>{
//that moment you bring 3 method of the Generic
// you need implement specific method of class
#Override
public float getWorth(){
//so something
}
//that case you need overred same method commun
#Override
public E getSameCommun(){
System.out.println("do other samethink");
}
}
//other class, you need additional functionality for method
public class Class3 extends Generic<Class3> implements Accountable<Class3>{
//that moment you bring 3 method of the Generic
// you need implement specific method of class
#Override
public float getWorth(){
//so something
}
//that case you need overred same method commun
#Override
public E getSameCommun(){
super.getSameCommun();
System.out.println("additional functionality");
return e;
}
}
that same objective of the "Design Patterns"
I am trying to pass a Class to a method. The Class changes as the program runs, so I'd like to reuse the same method through out my program instead of calling the same functions throughout my resetWords() method.
Here is where I am stuck:
private void getWords(Class c) {
singles = c.getSingleSyllables();
doubles = c.getDoubleSyllables();
triples = c.getTripleSyllables();
quadruples = c.getQuadrupleSyllables();
quintuples = c.getQuintupleSyllables();
}
private void resetWords() {
if (generated.equals("SOMETHING")) {
Something c = new Something();
getWords(c);
}
else if (generated.equals("ANOTHER")) {
Another c = new Another();
getWords(c);
}
}
I think what you are looking for is an interface. You should declare an interface like this:
public interface Passable
{
public List<String> getSingleSyllables();
public List<String> getDoubleSyllables();
// ...
}
Then, let Something and Another implement them:
public class Something implements Passable
{
// method declarations
}
Now, change your method to this:
private void getWords (Passable c) {
singles = c.getSingleSyllables();
doubles = c.getDoubleSyllables();
triples = c.getTripleSyllables();
quadruples = c.getQuadrupleSyllables();
quintuples = c.getQuintupleSyllables();
}
A little vague what you're asking but perhaps create an Interface that defines all of the getXSyllables() methods. Have your classes (Something and Another) implement that Interface. Finally, define getWords as private void getWords(YourInterface c).
You're confusing classes, and objects.
What you're passing to getWords() is an object. In the first case, it's an object of type Something. In the second case, it's an object of type Another.
The only way for such code to work is to define a common base class or interface for Something and Another (let's call it HavingSyllabes), containing the 5 methods used in getWords(): getSingleSyllables(), getDoubleSyllabes(), etc. And the signature of getWords() should be
private void getWords(HavingSyllabes c)
If the classes always implement getSingleSyllables(), getDoubleSyllables(), etc.. then you should consider inheriting from an abstract class, or implementing an interface.
Then...
private void getWords(YourInterface / YourAbstractClass foo) {
...
}
Your question does not provide enough detail to answer clearly.
Depending upon your design / end-goals, there are three concepts you should take a look at and understand:
Interfaces
Abstract Classes
Reflection
An Interface will define the methods that classes that implement the interface must provide. Each class that implements the interface must provide the code for the method.
An Abstract Class will provide a single implementation of the behavior that you are looking for.
Reflection is an advanced concept. I would recommend you stay away from it at this time - but you should be aware of it.
Given your example code, you may want to use an Abstract Class. Designed properly, you can increase flexibility/reuse by defining an interface, implementing that interface with an Abstract Class and then extending that Abstract Class as needed. Every class that extends the Abstract will pick up the default implementation you provided in the Abstract class definition; the Interface will make it easy for you to extend in the future.
Is it correct to extend an empty interface? I just need to have a method (EventPlayer) with a parameter (EventCLass myEvent) that could be one time a class and the next time another class.
public interface EventClass {
// ... empty ...
}
public interface EventClassExt1 extends EventClass {
public void firstEvent();
public void secondEvent();
}
public interface EventClassExt2 extends EventClass {
public void thirdEvent(String text);
}
public EventPlayer(final EventCLass myEvent)
yes it is correct. it is called Marker Interface.
http://en.wikipedia.org/wiki/Marker_interface_pattern
Yes it's OK to do that.
When an interface has no methods, it's generally called a marker interface; Serializable is one of many examples of such an interface from the JDK.
Also, you probably don't want "class" in your interface name. Just Event is a better choice.
Is it correct to extend a Class that has not other object in it?
I assume by this you mean an empty interface.
This is something that was used in Java a lot before they had annotations to sign a class is of that type ( from Java 5 ).
What you are doing is correct - basically you are marking the extended interfaces/classes type of EventClass but I would use annotation which is the new way to do that
http://tutorials.jenkov.com/java-reflection/annotations.html
I know that an interface must be public. However, I don't want that.
I want my implemented methods to only be accessible from their own package, so I want my implemented methods to be protected.
The problem is I can't make the interface or the implemented methods protected.
What is a work around? Is there a design pattern that pertains to this problem?
From the Java guide, an abstract class wouldn't do the job either.
read this.
"The public access specifier indicates that the interface can be used by any class in any package. If you do not specify that the interface is public, your interface will be accessible only to classes defined in the same package as the interface."
Is that what you want?
You class can use package protection and still implement an interface:
class Foo implements Runnable
{
public void run()
{
}
}
If you want some methods to be protected / package and others not, it sounds like your classes have more than one responsibility, and should be split into multiple.
Edit after reading comments to this and other responses:
If your are somehow thinking that the visibility of a method affects the ability to invoke that method, think again. Without going to extremes, you cannot prevent someone from using reflection to identify your class' methods and invoke them. However, this is a non-issue: unless someone is trying to crack your code, they're not going to invoke random methods.
Instead, think of private / protected methods as defining a contract for subclasses, and use interfaces to define the contract with the outside world.
Oh, and to the person who decided my example should use K&R bracing: if it's specified in the Terms of Service, sure. Otherwise, can't you find anything better to do with your time?
When I have butted up against this I use a package accessible inner or nested class to implement the interface, pushing the implemented method out of the public class.
Usually it's because I have a class with a specific public API which must implement something else to get it's job done (quite often because the something else was a callback disguised as an interface <grin>) - this happens a lot with things like Comparable. I don't want the public API polluted with the (forced public) interface implementation.
Hope this helps.
Also, if you truly want the methods accessed only by the package, you don't want the protected scope specifier, you want the default (omitted) scope specifier. Using protected will, of course, allow subclasses to see the methods.
BTW, I think that the reason interface methods are inferred to be public is because it is very much the exception to have an interface which is only implemented by classes in the same package; they are very much most often invoked by something in another package, which means they need to be public.
This question is based on a wrong statement:
I know that an interface must be public
Not really, you can have interfaces with default access modifier.
The problem is I can't make the interface or the implemented methods protected
Here it is:
C:\oreyes\cosas\java\interfaces>type a\*.java
a\Inter.java
package a;
interface Inter {
public void face();
}
a\Face.java
package a;
class Face implements Inter {
public void face() {
System.out.println( "face" );
}
}
C:\oreyes\cosas\java\interfaces>type b\*.java
b\Test.java
package b;
import a.Inter;
import a.Face;
public class Test {
public static void main( String [] args ) {
Inter inter = new Face();
inter.face();
}
}
C:\oreyes\cosas\java\interfaces>javac -d . a\*.java b\Test.java
b\Test.java:2: a.Inter is not public in a; cannot be accessed from outside package
import a.Inter;
^
b\Test.java:3: a.Face is not public in a; cannot be accessed from outside package
import a.Face;
^
b\Test.java:7: cannot find symbol
symbol : class Inter
location: class b.Test
Inter inter = new Face();
^
b\Test.java:7: cannot find symbol
symbol : class Face
location: class b.Test
Inter inter = new Face();
^
4 errors
C:\oreyes\cosas\java\interfaces>
Hence, achieving what you wanted, prevent interface and class usage outside of the package.
Here's how it could be done using abstract classes.
The only inconvenient is that it makes you "subclass".
As per the java guide, you should follow that advice "most" of the times, but I think in this situation it will be ok.
public abstract class Ab {
protected abstract void method();
abstract void otherMethod();
public static void main( String [] args ) {
Ab a = new AbImpl();
a.method();
a.otherMethod();
}
}
class AbImpl extends Ab {
protected void method(){
System.out.println( "method invoked from: " + this.getClass().getName() );
}
void otherMethod(){
System.out.println("This time \"default\" access from: " + this.getClass().getName() );
}
}
Here's another solution, inspired by the C++ Pimpl idiom.
If you want to implement an interface, but don't want that implementation to be public, you can create a composed object of an anonymous inner class that implements the interface.
Here's an example. Let's say you have this interface:
public interface Iface {
public void doSomething();
}
You create an object of the Iface type, and put your implementation in there:
public class IfaceUser {
private int someValue;
// Here's our implementor
private Iface impl = new Iface() {
public void doSomething() {
someValue++;
}
};
}
Whenever you need to invoke doSomething(), you invoke it on your composed impl object.
I just came across this trying to build a protected method with the intention of it only being used in a test case. I wanted to delete test data that I had stuffed into a DB table. In any case I was inspired by #Karl Giesing's post. Unfortunately it did not work. I did figure a way to make it work using a protected inner class.
The interface:
package foo;
interface SomeProtectedFoo {
int doSomeFoo();
}
Then the inner class defined as protected in public class:
package foo;
public class MyFoo implements SomePublicFoo {
// public stuff
protected class ProtectedFoo implements SomeProtectedFoo {
public int doSomeFoo() { ... }
}
protected ProtectedFoo pFoo;
protected ProtectedFoo gimmeFoo() {
return new ProtectedFoo();
}
}
You can then access the protected method only from other classes in the same package, as my test code was as show:
package foo;
public class FooTest {
MyFoo myFoo = new MyFoo();
void doProtectedFoo() {
myFoo.pFoo = myFoo.gimmeFoo();
myFoo.pFoo.doSomeFoo();
}
}
A little late for the original poster, but hey, I just found it. :D
You can go with encapsulation instead of inheritance.
That is, create your class (which won't inherit anything) and in it, have an instance of the object you want to extend.
Then you can expose only what you want.
The obvious disadvantage of this is that you must explicitly pass-through methods for everything you want exposed. And it won't be a subclass...
I would just create an abstract class. There is no harm in it.
With an interface you want to define methods that can be exposed by a variety of implementing classes.
Having an interface with protected methods just wouldn't serve that purpose.
I am guessing your problem can be solved by redesigning your class hierarchy.
One way to get around this is (depending on the situation) to just make an anonymous inner class that implements the interface that has protected or private scope. For example:
public class Foo {
interface Callback {
void hiddenMethod();
}
public Foo(Callback callback) {
}
}
Then in the user of Foo:
public class Bar {
private Foo.Callback callback = new Foo.Callback() {
#Override public void hiddenMethod() { ... }
};
private Foo foo = new Foo(callback);
}
This saves you from having the following:
public class Bar implements Foo.Callback {
private Foo foo = new Foo(this);
// uh-oh! the method is public!
#Override public void hiddenMethod() { ... }
}
I think u can use it now with Java 9 release. From the openJdk notes for Java 9,
Support for private methods in interfaces was briefly in consideration
for inclusion in Java SE 8 as part of the effort to add support for
Lambda Expressions, but was withdrawn to enable better focus on higher
priority tasks for Java SE 8. It is now proposed that support for
private interface methods be undertaken thereby enabling non abstract
methods of an interface to share code between them.
refer https://bugs.openjdk.java.net/browse/JDK-8071453