I have unix timestammp stored in mysql. I am converting it into time. It displays wrong time.
Here is code:
Date date = new Date((long)timestamp*1000);
SimpleDateFormat sdf = new SimpleDateFormat("h:mm a");
sdf.setTimeZone(TimeZone.getTimeZone("GMT+5:30"));
timeString = sdf.format(date);
System.out.println(timeString);`
timestamp is variable which contains unix timestamp.
Ex: for timestamp=1417437428505 it should show 6:07 PM and showing 12:31 AM
What is solution for it?
You're multiplying a timestamp which is already in milliseconds since the Unix epoch by 1000. You just want:
Date date = new Date(timestamp);
If you look at all of the date, not just the time, you'll see it's currently in 46886!
Are You sure that need multiplied by 1000? I tried pass without multiplying Date date = new Date(timestamp); and it printed 6:07 PM
Remove multiply with 1000 in
Date date = new Date((long)timestamp*1000);
than it works.
Related
I'm trying to convert milliseconds to Timestamp with timezone UTC but it doesn't work as is expected because it convert to my localdatetime.
I have tried following. While debugging the code I have found that when execute this: new DateTime(eventDate) it is working properly because it's value is 10:34:18.721 but later new Timestamp() change it to localdatetime.
long eventDate = 1566297258721L;
DateTimeZone.setDefault(DateTimeZone.UTC);
Timestamp timestamp = new Timestamp(new DateTime(eventDate).getMillis());
I expect to output as:2019-08-20 10:34:18.721 but actual output is: 2019-08-20 12:34:18.721
You can use java.time package of Java 8 and later:
ZonedDateTime zonedDateTime = Instant.ofEpochMilli(1566817891743L).atZone(ZoneOffset.UTC);
I don't understand why you are creating a new DateTime and then get the milliseconds from there, if you already have the milliseconds in the beginning.
Maybe I'm misunderstanding your problem. The milliseconds have nothing to do with the timezone. The timezone is used to compare the same moment in 2 different places and get the respective date. Here are my solutions
If you want a timestamp from milliseconds:
long eventDate = 1566297258721L;
Timestamp time=new Timestamp(eventDate);
System.out.println(time);
The result would be 2019-08-20 10:34:18.721 , also the wished SQL format
If you want to convert a moment from a Timezone to another:
You will get the moment in your actual timezone and transform it in a different one in order to see e.g. what time it was in an other country
long eventDate = 1566297258721L;
Calendar calendar = Calendar.getInstance();
calendar.setTime(eventDate);
SimpleDateFormat dateFormat = new SimpleDateFormat("yyyy-MM-dd hh:mm:ss");
dateFormat.setTimeZone(TimeZone.getTimeZone("UTC"));
dateFormat.format(calendar.getTime());
I hope those snippets could be useful. Happy Programming!
You can try the following,
long eventDate = 1566297258721L;
SimpleDateFormat simpleDateFormat = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss z", Locale.US);
simpleDateFormat.setTimeZone(TimeZone.getTimeZone("UTC"));
String stringDate = simpleDateFormat.format(new Date(eventDate));
System.out.println(stringDate);
It gives me the following output.
2019-08-20 10:34:18 UTC
I'm trying to update the last modified date of a specific folder, here's what I've got:
public void touchFolder(){
File folderToTest = new File("C:\\Temp");
SimpleDateFormat dateFormatUtc = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
dateFormatUtc.setTimeZone(TimeZone.getTimeZone("UTC"));
String newTime = dateFormatUtc.format(new Date());
folderToTest.setLastModified(Long.parseLong(newTime));
}
I am just putting this code in a test case so don't worry about calling this method etc.
I'm getting errors with the parsing that date format as a long, what's the format used in setting the last modified date & time?
This is an example from the documentation, using java.nio.file.Files:
Path path = ...
FileTime now = FileTime.fromMillis(System.currentTimeMillis());
Files.setLastModifiedTime(path, now);
I think you should just do folderToTest.setLastModified(System.currentTimeMillis());
In your code newTime is a formatted date 2018-12-19 15:21:31 which can't be parsed to Long. What you want to do is supply the time in milliseconds e.g.:
Date d = new Date();
file.setLastModified(d.getTime());
As per File.setLastModified() method javadoc:
time - The new last-modified time, measured in milliseconds since the epoch (00:00:00 GMT, January 1, 1970)
I'm trying to convert a time stamp into date using this code:
String str = "14799744000000800";//last four digit is time zone
DateFormat timeZoneFormat = new SimpleDateFormat("dd-MM-yyyy HH:mm:ss");
timeZoneFormat.setTimeZone(TimeZone.getTimeZone("GMT-8"));
Date time = new java.util.Date(Long.parseLong(str));
System.out.println(timeZoneFormat.format(time));
But it prints '21-03-470955 00:00:00' instead of 21-03-2016 00:00:00.
As you can see year part is not converted properly.how to fix this?
The current milliseconds value is 1481007881541, so 14799744000000800 does seem to be really in the future.
Edit
As per your later comments, you could just remove last four digit from string.
This question already has answers here:
Java: Date from unix timestamp
(11 answers)
Closed 6 years ago.
I am trying to get dd.MM.yyyy and hh:mm from 1436536800 but only the time is correct, the date is completely wrong. I don't really understand how this is supposed to work
int dt = time.getInt("start")*1000;
Date date = new Date(dt);
startDate = dateFormat.format(date);
If time.getInt("start") is a valid unix timestamp, you must add "000" to the number. Example: 1436536800 * 1000 = 1436536800000. Then you can use the timestamp to get a Date:
final Date date = new Date(Long.parseLong("1436536800000"));
SimpleDateFormat sdf = new SimpleDateFormat("dd.MM.yyyy hh:mm");
System.out.println(sdf.format(date));
Console exit: 10.07.2015 09:00
Assuming the time is correct, it's likely the fact that you're multiplying by 1,000. When creating the date the way you are, it takes in milliseconds. Is it possible that your input is already in milliseconds? (Your current method will be ~2 minutes off if so)
Date date=new Date(1436536800);
SimpleDateFormat df2 = new SimpleDateFormat("dd.MM.yyyy");
String dateText = df2.format(date);
Date you are getting is a JSON string value. follow steps below to format it correctly.
First download Moment.js file and add it in your project.
var date1 = "1436536800"; // your long value contain in this variable.
var date2 = moment(date1).format(MMMM Do YYYY);//It will give you formatted date value.
see more formats below
I create a Android app and I want to show the current date on screen. I use this code:
Date date = new Date(0);
java.text.DateFormat dateFormat = android.text.format.DateFormat.getDateFormat(getApplicationContext());
text.setText("Time: " + dateFormat.format(date));`
But this code shown me date "1.1.1970".
How can I show the current date?
Date(0) is the first January 1970, see the documentation of the Date(long milliseconds) constructor:
public Date(long milliseconds)
Initializes this Date instance using the specified millisecond value. The value is the number of milliseconds since Jan. 1, 1970 GMT.
To get the current date, use Date(), the constructor without a parameter:
public Date()
Initializes this Date instance to the current time.
use
text.setText(new SimpleDateFormat("yyyy-MM-dd").format( Calendar.getInstance().getTime());
SimpleDateFormat dfDate = new SimpleDateFormat("yyyy-MM-dd");
Calendar c = Calendar.getInstance();
String date = dfDate.format(c.getTime());
System.out.println("Date is "+date);
Result will be ========> 2012-08-07
Just remove the 0, so replace this: Date date = new Date(0); by this: Date date = new Date();
As per Android Documentation:
Initializes this Date instance using the specified millisecond value.
The value is the number of milliseconds since Jan. 1, 1970 GMT.
Since you passed on a value of 0, it was taking the above date and adding 0 milliseconds to it, hence the reason why you got the 1.1.1970 date.
To show the current Date on the Screen do this..
String s = new SimpleDateFormat("dd-MM-YYYY").format(new Date());
Now display the String s on the screen.
new Date() is enough otherwise you get the date 0 seconds after the 01.01.1970 00:00:00 if you call new Date(0)
Don't use new Date(0). The parameter is time since the epoch, which is 1.1.1970. Just use new Date().
Make sure you import "java.util.Date;" and not "java.sql.Date;" or else you wont be able to pass through no parameter.