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what happens to a message when it gets to a server without reading stream in java?

If I have a server and a client and I opened a socket between the two:
1.Is it possible that the client will have a printWriter stream, in order to write things to the socket, but the server won't have in the mean time a bufferReader?
If the answer of 1 is yes, if that client will send a message to the server (who currently doesn't have a reading stream), what will happend to this message until te server will create a reading stream and read the message?
thank you

This is not at all specific to Java, but TCP/IP. There are buffers to keep the data received, so it's not possible that some data would be lost because one end isn't "ready" yet. This is because TCP will retransmit data that hasn't been acknowledged as received, guaranteeing that all the bytes that are written are received on the other (barring obvious cases).

in addition to #Kayaman's answer:
consider this Compile-able simple Java implemented example:
Server Side:
import java.io.*;
import java.net.*;
public class SimpleServer implements Runnable{
int serverPort = 45000;
ServerSocket serverSocket = null;
boolean isStopped = false;
public SimpleServer(int port){
this.serverPort = port;
}
public void run(){
try {
serverSocket = new ServerSocket(serverPort);
} catch (IOException e) {
System.err.println("Cannot listen on this port.\n" + e.getMessage());
System.exit(1);
}
while(!isStopped){
try {
Socket clientSocket = serverSocket.accept();
} catch (IOException e) {
// do nothing
}
}
}
public static void main(String[] args) throws IOException {
SimpleServer server = new SimpleServer(45000);
new Thread(server).start();
System.out.println("Server is waiting to connect");
}
}
Client Side:
import java.io.*;
import java.net.*;
public class SimpleClient {
public static void main(String[] args) throws IOException {
Socket socket = null;
PrintWriter out = null;
try {
socket = new Socket("127.0.0.1", 45000);
out = new PrintWriter(socket.getOutputStream(), true);
System.out.println("output stream created");
out.write(9);
System.out.println("message was sent to output with no listener");
} catch (UnknownHostException e) {
// do nothing
} catch (IOException e) {
// do nothing
}
}
}
the example is an implementation of a very basic client server connection in which a socket is created and a stream is defined only on the client side, followed by a write to the stream that will eventually be read by the server (if at all).
therefore, to answer you questions:
1) yes, it's possible to open a one-way connection stream without a "listener"
2) edit: according to #EJP: It will be saved within the socket's buffer until it is read or the socket is closed.

How to return files from a Server through OutputStream?

I have the following server called Server.class and what exactly does, it receives text from the client and then sends that exact text back to the client. I'm just learning and I used the server from this website http://www.javaworld.com/article/2077322/core-java/core-java-sockets-programming-in-java-a-tutorial.html.
The Client in my case is the browser so i don't need to implement it.
What I want to get is when a client asks for a file like: localhost:8888/myfile.txt
I should give him back that file, so he can download it or see it from the browser.
I tried to use a BufferedReader
BufferedReader br = new BufferedReader(new InputStreamReader(is));
is is a variable from InputStream
So now i can know what the client introduced doing String clientData = br.readLine()
But how can I get the file (myfile.txt) from that string and return that file so it can be observed or downloaded in the browser??
The Server:
import java.io.*;
import java.net.*;
public class Server {
public static void main(String args[]) {
// declaration section:
// declare a server socket and a client socket for the server
// declare an input and an output stream
ServerSocket echoServer = null;
String line;
DataInputStream is;
PrintStream os;
Socket clientSocket = null;
// Try to open a server socket on port 8888
// Note that we can't choose a port less than 1023 if we are not
// privileged users (root)
try {
echoServer = new ServerSocket(8888);
}
catch (IOException e) {
System.out.println(e);
}
// Create a socket object from the ServerSocket to listen and accept
// connections.
// Open input and output streams
try {
clientSocket = echoServer.accept();
is = new DataInputStream(clientSocket.getInputStream());
os = new PrintStream(clientSocket.getOutputStream());
// As long as we receive data, echo that data back to the client.
while (true) {
line = is.readLine();
os.println(line);
}
}
catch (IOException e) {
System.out.println(e);
}
}
}

Receive an object over TCP/IP

I am going to write a program over TCP/IP and I should send objects by client or by server, It is going right when I want to send or receive strings but when I am trying to read an object:
private Socket client;
public ThreadedClient(Socket client) {
this.client = client;
}
#Override
public void run() {
try {
ObjectInputStream objIn = new ObjectInputStream(client.getInputStream());
while(true){
try {
Object fromClient = objIn.readObject();
} catch (ClassNotFoundException e) {e.printStackTrace();}
}
} catch (IOException e) {e.printStackTrace();}
}
I receive an exception:
java.io.StreamCorruptedException: invalid stream header: 306E6165
at java.io.ObjectInputStream.readStreamHeader(Unknown Source)
at java.io.ObjectInputStream.<init>(Unknown Source)
at org.bihe.serverSocket.ThreadedClient.run(Server.java:137)
at java.lang.Thread.run(Unknown Source)
and it refers to this line:
ObjectInputStream objIn = new ObjectInputStream(client.getInputStream());
It is my server code:
ServerSocket ss = new ServerSocket(8800);
while(true){
Socket newClient = ss.accept();
System.out.println(">>>> Client number " + (++counter) + " connected.");
OutputStream outputStream = newClient.getOutputStream();
PrintWriter sender = new PrintWriter(outputStream);
sender.println(true);
sender.flush();
ThreadedClient client = new ThreadedClient(newClient);
clients.add(client);
new Thread(client).start();
Client side code:
sc = new Socket("127.0.0.1", 8800);
InputStream inputStream = sc.getInputStream();
Scanner scanner = new Scanner(inputStream);
boolean s = scanner.nextBoolean();
if(s){
System.out.println("Client connected successfully.");
return true;
}else{
System.out.println("Ohhh, Some problem happened, try again later!");
}
Can anyone explain me what is happening, what is this exception and why I received this exception?

If you want to send object over network you must serialize your objects.
Check this question:
How To send an object over TCP in Java
Java Serialization:
Serialization
You could do it like this:
import java.net.*;
import java.io.*;
class testobject implements Serializable {
int value;
String id;
public testobject(int v, String s ){
this.value=v;
this.id=s;
}
}
public class SimpleServer {
public static void main(String args[]) {
int port = 2002;
try {
ServerSocket ss = new ServerSocket(port);
Socket s = ss.accept();
InputStream is = s.getInputStream();
ObjectInputStream ois = new ObjectInputStream(is);
testobject to = (testobject)ois.readObject();
if (to!=null){System.out.println(to.id);}
System.out.println((String)ois.readObject());
is.close();
s.close();
ss.close();
}catch(Exception e){System.out.println(e);}
}
}
import java.net.*;
import java.io.*;
public class SimpleClient {
public static void main(String args[]){
try{
Socket s = new Socket("localhost",2002);
OutputStream os = s.getOutputStream();
ObjectOutputStream oos = new ObjectOutputStream(os);
testobject to = new testobject(1,"object from client");
oos.writeObject(to);
oos.writeObject(new String("another object from the client"));
oos.close();
os.close();
s.close();
}catch(Exception e){System.out.println(e);}
}
}

Just get rid of sending and receiving the Boolean. It's redundant. If there was some problem creating the connection, the socket wouldn't get created: an exception would be thrown instead. You're confusing everything with multiple streams on the same socket. Don't do that.
In your read-object loop, you need to catch EOFException separately, and when you get it, close the socket and exit the loop. If you get any other IOException, log it, close the socket, and exit the loop.

If you'd like to achieve good performance and send object then you definitely should use Google Protobuf
It allows you to define messages in simple .proto files. Then you use bundled compiler to generate Java classes which will be serialized and sent.
Also better idea is to use Netty over plain Java sockets. This prevent you from writing a lot of boilerplate code and define simple serialization/deserialization pipelines. Take a look at user-guide.

TCP socket connection

I'm new to the network communication and I'm trying to build client-server application.
protected void init(){
Server myServer = new Server();
Client myClient = new Client();
}
That's my Client class:
public class Client {
public Client() {
init();
}
private void init() {
Socket echoSocket = null;
DataOutputStream os = null;
DataInputStream is = null;
DataInputStream stdIn = new DataInputStream(System.in);
try {
echoSocket = new Socket("localhost", 1234);
os = new DataOutputStream(echoSocket.getOutputStream());
is = new DataInputStream(echoSocket.getInputStream());
os.writeInt(stdIn.readInt());
echoSocket.getOutputStream().close();
echoSocket.getInputStream().close();
echoSocket.close();
} catch (IOException e) {
e.printStackTrace();
}
}
}
And that's server:
public class Server {
public Server() {
init();
}
private void init() {
try {
boolean run = true;
ServerSocket ss = new ServerSocket(1234);
Socket s = ss.accept();
DataInputStream dis = new DataInputStream(s.getInputStream());
System.out.println(dis.readInt());
s.getInputStream().close();
s.getOutputStream().close();
s.close();
} catch (IOException e) {
e.printStackTrace();
}
}
}
First of all:
Can I initialize client and server simply like i did? new Server() and new Client()?
Question 2:
Is it important what i initialize at first? client or server?
Question 3:
When i compile this code with client first initialized, i become Connection refused: connect. I know it means that there is no listening socket running on the port you are trying to connect to. That's why server must go first, i think. Is it so? can i fix it using setSoTimeout and how?
Question 4:
When i compile it with server and then client, output is nothing. And i think it has nothing to do with client, because if i try to print "1", for example, it doesn't work either. I think it just waits for the client and does nothing that goes after. How can i fix this? maybe setSoTimeout goes here too?

You can't have both client and server in the same thread.
As you already have observed, the server accepts the connection and tries to read something. It doesn't know that the client is running in the very same thread.
Either make a multi-threaded application, where client and server have their own thread. Or make two prgrams that run independently of each other. The latter would be also the "normal case".

Make two different projects, first run server than client.
Server will write on console "Server started" than run client it will ask your name, type your name press ok . Your name will be sent to server and server will reply saying hello to you.
Here is server code
import java.net.*;
import java.io.*;
import javax.swing.*;
public class Server {
public static void main(String[] args) {
try{
ServerSocket ss= new ServerSocket(2224);
System.out.println("Serever started");
while(true)
{
Socket s=ss.accept();
InputStream is=s.getInputStream();
InputStreamReader isr=new InputStreamReader(is);
BufferedReader br=new BufferedReader(isr);
OutputStream os=s.getOutputStream();
PrintWriter pw=new PrintWriter(os);
String name=br.readLine();
String message="Hello "+name+"from server";
pw.println(message);
pw.flush();
}
}
catch(Exception exp)
{
System.out.println("Excepttion occured");
}
}
}
Here is client code
import java.net.*;
import java.io.*;
import java.util.Scanner;
import javax.swing.*;
public class Client {
public static void main(String[] args) throws IOException {
Socket s=new Socket("localhost",2224);
InputStream is=s.getInputStream();
InputStreamReader isr=new InputStreamReader(is);
BufferedReader br=new BufferedReader(isr);
OutputStream os=s.getOutputStream();
PrintWriter pw=new PrintWriter(os,true);
String message = JOptionPane.showInputDialog("Give your name");
pw.println(message);
pw.flush();
String servermessage = br.readLine();
JOptionPane.showMessageDialog(null, servermessage);
s.close();
}
}

Not able to run multithreaded server program in Java

Here is the server code
package echoserver;
import java.net.*;
import java.io.*;
public class EchoServer {
public static void main(String[] args) {
try {
//establish server socket
ServerSocket s = new ServerSocket(1981);
//Thread client connectionsincoming
while (true) {
//wait for incoming connection
Socket incoming = s.accept();
Runnable r = new ThreadedEchoHandler(incoming);
Thread t = new Thread(r);
t.start();
}
} catch (IOException e) {
e.printStackTrace();
}
}
}
package echoserver;
import java.net.*;
import java.util.*;
import java.io.*;
class ThreadedEchoHandler implements Runnable {
public ThreadedEchoHandler(Socket i) {
//initializing socket
incoming = i;
}
public void run() {
try {
try {
//recieve input stream from socket
InputStream inStream = incoming.getInputStream();
//recieve output stream from socket
OutputStream outStream = incoming.getOutputStream();
//Create a scanner from input stream
Scanner scan = new Scanner(inStream);
//Create printer writer from output stream and enabled auto flushing
PrintWriter out = new PrintWriter(outStream, true);
//prompt users on how to exit program soon as a long in into the server
out.println("Enter BYE to exit");
boolean done = false;
//while done is not true and scanner has next line loop
while (!done && scan.hasNextLine()) {
//reading text that came in from the socket
String line = scan.nextLine();
//On the server print the ip address of where the text is coming from and the text they typed
System.out.println("Recieved from " + incoming.getInetAddress().getHostAddress() + ": " + line);
//Echo back the text the client typed to the client
out.println("Echo: " + line);
//if they type BYE in caps terminate there connection and I also trimmed whitespaces
if (line.trim().equals("BYE")) {
done = true;
}
}
} //finally close the socket connection
finally {
incoming.close();
}
} catch (IOException e) {
e.printStackTrace();
}
}
private Socket incoming;
}
and here is the code for client
package client;
import java.net.*;
import java.io.*;
public class Client {
public static void main(String[] args) throws IOException {
PrintWriter out = null;
try {
Socket s = new Socket(InetAddress.getLocalHost(), 1981);
System.out.println("Connected to server on port 1981");
out = new PrintWriter(s.getOutputStream());
out.println("Hello");
s.close();
} catch (Exception ex) {
System.err.println(ex.getMessage());
}
}
}
Socktes are getting created successfully but when control goes to t.start() method call it is not calling run() method of ThreadedEchoHandler class.
Why is this happening? any idea?

The client writes "Hello" to the PrintWriter. So far, so good.
You may expect that the PrintWriter sends this text directly to the socket, but it doesn't. The documentation from the PrintWriter(OutputStream) constructor says that it creates a PrintWriter without automatic line flushing. This means that you have to call out.flush() whenever you want something to be actually sent.
Until you call out.flush() the text only exists in some internal buffer, and the server will not be able to see it.

My guess would be that the acept statement is blocking forever because no client is connecting to the server. You could wrap accept() in prints to prove or disprove.