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Caused by: java.lang.IllegalStateException: Query argument creationDateTime not found in the list of parameters provided during query execution

I am trying to cover the case where the :creationDateTime is Null to get the same result as the following query "SELECT o FROM ExtraNetOrder o". I searched it on the internet and found the solution by adding IS NULL, but it
does not work in my case. Currently I am getting the following error:
Caused by: java.lang.IllegalStateException: Query argument
creationDateTime not found in the list of parameters provided during
query execution.
If the paramter :creationDateTime does not exist, then the query should be executed without the where parameter clause. In my table, I don't have creationDateTime with the NULL value.
In the final query I have 3 paramter which I am passing to the query. for the simplicity I added just one paramter (creationDateTime).
I am using EclipseLink in the projekt.
#NamedQueries({
#NamedQuery(name="order_by_filter_options", query="SELECT o FROM ExtraNetOrder o "
+ " WHERE :creationDateTime IS NULL OR :creationDateTime = '' OR o.creationDateTime >=:creationDateTime ")
})
-------------------
Query q = em.createNamedQuery("order_by_filter_options");
if (fromDate != null)
q.setParameter("creationDateTime", fromDate);
#SuppressWarnings("unchecked")
List<ExtraNetOrder> orders = q.getResultList();

You need to set :creationDateTime to null if the fromDate is null. Just remove the if and always call q.setParameter("creationDateTime", fromDate);

JPA EclipseLink - Get multiple objects by primary key maintaining order

I'm using EclipseLink as JPA implementation and I need to get multiple objects using the primary key (numeric id). But I also need to maintain the given id order.
Using native mySQL this kind of behaviour can be obtained using ORDER BY FIELD
SELECT id FROM table WHERE id IN(9,5,2,6) ORDER BY FIELD(id,9,5,2,6);
I'm now trying to replicate this query using JPA implementation. As already established from this thread, the ORDER BY FIELD is not supported, so I went to a more low-level approach using a JPA native query.
I'm try to reach this goal using a parameter query, instead of using a raw statement. The first implementation was like this
Class<?> clazz = ...;
List<Long> ids = ...;
EntityManagerFactory emf = ...;
EntityManager em = emf.createEntityManager();
String statement = "SELECT * FROM table WHERE id IN (?)";
Query createNativeQuery = em.createNativeQuery(statement, clazz);
createNativeQuery.setParameter(1, ids);
List resultList = createNativeQuery.getResultList();
As you can see the ORDER clause is not there yet, for the first step I just trying to make the parameter query work using the ids list with the IN operator. In the setParameter method I tried to provide the List object, a comma separated list (as string) but none of them works. At the end they all finish with a sql syntax error.
I also tried to play with the parenthesis, with or without, but nothing works.
Here some test I made
String statement = "SELECT * FROM " + tableName + " WHERE id IN (?)";
Query createNativeQuery = emJpa.createNativeQuery(statement, this.em.getClassObject());
createNativeQuery.setParameter(1, ids);
The query does not give any error, but no results given.
String statement = "SELECT * FROM " + tableName + " WHERE id IN (?)";
Query createNativeQuery = emJpa.createNativeQuery(statement, this.em.getClassObject());
createNativeQuery.setParameter(1, Joiner.on(",").join(ids));
Only one result is given, but 7 ids was provided to the query
From this topic I also tried using ?1 instead of ?, but no changes. Is there a way to make the nativeQuery working with a list of ids?
For the moment I'm using the full raw SQL statement
String joinedId = Joiner.on(",").join(ids);
String statement = "SELECT * FROM " + tableName + " WHERE id IN (" + joinedId + ") ORDER BY FIELD(id," + joinedId + ")";
Query createNativeQuery = emJpa.createNativeQuery(statement, this.em.getClassObject());
createNativeQuery.getResultList();
But at first I started with the parameter query for optimization and performance related of parsing each time the statement.
EDIT
With the suggestion of Chris I tried a TypedQuery using the FUNCTION operator (which is available because I'm using the latest EclipseLink). Here is the resulting code
List<Long> ids = ...;
Class<?> clazz = ...;
String statement = "SELECT e FROM " + clazz.getSimpleName() + " e WHERE e.id IN (:idList) ORDER BY FUNCTION('FIELD', e.id, :idList)";
EntityManagerFactory emf = ...;
EntityManager em = emf.createEntityManager();
TypedQuery<?> query = em.createQuery(statement, clazz);
query.setParameter("idList", ids);
List resultList = query.getResultList();
And here is the error while executing this code
Local Exception Stack:
Exception [EclipseLink-4002] (Eclipse Persistence Services - 2.6.3.v20160428-59c81c5): org.eclipse.persistence.exceptions.DatabaseException
Internal Exception: java.sql.SQLException: Operand should contain 1 column(s)
Error Code: 1241
Call: SELECT ... all the fields ... FROM webcontent_type WHERE (ID IN ((?,?,?,?,?,?,?))) ORDER BY FIELD(ID, (?,?,?,?,?,?,?))
bind => [14 parameters bound]
Query: ReadAllQuery(referenceClass=WebContentType sql="SELECT ... all the fields ... FROM webcontent_type WHERE (ID IN (?)) ORDER BY FIELD(ID, ?)")
EDIT 2
Tried without the parenthesis but there is still an error
SELECT e FROM FrameWorkUser e WHERE e.id IN :idList ORDER BY FUNCTION('FIELD', e.id, :idList)
I must say that with a list of one element the code works, but with another list of 10 elements there is an error
javax.persistence.PersistenceException: Exception [EclipseLink-4002] (Eclipse Persistence Services - 2.6.3.v20160428-59c81c5): org.eclipse.persistence.exceptions.DatabaseException
Internal Exception: java.sql.SQLException: Operand should contain 1 column(s)
Error Code: 1241
Call: SELECT .... FROM webcontent_type WHERE (ID IN (?,?,?,?,?,?,?)) ORDER BY FIELD(ID, (?,?,?,?,?,?,?))
bind => [14 parameters bound]
Query: ReadAllQuery(referenceClass=WebContentType sql="SELECT .... FROM webcontent_type WHERE (ID IN ?) ORDER BY FIELD(ID, ?)")
at org.eclipse.persistence.internal.jpa.QueryImpl.getDetailedException(QueryImpl.java:382)
at org.eclipse.persistence.internal.jpa.QueryImpl.executeReadQuery(QueryImpl.java:260)
at org.eclipse.persistence.internal.jpa.QueryImpl.getResultList(QueryImpl.java:473)
It seems that even w/o the parenthesis, the resulting statement has them

If you are going to use a native query, you must do it exactly like you would form the SQL for your database - this means you must break the list into its component parameters as JPA providers are not expected to change the SQL for you. Most providers handle lists in JPQL though, so "select e from Entity e where e.id in (:idList)" will work in EclipseLink.
Your missing bit is that 'FIELD' is not a JPQL construct. For this, you would have to use the JPQL 2.1 FUNCTION operator. Something like:
"Select e from Entity e where e.id in :idList order by FUNCTION('FIELD', e.id, :idList)"

JPQL Query a list of Strings inside an Entity

I'm using Java EE7 with a GlassFish 4.1 Server to build a system where basically you can post Ideas, and each Idea may have tags.
I've declared the entity Idea as:
#Entity
#Table(name = "IDEAS")
public class Idea implements Serializable {
// Id, description, etc.
#ElementCollection
private List<String> tags;
// Getters, Setter, etc.
}
After reading JPA: Query an embeddable List inside an entity I tried to find by Tag the following way:
public List<Idea> getIdeasWithTag(String tag) {
String queryStr = "select ideatags from Idea i "
+ "inner join i.tags ideatags "
+ "where ideatags.tags = :pTag";
Object res = em.createQuery(queryStr)
.setParameter("pTag", tag)
.getResultList();
return (List<Idea>) res;
}
But I'm getting a TransactionRolledbackLocalException caused by:
Caused by: java.lang.IllegalArgumentException: An exception occurred while creating a query in EntityManager:
Exception Description: Problem compiling [select ideatags from Idea i inner join i.tags ideatags where ideatags.tags = :pTag].
[61, 74] The state field path 'ideatags.tags' cannot be resolved to a valid type.
I appreciate any help, thanks in advance!!

You have some problems with your query:
select ideatags
from Idea i inner join i.tags ideatags
where ideatags.tags = :pTag
You want the result as Idea but you select a List.
You get your List tags in ideatags, therefore you cant get the attribute tag of ideatags.
if you want to search in the list you have to use IN.
You can try this:
select i
from Idea i
where :pTag IN (i.tags)

Try this:
select e from entity e WHERE :element in elements(e.listOfStrings)

elements() - this work!
where :pTag IN (i.tags) is not work (

How to pass parameter on jpa query?

I have two entities Like SmsOut and SmsIn. The relation between two entities contains OneToMany where smsIn.id is primary key and smsOut.sms_in_id is foreign key.
Now I want to pass parameter like smsIn.mobileNumber, smsIn.smsText and so on, on the query
SELECT so FROM SmsOut so order by id desc
Following is my database diagram:
Edited
Following is my code :
String sql = "SELECT so FROM SmsOut so WHERE so.smsInId.mobileNumber =:mobileNumber AND so.smsInId.smsText =:smsText AND so.smsInId.shortCode =:shortCode between so.smsOutDate =:startDate and so.smsOutDate =:endDate order by id desc";
Query query = em.createQuery(sql);
query.setParameter("mobileNumber", mobileNumber);
query.setParameter("smsText", smsText);
query.setParameter("shortCode", shortCode);
query.setParameter("smsOutDate", startDate);
query.setParameter("smsOutDate", endDate);
smsOutList = query.getResultList();
and exception is :
SEVERE: line 1:188: expecting "and", found '='
java.lang.IllegalArgumentException: org.hibernate.hql.ast.QuerySyntaxException: expecting "and", found '=' near line 1, column 188 [SELECT so FROM com.f1soft.SMSC.entities.SmsOut so WHERE so.smsInId.mobileNumber =:mobileNumber AND so.smsInId.smsText =:smsText AND so.smsInId.shortCode =:shortCode between so.smsOutDate =:startDate and so.smsOutDate =:endDate order by id desc]
at org.hibernate.ejb.AbstractEntityManagerImpl.throwPersistenceException(AbstractEntityManagerImpl.java:624)
at org.hibernate.ejb.AbstractEntityManagerImpl.createQuery(AbstractEntityManagerImpl.java:96)
Please Help me.
Thanks

You haven't explained the JPA relationship between SmsIn and SmsOut, so I'll assume SmsOut has a getSmsIn() with a relation on the id field.
When you have an EntityManager em, you can call em.createQuery, which is like SQL prepare, and then setParameter:
TypedQuery<SmsOut> q = em.createQuery("SELECT so FROM SmsOut so WHERE so.smsIn.mobileNumber = :number ORDER BY id DESC");
q.setParameter("number", "12345678");
List<SmsOut> results = q.getResultList();
See the Javadoc for Query for the different ways you can specify the parameters.

SELECT so FROM SmsOut so WHERE smsIn.mobileNumber = ? AND smsIn.smsText =? order by id desc
Replace the ? sign with the apropiate values.

between is the problem:
between so.smsOutDate =:startDate and so.smsOutDate =:endDate
try
so.smsOutDate between =:startDate and =:endDate

Query using alias on column give an error

When i use alias for column i get error. Without alias everytinig works good. What is the problem with that ? This is simple example, but need to use more aliases in real project to wrap results in some not-entity class, but can't because of this error. How to solve this ?
NOT WORKING (with alias on id column):
public List<Long> findAll(Long ownerId) {
String sql = "select id as myId from products where ownerId = "+ownerId;
SQLQuery query = getSession().createSQLQuery(sql);
return query.list();
}
Error:
WARN [JDBCExceptionReporter:77] : SQL Error: 0, SQLState: S0022 ERROR
[JDBCExceptionReporter:78] : Column 'id' not found.
WORKING (without alias):
public List<Long> findAll(Long ownerId) {
String sql = "select id from products where ownerId = "+ownerId;
SQLQuery query = getSession().createSQLQuery(sql);
return query.list();
}

If your "product" is mapped, hibernate probably don't know about "myId" and therefore can't select it.
You can try something like:
getSession().createSQLQuery(sql).addScalar("myId", Hibernate.LONG)