Related
Here is my code
private static final String MEDIA_TYPE = "application/json";
private static final String FORMAT = "UTF-8";
private static String baseServiceUrl;
private static String apiServiceUrl;
#RequestMapping("/")
public ResponseEntity<?> getMessage() throws Exception {
logger.info("Started");
try {
messageProcessor.getMessage("test service");
// Read from request
StringBuilder buffer = new StringBuilder();
BufferedReader reader = request.getReader();
String line;
while ((line = reader.readLine()) != null) {
buffer.append(line);
}
String data = buffer.toString();
StringRequestEntity requestEntity = null;
HttpClient httpclient = new HttpClient();
int statusCode;
logger.info("RequestBody"+data);
baseServiceUrl="http://localhost:8080/services";
apiServiceUrl="/services/rest/json";
StringBuffer eventResponse = new StringBuffer();
requestEntity = new StringRequestEntity(data, MEDIA_TYPE, FORMAT);
PostMethod postMethod = new PostMethod(baseServiceUrl+apiServiceUrl);
postMethod.setRequestEntity(requestEntity);
statusCode = httpclient.executeMethod(postMethod);
logger.info("Status code"+statusCode);
}
catch (Exception ex) {
logger.error("Exception occurs ", ex);
return new ResponseEntity("Internal server error !!", HttpStatus.INTERNAL_SERVER_ERROR);
}
return new ResponseEntity("Successfully called the service!!", HttpStatus.OK);
}
I want to get the requestbody of one API and send to another API .And a json is my request body.But in this code,I got the status code as 400.Can anyone help me to solve the problem
I think you have appended the /services in the url twice. It should be like:
baseServiceUrl="http://localhost:8080/services";
apiServiceUrl="/rest/json";
In your code you are reading the request body as a string , could you share the request body that is logged.The HTTP response code 400 corresponds to BAD request . So probably, either the endpoint that you are trying to hit is different or the request body has an issue. Try removing the /services from your apiServiceUrl to correct the url path.Also, since you are most probably having a json as request body try the following approach :
String json = "{"id":1,"name":"xxxx"}";
StringEntity entity = new StringEntity(json);
postMethod.setEntity(entity);
postMethod.setHeader("Accept", "application/json");
postMethod.setHeader("Content-type", "application/json");
make sure that the string that you read from the request using BufferedReader reader = request.getReader(); is in appropriate json format.
I'm using http client to get data:
public static String getHttpResponse(String url) {
//LOGGER.info("Download page context from URL " + url);
String httpClientResponse = null;
try {
URI uri = new URIBuilder(url).build();
HttpResponse response;
HttpHost target = new HttpHost(uri.getHost());
HttpGet request = new HttpGet(uri);
//request.setConfig(config);
request.addHeader(new BasicHeader("User-Agent", "Mozilla/5.0"));
request.addHeader(new BasicHeader("Content-Type", "text/html"));
request.addHeader("Accept-Ranges", "bytes=100-1500");
org.apache.http.client.HttpClient
client = HttpClients.custom().build();
response = client.execute(target, request);
//LOGGER.info("Status Line for URL {} is {}", uri.getHost() + File.separator + uri.getPath(), response.getStatusLine());
InputStream inputStream = response.getEntity().getContent();
if (inputStream == null || response.getStatusLine().getStatusCode() != HttpStatus.SC_OK) {
/*LOGGER.error("Non-success response while downloading image. Response {}", response.getStatusLine());
LOGGER.error("Error while download data from url {}", url);*/
} else {
httpClientResponse = IOUtils.toString(inputStream, CharEncoding.UTF_8);
}
} catch (Exception e) {
System.out.println("Error while download content from URL");
}
return httpClientResponse;
}
Also: Can we do this using Jsoup?
Thanks.
Replace:
request.addHeader("Accept-Ranges", "bytes=100-1500");
with:
request.addHeader("Range", "bytes=100-1500");
The Accept-Ranges header is part of server response, which indicates that the server accepts partial requests.
In your request you should use Range header, which indicates which part of document server should return.
https://developer.mozilla.org/en-US/docs/Web/HTTP/Headers/Accept-Ranges
https://developer.mozilla.org/en-US/docs/Web/HTTP/Headers/Range
lets assume this URL...
http://www.example.com/page.php?id=10
(Here id needs to be sent in a POST request)
I want to send the id = 10 to the server's page.php, which accepts it in a POST method.
How can i do this from within Java?
I tried this :
URL aaa = new URL("http://www.example.com/page.php");
URLConnection ccc = aaa.openConnection();
But I still can't figure out how to send it via POST
Updated answer
Since some of the classes, in the original answer, are deprecated in the newer version of Apache HTTP Components, I'm posting this update.
By the way, you can access the full documentation for more examples here.
HttpClient httpclient = HttpClients.createDefault();
HttpPost httppost = new HttpPost("http://www.a-domain.example/foo/");
// Request parameters and other properties.
List<NameValuePair> params = new ArrayList<NameValuePair>(2);
params.add(new BasicNameValuePair("param-1", "12345"));
params.add(new BasicNameValuePair("param-2", "Hello!"));
httppost.setEntity(new UrlEncodedFormEntity(params, "UTF-8"));
//Execute and get the response.
HttpResponse response = httpclient.execute(httppost);
HttpEntity entity = response.getEntity();
if (entity != null) {
try (InputStream instream = entity.getContent()) {
// do something useful
}
}
Original answer
I recommend to use Apache HttpClient. its faster and easier to implement.
HttpPost post = new HttpPost("http://jakarata.apache.org/");
NameValuePair[] data = {
new NameValuePair("user", "joe"),
new NameValuePair("password", "bloggs")
};
post.setRequestBody(data);
// execute method and handle any error responses.
...
InputStream in = post.getResponseBodyAsStream();
// handle response.
for more information check this URL: http://hc.apache.org/
Sending a POST request is easy in vanilla Java. Starting with a URL, we need t convert it to a URLConnection using url.openConnection();. After that, we need to cast it to a HttpURLConnection, so we can access its setRequestMethod() method to set our method. We finally say that we are going to send data over the connection.
URL url = new URL("https://www.example.com/login");
URLConnection con = url.openConnection();
HttpURLConnection http = (HttpURLConnection)con;
http.setRequestMethod("POST"); // PUT is another valid option
http.setDoOutput(true);
We then need to state what we are going to send:
Sending a simple form
A normal POST coming from a http form has a well defined format. We need to convert our input to this format:
Map<String,String> arguments = new HashMap<>();
arguments.put("username", "root");
arguments.put("password", "sjh76HSn!"); // This is a fake password obviously
StringJoiner sj = new StringJoiner("&");
for(Map.Entry<String,String> entry : arguments.entrySet())
sj.add(URLEncoder.encode(entry.getKey(), "UTF-8") + "="
+ URLEncoder.encode(entry.getValue(), "UTF-8"));
byte[] out = sj.toString().getBytes(StandardCharsets.UTF_8);
int length = out.length;
We can then attach our form contents to the http request with proper headers and send it.
http.setFixedLengthStreamingMode(length);
http.setRequestProperty("Content-Type", "application/x-www-form-urlencoded; charset=UTF-8");
http.connect();
try(OutputStream os = http.getOutputStream()) {
os.write(out);
}
// Do something with http.getInputStream()
Sending JSON
We can also send json using java, this is also easy:
byte[] out = "{\"username\":\"root\",\"password\":\"password\"}" .getBytes(StandardCharsets.UTF_8);
int length = out.length;
http.setFixedLengthStreamingMode(length);
http.setRequestProperty("Content-Type", "application/json; charset=UTF-8");
http.connect();
try(OutputStream os = http.getOutputStream()) {
os.write(out);
}
// Do something with http.getInputStream()
Remember that different servers accept different content-types for json, see this question.
Sending files with java post
Sending files can be considered more challenging to handle as the format is more complex. We are also going to add support for sending the files as a string, since we don't want to buffer the file fully into the memory.
For this, we define some helper methods:
private void sendFile(OutputStream out, String name, InputStream in, String fileName) {
String o = "Content-Disposition: form-data; name=\"" + URLEncoder.encode(name,"UTF-8")
+ "\"; filename=\"" + URLEncoder.encode(filename,"UTF-8") + "\"\r\n\r\n";
out.write(o.getBytes(StandardCharsets.UTF_8));
byte[] buffer = new byte[2048];
for (int n = 0; n >= 0; n = in.read(buffer))
out.write(buffer, 0, n);
out.write("\r\n".getBytes(StandardCharsets.UTF_8));
}
private void sendField(OutputStream out, String name, String field) {
String o = "Content-Disposition: form-data; name=\""
+ URLEncoder.encode(name,"UTF-8") + "\"\r\n\r\n";
out.write(o.getBytes(StandardCharsets.UTF_8));
out.write(URLEncoder.encode(field,"UTF-8").getBytes(StandardCharsets.UTF_8));
out.write("\r\n".getBytes(StandardCharsets.UTF_8));
}
We can then use these methods to create a multipart post request as follows:
String boundary = UUID.randomUUID().toString();
byte[] boundaryBytes =
("--" + boundary + "\r\n").getBytes(StandardCharsets.UTF_8);
byte[] finishBoundaryBytes =
("--" + boundary + "--").getBytes(StandardCharsets.UTF_8);
http.setRequestProperty("Content-Type",
"multipart/form-data; charset=UTF-8; boundary=" + boundary);
// Enable streaming mode with default settings
http.setChunkedStreamingMode(0);
// Send our fields:
try(OutputStream out = http.getOutputStream()) {
// Send our header (thx Algoman)
out.write(boundaryBytes);
// Send our first field
sendField(out, "username", "root");
// Send a seperator
out.write(boundaryBytes);
// Send our second field
sendField(out, "password", "toor");
// Send another seperator
out.write(boundaryBytes);
// Send our file
try(InputStream file = new FileInputStream("test.txt")) {
sendFile(out, "identification", file, "text.txt");
}
// Finish the request
out.write(finishBoundaryBytes);
}
// Do something with http.getInputStream()
String rawData = "id=10";
String type = "application/x-www-form-urlencoded";
String encodedData = URLEncoder.encode( rawData, "UTF-8" );
URL u = new URL("http://www.example.com/page.php");
HttpURLConnection conn = (HttpURLConnection) u.openConnection();
conn.setDoOutput(true);
conn.setRequestMethod("POST");
conn.setRequestProperty( "Content-Type", type );
conn.setRequestProperty( "Content-Length", String.valueOf(encodedData.length()));
OutputStream os = conn.getOutputStream();
os.write(encodedData.getBytes());
The first answer was great, but I had to add try/catch to avoid Java compiler errors.
Also, I had troubles to figure how to read the HttpResponse with Java libraries.
Here is the more complete code :
/*
* Create the POST request
*/
HttpClient httpClient = new DefaultHttpClient();
HttpPost httpPost = new HttpPost("http://example.com/");
// Request parameters and other properties.
List<NameValuePair> params = new ArrayList<NameValuePair>();
params.add(new BasicNameValuePair("user", "Bob"));
try {
httpPost.setEntity(new UrlEncodedFormEntity(params, "UTF-8"));
} catch (UnsupportedEncodingException e) {
// writing error to Log
e.printStackTrace();
}
/*
* Execute the HTTP Request
*/
try {
HttpResponse response = httpClient.execute(httpPost);
HttpEntity respEntity = response.getEntity();
if (respEntity != null) {
// EntityUtils to get the response content
String content = EntityUtils.toString(respEntity);
}
} catch (ClientProtocolException e) {
// writing exception to log
e.printStackTrace();
} catch (IOException e) {
// writing exception to log
e.printStackTrace();
}
A simple way using Apache HTTP Components is
Request.Post("http://www.example.com/page.php")
.bodyForm(Form.form().add("id", "10").build())
.execute()
.returnContent();
Take a look at the Fluent API
I suggest using Postman to generate the request code. Simply make the request using Postman then hit the code tab:
Then you'll get the following window to choose in which language you want your request code to be:
simplest way to send parameters with the post request:
String postURL = "http://www.example.com/page.php";
HttpPost post = new HttpPost(postURL);
List<NameValuePair> params = new ArrayList<NameValuePair>();
params.add(new BasicNameValuePair("id", "10"));
UrlEncodedFormEntity ent = new UrlEncodedFormEntity(params, "UTF-8");
post.setEntity(ent);
HttpClient client = new DefaultHttpClient();
HttpResponse responsePOST = client.execute(post);
You have done. now you can use responsePOST.
Get response content as string:
BufferedReader reader = new BufferedReader(new InputStreamReader(responsePOST.getEntity().getContent()), 2048);
if (responsePOST != null) {
StringBuilder sb = new StringBuilder();
String line;
while ((line = reader.readLine()) != null) {
System.out.println(" line : " + line);
sb.append(line);
}
String getResponseString = "";
getResponseString = sb.toString();
//use server output getResponseString as string value.
}
Using okhttp :
Source code for okhttp can be found here https://github.com/square/okhttp.
If you're writing a pom project, add this dependency
<dependency>
<groupId>com.squareup.okhttp3</groupId>
<artifactId>okhttp</artifactId>
<version>4.2.2</version>
</dependency>
If not simply search the internet for 'download okhttp'. Several results will appear where you can download a jar.
your code :
import okhttp3.*;
import java.io.IOException;
public class ClassName{
private void sendPost() throws IOException {
// form parameters
RequestBody formBody = new FormBody.Builder()
.add("id", 10)
.build();
Request request = new Request.Builder()
.url("http://www.example.com/page.php")
.post(formBody)
.build();
OkHttpClient httpClient = new OkHttpClient();
try (Response response = httpClient.newCall(request).execute()) {
if (!response.isSuccessful()) throw new IOException("Unexpected code " + response);
// Get response body
System.out.println(response.body().string());
}
}
}
Easy with java.net:
public void post(String uri, String data) throws Exception {
HttpClient client = HttpClient.newBuilder().build();
HttpRequest request = HttpRequest.newBuilder()
.uri(URI.create(uri))
.POST(BodyPublishers.ofString(data))
.build();
HttpResponse<?> response = client.send(request, BodyHandlers.discarding());
System.out.println(response.statusCode());
Here is more information:
https://openjdk.java.net/groups/net/httpclient/recipes.html#post
Since java 11, HTTP requests can be made by using java.net.http.HttpClient with less code.
var values = new HashMap<String, Integer>() {{
put("id", 10);
}};
var objectMapper = new ObjectMapper();
String requestBody = objectMapper
.writeValueAsString(values);
HttpClient client = HttpClient.newHttpClient();
HttpRequest request = HttpRequest.newBuilder()
.uri(URI.create("http://www.example.com/abc"))
.POST(HttpRequest.BodyPublishers.ofString(requestBody))
.build();
HttpResponse<String> response = client.send(request,
HttpResponse.BodyHandlers.ofString());
System.out.println(response.body());
Call HttpURLConnection.setRequestMethod("POST") and HttpURLConnection.setDoOutput(true); Actually only the latter is needed as POST then becomes the default method.
I recomend use http-request built on apache http api.
HttpRequest<String> httpRequest = HttpRequestBuilder.createPost("http://www.example.com/page.php", String.class)
.responseDeserializer(ResponseDeserializer.ignorableDeserializer()).build();
public void send(){
String response = httpRequest.execute("id", "10").get();
}
I am trying to post an image from my galery to the server from my android device.
They are using Python in the back office.
That's what the Back office developper say:
- Django cannot read the file posted by the Android app in request.FILES. iOS does this properly.
- It seems the the Multipart POST does not properly set the key:value required to properly read the requests.
I am getting this error:
{"errorMessage":"","message":"Invalid mime
type","errorCode":0,"success":false}
Any idea why?
Here is my code:
public static final String IMAGE_JPEG = "image/jpeg";
private HttpEntity getImageEntity() throws Exception {
File imageFile;
Uri originalUri = Uri.parse(this.mFileName);
String originalPath = originalUri.getPath();
boolean isEncrypted = originalPath.contains(FileNames.CACHE_DIR.getPath());
// check if file encrypted or not
if (isEncrypted && ImageLoader.IMAGE_CODING_ENABLED) {
File originalImageFile = new File(originalPath);
String decodedPath = CipherUtils.decryptFile(SmartPagerApplication.getInstance(), originalImageFile);
imageFile = new File(decodedPath);
} else {
imageFile = new File(originalPath);
}
InputStream fis = imageFile.toURI().toURL().openStream();
int rotation = PhotoFileUtils.getOrientation(this.mFileName);
if (rotation > 0) {
byte[] data;
Bitmap rotateBitmap = PhotoFileUtils.checkOrientation(BitmapFactory.decodeStream(fis), rotation);
ByteArrayOutputStream stream = new ByteArrayOutputStream();
rotateBitmap.compress(Bitmap.CompressFormat.PNG, 100, stream);
data = stream.toByteArray();
stream.close();
rotateBitmap.recycle();
fis.close();
fis = new ByteArrayInputStream(data);
} else {
// data = IOUtils.toByteArray(fis);
}
return getMultipartEntity(originalUri, fis);
}
private MultipartEntity getMultipartEntity(Uri originalPath, InputStream fis) {
InputStreamBody isb = new InputStreamBody(fis, mMimeType, originalPath.getLastPathSegment());
MultipartEntity multipartEntity = new MultipartEntity(HttpMultipartMode.BROWSER_COMPATIBLE,
"----WebKitFormBoundaryzGJGBFWyGteE24tw", Charset.forName("ISO-8859-1"));
multipartEntity.addPart("binaryFile", isb);
return multipartEntity;
}
private String executePost(String url, HttpEntity params) throws ClientProtocolException, IOException {
Log.e("executePost url =" + url);
HttpPost httpPost = new HttpPost(url);
httpPost.setHeader("Accept", "application/json");
httpPost.setHeader("Content-Type", "multipart/form-data; boundary="+"----WebKitFormBoundaryzGJGBFWyGteE24tw");
httpPost.addHeader("Cache-Control", "no-cache");
httpPost.setEntity(params);
String response = SmartPagerHTTPClient.getHttpClient().execute(httpPost, new BasicResponseHandler());
return response;
}
I don't have enough reputation to comment, so I have to put this as an answer. In you method getMultipartEntity(), the first line:
InputStreamBody isb = new InputStreamBody(fis, mMimeType, originalPath.getLastPathSegment());
What is the value of mMimeType? Please make sure it's a correct mime type.
This is an OKHttp implementation
first, you need to include it in dependencies:
compile 'com.squareup.okhttp:okhttp:2.4.0'
Actual upload code : Call within an Asynctask
File upload;
upload = new File("<<Your Path to image>>");
Response response;
String finalResponce;
try {
RequestBody body = new MultipartBuilder()
.addFormDataPart("Image", upload.getName(), RequestBody.create(MediaType.parse("image/jpeg"), upload))
.build();
Request request = new Request.Builder()
.url("https://iamin-events.appspot.com/UploadServlet")
.post(body)
.build();
response = new OkHttpClient().newCall(request).execute();
finalResponce = response.body().string();
finalResponce = finalResponce.trim();
mainEventListing.setBackdropUrl(finalResponce);
} catch (Exception e) {
// show error
e.printStackTrace();
}
This is my code for uploading images.The "Content-Type" is like that httpConnection.setRequestProperty("Content-Type", "image/jpeg");
public String doPutUploadImage(File image) throws Exception {
String imageUrl = "http://" + Const.BUCKET_NAME
+ ".oss-cn-hangzhou.aliyuncs.com/" + image.getName();
URL localURL = new URL(imageUrl);
URLConnection connection = localURL.openConnection();
HttpURLConnection httpConnection = (HttpURLConnection) connection;
httpConnection.setDoOutput(true);
httpConnection.setRequestMethod("PUT");
httpConnection.setRequestProperty("Host",
Const.BUCKET_NAME.concat(".oss-cn-hangzhou.aliyuncs.com"));
String GMTDate = SignatureMaker.getGMTDate();
if(!GMTDate.contains("+")){
httpConnection.setRequestProperty("Date", GMTDate);
}else{
GMTDate=GMTDate.substring(0, GMTDate.indexOf("+"));
httpConnection.setRequestProperty("Date", GMTDate);
}
httpConnection.setRequestProperty("Content-Encoding", "UTF-8");
httpConnection.setRequestProperty("Content-Type", "image/jpeg");
httpConnection.setRequestProperty("Content-Length",
String.valueOf(image.length()));
httpConnection.setRequestProperty("Authorization",
"OSS "+ ACCESS_ID+ ":"
+ SignatureMaker.makeSignature(ACCESS_KEY, "PUT",
Const.BUCKET_NAME, image, GMTDate));
sendRequest(httpConnection, image);
return imageUrl;
}
Instead of MultipartEntity, I suggest that you use MultipartEntityBuilder with HttpURLConnection. Then, you can refer to my following code (pay attention to ContentType contentType = ContentType.create("image/jpeg");):
...
byte[] bitmapData = byteArrayOutputStream.toByteArray();
String address = "http://192.168.1.100/api/postfile";
String boundary = "----apiclient----" + System.currentTimeMillis();
String mimeType = "multipart/form-data;boundary=" + boundary;
MultipartEntityBuilder entityBuilder = MultipartEntityBuilder.create();
entityBuilder.setMode(HttpMultipartMode.BROWSER_COMPATIBLE);
entityBuilder.setBoundary(boundary);
// Add binary body
if (bitmapData != null) {
ContentType contentType = ContentType.create("image/jpeg"); //CREATE ContentType for the file part
String fileName = "some_file_name.jpeg";
entityBuilder.addBinaryBody("binaryFile", bitmapData, contentType, fileName);
try {
URL url = new URL(address);
HttpURLConnection urlConnection = (HttpURLConnection) url.openConnection();
urlConnection.setDoInput(true);
urlConnection.setDoOutput(true);
urlConnection.setRequestMethod("POST");
urlConnection.setRequestProperty("Content-Type", mimeType);
entityBuilder.build().writeTo(urlConnection.getOutputStream());
JSONObject jsonObject = new JSONObject();
try {
if (urlConnection.getResponseCode() < HttpURLConnection.HTTP_BAD_REQUEST) {
// process urlConnection.getInputStream();
} else {
// process urlConnection.getErrorStream();
}
jsonObject.put("Message", urlConnection.getResponseMessage());
jsonObject.put("Length", urlConnection.getContentLength());
jsonObject.put("Type", urlConnection.getContentType());
} catch (IOException | JSONException e) {
e.printStackTrace();
}
} catch (Exception e) {
e.printStackTrace();
}
}
...
If you still want to use MultipartEntityBuilder with HttpPost, you can refer to the following:
...
byte[] bytes = byteArrayOutputStream.toByteArray();
ContentType contentType = ContentType.create("image/jpeg");
String fileName = "some_filename.jpg";
MultipartEntityBuilder builder = MultipartEntityBuilder.create();
builder.setMode(HttpMultipartMode.BROWSER_COMPATIBLE);
// Add binary body
builder.addBinaryBody("binaryFile", bytes, contentType, fileName);
HttpEntity httpEntity = builder.build();
httpPost.setEntity(httpEntity);
...
You can find out that addBinaryBody in MultipartEntityBuilder class has many implementations such as:
public MultipartEntityBuilder addBinaryBody(String name, InputStream stream, ContentType contentType, String filename)
public MultipartEntityBuilder addBinaryBody(String name, File file, ContentType contentType, String filename)
public MultipartEntityBuilder addBinaryBody(String name, byte[] b, ContentType contentType, String filename)
...
Hope this helps!
I think this issue is because you are setting Content-Type yourself in code, I once had same issue in my case I just removed the Content-Type and It worked. If you remove the Content-Type, you mean that library will detect its Content-Type based on its type.
just remove this line
httpPost.setHeader("Content-Type", "multipart/form-data; boundary="+"----WebKitFormBoundaryzGJGBFWyGteE24tw");
Here is what i am doing and works fine for me -
MultipartEntity entity = new MultipartEntity(HttpMultipartMode.BROWSER_COMPATIBLE);
entity.addPart("photo", new FileBody(new File(imagePath), "image/jpeg"));
httppost.setEntity(entity);
According to this org.apache.http documentation Change your mime-type static declaration
public static final String IMAGE_JPEG = "image/jpeg";
to
public static final String IMAGE_JPEG = "image/png";
In addition to the #BNK answer Instead of MultipartEntity, you can use MultipartEntityBuilder with HttpURLConnection. In that you can upload the image as a binary body and there you can set the type and the name:
multiPartEntityBuilder.addBinaryBody(imageName, byteArray, ContentType.create("image/png"), "image.png");
You are probably running your code on Android 4.0.x which has buggy implementation for multipart/form-data (httpclient). This issue has been reported earlier and has a work around here
When I execute an API through following method, I always get 404 as response code.
private void execute() throws IllegalStateException, IOException, NoSuchAlgorithmException {
Map<String, String> comment = new HashMap<String, String>();
comment.put("accounts-groups", "customers/enterprise");
comment.put("companyType", "customer");
comment.put("companyName", "Test");
String json = new GsonBuilder().create().toJson(comment, Map.class);
Log.i(TAG, "json : "+json);
HttpResponse response = makeRequest(URL, json);
/*Checking response */
if(response != null) {
InputStream inputStream = response.getEntity().getContent(); //Get the data in the entity
int statusCode = response.getStatusLine().getStatusCode();
Log.i(TAG, "statusCode : "+statusCode);
String result;
// convert inputstream to string
if(inputStream != null)
result = convertStreamToString(inputStream);
else
result = "Did not work!";
Log.i(TAG, "result : "+result);
}
}
private HttpResponse makeRequest(String uri, String json) throws NoSuchAlgorithmException {
Log.i(TAG, "uri : "+uri);
try {
HttpPost httpPost = new HttpPost(uri);
httpPost.setEntity(new StringEntity(json, HTTP.UTF_8));
long timestamp = System.currentTimeMillis();
String signatureKey = PRIVATE_KEY + timestamp;
byte[] bytesOfMessage = signatureKey.getBytes(HTTP.UTF_8);
MessageDigest md = MessageDigest.getInstance("MD5");
byte[] thedigest = md.digest(bytesOfMessage);
char[] signature = Hex.encodeHex(thedigest);
String finalSignature = String.valueOf(signature);
Log.i(TAG, "finalSignature : "+finalSignature);
httpPost.setHeader("Timestamp", ""+timestamp);
httpPost.setHeader("Api_token", API_TOKEN);
httpPost.setHeader("Signature" , finalSignature);
httpPost.setHeader("Accept", "application/json");
httpPost.setHeader(HTTP.CONTENT_TYPE, "application/json");
return new DefaultHttpClient().execute(httpPost);
} catch (UnsupportedEncodingException e) {
e.printStackTrace();
} catch (ClientProtocolException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
return null;
}
I am not getting where am I going wrong. Can anybody please help me out?
from wiki:
The 404 or Not Found error message is a HTTP standard response code
indicating that the client was able to communicate with the server,
but the server could not find what was requested.
so, your code is OK, but server cannot find resource you are looking for. Double check if your url is correct.
how to pass request through fiddler proxy for debugging purposes:
HttpParams params = new BasicHttpParams();
// ....
HttpHost proxy = new HttpHost("192.168.1.12", 8888); // IP to your PC with fiddler proxy
params.setParameter(ConnRoutePNames.DEFAULT_PROXY, proxy);
// use params as a second parameter to: following constructor:
// public DefaultHttpClient (ClientConnectionManager conman, HttpParams params)
I was getting 404 for POST requests because mod_headers module of Apache 2 server was not enabled. If that happens you can enable it with:
sudo a2enmod headers
and then restart apache:
sudo service apache2 restart