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What is the equivalent Java for this PHP code?
//print string plus/with variable
$mystring = "this is string " .$string
//print sum one + two
$count = $one + $two
//print sum one*two
$count = $one * $two
It should be like :
String mystring= "this is string " + string; // here `string` is aloso String object
/*
* if count ,one and two all of them are int
*/
int count = one + two;
int count = one * two;
But i would suggest to learn basics of java before starting android. As you know php it will not take long to learn java syntax.
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I am trying to convert the following Java code into swift, but I do not know about this data structure new (int start, int end)[input. length], any guidance would be appraciated.
public override void collection_entries(int[] input)
{
var ranges = new (int start, int end)[input.length];
}
In swift, you should use a Range().
let start = 0
let end = 6
var ranges = Range(start...end)[input.count]
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I have the below one line of code:
variableDoubleValue = ((10*variableDoubleA) + (6.25*variableDoubleB) – (5*variableByteC) + 5);
How can I write it in a Java understandable code?
From what I infer from your question, you want a Java-language based variable declaration and assignment.
Well, if this is the case, then the result will be :-
//public class MathemathicalExpression{
// public static void main(String[] args){
// Double A=some_value,B=some_value,Value=0; considering A,B and Value to be of type Double
// Byte C=some_value; considering C to be of type Byte.
Value = 10 * A + 6.25 * B - 5 * C + 5;
// }
//}
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I need to write an if statement where I return the string "Close String" when int d is within 10% of int e. This is what I have now:
public String game(double d, double e) {
if((d>=.95*e)||(d<=e*1.05)) {
return "close string";
} else {
return "other";
}
}
TEST CASE
String game = game(100.0d, 90.0d);
System.out.println(game);
game = game(100.0d, 99.0d);
System.out.println(game);
game = game(100.0d, 100.0d);
System.out.println(game);
EXPECTED OUTPUT
other
close string
close string
CURRENT OUTPUT
close string
close string
close string
Where is the mistake?
I'm not sure exactly what you're asking, but I think you want and instead of or.
(a>=.95*b)||(a<=b*1.05)
a can then be any number, because it will be less than 5% above b, or 5% below b as long as it is a real number.
(a>=.95*b)&&(a<=b*1.05)
a can only be within + or - 5%
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i want to store string value in array or in in separate variable using java please short out my problem
Thanks
String a1,a2,a3;
while (resultSet.next()) {
isFound=true;
jLabel2.setText("hello");
String s1=resultSet.getString("Court_Num");
System.out.println(s1);
output s1=: 101
102
103
Desired out put: a1=101
a2=102
a3=103
Your question is confusing I think for 1st record you want a1=101 for 2nd a2=102 etc
int i=1;
while (resultSet.next()) {
if(i==1)
{String s1=resultSet.getString("Court_Num");
System.out.println(a1+"="+s1);}
if(i==2)
{String s1=resultSet.getString("Court_Num");
System.out.println(a2+"="+s1);}
if(i==3)
{String s1=resultSet.getString("Court_Num");
System.out.println(a3+"="+s1);}
i++
The title mentioned using an array. That would look something like this:
String[] a = new String[3];
for(int i=0; resultSet.next(); i++) {
a[i] = resultSet.getString("Court_Num");
System.out.println("a" + i + "=" + a[i]);
}
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public static int secret(int value) {
int prod = 1;
for(int i =1; i <= 3; i++) {
prod = prod * value;
}
return prod;
}
What would be the output of:
System.out.println("First secret call: " + secret(5));
System.out.println("Second secret call: " + (2 * secret(6)));
and what does the method secret do
The output would be 125 and then 432. The method, "secret", cubes the number passed into it.
everything fits in a very small screenshot in two windows... try it, you will see it is fun, like playing lego but with more magic!!!