I am trying to build simple webservices using Java, Rest Webservices(Jersey), Glass fish. project is successfully deploying in server without any errors, but when i access resources in browser it is giving 404-Not Found Error.
My resources class:
package org.student.services;
import javax.ws.rs.GET;
import javax.ws.rs.Path;
import javax.ws.rs.PathParam;
import javax.ws.rs.Produces;
import javax.ws.rs.core.MediaType;
#Path("/ConversionService")
public class FeetToInchAndInchToFeetConversionService {
#GET
#Path("/InchToFeet/{i}")
#Produces(MediaType.TEXT_XML)
public String convertInchToFeet(#PathParam("i") int i) {
int inch=i;
double feet = 0;
feet =(double) inch/12;
return "<InchToFeetService>"
+ "<Inch>" + inch + "</Inch>"
+ "<Feet>" + feet + "</Feet>"
+ "</InchToFeetService>";
}
#Path("/FeetToInch/{f}")
#GET
#Produces(MediaType.TEXT_XML)
public String convertFeetToInch(#PathParam("f") int f) {
int inch=0;
int feet = f;
inch = 12*feet;
return "<FeetToInchService>"
+ "<Feet>" + feet + "</Feet>"
+ "<Inch>" + inch + "</Inch>"
+ "</FeetToInchService>";
}
}
And Web.xml is:
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd"
version="3.0">
<display-name>StudentPortal</display-name>
<servlet>
<servlet-name>Jersey REST Service</servlet-name>
<servlet-class>org.glassfish.jersey.servlet.ServletContainer</servlet-class>
<init-param>
<param-name>jersey.config.server.provider.packages</param-name>
<param-value>org.student.services</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>Jersey REST Service</servlet-name>
<url-pattern>/rest/*</url-pattern>
</servlet-mapping>
</web-app>
using following Url with https//
mylocalhost:port/StudentPortal/rest/ConversionService/InchToFeet/2
Please Someone point what i am doing wrong
Related
I am new to Spring and trying to make integration between spring and primefaces. I am getting 404 page no found when I run the project on tomcat after adding the ContextLoaderListener and RequestContextListener.
My web.xml file:
<?xml version = "1.0" encoding = "UTF-8"?>
<web-app xmlns:xsi = "http://www.w3.org/2001/XMLSchema-instance"
xmlns = "http://java.sun.com/xml/ns/javaee"
xmlns:web = "http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
xsi:schemaLocation = "http://java.sun.com/xml/ns/javaee
http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
id = "WebApp_ID" version="2.5">
<welcome-file-list>
<welcome-file>login.xhtml</welcome-file>
</welcome-file-list>
<servlet>
<servlet-name>Faces Servlet</servlet-name>
<servlet-class>javax.faces.webapp.FacesServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet>
<servlet-name>dispatcher</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>dispatcher</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
<servlet-mapping>
<servlet-name>Faces Servlet</servlet-name>
<url-pattern>*.xhtml</url-pattern>
<url-pattern>/faces/*</url-pattern>
</servlet-mapping>
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>
/WEB-INF/spring/spring.xml
</param-value>
</context-param>
<listener>
<listener-class>
org.springframework.web.context.ContextLoaderListener
</listener-class>
</listener>
<listener>
<listener-class>
org.springframework.web.context.request.RequestContextListener
</listener-class>
</listener>
</web-app>
and this is my faces-config.xml file:
<?xml version="1.0" encoding="UTF-8"?>
<faces-config
xmlns="http://xmlns.jcp.org/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/javaee http://xmlns.jcp.org/xml/ns/javaee/web-facesconfig_2_3.xsd"
version="2.3">
<application>
<el-resolver>org.springframework.web.jsf.el.SpringBeanFacesELResolver</el-resolver>
</application>
<navigation-rule>
<display-name>/login.xhtml</display-name>
<from-view-id>/login.xhtml</from-view-id>
</navigation-rule>
<navigation-rule>
<display-name>/login.xhtml</display-name>
<from-view-id>/login.xhtml</from-view-id>
<navigation-case>
<from-outcome>viewRecords</from-outcome>
<to-view-id>view.xhtml</to-view-id>
<redirect/>
</navigation-case>
</navigation-rule>
</faces-config>
and following is my controller class:
package com.testtask.nagarro.controller;
import java.util.List;
import java.util.Map;
import javax.annotation.Resource;
import javax.validation.Valid;
import org.hibernate.annotations.Source;
import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.stereotype.Controller;
import org.springframework.validation.BindingResult;
import org.springframework.web.bind.annotation.ModelAttribute;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RequestMethod;
import org.springframework.web.servlet.ModelAndView;
import com.testtask.nagarro.forms.LoginForm;
import com.testtask.nagarro.forms.StatementForm;
import com.testtask.nagarro.interfaces.StatementRepository;
import com.testtask.nagarro.interfaces.UserService;
import com.testtask.nagarro.models.Statement;
#Controller
public class NagarroController {
#Autowired
private UserService userService;
public UserService getUserService() {
return userService;
}
public void setUserService(UserService userService) {
this.userService = userService;
}
#RequestMapping(value= "/", method=RequestMethod.GET)
public String loginPage() {
return "login";
}
#RequestMapping(value="/login", method=RequestMethod.GET)
public ModelAndView login() {
ModelAndView model = new ModelAndView();
model.setViewName("login");
return model;
}
#RequestMapping(value="/viewRecords", method = RequestMethod.POST)
public String showHomePage(StatementForm form) {
System.out.println("In view records controller");
List<Statement> records = getUserService().getRecordsByAccountId(form.getAccountId());
return "view";
}
#RequestMapping(method=RequestMethod.POST)
public String processForm(#Valid LoginForm loginForm, BindingResult result,
Map<String, LoginForm> model) {
String username = "UserName";
String password = "password";
if(result.hasErrors()) {
return "loginform";
}
loginForm = (LoginForm) model.get("loginForm");
if(!loginForm.getUsername().equals(username) || !loginForm.getPassword().equals(password)) {
return "loginForm";
}
model.put("loginForm", loginForm);
return "home";
}
}
I tried to find a solution online but I am confused because most of the examples are using jsps.
please point me to the problem, I am attaching the github link.
Your views are NOT in webapp/WEB-INF folder as you defined in your InternalViewResolver bean.
They are located in webapp folder.
I need to configure This file i tried to run this file but error was file not found : 404. so what would be the configure file I need to configure This file i tried to run this file but error was file not found : 404. so what would be the configure file
LoginService.java
package com.webService;
import java.util.ArrayList;
import javax.ws.rs.Consumes;
import javax.ws.rs.FormParam;
import javax.ws.rs.POST;
import javax.ws.rs.Path;
import javax.ws.rs.core.MediaType;
import com.pojo.UserVO;
import com.model.SecurityManager;;
#Path("/WebService")
public class LoginService
{
#POST
#Path("/login")
#Consumes(MediaType.APPLICATION_FORM_URLENCODED)
public String login(#FormParam("username") String username, #FormParam("password") String password)
{
return getAllUsersList(username, password);
}
public String getAllUsersList(String username, String password)
{
String userListData=null;
ArrayList<UserVO> userList = null;
SecurityManager sm = new SecurityManager();
userList =sm.getAllUsersList();
for(UserVO userVO: userList)
{
if(userVO.getUsername().equals(username))
{
if(userVO.getPassword().equals(password))
{
return "Logged In User :" + username;
}
}
}
return "You Are not a Valid User";
}
}
web.xml
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" id="WebApp_ID" version="2.5">
<display-name>FirstProject</display-name>
<welcome-file-list>
<welcome-file>index.html</welcome-file>
<welcome-file>index.htm</welcome-file>
<welcome-file>index.jsp</welcome-file>
<welcome-file>default.html</welcome-file>
<welcome-file>default.htm</welcome-file>
<welcome-file>default.jsp</welcome-file>
</welcome-file-list>
<servlet>
<servlet-name>ServletAdaptor</servlet-name>
<servlet-class>com.sun.jersey.server.impl.container.servlet.ServletAdaptor</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>REST</servlet-name>
<url-pattern>/rest/*</url-pattern>
</servlet-mapping>
</web-app>
I have written a simple RESTful web service in JAVA but when I run it using Run As --> Run on server option from Eclipse IDE, I am getting HTTP Status 404 – Not Found error. Please tell what can be the issue in my code?
Response:
web.xml
<?xml version="1.0" encoding="UTF-8"?> <!--?xml version="1.0" encoding="UTF-8"?-->
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" id="WebApp_ID" version="2.5">
<display-name>RESTfulWebServiceExample</display-name>
<servlet>
<servlet-name>Jersey REST Service</servlet-name>
<servlet-class>com.sun.jersey.spi.container.servlet.ServletContainer</servlet-class>
<init-param>
<param-name>com.sun.jersey.config.property.packages</param-name>
<param-value>org.arpit.javapostsforlearning.webservice</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>Jersey REST Service</servlet-name>
<url-pattern>/rest/*</url-pattern>
</servlet-mapping>
</web-app>
FeetToInchAndInchToFeetConversionService.java
package org.arpit.javapostsforlearning.webservice;
import javax.ws.rs.GET;
import javax.ws.rs.Path;
import javax.ws.rs.PathParam;
import javax.ws.rs.Produces;
import javax.ws.rs.core.MediaType;
#Path("ConversionService")
public class FeetToInchAndInchToFeetConversionService {
#GET
#Path("/InchToFeet/{i}")
#Produces(MediaType.TEXT_XML)
public String convertInchToFeet(#PathParam("i") int i) {
int inch=i;
double feet = 0;
feet =(double) inch/12;
return ""
+ "" + inch + ""
+ "" + feet + ""
+ "";
}
#Path("/FeetToInch/{f}")
#GET
#Produces(MediaType.TEXT_XML)
public String convertFeetToInch(#PathParam("f") int f) {
int inch=0;
int feet = f;
inch = 12*feet;
return ""
+ "" + feet + ""
+ "" + inch + ""
+ "";
}
}
You're trying to go to localhost:8080/RESTfulWebServiceExample when, according to your web.xml, RESTfulWebServiceExample is your display name. You need to go to localhost:8080/rest/ to hit your servlet context root (as defined in your servlet-mapping section of the web.xml).
I have created my very first basic rest api. Its working find and give me output in xml using this url
http://localhost:8080/Webservice/Test/RestClient
Now, I'm thinking If I want my api to ask server only specific data then I how can I use parameters for the same in api url.
Here is my little updated code
package RestClient;
//import javax.servlet.annotation.WebServlet;
import javax.ws.rs.GET;
import javax.ws.rs.Path;
import javax.ws.rs.PathParam;
import javax.ws.rs.Produces;
import javax.ws.rs.core.MediaType;
import javax.xml.bind.annotation.XmlRootElement;
#Path("/RestClient")
#XmlRootElement
public class Restwebclient {
#GET
#Produces(MediaType.TEXT_XML)
public String sayXMLHello(#PathParam("x") int x, #PathParam("y") int y) {
String output = "";
if (x == 1 && y == 1) {
output = "<?xml version=\"1.0\"?>" + "<hello> Hello Jersey" + "</hello>";
}
else if (x == 2 && y == 2) {
output = "<?xml version=\"1.0\"?>" + "<hello> Hello Jersey" + "</hello>";
}
return output;
}
}
And web.xml is here
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://xmlns.jcp.org/xml/ns/javaee" xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/javaee http://xmlns.jcp.org/xml/ns/javaee/web-app_3_1.xsd" version="3.1">
<display-name>Webservice</display-name>
<welcome-file-list>
<welcome-file>index.html</welcome-file>
<welcome-file>index.htm</welcome-file>
<welcome-file>index.jsp</welcome-file>
<welcome-file>default.html</welcome-file>
<welcome-file>default.htm</welcome-file>
<welcome-file>default.jsp</welcome-file>
</welcome-file-list>
<servlet>
<servlet-name>JAVA WS</servlet-name>
<servlet-class>org.glassfish.jersey.servlet.ServletContainer</servlet-class>
<init-param>
<param-name>jersey.config.server.provider.packages</param-name>
<param-value>RestClient</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>JAVA WS</servlet-name>
<url-pattern>/Test/*</url-pattern>
</servlet-mapping>
</web-app>
But when run the url passing parameters like this nothing comes up in output
http://localhost:8080/Webservice/Test/RestClient?x=1&y=1
Note: Expected output from above parameters in url should be first if condition
May I know What I'm missing to achieve this ?
You are sending parameters in query so you should use #QueryParam and not #PathParam. change method to:
public String sayXMLHello(#QueryParam("x") int x, #QueryParam("y") int y) {
Query Params:
http://localhost:8080/Webservice/Test/RestClient?x=1&y=1
Path Params need to change Path:
#Path("{x}/{y}/RestClient")
http://localhost:8080/Webservice/Test/1/1/RestClient
I met a surious problem when I want to develop an API to call an "exterior" method (this method is called "createClientNode" which is a simple request for neo4j).
Anyways, this is my web.xml :
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" id="WebApp_ID" version="2.5">
<display-name>API</display-name>
<servlet>
<servlet-name>jersey-serlvet</servlet-name>
<servlet-class>com.sun.jersey.spi.container.servlet.ServletContainer</servlet-class>
<init-param>
<param-name>jersey.config.server.provider.packages</param-name>
<param-value>API</param-value>
</init-param>
<init-param>
<param-name>com.sun.jersey.api.json.POJOMappingFeature</param-name>
<param-value>true</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>jersey-serlvet</servlet-name>
<url-pattern>/API/*</url-pattern>
</servlet-mapping>
</web-app>
And this my class :
package API;
import javax.ws.rs.DefaultValue;
import javax.ws.rs.GET;
import javax.ws.rs.POST;
import javax.ws.rs.Path;
import javax.ws.rs.PathParam;
import javax.ws.rs.Produces;
import javax.ws.rs.QueryParam;
import javax.ws.rs.core.MediaType;
import org.neo4j.graphdb.Node;
import function.query.weceipt.GraphManagement;
#Path("/API")
public class MyService {
#POST
#Path("/node")
#Produces({ MediaType.APPLICATION_JSON })
public Node createNode(#DefaultValue("default_id") #QueryParam("ID") String id) {
GraphManagement gm = new GraphManagement();
Node node = gm.createClientNode(id);
return node;
}
#GET
#Path("/node/{ID}")
#Produces({ MediaType.APPLICATION_JSON })
public Node getNode(#PathParam("ID") String id) {
GraphManagement gm = new GraphManagement();
Node node = gm.getClientNode(id);
return node;
}
#Path("/test")
#GET
#Produces(MediaType.TEXT_PLAIN)
public void afficher() {
System.out.println("test");
}
}
the error that I get is "the Servlet jersey-serlvet is not available".
I have the impression that I have-perhaps- a problem with a specific JAR or Tomcat, but I coudn't find the cause of this problem. So, can anyone help me please because I tried a loooong time with this!