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reversing an integer in java without a loop

This is an homework problem
Is there a way tor reverse a number in Java without using any loops? The only solution I can think of is reversing it using String and then casting it back to an integer.

If you want to reverse a number withour using any loop you can use Recursion method call. Following program is doing same
public static void reverseMethod(int number) {
if (number < 10) {
System.out.println(number);
return;
} else {
System.out.print(number % 10);
reverseMethod(number / 10);
}
}
public static void main(String args[]) {
int num = 4567;
reverseMethod(num);
}

Even if you were to reverse the number by casting it into a String, you would still need a loop if you want the program to work when having ints of different sizes. If I were to make a method to reverse a number but could not do it with loops, I would probably do it with recursion (which still uses loops indirectly). The code will look something like this:
class Main {
public static void main(String[] args) {
String input = "1234"; // or scanner to take in input can be implemented
System.out.println(Integer.parseInt(reverseInt(input)));
}
public static String reverseInt(String x) {
if (x.length() == 1) {
return x;
} else {
return x.substring(x.length() - 1) + reverseInt(x.substring(0, x.length() - 1));
}
}
}
Hope this helps!

By using reverse() of StringBuilder:
int number = 1234;
String str = String.valueOf(number);
StringBuilder builder = new StringBuilder(str);
builder.reverse();
number = Integer.parseInt(builder.toString());
System.out.println(number);
will print:
4321

if you want reverse method without loop and recursion then use this code
int a=12345;
int b,c,d,e,f;
b=a%10;
c=a%100/10;
d=a%1000/100;
e=a%10000/1000;
f=a%100000/10000;
System.out.println(b+","+c+","+d+","+e+","+f);

you can go like :
public int reverse(int x) {
String o = "";
if (x < 0) {
x *= -1;
String s = Integer.toString(x);
o += "-";
o += new StringBuilder(s).reverse().toString();
}
else {
String s = Integer.toString(x);
o += new StringBuilder(s).reverse().toString();
}
try {
int out = Integer.parseInt(o);
//System.out.println(s);
return out; }
catch (NumberFormatException e) {
return 0;
}
}

This is a solution using recursive method call
public class Tester{
public static int findReverse(int num, int temp){
if(num==0){
return temp;
}else if(num<10){
return temp*10 + num; //up to this is stopping condition
}else{
temp = temp*10 + num%10;
return findReverse(num/10, temp);
}
}
public static void main(String args[]){
int num = 120021;
int reverseNum = findReverse(num, 0);
System.out.println(reverseNum);
if(num == reverseNum)
System.out.println(num +" is a palindrome!");
else
System.out.println(num +" is not a palindrome!");
}
}

This will be fast.
static int reverseNum(int num) {
StringBuilder sb = new StringBuilder(String.valueOf(num));
sb.reverse();
return Integer.parseInt(sb.toString());
}

How to create dynamic array in java with unclear and diffrent inpu INDEXes?

I am new to Java and I needed dynamic Array ... all of thing I found that's for dynamic Array we should use "Array List' that's ok but when I want the indexes to be the power of X that given from input , I face ERORR ! .. the indexes are unclear and the are not specified what is the first or 2th power ! .... can anyone help me how solve it?
public static void main(String[] args) throws Exception {
Scanner Reader = new Scanner(System.in);
ArrayList<Float> Zarayeb = new ArrayList<Float>();
Float s ;
int m;
System.out.print("Add Count of equation Sentences : ");
int N = Reader.nextInt();
if (N == 0)
return;
for (int i = 0; i < N ; i++) {
s = Reader.nextFloat() ;
System.out.print("x^");
m = Reader.nextInt();
if (Zarayeb.get(m)== null)
Zarayeb.add(0 , s);
else{
Float l ;
l = Zarayeb.get(m);
Zarayeb.add (m , l+s);
}
if (i < N-1)
System.out.print("\r+");
}
System.out.print("Add Count of equation Sentences : ");
N = Reader.nextInt();
if (N == 0)
return;
for (int i = 0; i < N ; i++) {
s = Reader.nextFloat() ;
System.out.print("x^");
m = Reader.nextInt();
if (Zarayeb.get(m)== null)
Zarayeb.add(m , s);
else{
Float l ;
l = Zarayeb.get(m);
Zarayeb.add (m , l+s);
}
if (i < N-1)
System.out.print("\r+");
}
System.out.print("Enter X: ");
float X = Reader.nextFloat();
float Sum = 0;
for (int i = 0; i < Zarayeb.size();i++) {
Sum += (Zarayeb.get(i) * Math.pow(X,i));
}
System.out.println("\nThe final answer is : " + Sum);

First I refactored your code a bit to make sense of it:
Main class with the top level logic:
import java.util.Scanner;
public class Main {
private Scanner scanner;
private final Totals totals = new Totals();
public static void main(final String[] args) {
final Main app = new Main();
app.run();
}
private void run() {
scanner = new Scanner(System.in);
try {
readAndProcessEquationSentences();
} finally {
scanner.close();
}
}
private void readAndProcessEquationSentences() {
readSentences(true);
readSentences(false);
System.out.println("The final answer is : " + totals.calculateSum(readBaseInput()));
}
private void readSentences(final boolean useInitialLogic) {
System.out.print("Enter number of equation sentences:");
final int numberOfSentences = scanner.nextInt();
if (numberOfSentences == 0) {
throw new RuntimeException("No sentences");
}
for (int i = 0; i < numberOfSentences; i++) {
Sentence sentence = Sentence.read(scanner);
if (useInitialLogic) {
totals.addInitialSentence(sentence);
} else {
totals.addNextSentence(sentence);
}
if (i < numberOfSentences - 1) {
System.out.print("\r+");
}
}
}
private float readBaseInput() {
System.out.print("Enter base: ");
return scanner.nextFloat();
}
}
Sentence class which represents one equation sentence entered by the user:
import java.util.Scanner;
public class Sentence {
private Float x;
private int y;
public static Sentence read(final Scanner scanner) {
final Sentence sentence = new Sentence();
System.out.println("Enter x^y");
System.out.print("x=");
sentence.x = scanner.nextFloat();
System.out.println();
System.out.print("y=");
sentence.y = scanner.nextInt();
System.out.println();
return sentence;
}
public Float getX() {
return x;
}
public int getY() {
return y;
}
}
Totals class which keeps track of the totals:
import java.util.ArrayList;
import java.util.List;
public class Totals {
private final List<Float> values = new ArrayList<Float>();
public void addInitialSentence(final Sentence sentence) {
if (values.size() <= sentence.getY()) {
addToStart(sentence);
} else {
addToValue(sentence);
}
}
private void addToStart(final Sentence sentence) {
values.add(0, sentence.getX());
}
public void addNextSentence(final Sentence sentence) {
if (values.size() <= sentence.getY()) {
values.add(sentence.getY(), sentence.getX());
} else {
addToValue(sentence);
}
}
private void addToValue(final Sentence sentence) {
Float total = values.get(sentence.getY());
total = total + sentence.getX();
values.add(sentence.getY(), total);
}
public float calculateSum(final float base) {
float sum = 0;
for (int i = 0; i < values.size(); i++) {
sum += (values.get(i) * Math.pow(base, i));
}
return sum;
}
}
I don't have the foggiest idea what this is supposed to do. I named the variables according to this foggy idea.
You are letting the user input values in two separate loops, with a slightly different logic I called 'initial' and 'next'.
In the initial loop you were doing this:
if (Zarayeb.get(m) == null)
Zarayeb.add(0 , s);
In the next loop this:
if (Zarayeb.get(m) == null)
Zarayeb.add(m , s);
There are problems with this because the ArrayList.get(m) will throw an IndexOutOfBoundException if m is out or range. So I changed that to the equivalent of:
if (Zarayeb.size() <= m) {
....
}
However, in the 'next' case this still does not solve it. What should happen in the second loop when an 'm' value is entered for which no element yet exists in the ArrayList?
Why do you need to enter sentences in two loops?
What is the logic supposed to achieve exactly?

How to print the maximum valued path in a 2D array in Java?

I guess you all know the "strawberry" problem that some give you in job interviews, where you need to calculate the path between 2 corners of a 2D array that you can only move up or to the right and you have the calculate the maximum valued path.
I have a perfectly working code that does it in Recursion, but it's complexity is to high.
i also solved the problem in the "for loop" solution that does it in O(n^2) complexity.
but in this solution i just couldn't figure out a way to print the route like i did in the recursion solution.
This is my code (it is quite long to read here so i guess you should copy,compile and run).
look at the results of the recursion solution, BTW - The path needs to be from the left bottom corner to the right upper corner
I want to print the route the same way in the better solution:
public class Alg
{
public static void main(String args[])
{
String[] route = new String[100];
int[][]array = {{4,-2,3,6}
,{9,10,-4,1}
,{-1,2,1,4}
,{0,3,7,-3}};
String[][] route2 = new String[array.length][array[0].length];
int max = recursionAlg(array,array.length-1,0,route);
int max2 = loopAlg(array,array.length-1,0,route2);
System.out.println("The max food in the recursion solution is: "+max);
System.out.println("and the route is: ");
printRouteArray(route);
System.out.println("The max food in the loop solution: "+max2);
System.out.println("The route is: ");
//SHOULD PRINT HERE THE ROUTE
}
public static int loopAlg(int [][] arr,int x, int y, String[][] route)
{
int n=0;
int[][]count = new int[arr.length][arr[0].length];
for(int i = x; i>=0 ; i--)
{
for(int j = 0; j<arr[0].length; j++)
{
if (i==x && j==0) {count[i][j]=arr[i][j];}
else if (i == x) { count[i][j]=count[i][j-1]+arr[i][j];}
else if (j == 0) { count[i][j]=count[i+1][j]+arr[i][j]; }
else{
if (count[i][j-1]>count[i+1][j]) {count[i][j]=count[i][j-1]+arr[i][j];}
else { count[i][j]= count[i+1][j]+arr[i][j];}
}
}
}
return count[0][arr[0].length-1];
}
public static int recursionAlg(int [][] arr, int x, int y,String[] route)
{
return recursionAlg(arr,0,x,y,arr[0].length-1,route,0);
}
public static int recursionAlg(int[][]arr,int count,int x, int y, int max_y, String[] route, int i)
{
if (x == 0 && y == max_y) {return count;}
else if (x == 0) {
route[i]="Right";
return recursionAlg(arr,count+arr[x][y+1],x,y+1,max_y,route,i+1);
}
else if (y==max_y){
route[i]="Up";
return recursionAlg(arr,count+arr[x-1][y],x-1,y,max_y,route,i+1);
}
else if (recursionAlg(arr,count+arr[x-1][y],x-1,y,max_y,route,i+1)>recursionAlg(arr,count+arr[x][y+1],x,y+1,max_y,route,i+1))
{
route[i]="Up";
return recursionAlg(arr,count+arr[x-1][y],x-1,y,max_y,route,i+1);
}
else
{
route[i]="Right";
return recursionAlg(arr,count+arr[x][y+1],x,y+1,max_y,route,i+1);
}
}
public static void printRouteArray(String[] arr)
{
int i=0;
while (i<arr.length && (arr[i]=="Up" || arr[i]=="Right"))
{
System.out.print(arr[i]+"-->");
i++;
}
System.out.println("End");
}
}
Hope you can help, thanks!

You need another 2-dimensional array inside loopAlg that memorizes which step to take to come to this next entry for every entry in your initial 2-dim array. See the following code and https://ideone.com/kM8BAZ for a demo:
public static void main(String args[])
{
String[] route = new String[100];
int[][]array = {{4,-2,3,6}
,{9,10,-4,1}
,{-1,2,1,4}
,{0,3,7,-3}};
String[] route2 = new String[100];
int max = recursionAlg(array,array.length-1,0,route);
int max2 = loopAlg(array,array.length-1,0,route2);
System.out.println("The max food in the recursion solution is: "+max);
System.out.println("and the route is: ");
printRouteArray(route);
System.out.println("The max food in the loop solution: "+max2);
System.out.println("The route is: ");
printRouteArray(route2);
}
public enum Dirs {START, FROM_LEFT, FROM_DOWN};
public static int loopAlg(int [][] arr,int x, int y, String[] route)
{
int n=0;
int[][]count = new int[arr.length][arr[0].length];
Dirs[][] directions = new Dirs[arr.length][arr[0].length];
List<String> path = new ArrayList<String>();
for(int i = x; i>=0 ; i--)
{
for(int j = 0; j<arr[0].length; j++)
{
if (i==x && j==0) {count[i][j]=arr[i][j]; directions[i][j] = Dirs.START;}
else if (i == x) { count[i][j]=count[i][j-1]+arr[i][j]; directions[i][j] = Dirs.FROM_LEFT;}
else if (j == 0) { count[i][j]=count[i+1][j]+arr[i][j]; directions[i][j] = Dirs.FROM_DOWN;}
else{
if (count[i][j-1]>count[i+1][j]) {count[i][j]=count[i][j-1]+arr[i][j];directions[i][j] = Dirs.FROM_LEFT;}
else { count[i][j]= count[i+1][j]+arr[i][j];directions[i][j] = Dirs.FROM_DOWN;}
}
}
}
int i=0, j=arr[0].length-1;
while(directions[i][j]!= Dirs.START) {
if(directions[i][j] == Dirs.FROM_LEFT) {
path.add("Right");
j--;
}
else {
path.add("Up");
i++;
}
}
Collections.reverse(path);
i=0;
for(String part:path) {
route[i] = part;
i++;
}
return count[0][arr[0].length-1];
}

what is wrong with this code when dealing with large values of "long"?

I wrote an utility class to encode numbers in a custom numeral system with base N. As any self-respecting Java programmer I then wrote a unit test to check that the code works as expected (for any number I could throw at it).
It turned out, that for small numbers, it worked. However, for sufficiently large numbers, the tests failed.
The code:
public class EncodeUtil {
private String symbols;
private boolean isCaseSensitive;
private boolean useDefaultSymbols;
private int[] symbolLookup = new int[255];
public EncodeUtil() {
this(true);
}
public EncodeUtil(boolean isCaseSensitive) {
this.useDefaultSymbols = true;
setCaseSensitive(isCaseSensitive);
}
public EncodeUtil(boolean isCaseSensitive, String symbols) {
this.useDefaultSymbols = false;
setCaseSensitive(isCaseSensitive);
setSymbols(symbols);
}
public void setSymbols(String symbols) {
this.symbols = symbols;
fillLookupArray();
}
public void setCaseSensitive(boolean isCaseSensitive) {
this.isCaseSensitive = isCaseSensitive;
if (useDefaultSymbols) {
setSymbols(makeAlphaNumericString(isCaseSensitive));
}
}
private void fillLookupArray() {
//reset lookup array
for (int i = 0; i < symbolLookup.length; i++) {
symbolLookup[i] = -1;
}
for (int i = 0; i < symbols.length(); i++) {
char c = symbols.charAt(i);
if (symbolLookup[(int) c] == -1) {
symbolLookup[(int) c] = i;
} else {
throw new IllegalArgumentException("duplicate symbol:" + c);
}
}
}
private static String makeAlphaNumericString(boolean caseSensitive) {
StringBuilder sb = new StringBuilder(255);
int caseDiff = 'a' - 'A';
for (int i = 'A'; i <= 'Z'; i++) {
sb.append((char) i);
if (caseSensitive) sb.append((char) (i + caseDiff));
}
for (int i = '0'; i <= '9'; i++) {
sb.append((char) i);
}
return sb.toString();
}
public String encodeNumber(long decNum) {
return encodeNumber(decNum, 0);
}
public String encodeNumber(long decNum, int minLen) {
StringBuilder result = new StringBuilder(20);
long num = decNum;
long mod = 0;
int base = symbols.length();
do {
mod = num % base;
result.append(symbols.charAt((int) mod));
num = Math.round(Math.floor((num-mod) / base));
} while (num > 0);
if (result.length() < minLen) {
for (int i = result.length(); i < minLen; i++) {
result.append(symbols.charAt(0));
}
}
return result.toString();
}
public long decodeNumber(String encNum) {
if (encNum == null) return 0;
if (!isCaseSensitive) encNum = encNum.toUpperCase();
long result = 0;
int base = symbols.length();
long multiplier = 1;
for (int i = 0; i < encNum.length(); i++) {
char c = encNum.charAt(i);
int pos = symbolLookup[(int) c];
if (pos == -1) {
String debugValue = encNum.substring(0, i) + "[" + c + "]";
if (encNum.length()-1 > i) {
debugValue += encNum.substring(i + 1);
}
throw new IllegalArgumentException(
"invalid symbol '" + c + "' at position "
+ (i+1) + ": " + debugValue);
} else {
result += pos * multiplier;
multiplier = multiplier * base;
}
}
return result;
}
#Override
public String toString() {
return symbols;
}
}
The test:
public class EncodeUtilTest {
#Test
public void testRoundTrip() throws Exception {
//for some reason, numbers larger than this range will not be decoded correctly
//maybe some bug in JVM with arithmetic with long values?
//tried also BigDecimal, didn't make any difference
//anyway, it is highly improbable that we ever need such large numbers
long value = 288230376151711743L;
test(value, new EncodeUtil());
test(value, new EncodeUtil(false));
test(value, new EncodeUtil(true, "1234567890qwertyuiopasdfghjklzxcvbnm"));
}
#Test
public void testRoundTripMax() throws Exception {
//this will fail, see above
test(Long.MAX_VALUE, new EncodeUtil());
}
#Test
public void testRoundTripGettingCloserToMax() throws Exception {
//here we test different values, getting closer to Long.MAX_VALUE
//this will fail, see above
EncodeUtil util = new EncodeUtil();
for (long i = 1000; i > 0; i--) {
System.out.println(i);
test(Long.MAX_VALUE / i, util);
}
}
private void test(long number, EncodeUtil util) throws Exception {
String encoded = util.encodeNumber(number);
long result = util.decodeNumber(encoded);
long diff = number - result;
//System.out.println(number + " = " + encoded + " diff " + diff);
assertEquals("original=" + number + ", result=" + result + ", encoded=" + encoded, 0, diff);
}
}
Any ideas why things start failing when the values get large? I also tried BigInteger, but it did not seem to make a difference.

You're using floating point maths in your encodeNumber method, which makes your code rely on the precision of the double type.
Replacing
num = Math.round(Math.floor((num-mod) / base));
with
num = (num - mod) / base;
Makes the tests pass. Actually
num = num / base;
Should work just as well (thought experiment: what is 19 / 10 when / is integer division?).

You have a conversion to double in your code, which could be generating strange results for large values.
num = Math.round(Math.floor((num-mod) / base));
that would be my first port of call.

Uva's 3n+1 problem

I'm solving Uva's 3n+1 problem and I don't get why the judge is rejecting my answer. The time limit hasn't been exceeded and the all test cases I've tried have run correctly so far.
import java.io.*;
public class NewClass{
/**
* #param args the command line arguments
*/
public static void main(String[] args) throws IOException {
int maxCounter= 0;
int input;
int lowerBound;
int upperBound;
int counter;
int numberOfCycles;
int maxCycles= 0;
int lowerInt;
BufferedReader consoleInput = new BufferedReader(new InputStreamReader(System.in));
String line = consoleInput.readLine();
String [] splitted = line.split(" ");
lowerBound = Integer.parseInt(splitted[0]);
upperBound = Integer.parseInt(splitted[1]);
int [] recentlyused = new int[1000001];
if (lowerBound > upperBound )
{
int h = upperBound;
upperBound = lowerBound;
lowerBound = h;
}
lowerInt = lowerBound;
while (lowerBound <= upperBound)
{
counter = lowerBound;
numberOfCycles = 0;
if (recentlyused[counter] == 0)
{
while ( counter != 1 )
{
if (recentlyused[counter] != 0)
{
numberOfCycles = recentlyused[counter] + numberOfCycles;
counter = 1;
}
else
{
if (counter % 2 == 0)
{
counter = counter /2;
}
else
{
counter = 3*counter + 1;
}
numberOfCycles++;
}
}
}
else
{
numberOfCycles = recentlyused[counter] + numberOfCycles;
counter = 1;
}
recentlyused[lowerBound] = numberOfCycles;
if (numberOfCycles > maxCycles)
{
maxCycles = numberOfCycles;
}
lowerBound++;
}
System.out.println(lowerInt +" "+ upperBound+ " "+ (maxCycles+1));
}
}

Are you making sure to accept the entire input? It looks like your program terminates after reading only one line, and then processing one line. You need to be able to accept the entire sample input at once.

I faced the same problem. The following changes worked for me:
Changed the class name to Main.
Removed the public modifier from the class name.
The following code gave a compilation error:
public class Optimal_Parking_11364 {
public static void main(String[] args) {
...
}
}
Whereas after the changes, the following code was accepted:
class Main {
public static void main(String[] args) {
...
}
}
This was a very very simple program. Hopefully, the same trick will also work for more complex programs.

If I understand correctly you are using a memoizing approach. You create a table where you store full results for all the elements you have already calculated so that you do not need to re-calculate results that you already know (calculated before).
The approach itself is not wrong, but there are a couple of things you must take into account. First, the input consists of a list of pairs, you are only processing the first pair. Then, you must take care of your memoizing table limits. You are assuming that all numbers you will hit fall in the range [1...1000001), but that is not true. For the input number 999999 (first odd number below the upper limit) the first operation will turn it into 3*n+1, which is way beyond the upper limit of the memoization table.
Some other things you may want to consider are halving the memoization table and only memorize odd numbers, since you can implement the divide by two operation almost free with bit operations (and checking for even-ness is also just one bit operation).

Did you make sure that the output was in the same order specified in the input. I see where you are swapping the input if the first input was higher than the second, but you also need to make sure that you don't alter the order it appears in the input when you print the results out.
ex.
Input
10 1
Output
10 1 20

If possible Please use this Java specification : to read input lines
http://online-judge.uva.es/problemset/data/p100.java.html
I think the most important thing in UVA judge is 1) Get the output Exactly same , No Extra Lines at the end or anywhere . 2) I am assuming , Never throw exception just return or break with No output for Outside boundary parameters.
3)Output is case sensitive 4)Output Parameters should Maintain Space as shown in problem
One possible solution based on above patterns is here
https://gist.github.com/4676999
/*
Problem URL: http://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&page=show_problem&problem=36
Home>Online Judge > submission Specifications
Sample code to read input is from : http://online-judge.uva.es/problemset/data/p100.java.html
Runtime : 1.068
*/
import java.io.*;
import java.util.*;
class Main
{
static String ReadLn (int maxLg) // utility function to read from stdin
{
byte lin[] = new byte [maxLg];
int lg = 0, car = -1;
String line = "";
try
{
while (lg < maxLg)
{
car = System.in.read();
if ((car < 0) || (car == '\n')) break;
lin [lg++] += car;
}
}
catch (IOException e)
{
return (null);
}
if ((car < 0) && (lg == 0)) return (null); // eof
return (new String (lin, 0, lg));
}
public static void main (String args[]) // entry point from OS
{
Main myWork = new Main(); // create a dinamic instance
myWork.Begin(); // the true entry point
}
void Begin()
{
String input;
StringTokenizer idata;
int a, b,max;
while ((input = Main.ReadLn (255)) != null)
{
idata = new StringTokenizer (input);
a = Integer.parseInt (idata.nextToken());
b = Integer.parseInt (idata.nextToken());
if (a<b){
max=work(a,b);
}else{
max=work(b,a);
}
System.out.println (a + " " + b + " " +max);
}
}
int work( int a , int b){
int max=0;
for ( int i=a;i<=b;i++){
int temp=process(i);
if (temp>max) max=temp;
}
return max;
}
int process (long n){
int count=1;
while(n!=1){
count++;
if (n%2==1){
n=n*3+1;
}else{
n=n>>1;
}
}
return count;
}
}

Please consider that the integers i and j must appear in the output in the same order in which they appeared in the input, so for:
10 1
You should print
10 1 20

package pandarium.java.preparing2topcoder;/*
* Main.java
* java program model for www.programming-challenges.com
*/
import java.io.*;
import java.util.*;
class Main implements Runnable{
static String ReadLn(int maxLg){ // utility function to read from stdin,
// Provided by Programming-challenges, edit for style only
byte lin[] = new byte [maxLg];
int lg = 0, car = -1;
String line = "";
try
{
while (lg < maxLg)
{
car = System.in.read();
if ((car < 0) || (car == '\n')) break;
lin [lg++] += car;
}
}
catch (IOException e)
{
return (null);
}
if ((car < 0) && (lg == 0)) return (null); // eof
return (new String (lin, 0, lg));
}
public static void main(String args[]) // entry point from OS
{
Main myWork = new Main(); // Construct the bootloader
myWork.run(); // execute
}
public void run() {
new myStuff().run();
}
}
class myStuff implements Runnable{
private String input;
private StringTokenizer idata;
private List<Integer> maxes;
public void run(){
String input;
StringTokenizer idata;
int a, b,max=Integer.MIN_VALUE;
while ((input = Main.ReadLn (255)) != null)
{
max=Integer.MIN_VALUE;
maxes=new ArrayList<Integer>();
idata = new StringTokenizer (input);
a = Integer.parseInt (idata.nextToken());
b = Integer.parseInt (idata.nextToken());
System.out.println(a + " " + b + " "+max);
}
}
private static int getCyclesCount(long counter){
int cyclesCount=0;
while (counter!=1)
{
if(counter%2==0)
counter=counter>>1;
else
counter=counter*3+1;
cyclesCount++;
}
cyclesCount++;
return cyclesCount;
}
// You can insert more classes here if you want.
}

This solution gets accepted within 0.5s. I had to remove the package modifier.
import java.util.*;
public class Main {
static Map<Integer, Integer> map = new HashMap<>();
private static int f(int N) {
if (N == 1) {
return 1;
}
if (map.containsKey(N)) {
return map.get(N);
}
if (N % 2 == 0) {
N >>= 1;
map.put(N, f(N));
return 1 + map.get(N);
} else {
N = 3*N + 1;
map.put(N, f(N) );
return 1 + map.get(N);
}
}
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
try {
while(scanner.hasNextLine()) {
int i = scanner.nextInt();
int j = scanner.nextInt();
int maxx = 0;
if (i <= j) {
for(int m = i; m <= j; m++) {
maxx = Math.max(Main.f(m), maxx);
}
} else {
for(int m = j; m <= i; m++) {
maxx = Math.max(Main.f(m), maxx);
}
}
System.out.println(i + " " + j + " " + maxx);
}
System.exit(0);
} catch (Exception e) {
}
}
}