Related
To be specific, I was trying this code:
package hello;
public class Hello {
Clock clock = new Clock();
public static void main(String args[]) {
clock.sayTime();
}
}
But it gave the error
Cannot access non-static field in static method main
So I changed the declaration of clock to this:
static Clock clock = new Clock();
And it worked. What does it mean to put that keyword before the declaration? What exactly will it do and/or restrict in terms of what can be done to that object?
static members belong to the class instead of a specific instance.
It means that only one instance of a static field exists[1] even if you create a million instances of the class or you don't create any. It will be shared by all instances.
Since static methods also do not belong to a specific instance, they can't refer to instance members. In the example given, main does not know which instance of the Hello class (and therefore which instance of the Clock class) it should refer to. static members can only refer to static members. Instance members can, of course access static members.
Side note: Of course, static members can access instance members through an object reference.
Example:
public class Example {
private static boolean staticField;
private boolean instanceField;
public static void main(String[] args) {
// a static method can access static fields
staticField = true;
// a static method can access instance fields through an object reference
Example instance = new Example();
instance.instanceField = true;
}
[1]: Depending on the runtime characteristics, it can be one per ClassLoader or AppDomain or thread, but that is beside the point.
It means that there is only one instance of "clock" in Hello, not one per each separate instance of the "Hello" class, or more-so, it means that there will be one commonly shared "clock" reference among all instances of the "Hello" class.
So if you were to do a "new Hello" anywhere in your code:
A- in the first scenario (before the change, without using "static"), it would make a new clock every time a "new Hello" is called, but
B- in the second scenario (after the change, using "static"), every "new Hello" instance would still share and use the initial and same "clock" reference first created.
Unless you needed "clock" somewhere outside of main, this would work just as well:
package hello;
public class Hello
{
public static void main(String args[])
{
Clock clock=new Clock();
clock.sayTime();
}
}
The static keyword means that something (a field, method or nested class) is related to the type rather than any particular instance of the type. So for example, one calls Math.sin(...) without any instance of the Math class, and indeed you can't create an instance of the Math class.
For more information, see the relevant bit of Oracle's Java Tutorial.
Sidenote
Java unfortunately allows you to access static members as if they were instance members, e.g.
// Bad code!
Thread.currentThread().sleep(5000);
someOtherThread.sleep(5000);
That makes it look as if sleep is an instance method, but it's actually a static method - it always makes the current thread sleep. It's better practice to make this clear in the calling code:
// Clearer
Thread.sleep(5000);
The static keyword in Java means that the variable or function is shared between all instances of that class as it belongs to the type, not the actual objects themselves.
So if you have a variable: private static int i = 0; and you increment it (i++) in one instance, the change will be reflected in all instances. i will now be 1 in all instances.
Static methods can be used without instantiating an object.
Basic usage of static members...
public class Hello
{
// value / method
public static String staticValue;
public String nonStaticValue;
}
class A
{
Hello hello = new Hello();
hello.staticValue = "abc";
hello.nonStaticValue = "xyz";
}
class B
{
Hello hello2 = new Hello(); // here staticValue = "abc"
hello2.staticValue; // will have value of "abc"
hello2.nonStaticValue; // will have value of null
}
That's how you can have values shared in all class members without sending class instance Hello to other class. And whit static you don't need to create class instance.
Hello hello = new Hello();
hello.staticValue = "abc";
You can just call static values or methods by class name:
Hello.staticValue = "abc";
Static means that you don't have to create an instance of the class to use the methods or variables associated with the class. In your example, you could call:
Hello.main(new String[]()) //main(...) is declared as a static function in the Hello class
directly, instead of:
Hello h = new Hello();
h.main(new String[]()); //main(...) is a non-static function linked with the "h" variable
From inside a static method (which belongs to a class) you cannot access any members which are not static, since their values depend on your instantiation of the class. A non-static Clock object, which is an instance member, would have a different value/reference for each instance of your Hello class, and therefore you could not access it from the static portion of the class.
Static in Java:
Static is a Non Access Modifier.
The static keyword belongs to the class than instance of the class.
can be used to attach a Variable or Method to a Class.
Static keyword CAN be used with:
Method
Variable
Class nested within another Class
Initialization Block
CAN'T be used with:
Class (Not Nested)
Constructor
Interfaces
Method Local Inner Class(Difference then nested class)
Inner Class methods
Instance Variables
Local Variables
Example:
Imagine the following example which has an instance variable named count which in incremented in the constructor:
package pkg;
class StaticExample {
int count = 0;// will get memory when instance is created
StaticExample() {
count++;
System.out.println(count);
}
public static void main(String args[]) {
StaticExample c1 = new StaticExample();
StaticExample c2 = new StaticExample();
StaticExample c3 = new StaticExample();
}
}
Output:
1 1 1
Since instance variable gets the memory at the time of object creation, each object will have the copy of the instance variable, if it is incremented, it won't reflect to other objects.
Now if we change the instance variable count to a static one then the program will produce different output:
package pkg;
class StaticExample {
static int count = 0;// will get memory when instance is created
StaticExample() {
count++;
System.out.println(count);
}
public static void main(String args[]) {
StaticExample c1 = new StaticExample();
StaticExample c2 = new StaticExample();
StaticExample c3 = new StaticExample();
}
}
Output:
1 2 3
In this case static variable will get the memory only once, if any object changes the value of the static variable, it will retain its value.
Static with Final:
The global variable which is declared as final and static remains unchanged for the whole execution. Because, Static members are stored in the class memory and they are loaded only once in the whole execution. They are common to all objects of the class. If you declare static variables as final, any of the objects can’t change their value as it is final. Therefore, variables declared as final and static are sometimes referred to as Constants. All fields of interfaces are referred as constants, because they are final and static by default.
Picture Resource : Final Static
To add to existing answers, let me try with a picture:
An interest rate of 2% is applied to ALL savings accounts. Hence it is static.
A balance should be individual, so it is not static.
This discussion has so far ignored classloader considerations. Strictly speaking, Java static fields are shared between all instances of a class for a given classloader.
A field can be assigned to either the class or an instance of a class. By default fields are instance variables. By using static the field becomes a class variable, thus there is one and only one clock. If you make a changes in one place, it's visible everywhere. Instance varables are changed independently of one another.
In Java, the static keyword can be simply regarded as indicating the following:
"without regard or relationship to any particular instance"
If you think of static in this way, it becomes easier to understand its use in the various contexts in which it is encountered:
A static field is a field that belongs to the class rather than to any particular instance
A static method is a method that has no notion of this; it is defined on the class and doesn't know about any particular instance of that class unless a reference is passed to it
A static member class is a nested class without any notion or knowledge of an instance of its enclosing class (unless a reference to an enclosing class instance is passed to it)
The keyword static is used to denote a field or a method as belonging to the class itself and not to any particular instance. Using your code, if the object Clock is static, all of the instances of the Hello class will share this Clock data member (field) in common. If you make it non-static, each individual instance of Hello will have a unique Clock.
You added a main method to your class Hello so that you could run the code. The problem with that is that the main method is static and as such, it cannot refer to non-static fields or methods inside of it. You can resolve this in two ways:
Make all fields and methods of the Hello class static so that they could be referred to inside the main method. This is not a good thing to do (or the wrong reason to make a field and/or a method static)
Create an instance of your Hello class inside the main method and access all its fields and methods the way they were intended to be accessed and used in the first place.
For you, this means the following change to your code:
package hello;
public class Hello {
private Clock clock = new Clock();
public Clock getClock() {
return clock;
}
public static void main(String args[]) {
Hello hello = new Hello();
hello.getClock().sayTime();
}
}
static methods don't use any instance variables of the class they are defined in. A very good explanation of the difference can be found on this page
I have developed a liking for static methods (only, if possible) in "helper" classes.
The calling class need not create another member (instance) variable of the helper class. You just call the methods of the helper class. Also the helper class is improved because you no longer need a constructor, and you need no member (instance) variables.
There are probably other advantages.
Static makes the clock member a class member instead of an instance member. Without the static keyword you would need to create an instance of the Hello class (which has a clock member variable) - e.g.
Hello hello = new Hello();
hello.clock.sayTime();
//Here is an example
public class StaticClass
{
static int version;
public void printVersion() {
System.out.println(version);
}
}
public class MainClass
{
public static void main(String args[]) {
StaticClass staticVar1 = new StaticClass();
staticVar1.version = 10;
staticVar1.printVersion() // Output 10
StaticClass staticVar2 = new StaticClass();
staticVar2.printVersion() // Output 10
staticVar2.version = 20;
staticVar2.printVersion() // Output 20
staticVar1.printVersion() // Output 20
}
}
Can also think of static members not having a "this" pointer. They are shared among all instances.
Understanding Static concepts
public class StaticPractise1 {
public static void main(String[] args) {
StaticPractise2 staticPractise2 = new StaticPractise2();
staticPractise2.printUddhav(); //true
StaticPractise2.printUddhav(); /* false, because printUddhav() is although inside StaticPractise2, but it is where exactly depends on PC program counter on runtime. */
StaticPractise2.printUddhavsStatic1(); //true
staticPractise2.printUddhavsStatic1(); /*false, because, when staticPractise2 is blueprinted, it tracks everything other than static things and it organizes in its own heap. So, class static methods, object can't reference */
}
}
Second Class
public class StaticPractise2 {
public static void printUddhavsStatic1() {
System.out.println("Uddhav");
}
public void printUddhav() {
System.out.println("Uddhav");
}
}
main() is a static method which has two fundamental restrictions:
The static method cannot use a non-static data member or directly call non-static method.
this() and super() cannot be used in static context.
class A {
int a = 40; //non static
public static void main(String args[]) {
System.out.println(a);
}
}
Output: Compile Time Error
A question was asked here about the choice of the word 'static' for this concept. It was dup'd to this question, but I don't think the etymology has been clearly addressed. So...
It's due to keyword reuse, starting with C.
Consider data declarations in C (inside a function body):
void f() {
int foo = 1;
static int bar = 2;
:
}
The variable foo is created on the stack when the function is entered (and destroyed when the function terminates). By contrast, bar is always there, so it's 'static' in the sense of common English - it's not going anywhere.
Java, and similar languages, have the same concept for data. Data can either be allocated per instance of the class (per object) or once for the entire class. Since Java aims to have familiar syntax for C/C++ programmers, the 'static' keyword is appropriate here.
class C {
int foo = 1;
static int bar = 2;
:
}
Lastly, we come to methods.
class C {
int foo() { ... }
static int bar() { ... }
:
}
There is, conceptually speaking, an instance of foo() for every instance of class C. There is only one instance of bar() for the entire class C. This is parallel to the case we discussed for data, and therefore using 'static' is again a sensible choice, especially if you don't want to add more reserved keywords to your language.
Static Variables Can only be accessed only in static methods, so when we declare the static variables those getter and setter methods will be static methods
static methods is a class level we can access using class name
The following is example for Static Variables Getters And Setters:
public class Static
{
private static String owner;
private static int rent;
private String car;
public String getCar() {
return car;
}
public void setCar(String car) {
this.car = car;
}
public static int getRent() {
return rent;
}
public static void setRent(int rent) {
Static.rent = rent;
}
public static String getOwner() {
return owner;
}
public static void setOwner(String owner) {
Static.owner = owner;
}
}
A member in a Java program can be declared as static using the keyword “static” preceding its declaration/definition. When a member is declared static, then it essentially means that the member is shared by all the instances of a class without making copies of per instance.
Thus static is a non-class modifier used in Java and can be applied to the following members:
Variables
Methods
Blocks
Classes (more specifically, nested classes)
When a member is declared static, then it can be accessed without using an object. This means that before a class is instantiated, the static member is active and accessible. Unlike other non-static class members that cease to exist when the object of the class goes out of scope, the static member is still obviously active.
Static Variable in Java
A member variable of a class that is declared as static is called the Static Variable. It is also called as the “Class variable”. Once the variable is declared as static, memory is allocated only once and not every time when a class is instantiated. Hence you can access the static variable without a reference to an object.
The following Java program depicts the usage of Static variables:
class Main
{
// static variables a and b
static int a = 10;
static int b;
static void printStatic()
{
a = a /2;
b = a;
System.out.println("printStatic::Value of a : "+a + " Value of b :
"+b);
}
public static void main(String[] args)
{
printStatic();
b = a*5;
a++;
System.out.println("main::Value of a : "+a + " Value of b : "+b);
}
}
output::
printStatic::Value of a : Value of b : 5
main::Value of a : 6 Value of b : 25
In the above program, we have two static variables i.e. a and b. We modify these variables in a function “printStatic” as well as in “main”. Note that the values of these static variables are preserved across the functions even when the scope of the function ends. The output shows the values of variables in two functions.
Static Method
A method in Java is static when it is preceded by the keyword “static”.
Some points that you need to remember about the static method include:
A static method belongs to the class as against other non-static
methods that are invoked using the instance of a class.
To invoke a static method, you don’t need a class object.
The static data members of the class are accessible to the static
method. The static method can even change the values of the static
data member.
A static method cannot have a reference to ‘this’ or ‘super’ members.
Even if a static method tries to refer them, it will be a compiler
error.
Just like static data, the static method can also call other static
methods. A static method cannot refer to non-static data members or
variables and cannot call non-static methods too.
The following program shows the implementation of the static method in Java:
class Main
{
// static method
static void static_method()
{
System.out.println("Static method in Java...called without any
object");
}
public static void main(String[] args)
{
static_method();
}
}
output:
Static method in Java...called without any object
Static Block In Java
Just as you have function blocks in programming languages like C++, C#, etc. in Java also, there is a special block called “static” block that usually includes a block of code related to static data.
This static block is executed at the moment when the first object of the class is created (precisely at the time of classloading) or when the static member inside the block is used.
The following program shows the usage of a static block.
class Main
{
static int sum = 0;
static int val1 = 5;
static int val2;
// static block
static {
sum = val1 + val2;
System.out.println("In static block, val1: " + val1 + " val2: "+
val2 + " sum:" + sum);
val2 = val1 * 3;
sum = val1 + val2;
}
public static void main(String[] args)
{
System.out.println("In main function, val1: " + val1 + " val2: "+ val2 + " sum:" + sum);
}
}
output:
In static block, val1: 5 val2: 0 sum:5
In main function, val1: val2: 15 sum:20
Static Class
In Java, you have static blocks, static methods, and even static variables. Hence it’s obvious that you can also have static classes. In Java, it is possible to have a class inside another class and this is called a Nested class. The class that encloses the nested class is called the Outer class.
In Java, although you can declare a nested class as Static it is not possible to have the outer class as Static.
Let’s now explore the static nested classes in Java.
Static Nested Class
As already mentioned, you can have a nested class in Java declared as static. The static nested class differs from the non-static nested class(inner class) in certain aspects as listed below.
Unlike the non-static nested class, the nested static class doesn’t need an outer class reference.
A static nested class can access only static members of the outer class as against the non-static classes that can access static as well as non-static members of the outer class.
An example of a static nested class is given below.
class Main{
private static String str = "SoftwareTestingHelp";
//Static nested class
static class NestedClass{
//non-static method
public void display() {
System.out.println("Static string in OuterClass: " + str);
}
}
public static void main(String args[])
{
Main.NestedClassobj = new Main.NestedClass();
obj.display();
}
}
output
Static string in OuterClass: SoftwareTestingHelp
I think this is how static keyword works in java.
To be specific, I was trying this code:
package hello;
public class Hello {
Clock clock = new Clock();
public static void main(String args[]) {
clock.sayTime();
}
}
But it gave the error
Cannot access non-static field in static method main
So I changed the declaration of clock to this:
static Clock clock = new Clock();
And it worked. What does it mean to put that keyword before the declaration? What exactly will it do and/or restrict in terms of what can be done to that object?
static members belong to the class instead of a specific instance.
It means that only one instance of a static field exists[1] even if you create a million instances of the class or you don't create any. It will be shared by all instances.
Since static methods also do not belong to a specific instance, they can't refer to instance members. In the example given, main does not know which instance of the Hello class (and therefore which instance of the Clock class) it should refer to. static members can only refer to static members. Instance members can, of course access static members.
Side note: Of course, static members can access instance members through an object reference.
Example:
public class Example {
private static boolean staticField;
private boolean instanceField;
public static void main(String[] args) {
// a static method can access static fields
staticField = true;
// a static method can access instance fields through an object reference
Example instance = new Example();
instance.instanceField = true;
}
[1]: Depending on the runtime characteristics, it can be one per ClassLoader or AppDomain or thread, but that is beside the point.
It means that there is only one instance of "clock" in Hello, not one per each separate instance of the "Hello" class, or more-so, it means that there will be one commonly shared "clock" reference among all instances of the "Hello" class.
So if you were to do a "new Hello" anywhere in your code:
A- in the first scenario (before the change, without using "static"), it would make a new clock every time a "new Hello" is called, but
B- in the second scenario (after the change, using "static"), every "new Hello" instance would still share and use the initial and same "clock" reference first created.
Unless you needed "clock" somewhere outside of main, this would work just as well:
package hello;
public class Hello
{
public static void main(String args[])
{
Clock clock=new Clock();
clock.sayTime();
}
}
The static keyword means that something (a field, method or nested class) is related to the type rather than any particular instance of the type. So for example, one calls Math.sin(...) without any instance of the Math class, and indeed you can't create an instance of the Math class.
For more information, see the relevant bit of Oracle's Java Tutorial.
Sidenote
Java unfortunately allows you to access static members as if they were instance members, e.g.
// Bad code!
Thread.currentThread().sleep(5000);
someOtherThread.sleep(5000);
That makes it look as if sleep is an instance method, but it's actually a static method - it always makes the current thread sleep. It's better practice to make this clear in the calling code:
// Clearer
Thread.sleep(5000);
The static keyword in Java means that the variable or function is shared between all instances of that class as it belongs to the type, not the actual objects themselves.
So if you have a variable: private static int i = 0; and you increment it (i++) in one instance, the change will be reflected in all instances. i will now be 1 in all instances.
Static methods can be used without instantiating an object.
Basic usage of static members...
public class Hello
{
// value / method
public static String staticValue;
public String nonStaticValue;
}
class A
{
Hello hello = new Hello();
hello.staticValue = "abc";
hello.nonStaticValue = "xyz";
}
class B
{
Hello hello2 = new Hello(); // here staticValue = "abc"
hello2.staticValue; // will have value of "abc"
hello2.nonStaticValue; // will have value of null
}
That's how you can have values shared in all class members without sending class instance Hello to other class. And whit static you don't need to create class instance.
Hello hello = new Hello();
hello.staticValue = "abc";
You can just call static values or methods by class name:
Hello.staticValue = "abc";
Static means that you don't have to create an instance of the class to use the methods or variables associated with the class. In your example, you could call:
Hello.main(new String[]()) //main(...) is declared as a static function in the Hello class
directly, instead of:
Hello h = new Hello();
h.main(new String[]()); //main(...) is a non-static function linked with the "h" variable
From inside a static method (which belongs to a class) you cannot access any members which are not static, since their values depend on your instantiation of the class. A non-static Clock object, which is an instance member, would have a different value/reference for each instance of your Hello class, and therefore you could not access it from the static portion of the class.
Static in Java:
Static is a Non Access Modifier.
The static keyword belongs to the class than instance of the class.
can be used to attach a Variable or Method to a Class.
Static keyword CAN be used with:
Method
Variable
Class nested within another Class
Initialization Block
CAN'T be used with:
Class (Not Nested)
Constructor
Interfaces
Method Local Inner Class(Difference then nested class)
Inner Class methods
Instance Variables
Local Variables
Example:
Imagine the following example which has an instance variable named count which in incremented in the constructor:
package pkg;
class StaticExample {
int count = 0;// will get memory when instance is created
StaticExample() {
count++;
System.out.println(count);
}
public static void main(String args[]) {
StaticExample c1 = new StaticExample();
StaticExample c2 = new StaticExample();
StaticExample c3 = new StaticExample();
}
}
Output:
1 1 1
Since instance variable gets the memory at the time of object creation, each object will have the copy of the instance variable, if it is incremented, it won't reflect to other objects.
Now if we change the instance variable count to a static one then the program will produce different output:
package pkg;
class StaticExample {
static int count = 0;// will get memory when instance is created
StaticExample() {
count++;
System.out.println(count);
}
public static void main(String args[]) {
StaticExample c1 = new StaticExample();
StaticExample c2 = new StaticExample();
StaticExample c3 = new StaticExample();
}
}
Output:
1 2 3
In this case static variable will get the memory only once, if any object changes the value of the static variable, it will retain its value.
Static with Final:
The global variable which is declared as final and static remains unchanged for the whole execution. Because, Static members are stored in the class memory and they are loaded only once in the whole execution. They are common to all objects of the class. If you declare static variables as final, any of the objects can’t change their value as it is final. Therefore, variables declared as final and static are sometimes referred to as Constants. All fields of interfaces are referred as constants, because they are final and static by default.
Picture Resource : Final Static
To add to existing answers, let me try with a picture:
An interest rate of 2% is applied to ALL savings accounts. Hence it is static.
A balance should be individual, so it is not static.
This discussion has so far ignored classloader considerations. Strictly speaking, Java static fields are shared between all instances of a class for a given classloader.
A field can be assigned to either the class or an instance of a class. By default fields are instance variables. By using static the field becomes a class variable, thus there is one and only one clock. If you make a changes in one place, it's visible everywhere. Instance varables are changed independently of one another.
In Java, the static keyword can be simply regarded as indicating the following:
"without regard or relationship to any particular instance"
If you think of static in this way, it becomes easier to understand its use in the various contexts in which it is encountered:
A static field is a field that belongs to the class rather than to any particular instance
A static method is a method that has no notion of this; it is defined on the class and doesn't know about any particular instance of that class unless a reference is passed to it
A static member class is a nested class without any notion or knowledge of an instance of its enclosing class (unless a reference to an enclosing class instance is passed to it)
The keyword static is used to denote a field or a method as belonging to the class itself and not to any particular instance. Using your code, if the object Clock is static, all of the instances of the Hello class will share this Clock data member (field) in common. If you make it non-static, each individual instance of Hello will have a unique Clock.
You added a main method to your class Hello so that you could run the code. The problem with that is that the main method is static and as such, it cannot refer to non-static fields or methods inside of it. You can resolve this in two ways:
Make all fields and methods of the Hello class static so that they could be referred to inside the main method. This is not a good thing to do (or the wrong reason to make a field and/or a method static)
Create an instance of your Hello class inside the main method and access all its fields and methods the way they were intended to be accessed and used in the first place.
For you, this means the following change to your code:
package hello;
public class Hello {
private Clock clock = new Clock();
public Clock getClock() {
return clock;
}
public static void main(String args[]) {
Hello hello = new Hello();
hello.getClock().sayTime();
}
}
static methods don't use any instance variables of the class they are defined in. A very good explanation of the difference can be found on this page
I have developed a liking for static methods (only, if possible) in "helper" classes.
The calling class need not create another member (instance) variable of the helper class. You just call the methods of the helper class. Also the helper class is improved because you no longer need a constructor, and you need no member (instance) variables.
There are probably other advantages.
Static makes the clock member a class member instead of an instance member. Without the static keyword you would need to create an instance of the Hello class (which has a clock member variable) - e.g.
Hello hello = new Hello();
hello.clock.sayTime();
//Here is an example
public class StaticClass
{
static int version;
public void printVersion() {
System.out.println(version);
}
}
public class MainClass
{
public static void main(String args[]) {
StaticClass staticVar1 = new StaticClass();
staticVar1.version = 10;
staticVar1.printVersion() // Output 10
StaticClass staticVar2 = new StaticClass();
staticVar2.printVersion() // Output 10
staticVar2.version = 20;
staticVar2.printVersion() // Output 20
staticVar1.printVersion() // Output 20
}
}
Can also think of static members not having a "this" pointer. They are shared among all instances.
Understanding Static concepts
public class StaticPractise1 {
public static void main(String[] args) {
StaticPractise2 staticPractise2 = new StaticPractise2();
staticPractise2.printUddhav(); //true
StaticPractise2.printUddhav(); /* false, because printUddhav() is although inside StaticPractise2, but it is where exactly depends on PC program counter on runtime. */
StaticPractise2.printUddhavsStatic1(); //true
staticPractise2.printUddhavsStatic1(); /*false, because, when staticPractise2 is blueprinted, it tracks everything other than static things and it organizes in its own heap. So, class static methods, object can't reference */
}
}
Second Class
public class StaticPractise2 {
public static void printUddhavsStatic1() {
System.out.println("Uddhav");
}
public void printUddhav() {
System.out.println("Uddhav");
}
}
main() is a static method which has two fundamental restrictions:
The static method cannot use a non-static data member or directly call non-static method.
this() and super() cannot be used in static context.
class A {
int a = 40; //non static
public static void main(String args[]) {
System.out.println(a);
}
}
Output: Compile Time Error
A question was asked here about the choice of the word 'static' for this concept. It was dup'd to this question, but I don't think the etymology has been clearly addressed. So...
It's due to keyword reuse, starting with C.
Consider data declarations in C (inside a function body):
void f() {
int foo = 1;
static int bar = 2;
:
}
The variable foo is created on the stack when the function is entered (and destroyed when the function terminates). By contrast, bar is always there, so it's 'static' in the sense of common English - it's not going anywhere.
Java, and similar languages, have the same concept for data. Data can either be allocated per instance of the class (per object) or once for the entire class. Since Java aims to have familiar syntax for C/C++ programmers, the 'static' keyword is appropriate here.
class C {
int foo = 1;
static int bar = 2;
:
}
Lastly, we come to methods.
class C {
int foo() { ... }
static int bar() { ... }
:
}
There is, conceptually speaking, an instance of foo() for every instance of class C. There is only one instance of bar() for the entire class C. This is parallel to the case we discussed for data, and therefore using 'static' is again a sensible choice, especially if you don't want to add more reserved keywords to your language.
Static Variables Can only be accessed only in static methods, so when we declare the static variables those getter and setter methods will be static methods
static methods is a class level we can access using class name
The following is example for Static Variables Getters And Setters:
public class Static
{
private static String owner;
private static int rent;
private String car;
public String getCar() {
return car;
}
public void setCar(String car) {
this.car = car;
}
public static int getRent() {
return rent;
}
public static void setRent(int rent) {
Static.rent = rent;
}
public static String getOwner() {
return owner;
}
public static void setOwner(String owner) {
Static.owner = owner;
}
}
A member in a Java program can be declared as static using the keyword “static” preceding its declaration/definition. When a member is declared static, then it essentially means that the member is shared by all the instances of a class without making copies of per instance.
Thus static is a non-class modifier used in Java and can be applied to the following members:
Variables
Methods
Blocks
Classes (more specifically, nested classes)
When a member is declared static, then it can be accessed without using an object. This means that before a class is instantiated, the static member is active and accessible. Unlike other non-static class members that cease to exist when the object of the class goes out of scope, the static member is still obviously active.
Static Variable in Java
A member variable of a class that is declared as static is called the Static Variable. It is also called as the “Class variable”. Once the variable is declared as static, memory is allocated only once and not every time when a class is instantiated. Hence you can access the static variable without a reference to an object.
The following Java program depicts the usage of Static variables:
class Main
{
// static variables a and b
static int a = 10;
static int b;
static void printStatic()
{
a = a /2;
b = a;
System.out.println("printStatic::Value of a : "+a + " Value of b :
"+b);
}
public static void main(String[] args)
{
printStatic();
b = a*5;
a++;
System.out.println("main::Value of a : "+a + " Value of b : "+b);
}
}
output::
printStatic::Value of a : Value of b : 5
main::Value of a : 6 Value of b : 25
In the above program, we have two static variables i.e. a and b. We modify these variables in a function “printStatic” as well as in “main”. Note that the values of these static variables are preserved across the functions even when the scope of the function ends. The output shows the values of variables in two functions.
Static Method
A method in Java is static when it is preceded by the keyword “static”.
Some points that you need to remember about the static method include:
A static method belongs to the class as against other non-static
methods that are invoked using the instance of a class.
To invoke a static method, you don’t need a class object.
The static data members of the class are accessible to the static
method. The static method can even change the values of the static
data member.
A static method cannot have a reference to ‘this’ or ‘super’ members.
Even if a static method tries to refer them, it will be a compiler
error.
Just like static data, the static method can also call other static
methods. A static method cannot refer to non-static data members or
variables and cannot call non-static methods too.
The following program shows the implementation of the static method in Java:
class Main
{
// static method
static void static_method()
{
System.out.println("Static method in Java...called without any
object");
}
public static void main(String[] args)
{
static_method();
}
}
output:
Static method in Java...called without any object
Static Block In Java
Just as you have function blocks in programming languages like C++, C#, etc. in Java also, there is a special block called “static” block that usually includes a block of code related to static data.
This static block is executed at the moment when the first object of the class is created (precisely at the time of classloading) or when the static member inside the block is used.
The following program shows the usage of a static block.
class Main
{
static int sum = 0;
static int val1 = 5;
static int val2;
// static block
static {
sum = val1 + val2;
System.out.println("In static block, val1: " + val1 + " val2: "+
val2 + " sum:" + sum);
val2 = val1 * 3;
sum = val1 + val2;
}
public static void main(String[] args)
{
System.out.println("In main function, val1: " + val1 + " val2: "+ val2 + " sum:" + sum);
}
}
output:
In static block, val1: 5 val2: 0 sum:5
In main function, val1: val2: 15 sum:20
Static Class
In Java, you have static blocks, static methods, and even static variables. Hence it’s obvious that you can also have static classes. In Java, it is possible to have a class inside another class and this is called a Nested class. The class that encloses the nested class is called the Outer class.
In Java, although you can declare a nested class as Static it is not possible to have the outer class as Static.
Let’s now explore the static nested classes in Java.
Static Nested Class
As already mentioned, you can have a nested class in Java declared as static. The static nested class differs from the non-static nested class(inner class) in certain aspects as listed below.
Unlike the non-static nested class, the nested static class doesn’t need an outer class reference.
A static nested class can access only static members of the outer class as against the non-static classes that can access static as well as non-static members of the outer class.
An example of a static nested class is given below.
class Main{
private static String str = "SoftwareTestingHelp";
//Static nested class
static class NestedClass{
//non-static method
public void display() {
System.out.println("Static string in OuterClass: " + str);
}
}
public static void main(String args[])
{
Main.NestedClassobj = new Main.NestedClass();
obj.display();
}
}
output
Static string in OuterClass: SoftwareTestingHelp
I think this is how static keyword works in java.
To be specific, I was trying this code:
package hello;
public class Hello {
Clock clock = new Clock();
public static void main(String args[]) {
clock.sayTime();
}
}
But it gave the error
Cannot access non-static field in static method main
So I changed the declaration of clock to this:
static Clock clock = new Clock();
And it worked. What does it mean to put that keyword before the declaration? What exactly will it do and/or restrict in terms of what can be done to that object?
static members belong to the class instead of a specific instance.
It means that only one instance of a static field exists[1] even if you create a million instances of the class or you don't create any. It will be shared by all instances.
Since static methods also do not belong to a specific instance, they can't refer to instance members. In the example given, main does not know which instance of the Hello class (and therefore which instance of the Clock class) it should refer to. static members can only refer to static members. Instance members can, of course access static members.
Side note: Of course, static members can access instance members through an object reference.
Example:
public class Example {
private static boolean staticField;
private boolean instanceField;
public static void main(String[] args) {
// a static method can access static fields
staticField = true;
// a static method can access instance fields through an object reference
Example instance = new Example();
instance.instanceField = true;
}
[1]: Depending on the runtime characteristics, it can be one per ClassLoader or AppDomain or thread, but that is beside the point.
It means that there is only one instance of "clock" in Hello, not one per each separate instance of the "Hello" class, or more-so, it means that there will be one commonly shared "clock" reference among all instances of the "Hello" class.
So if you were to do a "new Hello" anywhere in your code:
A- in the first scenario (before the change, without using "static"), it would make a new clock every time a "new Hello" is called, but
B- in the second scenario (after the change, using "static"), every "new Hello" instance would still share and use the initial and same "clock" reference first created.
Unless you needed "clock" somewhere outside of main, this would work just as well:
package hello;
public class Hello
{
public static void main(String args[])
{
Clock clock=new Clock();
clock.sayTime();
}
}
The static keyword means that something (a field, method or nested class) is related to the type rather than any particular instance of the type. So for example, one calls Math.sin(...) without any instance of the Math class, and indeed you can't create an instance of the Math class.
For more information, see the relevant bit of Oracle's Java Tutorial.
Sidenote
Java unfortunately allows you to access static members as if they were instance members, e.g.
// Bad code!
Thread.currentThread().sleep(5000);
someOtherThread.sleep(5000);
That makes it look as if sleep is an instance method, but it's actually a static method - it always makes the current thread sleep. It's better practice to make this clear in the calling code:
// Clearer
Thread.sleep(5000);
The static keyword in Java means that the variable or function is shared between all instances of that class as it belongs to the type, not the actual objects themselves.
So if you have a variable: private static int i = 0; and you increment it (i++) in one instance, the change will be reflected in all instances. i will now be 1 in all instances.
Static methods can be used without instantiating an object.
Basic usage of static members...
public class Hello
{
// value / method
public static String staticValue;
public String nonStaticValue;
}
class A
{
Hello hello = new Hello();
hello.staticValue = "abc";
hello.nonStaticValue = "xyz";
}
class B
{
Hello hello2 = new Hello(); // here staticValue = "abc"
hello2.staticValue; // will have value of "abc"
hello2.nonStaticValue; // will have value of null
}
That's how you can have values shared in all class members without sending class instance Hello to other class. And whit static you don't need to create class instance.
Hello hello = new Hello();
hello.staticValue = "abc";
You can just call static values or methods by class name:
Hello.staticValue = "abc";
Static means that you don't have to create an instance of the class to use the methods or variables associated with the class. In your example, you could call:
Hello.main(new String[]()) //main(...) is declared as a static function in the Hello class
directly, instead of:
Hello h = new Hello();
h.main(new String[]()); //main(...) is a non-static function linked with the "h" variable
From inside a static method (which belongs to a class) you cannot access any members which are not static, since their values depend on your instantiation of the class. A non-static Clock object, which is an instance member, would have a different value/reference for each instance of your Hello class, and therefore you could not access it from the static portion of the class.
Static in Java:
Static is a Non Access Modifier.
The static keyword belongs to the class than instance of the class.
can be used to attach a Variable or Method to a Class.
Static keyword CAN be used with:
Method
Variable
Class nested within another Class
Initialization Block
CAN'T be used with:
Class (Not Nested)
Constructor
Interfaces
Method Local Inner Class(Difference then nested class)
Inner Class methods
Instance Variables
Local Variables
Example:
Imagine the following example which has an instance variable named count which in incremented in the constructor:
package pkg;
class StaticExample {
int count = 0;// will get memory when instance is created
StaticExample() {
count++;
System.out.println(count);
}
public static void main(String args[]) {
StaticExample c1 = new StaticExample();
StaticExample c2 = new StaticExample();
StaticExample c3 = new StaticExample();
}
}
Output:
1 1 1
Since instance variable gets the memory at the time of object creation, each object will have the copy of the instance variable, if it is incremented, it won't reflect to other objects.
Now if we change the instance variable count to a static one then the program will produce different output:
package pkg;
class StaticExample {
static int count = 0;// will get memory when instance is created
StaticExample() {
count++;
System.out.println(count);
}
public static void main(String args[]) {
StaticExample c1 = new StaticExample();
StaticExample c2 = new StaticExample();
StaticExample c3 = new StaticExample();
}
}
Output:
1 2 3
In this case static variable will get the memory only once, if any object changes the value of the static variable, it will retain its value.
Static with Final:
The global variable which is declared as final and static remains unchanged for the whole execution. Because, Static members are stored in the class memory and they are loaded only once in the whole execution. They are common to all objects of the class. If you declare static variables as final, any of the objects can’t change their value as it is final. Therefore, variables declared as final and static are sometimes referred to as Constants. All fields of interfaces are referred as constants, because they are final and static by default.
Picture Resource : Final Static
To add to existing answers, let me try with a picture:
An interest rate of 2% is applied to ALL savings accounts. Hence it is static.
A balance should be individual, so it is not static.
This discussion has so far ignored classloader considerations. Strictly speaking, Java static fields are shared between all instances of a class for a given classloader.
A field can be assigned to either the class or an instance of a class. By default fields are instance variables. By using static the field becomes a class variable, thus there is one and only one clock. If you make a changes in one place, it's visible everywhere. Instance varables are changed independently of one another.
In Java, the static keyword can be simply regarded as indicating the following:
"without regard or relationship to any particular instance"
If you think of static in this way, it becomes easier to understand its use in the various contexts in which it is encountered:
A static field is a field that belongs to the class rather than to any particular instance
A static method is a method that has no notion of this; it is defined on the class and doesn't know about any particular instance of that class unless a reference is passed to it
A static member class is a nested class without any notion or knowledge of an instance of its enclosing class (unless a reference to an enclosing class instance is passed to it)
The keyword static is used to denote a field or a method as belonging to the class itself and not to any particular instance. Using your code, if the object Clock is static, all of the instances of the Hello class will share this Clock data member (field) in common. If you make it non-static, each individual instance of Hello will have a unique Clock.
You added a main method to your class Hello so that you could run the code. The problem with that is that the main method is static and as such, it cannot refer to non-static fields or methods inside of it. You can resolve this in two ways:
Make all fields and methods of the Hello class static so that they could be referred to inside the main method. This is not a good thing to do (or the wrong reason to make a field and/or a method static)
Create an instance of your Hello class inside the main method and access all its fields and methods the way they were intended to be accessed and used in the first place.
For you, this means the following change to your code:
package hello;
public class Hello {
private Clock clock = new Clock();
public Clock getClock() {
return clock;
}
public static void main(String args[]) {
Hello hello = new Hello();
hello.getClock().sayTime();
}
}
static methods don't use any instance variables of the class they are defined in. A very good explanation of the difference can be found on this page
I have developed a liking for static methods (only, if possible) in "helper" classes.
The calling class need not create another member (instance) variable of the helper class. You just call the methods of the helper class. Also the helper class is improved because you no longer need a constructor, and you need no member (instance) variables.
There are probably other advantages.
Static makes the clock member a class member instead of an instance member. Without the static keyword you would need to create an instance of the Hello class (which has a clock member variable) - e.g.
Hello hello = new Hello();
hello.clock.sayTime();
//Here is an example
public class StaticClass
{
static int version;
public void printVersion() {
System.out.println(version);
}
}
public class MainClass
{
public static void main(String args[]) {
StaticClass staticVar1 = new StaticClass();
staticVar1.version = 10;
staticVar1.printVersion() // Output 10
StaticClass staticVar2 = new StaticClass();
staticVar2.printVersion() // Output 10
staticVar2.version = 20;
staticVar2.printVersion() // Output 20
staticVar1.printVersion() // Output 20
}
}
Can also think of static members not having a "this" pointer. They are shared among all instances.
Understanding Static concepts
public class StaticPractise1 {
public static void main(String[] args) {
StaticPractise2 staticPractise2 = new StaticPractise2();
staticPractise2.printUddhav(); //true
StaticPractise2.printUddhav(); /* false, because printUddhav() is although inside StaticPractise2, but it is where exactly depends on PC program counter on runtime. */
StaticPractise2.printUddhavsStatic1(); //true
staticPractise2.printUddhavsStatic1(); /*false, because, when staticPractise2 is blueprinted, it tracks everything other than static things and it organizes in its own heap. So, class static methods, object can't reference */
}
}
Second Class
public class StaticPractise2 {
public static void printUddhavsStatic1() {
System.out.println("Uddhav");
}
public void printUddhav() {
System.out.println("Uddhav");
}
}
main() is a static method which has two fundamental restrictions:
The static method cannot use a non-static data member or directly call non-static method.
this() and super() cannot be used in static context.
class A {
int a = 40; //non static
public static void main(String args[]) {
System.out.println(a);
}
}
Output: Compile Time Error
A question was asked here about the choice of the word 'static' for this concept. It was dup'd to this question, but I don't think the etymology has been clearly addressed. So...
It's due to keyword reuse, starting with C.
Consider data declarations in C (inside a function body):
void f() {
int foo = 1;
static int bar = 2;
:
}
The variable foo is created on the stack when the function is entered (and destroyed when the function terminates). By contrast, bar is always there, so it's 'static' in the sense of common English - it's not going anywhere.
Java, and similar languages, have the same concept for data. Data can either be allocated per instance of the class (per object) or once for the entire class. Since Java aims to have familiar syntax for C/C++ programmers, the 'static' keyword is appropriate here.
class C {
int foo = 1;
static int bar = 2;
:
}
Lastly, we come to methods.
class C {
int foo() { ... }
static int bar() { ... }
:
}
There is, conceptually speaking, an instance of foo() for every instance of class C. There is only one instance of bar() for the entire class C. This is parallel to the case we discussed for data, and therefore using 'static' is again a sensible choice, especially if you don't want to add more reserved keywords to your language.
Static Variables Can only be accessed only in static methods, so when we declare the static variables those getter and setter methods will be static methods
static methods is a class level we can access using class name
The following is example for Static Variables Getters And Setters:
public class Static
{
private static String owner;
private static int rent;
private String car;
public String getCar() {
return car;
}
public void setCar(String car) {
this.car = car;
}
public static int getRent() {
return rent;
}
public static void setRent(int rent) {
Static.rent = rent;
}
public static String getOwner() {
return owner;
}
public static void setOwner(String owner) {
Static.owner = owner;
}
}
A member in a Java program can be declared as static using the keyword “static” preceding its declaration/definition. When a member is declared static, then it essentially means that the member is shared by all the instances of a class without making copies of per instance.
Thus static is a non-class modifier used in Java and can be applied to the following members:
Variables
Methods
Blocks
Classes (more specifically, nested classes)
When a member is declared static, then it can be accessed without using an object. This means that before a class is instantiated, the static member is active and accessible. Unlike other non-static class members that cease to exist when the object of the class goes out of scope, the static member is still obviously active.
Static Variable in Java
A member variable of a class that is declared as static is called the Static Variable. It is also called as the “Class variable”. Once the variable is declared as static, memory is allocated only once and not every time when a class is instantiated. Hence you can access the static variable without a reference to an object.
The following Java program depicts the usage of Static variables:
class Main
{
// static variables a and b
static int a = 10;
static int b;
static void printStatic()
{
a = a /2;
b = a;
System.out.println("printStatic::Value of a : "+a + " Value of b :
"+b);
}
public static void main(String[] args)
{
printStatic();
b = a*5;
a++;
System.out.println("main::Value of a : "+a + " Value of b : "+b);
}
}
output::
printStatic::Value of a : Value of b : 5
main::Value of a : 6 Value of b : 25
In the above program, we have two static variables i.e. a and b. We modify these variables in a function “printStatic” as well as in “main”. Note that the values of these static variables are preserved across the functions even when the scope of the function ends. The output shows the values of variables in two functions.
Static Method
A method in Java is static when it is preceded by the keyword “static”.
Some points that you need to remember about the static method include:
A static method belongs to the class as against other non-static
methods that are invoked using the instance of a class.
To invoke a static method, you don’t need a class object.
The static data members of the class are accessible to the static
method. The static method can even change the values of the static
data member.
A static method cannot have a reference to ‘this’ or ‘super’ members.
Even if a static method tries to refer them, it will be a compiler
error.
Just like static data, the static method can also call other static
methods. A static method cannot refer to non-static data members or
variables and cannot call non-static methods too.
The following program shows the implementation of the static method in Java:
class Main
{
// static method
static void static_method()
{
System.out.println("Static method in Java...called without any
object");
}
public static void main(String[] args)
{
static_method();
}
}
output:
Static method in Java...called without any object
Static Block In Java
Just as you have function blocks in programming languages like C++, C#, etc. in Java also, there is a special block called “static” block that usually includes a block of code related to static data.
This static block is executed at the moment when the first object of the class is created (precisely at the time of classloading) or when the static member inside the block is used.
The following program shows the usage of a static block.
class Main
{
static int sum = 0;
static int val1 = 5;
static int val2;
// static block
static {
sum = val1 + val2;
System.out.println("In static block, val1: " + val1 + " val2: "+
val2 + " sum:" + sum);
val2 = val1 * 3;
sum = val1 + val2;
}
public static void main(String[] args)
{
System.out.println("In main function, val1: " + val1 + " val2: "+ val2 + " sum:" + sum);
}
}
output:
In static block, val1: 5 val2: 0 sum:5
In main function, val1: val2: 15 sum:20
Static Class
In Java, you have static blocks, static methods, and even static variables. Hence it’s obvious that you can also have static classes. In Java, it is possible to have a class inside another class and this is called a Nested class. The class that encloses the nested class is called the Outer class.
In Java, although you can declare a nested class as Static it is not possible to have the outer class as Static.
Let’s now explore the static nested classes in Java.
Static Nested Class
As already mentioned, you can have a nested class in Java declared as static. The static nested class differs from the non-static nested class(inner class) in certain aspects as listed below.
Unlike the non-static nested class, the nested static class doesn’t need an outer class reference.
A static nested class can access only static members of the outer class as against the non-static classes that can access static as well as non-static members of the outer class.
An example of a static nested class is given below.
class Main{
private static String str = "SoftwareTestingHelp";
//Static nested class
static class NestedClass{
//non-static method
public void display() {
System.out.println("Static string in OuterClass: " + str);
}
}
public static void main(String args[])
{
Main.NestedClassobj = new Main.NestedClass();
obj.display();
}
}
output
Static string in OuterClass: SoftwareTestingHelp
I think this is how static keyword works in java.
To be specific, I was trying this code:
package hello;
public class Hello {
Clock clock = new Clock();
public static void main(String args[]) {
clock.sayTime();
}
}
But it gave the error
Cannot access non-static field in static method main
So I changed the declaration of clock to this:
static Clock clock = new Clock();
And it worked. What does it mean to put that keyword before the declaration? What exactly will it do and/or restrict in terms of what can be done to that object?
static members belong to the class instead of a specific instance.
It means that only one instance of a static field exists[1] even if you create a million instances of the class or you don't create any. It will be shared by all instances.
Since static methods also do not belong to a specific instance, they can't refer to instance members. In the example given, main does not know which instance of the Hello class (and therefore which instance of the Clock class) it should refer to. static members can only refer to static members. Instance members can, of course access static members.
Side note: Of course, static members can access instance members through an object reference.
Example:
public class Example {
private static boolean staticField;
private boolean instanceField;
public static void main(String[] args) {
// a static method can access static fields
staticField = true;
// a static method can access instance fields through an object reference
Example instance = new Example();
instance.instanceField = true;
}
[1]: Depending on the runtime characteristics, it can be one per ClassLoader or AppDomain or thread, but that is beside the point.
It means that there is only one instance of "clock" in Hello, not one per each separate instance of the "Hello" class, or more-so, it means that there will be one commonly shared "clock" reference among all instances of the "Hello" class.
So if you were to do a "new Hello" anywhere in your code:
A- in the first scenario (before the change, without using "static"), it would make a new clock every time a "new Hello" is called, but
B- in the second scenario (after the change, using "static"), every "new Hello" instance would still share and use the initial and same "clock" reference first created.
Unless you needed "clock" somewhere outside of main, this would work just as well:
package hello;
public class Hello
{
public static void main(String args[])
{
Clock clock=new Clock();
clock.sayTime();
}
}
The static keyword means that something (a field, method or nested class) is related to the type rather than any particular instance of the type. So for example, one calls Math.sin(...) without any instance of the Math class, and indeed you can't create an instance of the Math class.
For more information, see the relevant bit of Oracle's Java Tutorial.
Sidenote
Java unfortunately allows you to access static members as if they were instance members, e.g.
// Bad code!
Thread.currentThread().sleep(5000);
someOtherThread.sleep(5000);
That makes it look as if sleep is an instance method, but it's actually a static method - it always makes the current thread sleep. It's better practice to make this clear in the calling code:
// Clearer
Thread.sleep(5000);
The static keyword in Java means that the variable or function is shared between all instances of that class as it belongs to the type, not the actual objects themselves.
So if you have a variable: private static int i = 0; and you increment it (i++) in one instance, the change will be reflected in all instances. i will now be 1 in all instances.
Static methods can be used without instantiating an object.
Basic usage of static members...
public class Hello
{
// value / method
public static String staticValue;
public String nonStaticValue;
}
class A
{
Hello hello = new Hello();
hello.staticValue = "abc";
hello.nonStaticValue = "xyz";
}
class B
{
Hello hello2 = new Hello(); // here staticValue = "abc"
hello2.staticValue; // will have value of "abc"
hello2.nonStaticValue; // will have value of null
}
That's how you can have values shared in all class members without sending class instance Hello to other class. And whit static you don't need to create class instance.
Hello hello = new Hello();
hello.staticValue = "abc";
You can just call static values or methods by class name:
Hello.staticValue = "abc";
Static means that you don't have to create an instance of the class to use the methods or variables associated with the class. In your example, you could call:
Hello.main(new String[]()) //main(...) is declared as a static function in the Hello class
directly, instead of:
Hello h = new Hello();
h.main(new String[]()); //main(...) is a non-static function linked with the "h" variable
From inside a static method (which belongs to a class) you cannot access any members which are not static, since their values depend on your instantiation of the class. A non-static Clock object, which is an instance member, would have a different value/reference for each instance of your Hello class, and therefore you could not access it from the static portion of the class.
Static in Java:
Static is a Non Access Modifier.
The static keyword belongs to the class than instance of the class.
can be used to attach a Variable or Method to a Class.
Static keyword CAN be used with:
Method
Variable
Class nested within another Class
Initialization Block
CAN'T be used with:
Class (Not Nested)
Constructor
Interfaces
Method Local Inner Class(Difference then nested class)
Inner Class methods
Instance Variables
Local Variables
Example:
Imagine the following example which has an instance variable named count which in incremented in the constructor:
package pkg;
class StaticExample {
int count = 0;// will get memory when instance is created
StaticExample() {
count++;
System.out.println(count);
}
public static void main(String args[]) {
StaticExample c1 = new StaticExample();
StaticExample c2 = new StaticExample();
StaticExample c3 = new StaticExample();
}
}
Output:
1 1 1
Since instance variable gets the memory at the time of object creation, each object will have the copy of the instance variable, if it is incremented, it won't reflect to other objects.
Now if we change the instance variable count to a static one then the program will produce different output:
package pkg;
class StaticExample {
static int count = 0;// will get memory when instance is created
StaticExample() {
count++;
System.out.println(count);
}
public static void main(String args[]) {
StaticExample c1 = new StaticExample();
StaticExample c2 = new StaticExample();
StaticExample c3 = new StaticExample();
}
}
Output:
1 2 3
In this case static variable will get the memory only once, if any object changes the value of the static variable, it will retain its value.
Static with Final:
The global variable which is declared as final and static remains unchanged for the whole execution. Because, Static members are stored in the class memory and they are loaded only once in the whole execution. They are common to all objects of the class. If you declare static variables as final, any of the objects can’t change their value as it is final. Therefore, variables declared as final and static are sometimes referred to as Constants. All fields of interfaces are referred as constants, because they are final and static by default.
Picture Resource : Final Static
To add to existing answers, let me try with a picture:
An interest rate of 2% is applied to ALL savings accounts. Hence it is static.
A balance should be individual, so it is not static.
This discussion has so far ignored classloader considerations. Strictly speaking, Java static fields are shared between all instances of a class for a given classloader.
A field can be assigned to either the class or an instance of a class. By default fields are instance variables. By using static the field becomes a class variable, thus there is one and only one clock. If you make a changes in one place, it's visible everywhere. Instance varables are changed independently of one another.
In Java, the static keyword can be simply regarded as indicating the following:
"without regard or relationship to any particular instance"
If you think of static in this way, it becomes easier to understand its use in the various contexts in which it is encountered:
A static field is a field that belongs to the class rather than to any particular instance
A static method is a method that has no notion of this; it is defined on the class and doesn't know about any particular instance of that class unless a reference is passed to it
A static member class is a nested class without any notion or knowledge of an instance of its enclosing class (unless a reference to an enclosing class instance is passed to it)
The keyword static is used to denote a field or a method as belonging to the class itself and not to any particular instance. Using your code, if the object Clock is static, all of the instances of the Hello class will share this Clock data member (field) in common. If you make it non-static, each individual instance of Hello will have a unique Clock.
You added a main method to your class Hello so that you could run the code. The problem with that is that the main method is static and as such, it cannot refer to non-static fields or methods inside of it. You can resolve this in two ways:
Make all fields and methods of the Hello class static so that they could be referred to inside the main method. This is not a good thing to do (or the wrong reason to make a field and/or a method static)
Create an instance of your Hello class inside the main method and access all its fields and methods the way they were intended to be accessed and used in the first place.
For you, this means the following change to your code:
package hello;
public class Hello {
private Clock clock = new Clock();
public Clock getClock() {
return clock;
}
public static void main(String args[]) {
Hello hello = new Hello();
hello.getClock().sayTime();
}
}
static methods don't use any instance variables of the class they are defined in. A very good explanation of the difference can be found on this page
I have developed a liking for static methods (only, if possible) in "helper" classes.
The calling class need not create another member (instance) variable of the helper class. You just call the methods of the helper class. Also the helper class is improved because you no longer need a constructor, and you need no member (instance) variables.
There are probably other advantages.
Static makes the clock member a class member instead of an instance member. Without the static keyword you would need to create an instance of the Hello class (which has a clock member variable) - e.g.
Hello hello = new Hello();
hello.clock.sayTime();
//Here is an example
public class StaticClass
{
static int version;
public void printVersion() {
System.out.println(version);
}
}
public class MainClass
{
public static void main(String args[]) {
StaticClass staticVar1 = new StaticClass();
staticVar1.version = 10;
staticVar1.printVersion() // Output 10
StaticClass staticVar2 = new StaticClass();
staticVar2.printVersion() // Output 10
staticVar2.version = 20;
staticVar2.printVersion() // Output 20
staticVar1.printVersion() // Output 20
}
}
Can also think of static members not having a "this" pointer. They are shared among all instances.
Understanding Static concepts
public class StaticPractise1 {
public static void main(String[] args) {
StaticPractise2 staticPractise2 = new StaticPractise2();
staticPractise2.printUddhav(); //true
StaticPractise2.printUddhav(); /* false, because printUddhav() is although inside StaticPractise2, but it is where exactly depends on PC program counter on runtime. */
StaticPractise2.printUddhavsStatic1(); //true
staticPractise2.printUddhavsStatic1(); /*false, because, when staticPractise2 is blueprinted, it tracks everything other than static things and it organizes in its own heap. So, class static methods, object can't reference */
}
}
Second Class
public class StaticPractise2 {
public static void printUddhavsStatic1() {
System.out.println("Uddhav");
}
public void printUddhav() {
System.out.println("Uddhav");
}
}
main() is a static method which has two fundamental restrictions:
The static method cannot use a non-static data member or directly call non-static method.
this() and super() cannot be used in static context.
class A {
int a = 40; //non static
public static void main(String args[]) {
System.out.println(a);
}
}
Output: Compile Time Error
A question was asked here about the choice of the word 'static' for this concept. It was dup'd to this question, but I don't think the etymology has been clearly addressed. So...
It's due to keyword reuse, starting with C.
Consider data declarations in C (inside a function body):
void f() {
int foo = 1;
static int bar = 2;
:
}
The variable foo is created on the stack when the function is entered (and destroyed when the function terminates). By contrast, bar is always there, so it's 'static' in the sense of common English - it's not going anywhere.
Java, and similar languages, have the same concept for data. Data can either be allocated per instance of the class (per object) or once for the entire class. Since Java aims to have familiar syntax for C/C++ programmers, the 'static' keyword is appropriate here.
class C {
int foo = 1;
static int bar = 2;
:
}
Lastly, we come to methods.
class C {
int foo() { ... }
static int bar() { ... }
:
}
There is, conceptually speaking, an instance of foo() for every instance of class C. There is only one instance of bar() for the entire class C. This is parallel to the case we discussed for data, and therefore using 'static' is again a sensible choice, especially if you don't want to add more reserved keywords to your language.
Static Variables Can only be accessed only in static methods, so when we declare the static variables those getter and setter methods will be static methods
static methods is a class level we can access using class name
The following is example for Static Variables Getters And Setters:
public class Static
{
private static String owner;
private static int rent;
private String car;
public String getCar() {
return car;
}
public void setCar(String car) {
this.car = car;
}
public static int getRent() {
return rent;
}
public static void setRent(int rent) {
Static.rent = rent;
}
public static String getOwner() {
return owner;
}
public static void setOwner(String owner) {
Static.owner = owner;
}
}
A member in a Java program can be declared as static using the keyword “static” preceding its declaration/definition. When a member is declared static, then it essentially means that the member is shared by all the instances of a class without making copies of per instance.
Thus static is a non-class modifier used in Java and can be applied to the following members:
Variables
Methods
Blocks
Classes (more specifically, nested classes)
When a member is declared static, then it can be accessed without using an object. This means that before a class is instantiated, the static member is active and accessible. Unlike other non-static class members that cease to exist when the object of the class goes out of scope, the static member is still obviously active.
Static Variable in Java
A member variable of a class that is declared as static is called the Static Variable. It is also called as the “Class variable”. Once the variable is declared as static, memory is allocated only once and not every time when a class is instantiated. Hence you can access the static variable without a reference to an object.
The following Java program depicts the usage of Static variables:
class Main
{
// static variables a and b
static int a = 10;
static int b;
static void printStatic()
{
a = a /2;
b = a;
System.out.println("printStatic::Value of a : "+a + " Value of b :
"+b);
}
public static void main(String[] args)
{
printStatic();
b = a*5;
a++;
System.out.println("main::Value of a : "+a + " Value of b : "+b);
}
}
output::
printStatic::Value of a : Value of b : 5
main::Value of a : 6 Value of b : 25
In the above program, we have two static variables i.e. a and b. We modify these variables in a function “printStatic” as well as in “main”. Note that the values of these static variables are preserved across the functions even when the scope of the function ends. The output shows the values of variables in two functions.
Static Method
A method in Java is static when it is preceded by the keyword “static”.
Some points that you need to remember about the static method include:
A static method belongs to the class as against other non-static
methods that are invoked using the instance of a class.
To invoke a static method, you don’t need a class object.
The static data members of the class are accessible to the static
method. The static method can even change the values of the static
data member.
A static method cannot have a reference to ‘this’ or ‘super’ members.
Even if a static method tries to refer them, it will be a compiler
error.
Just like static data, the static method can also call other static
methods. A static method cannot refer to non-static data members or
variables and cannot call non-static methods too.
The following program shows the implementation of the static method in Java:
class Main
{
// static method
static void static_method()
{
System.out.println("Static method in Java...called without any
object");
}
public static void main(String[] args)
{
static_method();
}
}
output:
Static method in Java...called without any object
Static Block In Java
Just as you have function blocks in programming languages like C++, C#, etc. in Java also, there is a special block called “static” block that usually includes a block of code related to static data.
This static block is executed at the moment when the first object of the class is created (precisely at the time of classloading) or when the static member inside the block is used.
The following program shows the usage of a static block.
class Main
{
static int sum = 0;
static int val1 = 5;
static int val2;
// static block
static {
sum = val1 + val2;
System.out.println("In static block, val1: " + val1 + " val2: "+
val2 + " sum:" + sum);
val2 = val1 * 3;
sum = val1 + val2;
}
public static void main(String[] args)
{
System.out.println("In main function, val1: " + val1 + " val2: "+ val2 + " sum:" + sum);
}
}
output:
In static block, val1: 5 val2: 0 sum:5
In main function, val1: val2: 15 sum:20
Static Class
In Java, you have static blocks, static methods, and even static variables. Hence it’s obvious that you can also have static classes. In Java, it is possible to have a class inside another class and this is called a Nested class. The class that encloses the nested class is called the Outer class.
In Java, although you can declare a nested class as Static it is not possible to have the outer class as Static.
Let’s now explore the static nested classes in Java.
Static Nested Class
As already mentioned, you can have a nested class in Java declared as static. The static nested class differs from the non-static nested class(inner class) in certain aspects as listed below.
Unlike the non-static nested class, the nested static class doesn’t need an outer class reference.
A static nested class can access only static members of the outer class as against the non-static classes that can access static as well as non-static members of the outer class.
An example of a static nested class is given below.
class Main{
private static String str = "SoftwareTestingHelp";
//Static nested class
static class NestedClass{
//non-static method
public void display() {
System.out.println("Static string in OuterClass: " + str);
}
}
public static void main(String args[])
{
Main.NestedClassobj = new Main.NestedClass();
obj.display();
}
}
output
Static string in OuterClass: SoftwareTestingHelp
I think this is how static keyword works in java.
In Java we use final keyword with variables to specify its values are not to be changed.
But I see that you can change the value in the constructor / methods of the class. Again, if the variable is static then it is a compilation error.
Here is the code:
import java.util.ArrayList;
import java.util.List;
class Test {
private final List foo;
public Test()
{
foo = new ArrayList();
foo.add("foo"); // Modification-1
}
public static void main(String[] args)
{
Test t = new Test();
t.foo.add("bar"); // Modification-2
System.out.println("print - " + t.foo);
}
}
Above code works fine and no errors.
Now change the variable as static:
private static final List foo;
Now it is a compilation error. How does this final really work?
This is a favorite interview question. With this questions, the interviewer tries to find out how well you understand the behavior of objects with respect to constructors, methods, class variables (static variables) and instance variables.
Now a days interviewers are asking another favorite question what is effectively final from java 1.8. I will explain in the end about this effectively final in java 1.8.
import java.util.ArrayList;
import java.util.List;
class Test {
private final List foo;
public Test() {
foo = new ArrayList();
foo.add("foo"); // Modification-1
}
public void setFoo(List foo) {
//this.foo = foo; Results in compile time error.
}
}
In the above case, we have defined a constructor for 'Test' and gave it a 'setFoo' method.
About constructor: Constructor can be invoked only one time per object creation by using the new keyword. You cannot invoke constructor multiple times, because constructor are not designed to do so.
About method: A method can be invoked as many times as you want (Even never) and the compiler knows it.
Scenario 1
private final List foo; // 1
foo is an instance variable. When we create Test class object then the instance variable foo, will be copied inside the object of Test class. If we assign foo inside the constructor, then the compiler knows that the constructor will be invoked only once, so there is no problem assigning it inside the constructor.
If we assign foo inside a method, the compiler knows that a method can be called multiple times, which means the value will have to be changed multiple times, which is not allowed for a final variable. So the compiler decides constructor is good choice! You can assign a value to a final variable only one time.
Scenario 2
private static final List foo = new ArrayList();
foo is now a static variable. When we create an instance of Test class, foo will not be copied to the object because foo is static. Now foo is not an independent property of each object. This is a property of Test class. But foo can be seen by multiple objects and if every object which is created by using the new keyword which will ultimately invoke the Test constructor which changes the value at the time of multiple object creation (Remember static foo is not copied in every object, but is shared between multiple objects.)
Scenario 3
t.foo.add("bar"); // Modification-2
Above Modification-2 is from your question. In the above case, you are not changing the first referenced object, but you are adding content inside foo which is allowed. Compiler complains if you try to assign a new ArrayList() to the foo reference variable.
Rule If you have initialized a final variable, then you cannot change it to refer to a different object. (In this case ArrayList)
final classes cannot be subclassed
final methods cannot be overridden. (This method is in superclass)
final methods can override. (Read this in grammatical way. This method is in a subclass)
Now let's see what is effectively final in java 1.8?
public class EffectivelyFinalDemo { //compile code with java 1.8
public void process() {
int thisValueIsFinalWithoutFinalKeyword = 10; //variable is effectively final
//to work without final keyword you should not reassign value to above variable like given below
thisValueIsFinalWithoutFinalKeyword = getNewValue(); // delete this line when I tell you.
class MethodLocalClass {
public void innerMethod() {
//below line is now showing compiler error like give below
//Local variable thisValueIsFinalWithoutFinalKeyword defined in an enclosing scope must be final or effectively final
System.out.println(thisValueIsFinalWithoutFinalKeyword); //on this line only final variables are allowed because this is method local class
// if you want to test effectively final is working without final keyword then delete line which I told you to delete in above program.
}
}
}
private int getNewValue() {
return 0;
}
}
Above program will throw error in java 1.7 or <1.8 if you do not use final keyword. Effectively final is a part of Method Local Inner classes. I know you would rarely use such effectively final in method local classes, but for interview we have to be prepared.
You are always allowed to initialize a final variable. The compiler makes sure that you can do it only once.
Note that calling methods on an object stored in a final variable has nothing to do with the semantics of final. In other words: final is only about the reference itself, and not about the contents of the referenced object.
Java has no concept of object immutability; this is achieved by carefully designing the object, and is a far-from-trivial endeavor.
Final keyword has a numerous way to use:
A final class cannot be subclassed.
A final method cannot be overridden by subclasses
A final variable can only be initialized once
Other usage:
When an anonymous inner class is defined within the body of a method,
all variables declared final in the scope of that method are
accessible from within the inner class
A static class variable will exist from the start of the JVM, and should be initialized in the class. The error message won't appear if you do this.
The final keyword can be interpreted in two different ways depending on what it's used on:
Value types: For ints, doubles etc, it will ensure that the value cannot change,
Reference types: For references to objects, final ensures that the reference will never change, meaning that it will always refer to the same object. It makes no guarantees whatsoever about the values inside the object being referred to staying the same.
As such, final List<Whatever> foo; ensures that foo always refers to the same list, but the contents of said list may change over time.
If you make foo static, you must initialize it in the class constructor (or inline where you define it) like the following examples.
Class constructor (not instance):
private static final List foo;
static
{
foo = new ArrayList();
}
Inline:
private static final List foo = new ArrayList();
The problem here is not how the final modifier works, but rather how the static modifier works.
The final modifier enforces an initialization of your reference by the time the call to your constructor completes (i.e. you must initialize it in the constructor).
When you initialize an attribute in-line, it gets initialized before the code you have defined for the constructor is run, so you get the following outcomes:
if foo is static, foo = new ArrayList() will be executed before the static{} constructor you have defined for your class is executed
if foo is not static, foo = new ArrayList() will be executed before your constructor is run
When you do not initilize an attribute in-line, the final modifier enforces that you initialize it and that you must do so in the constructor. If you also have a static modifier, the constructor you will have to initialize the attribute in is the class' initialization block : static{}.
The error you get in your code is from the fact that static{} is run when the class is loaded, before the time you instantiate an object of that class. Thus, you will have not initialized foo when the class is created.
Think of the static{} block as a constructor for an object of type Class. This is where you must do the initialization of your static final class attributes (if not done inline).
Side note:
The final modifier assures const-ness only for primitive types and references.
When you declare a final object, what you get is a final reference to that object, but the object itself is not constant.
What you are really achieving when declaring a final attribute is that, once you declare an object for your specific purpose (like the final List that you have declared), that and only that object will be used for that purpose: you will not be able to change List foo to another List, but you can still alter your List by adding/removing items (the List you are using will be the same, only with its contents altered).
This is a very good interview question. Sometimes they might even ask you what is the difference between a final object and immutable object.
1) When someone mentions a final object, it means that the reference cannot be changed, but its state(instance variables) can be changed.
2) An immutable object is one whose state can not be changed, but its reference can be changed.
Ex:
String x = new String("abc");
x = "BCG";
ref variable x can be changed to point a different string, but value of "abc" cannot be changed.
3) Instance variables(non static fields) are initialized when a constructor is called. So you can initialize values to you variables inside a constructor.
4) "But i see that you can change the value in the constructor/methods of the class". -- You cannot change it inside a method.
5) A static variable is initialized during class loading. So you cannot initialize inside a constructor, it has to be done even before it. So you need to assign values to a static variable during declaration itself.
The final keyword in java is used to restrict the user. The java final keyword can be used in many context. Final can be:
variable
method
class
The final keyword can be applied with the variables, a final variable that has no value, is called blank final variable or uninitialized final variable. It can be initialized in the constructor only. The blank final variable can be static also which will be initialized in the static block only.
Java final variable:
If you make any variable as final, you cannot change the value of final variable(It will be constant).
Example of final variable
There is a final variable speedlimit, we are going to change the value of this variable, but It can't be changed because final variable once assigned a value can never be changed.
class Bike9{
final int speedlimit=90;//final variable
void run(){
speedlimit=400; // this will make error
}
public static void main(String args[]){
Bike9 obj=new Bike9();
obj.run();
}
}//end of class
Java final class:
If you make any class as final, you cannot extend it.
Example of final class
final class Bike{}
class Honda1 extends Bike{ //cannot inherit from final Bike,this will make error
void run(){
System.out.println("running safely with 100kmph");
}
public static void main(String args[]){
Honda1 honda= new Honda();
honda.run();
}
}
Java final method:
If you make any method as final, you cannot override it.
Example of final method
(run() in Honda cannot override run() in Bike)
class Bike{
final void run(){System.out.println("running");}
}
class Honda extends Bike{
void run(){System.out.println("running safely with 100kmph");}
public static void main(String args[]){
Honda honda= new Honda();
honda.run();
}
}
shared from:
http://www.javatpoint.com/final-keyword
Worth to mention some straightforward definitions:
Classes/Methods
You can declare some or all of a class methods as final, in order to indicate that the method cannot be overridden by subclasses.
Variables
Once a final variable has been initialized, it always contains the same value.
final basically avoid overwrite/superscribe by anything (subclasses, variable "reassign"), depending on the case.
"A final variable can only be assigned once"
*Reflection* - "wowo wait, hold my beer".
Freeze of final fields happen in two scenarios:
End of constructor.
When reflection sets the field's value. (as many times as it wants to)
Let's break the law
public class HoldMyBeer
{
final int notSoFinal;
public HoldMyBeer()
{
notSoFinal = 1;
}
static void holdIt(HoldMyBeer beer, int yetAnotherFinalValue) throws Exception
{
Class<HoldMyBeer> cl = HoldMyBeer.class;
Field field = cl.getDeclaredField("notSoFinal");
field.setAccessible(true);
field.set(beer, yetAnotherFinalValue);
}
public static void main(String[] args) throws Exception
{
HoldMyBeer beer = new HoldMyBeer();
System.out.println(beer.notSoFinal);
holdIt(beer, 50);
System.out.println(beer.notSoFinal);
holdIt(beer, 100);
System.out.println(beer.notSoFinal);
holdIt(beer, 666);
System.out.println(beer.notSoFinal);
holdIt(beer, 8888);
System.out.println(beer.notSoFinal);
}
}
Output:
1
50
100
666
8888
The "final" field has been assigned 5 different "final" values (note the quotes). And it could keep being assigned different values over and over...
Why? Because reflection is like Chuck Norris, and if it wants to change the value of an initialized final field, it does. Some say he himself is the one that pushes the new values into the stack :
Code:
7: astore_1
11: aload_1
12: getfield
18: aload_1
19: bipush 50 //wait what
27: aload_1
28: getfield
34: aload_1
35: bipush 100 //come on...
43: aload_1
44: getfield
50: aload_1
51: sipush 666 //...you were supposed to be final...
60: aload_1
61: getfield
67: aload_1
68: sipush 8888 //ok i'm out whatever dude
77: aload_1
78: getfield
final is a reserved keyword in Java to restrict the user and it can be applied to member variables, methods, class and local variables. Final variables are often declared with the static keyword in Java and are treated as constants. For example:
public static final String hello = "Hello";
When we use the final keyword with a variable declaration, the value stored inside that variable cannot be changed latter.
For example:
public class ClassDemo {
private final int var1 = 3;
public ClassDemo() {
...
}
}
Note: A class declared as final cannot be extended or inherited (i.e, there cannot be a subclass of the super class). It is also good to note that methods declared as final cannot be overridden by subclasses.
Benefits of using the final keyword are addressed in this thread.
First of all, the place in your code where you are initializing (i.e. assigning for the first time) foo is here:
foo = new ArrayList();
foo is an object (with type List) so it is a reference type, not a value type (like int). As such, it holds a reference to a memory location (e.g. 0xA7D2A834) where your List elements are stored. Lines like this
foo.add("foo"); // Modification-1
do not change the value of foo (which, again, is just a reference to a memory location). Instead, they just add elements into that referenced memory location. To violate the final keyword, you would have to try to re-assign foo as follows again:
foo = new ArrayList();
That would give you a compilation error.
Now, with that out of the way, think about what happens when you add the static keyword.
When you do NOT have the static keyword, each object that instantiates the class has its own copy of foo. Therefore, the constructor assigns a value to a blank, fresh copy of the foo variable, which is perfectly fine.
However, when you DO have the static keyword, only one foo exists in memory that is associated with the class. If you were to create two or more objects, the constructor would be attempting to re-assign that one foo each time, violating the final keyword.
Suppose you have two moneyboxes, red and white. You assign these moneyboxes only two children and they are not allowed interchange their boxes. So You have red or white moneyboxes(final) you cannot modify the box but you can put money on your box.Nobody cares (Modification-2).
Read all the answers.
There is another user case where final keyword can be used i.e. in a method argument:
public void showCaseFinalArgumentVariable(final int someFinalInt){
someFinalInt = 9; // won't compile as the argument is final
}
Can be used for variable which should not be changed.
When you make it static final it should be initialized in a static initialization block
private static final List foo;
static {
foo = new ArrayList();
}
public Test()
{
// foo = new ArrayList();
foo.add("foo"); // Modification-1
}
The final keyword indicates that a variable may only be initialized once. In your code you are only performing one initialization of final so the terms are satisfied. This statement performs the lone initialization of foo. Note that final != immutable, it only means that the reference cannot change.
foo = new ArrayList();
When you declare foo as static final the variable must be initialized when the class is loaded and cannot rely on instantiation (aka call to constructor) to initialize foo since static fields must be available without an instance of a class. There is no guarantee that the constructor will have been called prior to using the static field.
When you execute your method under the static final scenario the Test class is loaded prior to instantiating t at this time there is no instantiation of foo meaning it has not been initialized so foo is set to the default for all objects which is null. At this point I assume your code throws a NullPointerException when you attempt to add an item to the list.
Since the final variable is non-static, it can be initialized in constructor. But if you make it static it can not be initialized by constructor (because constructors are not static).
Addition to list is not expected to stop by making list final. final just binds the reference to particular object. You are free to change the 'state' of that object, but not the object itself.
Following are different contexts where final is used.
Final variables A final variable can only be assigned once. If the variable is a reference, this means that the variable cannot be re-bound to reference another object.
class Main {
public static void main(String args[]){
final int i = 20;
i = 30; //Compiler Error:cannot assign a value to final variable i twice
}
}
final variable can be assigned value later (not compulsory to assigned a value when declared), but only once.
Final classes A final class cannot be extended (inherited)
final class Base { }
class Derived extends Base { } //Compiler Error:cannot inherit from final Base
public class Main {
public static void main(String args[]) {
}
}
Final methods A final method cannot be overridden by subclasses.
//Error in following program as we are trying to override a final method.
class Base {
public final void show() {
System.out.println("Base::show() called");
}
}
class Derived extends Base {
public void show() { //Compiler Error: show() in Derived cannot override
System.out.println("Derived::show() called");
}
}
public class Main {
public static void main(String[] args) {
Base b = new Derived();;
b.show();
}
}
I thought of writing an updated and in depth answer here.
final keyword can be used in several places.
classes
A final class means that no other class can extend that final class. When Java Run Time (JRE) knows an object reference is in type of a final class (say F), it knows that the value of that reference can only be in type of F.
Ex:
F myF;
myF = new F(); //ok
myF = someOther; //someOther cannot be in type of a child class of F.
//because F cannot be extended.
So when it executes any method of that object, that method doesn't need to be resolved at run time using a virtual table. i.e. run-time polymorphism cannot be applied. So the run time doesn't bother about that. Which means it saves processing time, which will improve performance.
methods
A final method of any class means that any child class extending that class cannot override that final method(s). So the run time behavior in this scenario is also quite same with the previous behavior I mentioned for classes.
fields, local variables, method parameters
If one specified any kind of above as final, it means that the value is already finalized, so the value cannot be changed.
Ex:
For fields, local parameters
final FinalClass fc = someFC; //need to assign straight away. otherwise compile error.
final FinalClass fc; //compile error, need assignment (initialization inside a constructor Ok, constructor can be called only once)
final FinalClass fc = new FinalClass(); //ok
fc = someOtherFC; //compile error
fc.someMethod(); //no problem
someOtherFC.someMethod(); //no problem
For method parameters
void someMethod(final String s){
s = someOtherString; //compile error
}
This simply means that value of the final reference value cannot be changed. i.e. only one initialization is allowed. In this scenario, in run time, since JRE knows that values cannot be changed, it loads all these finalized values (of final references) into L1 cache. Because it doesn't need to load back again and again from main memory. Otherwise it loads to L2 cache and does time to time loading from main memory. So it is also a performance improvement.
So in all above 3 scenarios, when we have not specified the final keyword in places we can use, we don't need to worry, compiler optimizations will do that for us. There are also lots of other things that compiler optimizations do for us. :)
Above all are correct. Further if you do not want others to create sub classes from your class, then declare your class as final. Then it becomes the leaf level of your class tree hierarchy that no one can extend it further. It is a good practice to avoid huge hierarchy of classes.
I can only say in answer to your question that in this case you can't change reference value of foo. You just simply put value into the same reference, that's why you can add value into the foo reference. This problem is occur you can't understand very well difference between reference value and primitive value. Reference value is also a value which store object address(this is value) in heap memory.
public static void main(String[] args)
{
Test t = new Test();
t.foo.add("bar"); // Modification-2
System.out.println("print - " + t.foo);
}
but in this case you can see that if you try to write in the following code you will see that compile time error will occur.
public static void main(String[] args)
{
Main main = new Main();
main.foo=new ArrayList<>();//Cannot assign a value to final variable 'foo'
System.out.println("print - " + main.foo);
}