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org.hibernate.MappingException: Repeated column in mapping for entity

I am using Hibernate 3.2.5. I am getting the above exception while using many-to-one mapping. The training table is having a many to one relation with Department table, i.e. One Depatement is capable of taking more than one training.
The exception is asking me to add insert="false" update="false" in my hbm file. If I add this bit in hbm file, then the code works fine.
Here is the hbm file:
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE hibernate-mapping PUBLIC "-//Hibernate/Hibernate Mapping DTD 3.0//EN" "http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd">
<hibernate-mapping>
<class name="com.infy.model.Training" table="training">
<id name="Id" type="integer" column="ID">
<generator class="assigned"></generator>
</id>
<property name="trainerName">
<column name="TRAINER_NAME"></column>
</property>
<property name="deptId">
<column name="DEPT_ID"></column>
</property>
<property name="trainingSubject">
<column name="TRAINING_SUBJECT"></column>
</property>
<many-to-one name="departmentDetails" column="DEPT_ID"></many-to-one>
</class>
</hibernate-mapping>
If I change this line to:
<many-to-one name="departmentDetails" column="DEPT_ID" insert="false" update="false"></many-to-one>
Then the code works. I want to know what is the exact reason for adding this.
Regards,

You have mapped the DEPT_ID column twice, here:
<property name="deptId">
<column name="DEPT_ID"></column>
</property>
And here:
<many-to-one name="departmentDetails" column="DEPT_ID"></many-to-one>
When executing a select statement, Hibernate will be fine populating two properties of your object from the same column, however when doing an insert or an update it cannot decide which property to persist in the database.
Why do you need two properties mapped to the same column in the first place? If you need access to the deptId, you can probably remove the deptId property and instead do
training.getDepartmentDetails().getId()

The error message for this scenario is quite clear (you haven't put it here, but I've seen it a few times). The problem is that you've mapped the column DEPT_ID to two different fields in your class.
First, you've mapped it to the property deptId and then to departmentDetails. As you found out, hibernate allows to do this only if one of the mappings is configured to be insert="false" update="false".
The reason is quite simple. If you would change deptId to another id, hibernate would need to change the class that is mapped in departmentDetails, which is quite complicated.
if you need to get the deptId, you can add a getDeptId method on Training that returns departmentDetails.getId(). And don't provide a setDeptId.

If you are using the same column name twice in your mapping file. might be you get mapping Exception
Initial SessionFactory creation failed.org.hibernate.MappingException:
Also if u mark insert=flase and update=false .
if u try to update or insert in records in table or another legacy system try to update these column value. it wouldn't update or insert that filed.
Please check the below link .it will help to find your solutions.
http://www.techienjoy.com/hibernate-insert-update-control.php
Thanks
Sandeep G.

Two different Objects loading in hibernate

I am facing a strange problem and am unable to find a solution. I am trying to load a set of objects in Java using Hibernate from MySQl db.
These is a simplified version of my hibernate mappings and code:
<class name="org.Foo.Class1" table="class_profile" >
<cache usage="read-write"/>
<id name="id" column="id">
<generator class="native"/>
</id>
<property name="amount" column="amount"/>
</class>
<class name="org.Foo.Class2" table="class_profile" >
<cache usage="read-write"/>
<id name="id" column="id">
<generator class="native"/>
</id>
<property name="amount" column="amount"/>
</class>
This is my code to access, the objects:
public List<Class1> loadProfiles(final List<Integer> pIds)
{
return (List<Class1>)getHibernateTemplate().executeFind(new HibernateCallback() {
public Object doInHibernate(Session session) throws HibernateException {
return session.createQuery("from Class1 il where il.id in (:idList)")
.setParameterList("idList", pIds)
.list();
}
});
}
Now, when I run my code
List<Class1> profiles = fooService.loadProfiles(Arrays.asList(3,4));
I get FOUR objects (instead of 2) in the list profiles - TWO Class1 objects and TWO Class2 objects. Where are the TWO Class2 objects coming from?

When you have inheritance between two entities, Hibernate needs to be able to tell which class a particular database row is supposed to represent. You do this by adding a discriminator class to the table that tells it which class to build to represent the row.
Class2 needs to be declared using a <subclass/> element nested inside Class1 that specifies what value of what column is used to tell them apart.
Detials here: http://docs.jboss.org/hibernate/orm/3.5/reference/en/html/inheritance.html#inheritance-tableperclass

LONG as primary key in Hibernate mapping to MySQL

I am trying to implement persistence of some Java objects via Hibernate mapping to a MySQL table. When I commit I get a message saying 'Batch update returned unexpected row count from update [0]; actual row count: 0; expected: 1'.
My hypothesis is that the problem is caused from having a long-field in my Java POJO that I want to use as my primary key in the MySQL table. Since I was not able to use datatype LONG as my primary key in MySQL table (ERROR 1170: BLOB/TEXT column 'id' used in key specification without a key length) I concluded from some googling and this post that BIGINT would be the suitable mapping for long. However it is not updating.
My test POJO Personis very simple. It has 3 fields: id (long), firstname (String), lastname (String) with setters and getters, etc.
I do the hibernate mapping in xml (person.hbm.xml) that essentially looks like (minus headings):
<hibernate-mapping>
<class name="hibernatetest.Person" table="hibernatetest">
<id name="id" type="long" column="id" >
<generator class="native"/>
</id>
<property name="firstname">
<column name="firstname" />
</property>
<property name="lastname">
<column name="lastname"/>
</property>
</class>
</hibernate-mapping>
My actual java code snippet that is supposed to save or update the record is simple:
Transaction tr = session.beginTransaction();
Person person = new Person(1,"John","Doe");
session.saveOrUpdate(person);
tr.commit();
And here's that thing, this all works just fine if I change the type of id to an int (Integer) in the Person object and in the MySQL table. However, I do not have that option for the actual objects that I want to persist so the question is; what am I doing wrong or what should I do to get it to work? Thanks.
ADDING Stacktrace:
Hibernate: update hibernatetest set firstname=?, lastname=? where id=?
org.hibernate.StaleStateException: Batch update returned unexpected row count from update [0]; actual row count: 0; expected: 1
at org.hibernate.jdbc.Expectations$BasicExpectation.checkBatched(Expectations.java:81)
at org.hibernate.jdbc.Expectations$BasicExpectation.verifyOutcome(Expectations.java:73)
at org.hibernate.engine.jdbc.batch.internal.NonBatchingBatch.addToBatch(NonBatchingBatch.java:57)
at org.hibernate.persister.entity.AbstractEntityPersister.update(AbstractEntityPersister.java:3006)
at org.hibernate.persister.entity.AbstractEntityPersister.updateOrInsert(AbstractEntityPersister.java:2908)
at org.hibernate.persister.entity.AbstractEntityPersister.update(AbstractEntityPersister.java:3237)
at org.hibernate.action.internal.EntityUpdateAction.execute(EntityUpdateAction.java:113)
at org.hibernate.engine.spi.ActionQueue.execute(ActionQueue.java:273)
at org.hibernate.engine.spi.ActionQueue.executeActions(ActionQueue.java:265)
at org.hibernate.engine.spi.ActionQueue.executeActions(ActionQueue.java:187)
at org.hibernate.event.internal.AbstractFlushingEventListener.performExecutions(AbstractFlushingEventListener.java:337)
at org.hibernate.event.internal.DefaultFlushEventListener.onFlush(DefaultFlushEventListener.java:50)
at org.hibernate.internal.SessionImpl.flush(SessionImpl.java:1082)
at org.hibernate.internal.SessionImpl.managedFlush(SessionImpl.java:317)
at org.hibernate.engine.transaction.internal.jdbc.JdbcTransaction.beforeTransactionCommit(JdbcTransaction.java:101)
at org.hibernate.engine.transaction.spi.AbstractTransactionImpl.commit(AbstractTransactionImpl.java:175)
at com.hibernate.test.TestMain.main(TestMain.java:38)
nested transactions not supported
UPDATE:
OK, I have finally worked it out. I changed the hibernate generator class from 'native' to 'assigned' and now it works as expected. So now the hibernate mapping looks like:
<hibernate-mapping>
<class name="hibernatetest.Person" table="hibernatetest">
<id name="id" type="long" column="id" >
<generator class="assigned"/>
</id>
<property name="firstname">
<column name="firstname" />
</property>
<property name="lastname">
<column name="lastname"/>
</property>
</class>
</hibernate-mapping>
Must admit I did not know the meaning of that parameter (copied from somewhere) and had no idea it could cause this much headache. Found this explanation which was quite useful.
Apparently I do not have enough credentials to answer my own questions so I guess that it will remain open or if someone provides an empty answer, I will accept it. Thanks.

When you use the saveOrUpdate() method hibernate fires the insert query if the id of the object is null and update if it is any other value. I can see the code,
Person person = new Person(1,"John","Doe"); setting the id to 1 and calling the saveOrUpdate() method. I am assuming there are no entries for the id 1 and hence the error is thrown.
To make it work, you need to make the below changes.
Change the Type of id in person to Long from long(The wrapper class so that it can support null).
Write the constructor new Person("John","Doe"); and save that object.
It is not a good Idea to keep the <generator class="assigned"/> for the transactional data. Instead you should be sticking to the native as you were trying first.
I feel this is a cleaner way to solve your initial problem, even though you have found an alternate solution.

org.hibernate.TransientObjectException during Criteria.list()

I have seen posts all over the internet that talk about how to fix the TransientObjectExceptions during save/update/delete but I am having this problem when calling list on my Criteria.
I have two objects A and B. A has a field named b which is of type B. In my mapping b is mapped as a many-to-one. This all runs in a larger persistence framework (the framework is kind of like Core Data) and so I don't use any cascades in my hibernate mappings since cascades are handled at a higher level.
This is the interesting code surrounding my criteria:
A a = new A();
B b = new B();
a.setB(b);
session.save("B", b); // Actually handled by the higher level
session.save("A", a); // framework, this is just for clarity
// transaction committed and session closed
...
// new session opened
Criteria criteria = session.createCriteria(A.class);
criteria.add(Restrictions.eq("b", b));
List<?> objects = criteria.list();
Basically I am looking for all objects of type A such that A.b equals a particular instance of b (I actually tried restructuring a query so that I was passing in the id of b just to make sure that b wasn't causing me problems).
Here is the stack trace that occurs when I call criteria.list():
org.hibernate.TransientObjectException: object references an unsaved transient instance - save the transient instance before flushing: B
at org.hibernate.engine.ForeignKeys.getEntityIdentifierIfNotUnsaved(ForeignKeys.java:244)
at org.hibernate.type.EntityType.getIdentifier(EntityType.java:449)
at org.hibernate.type.ManyToOneType.nullSafeSet(ManyToOneType.java:141)
at org.hibernate.loader.Loader.bindPositionalParameters(Loader.java:1769)
at org.hibernate.loader.Loader.bindParameterValues(Loader.java:1740)
at org.hibernate.loader.Loader.prepareQueryStatement(Loader.java:1612)
at org.hibernate.loader.Loader.doQuery(Loader.java:717)
at org.hibernate.loader.Loader.doQueryAndInitializeNonLazyCollections(Loader.java:270)
at org.hibernate.loader.Loader.doList(Loader.java:2294)
at org.hibernate.loader.Loader.listIgnoreQueryCache(Loader.java:2172)
at org.hibernate.loader.Loader.list(Loader.java:2167)
at org.hibernate.loader.criteria.CriteriaLoader.list(CriteriaLoader.java:119)
at org.hibernate.impl.SessionImpl.list(SessionImpl.java:1706)
at org.hibernate.impl.CriteriaImpl.list(CriteriaImpl.java:347)
Here is my mapping:
<class entity-name="A" lazy="false">
<tuplizer entity-mode="dynamic-map" class="MyTuplizer" />
<id type="long" column="id">
<generator class="native" />
</id>
<many-to-one name="b" entity-name="B" column="b_id" lazy="false" />
</class>
<class entity-name="B" lazy="false">
<tuplizer entity-mode="dynamic-map" class="MyTuplizer" />
<id type="long" column="id">
<generator class="native" />
</id>
</class>
Can anyone help me figure out why I would be getting a TransientObjectException during a fetch? Preferably I would like to find a solution that does not rely on cascades since they tend to mask problems that occur in the higher level framework.

The problem is that b was made persistent in another session, which is closed and the query is created in a new session. When a session is closed, all objects in its persistence context become detached. If you want to later reuse them in another session, you need to re-attach them to that session first:
session.update(b);
Quote from the Hibernate book:
The update() operation
on the Session reattaches the detached object to the persistence context and
schedules an SQL UDPATE. Hibernate must assume that the client modified the
object while it was detached. (Otherwise, if you’re certain that it hasn’t been modified,
a lock() would be sufficient.) The persistence context is flushed automatically
when the second transaction in the conversation commits, and any
modifications to the once detached and now persistent object are synchronized
with the database.
The saveOrUpdate() method is in practice more useful than update(),
save(), or lock(): In complex conversations, you don’t know if the item is in
detached state or if it’s new and transient and must be saved. The automatic
state-detection provided by saveOrUpdate() becomes even more useful when you
not only work with single instances, but also want to reattach or persist a network
of connected objects and apply cascading options.
Note that there is also a merge() method, for cases when the same entity has been loaded into the new persistence context before the older detached instance could be re-attached. In this case, you have two physically distinct instances representing the same entity, thus they should be merged to avoid a NonUniqueObjectException.

Another easy way accomplish the same is to use the attribute cascade=all on the collection mapping of child class from within the parent class mapping. Here's how the mapping looks
<class entity-name="A" lazy="false">
<tuplizer entity-mode="dynamic-map" class="MyTuplizer" />
<id type="long" column="id">
<generator class="native" />
</id>
<many-to-one name="b" entity-name="B" column="b_id" lazy="false" cascade="all" />
</class>
<class entity-name="B" lazy="false">
<tuplizer entity-mode="dynamic-map" class="MyTuplizer" />
<id type="long" column="id">
<generator class="native" />
</id>
</class>

Since you have insert data such as in persist(),save() in hibernate..But the above error is you have just do merge() and others method which can perform the update information.

Hibernate Reference column in table to indicate how to unmarshall an attribute in a different column in the same table

I have an entity that I want to persist through Hibernate (3.2)
The EntityBean has a column that indicates how another value of the entity bean should be unmarshalled:
<class name="ServiceAttributeValue" table="service_attribute_value">
<cache usage="nonstrict-read-write"/>
<id name="id" column="id" type="int-long">
<generator class="native"/>
</id>
<property name="serviceAttribute" type="service-attribute" column="service_attribute" not-null="true" />
<!-- order is important here -->
<property name="value" type="attribute-value" not-null="true">
<column name="service_attribute" />
<column name="id_value"/>
<column name="enum_value"/>
<column name="string_value"/>
<column name="int_value"/>
<column name="boolean_value"/>
<column name="double_value"/>
</property>
</class>
The "service_attribute" column indicates which of the columns for the "value" property to look at when it unmarshalls the value and, more importantly, exactly what Type the value should be, for example the class of the Enum if the enum_value is to be read, or the type of Bean if the the id_value is to be read.
The value property uses a custom CompositeUserType to do the unmarshalling and within this I wish to reference the service_attribute column (although not write to it), however when I try to do this I get the following error:
org.hibernate.MappingException: Repeated column in mapping for entity: com.precurse.apps.rank.model.service.ServiceAttributeValue column: service_attribute (should be mapped with insert="false" update="false")
However within the definition of the composite property these xml attributes are not defined (only within a normal property).
Does anyone know of a way of overcoming this, or if there is a better solution to this propblem.
If you need any more information please let me know,
Cheers
Simon

I had a similar problem and changing the case of one column solved the problem. Could give a try!
e.g., one column could be service_attribute other Service_Attribute.

You can try this. Instead of mapping both values as property on the same table, map one of the property using join to itself and keep the other property as the way it is. This case you will be able to access the same property in both places. Just remember to name the property as different name.
<join table="service_attribute_value">
<key column = "id" />
<property name="serviceAttribute" type="service-attribute" column="service_attribute" not-null="true" />
</join>
<!-- order is important here -->
<property name="value" type="attribute-value" not-null="true">
<column name="service_attribute" />
<column name="id_value"/>
<column name="enum_value"/>
<column name="string_value"/>
<column name="int_value"/>
<column name="boolean_value"/>
<column name="double_value"/>
</property>

based on your description, it seems like what you want to do is creating different subclasses based on the service_attribute. Instead of trying to achieve repeated column mapping which is not allow in hibernate, you can take a look hibernate inheritance mapping.

I Think I found a solution albeit not a very elegant one.
in the
public Object nullSafeGet(ResultSet rs, String[] names, SessionImplementor session, Object owner)
throws HibernateException, SQLException {
method of the CompositeUserType the "owner" argument passed to the method contains the id of the object who's service_attribute I want to access.
Annoyingly the actual serviceAttribute of the owner is not accessable or has not been set at this stage (I played around with the ordering of the elements in the hbm.xml config, in case this was an ordering thing, but unfortunatly still no joy), so I can't simply access it.
Anyway the id of the owner object is set, so I then used the session argument to run a HQL query based on the id to access the serviceAttribute which I then used to correctly unmarshall the value property.
The drawback of this solution is that it requires a HQL query as an overhead to the unmarshalling process, although its within the same session, its still not optimal.
If anyone has any ideas for a better solution I'd be very grateful.
Cheers