I have two projects:
common and hrm
project common is a parent project(packaged as Jar) and hrm is a dependent project(packaged as war)
Dependency is specified through maven
Maven dependency is specified as:
<dependency>
<groupId>com.talentera</groupId>
<artifactId>common</artifactId>
<version>0.0.1-SNAPSHOT</version>
</dependency>
My persistence XML in hrm project:
<?xml version="1.0" encoding="UTF-8"?>
<persistence version="2.1"
xmlns="http://xmlns.jcp.org/xml/ns/persistence"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/persistence http://xmlns.jcp.org/xml/ns/persistence/persistence_2_1.xsd">
<persistence-unit name="talentera" transaction-type="RESOURCE_LOCAL">
<description>example of enabling the second level cache.</description>
<jta-data-source>java:jboss/datasources/TalenteraDS</jta-data-source>
<exclude-unlisted-classes>false</exclude-unlisted-classes>
<jar-file>../../lib/common-0.0.1-SNAPSHOT.jar</jar-file>
<properties>
<property name="hibernate.cache.use_second_level_cache" value="false" />
<property name="hibernate.dialect" value="org.hibernate.dialect.MySQL5InnoDBDialect" />
<property name="hibernate.bytecode.use_reflection_optimizer" value="false" />
<property name="hibernate.show_sql" value="true" />
<property name="hibernate.use_outer_join" value="false" />
<property name="hibernate.cache.use_structured_entries" value="true" />
<property name="hibernate.generate_statistics" value="true" />
<property name="hibernate.id.new_generator_mappings" value="false" />
<property name="hibernate.default_batch_fetch_size" value="500" />
<property name="hibernate.max_fetch_depth" value="5" />
<property name="hibernate.jdbc.batch_size" value="1000" />
<property name="jboss.as.jpa.managed" value="false" />
<property name="hibernate.archive.autodetection" value="class, hbm"/>
</properties>
</persistence-unit>
</persistence>
Spring configuration:
<bean id="entityManagerFactory"
class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean">
<property name="dataSource" ref="appDataSource" />
<property name="persistenceUnitName" value="talentera" />
<property name="jpaVendorAdapter">
<bean
class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter">
<property name="database" value="MYSQL" />
<property name="showSql" value="true" />
</bean>
</property>
<property name="jpaDialect">
<bean class="org.springframework.orm.jpa.vendor.HibernateJpaDialect" />
</property>
</bean>
<bean id="jpaTransactionManager" class="org.springframework.orm.jpa.JpaTransactionManager">
<property name="entityManagerFactory" ref="entityManagerFactory" />
<property name="dataSource" ref="appDataSource" />
</bean>
Please help me to make the entities available in common to be auto recognized in hrm project by spring-jpa
common is packaged as Jar and hrm is packaged as war.
Please let me know if I need to provide any more information here.
I had your same problem with a composite unit, I solved in this way:
you have to change
<jar-file>../../lib/common-0.0.1-SNAPSHOT.jar</jar-file>
with
<jar-file>WEB-INF/lib/common-0.0.1-SNAPSHOT.jar</jar-file>
ii should work
Related
I use hibernate and i want to basic crud but i didn't configure persistence.xml and applicationContext.xml configuration file. I want to use EntityManager instead of Session.
This is my applicationContext.xml
<context:annotation-config />
<context:component-scan base-package="com.toyotaproject" />
<tx:annotation-driven />
<bean class = "org.springframework.dao.annotation.PersistenceExceptionTranslationPostProcessor" />
<bean id="dataSource"
class="org.springframework.jdbc.datasource.DriverManagerDataSource">
<property name="driverClassName" value="com.mysql.jdbc.Driver" />
<property name="url" value="jdbc:mysql://localhost:3307/toyotadb" />
<property name="username" value="root" />
<property name="password" value="12345" />
</bean>
<bean id="entityManagerFactory"
class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean">
<context:component-scan base-package="com.toyotaproject.domain" />
<property name="persistenceXmlLocation" value="SpringJPA_PU"></property>
<property name="dataSource" ref="dataSource" />
<property name="jpaVendorAdapter" ref="jpaAdapter" />
<property name="loadTimeWeaver">
<bean
class="org.springframework.instrument.classloading.InstrumentationLoadTimeWeaver" />
</property>
</bean>
<bean id="transactionManager" class="org.springframework.orm.jpa.JpaTransactionManager">
<property name="entityManagerFactory" ref="entityManagerFactory" />
</bean>
<bean id="jpaAdapter"
class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter">
<property name="database" value="MYSQL" />
<property name="showSql" value="true" />
<property name="generateDdl" value="true" />
</bean>
</beans>
this is my persistence.xml.
<?xml version="1.0" encoding="UTF-8"?>
<persistence xmlns="http://java.sun.com/xml/ns/persistence"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/persistence
http://java.sun.com/xml/ns/persistence/persistence_1_0.xsd"
version="1.0">
<persistence-unit name="SpringJPA_PU" transaction-type="RESOURCE_LOCAL">
<provider>org.hibernate.jpa.HibernatePersistenceProvider</provider>
<class>com.toyotaproject.domain.Customer </class>
<class>com.toyotaproject.domain.Trip </class>
<class>com.toyotaproject.domain.Reservation </class>
<properties>
<property name="javax.persistence.jdbc.driver" value="com.mysql.jdbc.Driver" />
<property name="javax.persistence.jdbc.url" value="jdbc:mysql://localhost:3307/toyotadb" />
<property name="javax.persistence.jdbc.user" value="root" />
<property name="javax.persistence.jdbc.password" value="12345" />
<property name="hibernate.hbm2ddl.auto" value="create"/>
<property name="hibernate.id.new_generator_mappings" value="true"/>
<!-- If you are using Hibernate's proprietary API, you'll need the hibernate.cfg.xml.
If you are using JPA i.e. Hibernate EntityManager, you'll need the persistence.xml. -->
<!-- SQL -->
<property name="hibernate.dialect" value="org.hibernate.dialect.MySQLDialect"/>
<property name ="hibernate.format_sql" value="true"/>
<property name ="hibernate.show_sql" value="true"/>
<!-- C3P0 -->
<property name="hibernate.c3p0.acquire_increment" value="2"/>
<property name="hibernate.c3p0.max_size" value="20"/>
<property name="hibernate.c3p0.min_size" value="5"/>
<property name="hibernate.c3p0.timeout" value="180"/>
<property name="hibernate.c3p0.idle_test_period" value="100"/>
<property name="hbm2ddl.auto" value="update"/>
<!-- property name="eclipselink.logging.level" value="OFF" /-->
</properties>
</persistence-unit>
</persistence>
Where am i doing wrong ?
I am looking for a working version of configuration for spring boot application for hibernate 4 and mysql.
I am getting the following error with my configuration since yesterday:( :
org.springframework.beans.factory.BeanCreationException: Error
creating bean with name 'entityManagerFactory' defined in class path
resource [spring-config.xml]: Invocation of init method failed; nested
exception is java.lang.IllegalStateException: JPA PersistenceProvider
returned null EntityManagerFactory - check your JPA provider setup!
This is my persistence.xml file
<?xml version="1.0" encoding="UTF-8" ?>
<persistence xmlns="http://java.sun.com/xml/ns/persistence"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_2_0.xsd"
version="2.0">
<persistence-unit name="my-pu" transaction-type="RESOURCE_LOCAL">
<provider>org.hibernate.jpa.PersistenceProvider</provider>
<class>com.crossover.trial.travelmanagementportal.model.Order</class>
<class>com.crossover.trial.travelmanagementportal.model.User</class>
<properties>
<property name="hibernate.connection.driver_class" value="com.mysql.jdbc.Driver" />
<property name="hibernate.connection.username" value="root"/>
<property name="hibernate.connection.password" value="12345678"/>
<property name="hibernate.connection.url" value="jdbc:mysql://localhost:3306/travelmanagement" />
<property name="hibernate.default_schema" value="travelmanagement" />
<property name="hibernate.dialect" value="org.hibernate.dialect.MySQLDialect" />
<property name="hibernate.hbm2ddl.auto" value="create-drop" />
<property name="hibernate.show_sql" value="true"/>
</properties>
</persistence-unit>
</persistence>
And this is my spring.config file
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:context="http://www.springframework.org/schema/context"
xmlns:tx="http://www.springframework.org/schema/tx"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context.xsd
http://www.springframework.org/schema/tx/spring-tx-3.0.xsd
http://www.springframework.org/schema/tx">
<context:annotation-config />
<context:property-placeholder location="classpath:application.properties" />
<context:component-scan base-package="com.crossover.trial.travelmanagementportal" />
<!-- For #Transactional annotations -->
<!-- This makes Spring perform #PersistenceContext/#PersitenceUnit injection: -->
<bean
class="org.springframework.orm.jpa.support.PersistenceAnnotationBeanPostProcessor" />
<!-- Drives transactions using local JPA APIs -->
<bean id="transactionManager" class="org.springframework.orm.jpa.JpaTransactionManager">
<property name="entityManagerFactory" ref="entityManagerFactory" />
</bean>
<bean id="jpaAdapter" class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter">
<property name="showSql" value="true"/>
<property name="generateDdl" value="true"/>
<property name="database" value="MYSQL"/>
</bean>
<bean id="entityManagerFactory" class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean">
<property name="persistenceUnitName" value="my-pu" />
<property name="dataSource" ref="dataSource" />
<property name="jpaVendorAdapter" ref="jpaAdapter"/>
</bean>
<bean id="dataSource" class="org.springframework.jdbc.datasource.DriverManagerDataSource" >
<property name="driverClassName" value="com.mysql.jdbc.Driver" />
<property name="url" value="jdbc:mysql://localhost:3306/travelmanagement" />
<property name="username" value="root" />
<property name="password" value="xxxx" />
</bean>
<bean id="currentUserDetailsService" class="com.crossover.trial.travelmanagementportal.service.CurrentUserDetailsService" />
<bean id="encoder" class="org.springframework.security.crypto.bcrypt.BCryptPasswordEncoder"/>
<bean id="authProvider" class="org.springframework.security.authentication.dao.DaoAuthenticationProvider">
<property name="userDetailsService" ref="currentUserDetailsService" />
<property name="passwordEncoder" ref="encoder" />
</bean>
</beans>
If you use
<dependency>
<groupId>org.springframework.boot</groupId>
<artifactId>spring-boot-starter-data-jpa</artifactId>
</dependency>
in your pom.xml then you can simply set up you connection to db with:
spring.datasource.url=
spring.datasource.username=
spring.datasource.password=
spring.jpa.hibernate.ddl-auto=
in application.properties
There is an easy way to generate a starter project with spring boot.
My peristance file is:
<?xml version="1.0" encoding="UTF-8"?>
<persistence version="1.0"
xmlns="http://java.sun.com/xml/ns/persistence">
<persistence-unit name="jpa" transaction-type="RESOURCE_LOCAL">
<!-- provider -->
<provider>org.hibernate.ejb.HibernatePersistence</provider>
<class>sau.se.migration.model.TGridStation</class>
<class>sau.se.domain.model.Graph</class>
<class>sau.se.domain.model.Role</class>
<class>sau.se.domain.model.StationPrincipale</class>
<class>sau.se.domain.model.StationSecondaire</class>
<class>sau.se.domain.model.User</class>
<class>sau.se.domain.model.Incident</class>
<class>sau.se.domain.model.Listes</class>
<class>sau.se.domain.model.Vip</class>
<class>sau.se.domain.model.Feeder</class>
<properties>
<!-- Classes persistantes -->
<!--<property name="hibernate.archive.autodetection" value="class, hbm"
/> -->
<!-- logs SQL -->
<property name="hibernate.show_sql" value="false" />
<property name="hibernate.format_sql" value="true" />
<property name="use_sql_comments" value="true" />
<!-- connexion JDBC -->
<property name="hibernate.connection.driver_class" value="com.mysql.jdbc.Driver" />
<property name="hibernate.connection.url"
value="jdbc:mysql://localhost/semap?zeroDateTimeBehavior=convertToNull" />
<property name="hibernate.connection.useUnicode" value="true" />
<property name="hibernate.connection.characterEncoding"
value="UTF-8" />
<property name="hibernate.connection.charSet" value="UTF-8" />
<property name="hibernate.connection.username" value="root" />
<property name="hibernate.connection.password" value="123456789" />
<!-- Dialecte -->
<property name="hibernate.dialect" value="org.hibernate.dialect.MySQLDialect" />
</properties>
</persistence-unit>
</persistence>
And I am quiet sure that it is the only configuration file in my project because I tried to put wrong password and I got the expected error on connection.
I want to change semap db name to any other but in vain.
Is there any other configuration that I don't know?
UPDATE
The real problem is that my application is still working with semap db (the old one)
I'm developing an application with eclipseLink and Spring. For now I'm using h2 like database. My trouble is that eclipseLink is not able to create tables.
This is my configuration.
Persistence.xml:
<persistence>
<persistence-unit name="myUnit">
//some classes definition
<properties>
<property name="javax.persistence.jdbc.driver" value="org.h2.Driver" />
<property name="javax.persistence.jdbc.url" value="jdbc:h2:file:C:\Users\user\Desktop\myFolder\test.db" />
<property name="javax.persistence.jdbc.user" value="sa" />
<property name="javax.persistence.jdbc.password" value="" />
<property name="eclipselink.ddl-generation" value="create-tables" />
<property name="eclipselink.composite-unit.member" value="true"/>
<property name="eclipselink.target-database" value="org.eclipse.persistence.platform.database.H2Platform"/>
<property name="eclipselink.ddl-generation.output-mode" value="database" />
<property name="eclipselink.create-ddl-jdbc-file-name" value="create.sql"/>
</properties>
</persistence-unit>
</persistence>
spring-context.xml
<beans>
<bean id="transactionManager" class="org.springframework.orm.jpa.JpaTransactionManager"
p:entityManagerFactory-ref="emf">
<property name="persistenceUnitName" value="myUnit" />
</bean>
<bean id="eclipseLinkJpaVendorAdapter"
class="org.springframework.orm.jpa.vendor.EclipseLinkJpaVendorAdapter">
</bean>
<tx:annotation-driven />
<bean id="emf"
class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean"
p:jpaVendorAdapter-ref="eclipseLinkJpaVendorAdapter"
p:persistenceUnitName="myUnit">
<property name="jpaPropertyMap">
<map>
<entry key="eclipselink.cache.shared.default" value="false" />
<entry key="eclipselink.weaving" value="false" />
</map>
</property>
<property name="loadTimeWeaver">
<bean
class="org.springframework.instrument.classloading.InstrumentationLoadTimeWeaver" />
</property>
</bean>
</beans>
Moreover i find the file create.sql empty!!!
Where am I doing wrong?
I'm trying to make an application with Spring 3, JPA 2 and Hibernate 3.
I have a problem when y persist an entity : nothing happen ! Data are not inserted in database, and not query is executed.
But when i'm using a request like query.getResultList() a select works correctly.
So I think my problem is only on a persist/update and on the transaction manager but i'm not really good with spring.
Can you help me please ?
Here are my configuration files :
My applicationContext.xml
<jee:jndi-lookup id="soireeentreamis_DS" jndi-name="jdbc/soireeentreamis" />
<bean id="persistenceUnitManager"
class="org.springframework.orm.jpa.persistenceunit.DefaultPersistenceUnitManager">
<property name="persistenceXmlLocations">
<list>
<value>classpath*:META-INF/persistence.xml</value>
</list>
</property>
<property name="defaultDataSource" ref="soireeentreamis_DS" />
<property name="dataSources">
<map>
<entry key="soireeentreamisDS" value-ref="soireeentreamis_DS" />
</map>
</property>
</bean>
<bean id="entityManagerFactory"
class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean">
<property name="persistenceUnitManager" ref="persistenceUnitManager" />
<property name="persistenceUnitName" value="soireeentreamisPU" />
<property name="jpaDialect">
<bean class="org.springframework.orm.jpa.vendor.HibernateJpaDialect" />
</property>
<property name="jpaVendorAdapter">
<bean class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter">
<property name="showSql" value="false" />
</bean>
</property>
</bean>
<bean id="soireeentreamisTransactionManager" class="org.springframework.orm.jpa.JpaTransactionManager">
<property name="entityManagerFactory" ref="entityManagerFactory" />
<property name="jpaDialect">
<bean class="org.springframework.orm.jpa.vendor.HibernateJpaDialect" />
</property>
</bean>
<tx:annotation-driven transaction-manager="soireeentreamisTransactionManager" />
<context:annotation-config />
</beans>
My persistence.xml
<persistence-unit name="soireeentreamisPU"
transaction-type="RESOURCE_LOCAL">
<provider>org.hibernate.ejb.HibernatePersistence</provider>
<non-jta-data-source>soireeentreamisDS</non-jta-data-source>
<properties>
<property name="hibernate.dialect" value="org.hibernate.dialect.MySQLDialect" />
<property name="hibernate.hbm2ddl.auto" value="create"/>
</properties>
</persistence-unit>
My service
#Service
#Transactional("soireeentreamisTransactionManager")
public class UserServiceImpl implements UserService ...
My dao
#Repository
public class UserDaoImpl extends GenericDaoImpl<User, String> implements
UserDao {
#PersistenceContext(unitName = "soireeentreamisPU")
private EntityManager em;
public void persist(final User entity) {
em.persist(entity);
}
}
Can somebody help me please?
I find similar problem a while ago. In my case I needed to add line below to my dispacher-servlet.xml. So I need this in 2 places (applicationContex.xml and dispacher-servlet.xml)
<tx:annotation-driven />
And to clear something out, you didn't show your service methode that "store" object, but I believe that it's annotated with #Transactional - cause wihout this one you want create new transaction.
This happened to me recently. The problem is as you say a transactional problem, add the #Transactional annotation to all the methods that update the DB. Then add the CGLIB library to your calsspath or add it to your pom.xml if you are using Maven, this is necessary for spring make transactions. Even if I did it on a different way I hope it can help you. Here is my db.xml where I have all the data base related spring configuration.
<!-- Scans within the base package of the application for #Components to configure as beans -->
<context:property-placeholder location="classpath:db.properties"/>
<bean id="entityManagerFactory"
class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean">
<property name="jpaVendorAdapter">
<bean class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter">
<property name="showSql" value="true" />
<property name="generateDdl" value="true" />
<property name="databasePlatform" value="${db.dialect}" />
</bean>
</property>
</bean>
<bean id="dataSource" class="com.jolbox.bonecp.BoneCPDataSource"
destroy-method="close">
<property name="driverClass" value="${db.driver}" />
<property name="jdbcUrl" value="${db.url}" />
<property name="username" value="${db.username}" />
<property name="password" value="${db.password}" />
<property name="idleConnectionTestPeriodInMinutes" value="1" />
<property name="idleMaxAgeInMinutes" value="4" />
<property name="maxConnectionsPerPartition" value="30" />
<property name="minConnectionsPerPartition" value="10" />
<property name="partitionCount" value="3" />
<property name="acquireIncrement" value="5" />
<property name="statementsCacheSize" value="100" />
<property name="releaseHelperThreads" value="3" />
</bean>
<bean id="jpaDialect" class="org.springframework.orm.jpa.vendor.HibernateJpaDialect"/>
<bean id="transactionManager" class="org.springframework.orm.jpa.JpaTransactionManager">
<property name="entityManagerFactory" ref="entityManagerFactory"/>
<property name="jpaDialect" ref="jpaDialect"/>
</bean>
<tx:annotation-driven transaction-manager="transactionManager"/>
<bean
class="org.springframework.orm.jpa.support.PersistenceAnnotationBeanPostProcessor" />
And here is my persistence.xml
<persistence version="2.0"
xmlns="http://java.sun.com/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_2_0.xsd">
<persistence-unit name="pu-app" transaction-type="RESOURCE_LOCAL">
</persistence-unit>
You need to add the model object into the persistence.xml file. Right below the provider element add
<class>com.your.domain.object.User</class>