Develop Reference

is it possible to read the downloaded file from chrome browser using selenium

I downloaded a text file by a click button functionality, using Selenium Java.
then the file is downloaded to a particular location in the system, for example,
C://myAppfiles.
But I can't access that downloaded folder because of some reason. But I have to read that file while downloading.
How to do it? is it possible to read that file from the browser(chrome) using selenium or any other method is available?

so I'd suggest to do the following:
wait until file download is done completely.
After that- try to list all the files in the given directory:
all files inside folder and sub-folder
public static void main(String[]args)
{
File curDir = new File(".");
getAllFiles(curDir);
}
private static void getAllFiles(File curDir) {
File[] filesList = curDir.listFiles();
for(File f : filesList){
if(f.isDirectory())
getAllFiles(f);
if(f.isFile()){
System.out.println(f.getName());
}
}
}
files/folder only
public static void main(String[]args)
{
File curDir = new File(".");
getAllFiles(curDir);
}
private static void getAllFiles(File curDir) {
File[] filesList = curDir.listFiles();
for(File f : filesList){
if(f.isDirectory())
System.out.println(f.getName());
if(f.isFile()){
System.out.println(f.getName());
}
}
}
That will help You to understand if there any files at all (in the given directory).
Dont forget to make paths platform independent (to the folder/ file), like:
//platform independent and safe to use across Unix and Windows
File fileSafe = new File("tmp"+File.separator+"myDownloadedFile.txt");
Also, You might want to check whether file actually exists via Path methods.
import java.nio.file.Files;
import java.nio.file.LinkOption;
import java.nio.file.Path;
import java.nio.file.Paths;
public class Main {
public static void main(String[] args) throws Exception {
Path filePath= Paths.get("C:\\myAppfiles\\downloaded.txt");
System.out.println("if exists: " + Files.exists(firstPath));
}
}
Additionally, path suggests You to check some other options on the file:
The following code snippet verifies that a particular file exists and that the program has the ability to execute the file.
Path file = ...;
boolean isRegularExecutableFile = Files.isRegularFile(file) &
Files.isReadable(file) & Files.isExecutable(file);
Once You face any exception- feel free to post it here.
Hope this helps You

sub directory and main directory monitoring in java [duplicate]

This question already has answers here:
Monitor subfolders with a Java watch service
(3 answers)
Closed 6 years ago.
My program is monitoring any file change in specified file path, if there's any new file coming, it will raise a notification, But going to fail when there's any sub folder created in parent folder. The file path for parent folder is being monitor C:/play but when there is a new sub folder created like C:/play/abcinside the parent folder, my program able to detect, but when i am trying to insert any file into abc folder, my program is not able to detect that new file has been created. I have tested various methods but unfortunately i can't let it work.Anyone able to provide me any guide on my reference link?My sample code is following the guide in my reference link
This is my source code after adding into the function for checking sub directory
public class fileStatus
{
public static void main(String [] args) throws InterruptedException
{
try(WatchService svc = FileSystems.getDefault().newWatchService())
{
Map<WatchKey, Path> keyMap = new HashMap<>();
Path path = Paths.get("C:/play");
fileStatus fd = new fileStatus();
fd.registerAll(path);
keyMap.put(path.register(svc,
StandardWatchEventKinds.ENTRY_CREATE),
path);
WatchKey wk ;
do
{
wk = svc.take();
Path dir = keyMap.get(wk);
for(WatchEvent<?> event : wk.pollEvents())
{
WatchEvent.Kind<?> type = event.kind();
Path fileName = (Path)event.context();
System.out.println("\nThe new file :"+fileName+ "Event :" +type); //print the new file name
}
}while(wk.reset());
}
catch(IOException e)
{
System.out.println("Problem io in somewhere");
}
}
private void registerAll(Path path) throws IOException
{
Files.walkFileTree(path, new SimpleFileVisitor<Path>()
{
#SuppressWarnings("unused")
public FileVisitResult preVisitDireotry(Path path,BasicFileAttributes attrs) throws IOException
{
return FileVisitResult.CONTINUE;
}
});
}
}
This is my reference code and my folder structure look like this,
/root
/Folder A
/test.txt
/Folder B
/abc.txt

In short, you have only registered the parent directory to be watched. Any sub-directories you create will not be watched. See here.

Java opening File Streams in one class and closing/deletion of file in another class

I want to delete the file which is opened and done writing but not closed. Please refer to code below:
Class A (can't be changed):
import java.io.FileOutputStream;
public class A {
public void run(String file) throws Exception {
FileOutputStream s = new FileOutputStream(file);
}
}
Class B:
import java.io.File;
import java.nio.file.Files;
import java.nio.file.Paths;
public class B {
public static void main(String[] args) throws Exception {
String path = "D:\\CONFLUX_HOME\\TestClient\\Maps\\test\\newTest.txt";
A a = new A();
a.run(path);
File f = new File(path);
Files.delete(Paths.get(f.getAbsolutePath()));
}
}
In Class A , just open the stream without closing the file.
In class B , calling A's run method and then try to delete the file.
Since the file is still opened. I'm unable to delete the file.
Error is :
The process cannot access the file because it is being used by another process.
Actual Scenario is :
We are loading the jars dynamically. Classes inside jar are creating the file. When there is an exception, a file gets created whose size will be 0 bytes. We need to delete this file. Since the file is not closed during the exception, we can't delete the file.
We could fix the issue if we could close the streams in the jar classes, but we can't modify the jars that create the files as they are client specific jars.
Please suggest how to delete the opened file, without modifying the code in class A.

Make sure you close the file, even if there was an Exception when writing to it.
E.g.
public void run(String file) throws Exception {
FileOutputStream s = null;
try {
s = new FileOutputStream(file);
} finally {
try {
s.close();
} catch(Exception e) {
// log this exception
}
}
}

You have to close the file before any delete operation as firstly its a bad practice and second is it will lead to memory leaks.

If you are using Tomcat, it is possible to set AntiLockingOption and antiJARLocking in $CATALINA_HOME/conf/context.xml for Windows:
<Context antiJARLocking="true" antiResourceLocking="true" >
Important note:
The antiResourceLocking option can stop JSPs from redeploying when they are edited requiring a redeploy.
Read more about this option:
http://tomcat.apache.org/tomcat-7.0-doc/config/context.html
antiResourceLocking:
If true, Tomcat will prevent any file locking. This will significantly impact startup time of applications, but allows full webapp hot deploy and undeploy on platforms or configurations where file locking can occur. If not specified, the default value is false.

Pass the resource as a parameter and it becomes the caller's responsibility to clear up the resources
public void run(FileOutputStream stream) throws Exception {
...
}
caller:
try(FileStream stream = new FileStream(path)){
A a = new A();
a.run(stream);
}catch(Exception e){
.. exception handling
}

Updated according to OPs comment.
Another approach could be to subclass A and override run().
public static void main(String[] args) throws Exception {
String path = "D:\\CONFLUX_HOME\\TestClient\\Maps\\test\\newTest.txt";
A a = new A() {
#Override
public void run(String file) throws Exception {
FileOutputStream s = new FileOutputStream(file);
s.close();
}
};
a.run(path);
File f = new File(path);
Files.delete(Paths.get(f.getAbsolutePath()));
System.out.println("foo");
}

I don't think you'll find a pure java solution to this problem. One option is to install Unlocker (being careful to hit "Skip" on all the junkware) and invoke it from your code.
If you have UAC enabled, you'll also need to be running your java in an elevated process (e.g. start command prompt as Administrator). Then, assuming unlocker is in C:\Program Files\Unlocker:
Process p = new ProcessBuilder("c:\\Program Files\\Unlocker\\Unlocker.exe",path,"-s").start();
p.waitFor();
And after that you can delete the file as before. Or you could use "-d" instead of "-s" and Unlocker will delete the file for you.

Extracting Text From JPG

I've tried this code and added the needed jar files but still I'm getting an error message like Exception in thread "main" java.lang.UnsatisfiedLinkError: Unable to load library 'libtesseract302'.
Is there a complete tutorial how to extract text and what things should be done to address the error? Any help is appreciated...
import net.sourceforge.tess4j.*;
import java.io.File;
public class ExtractTxtFromImg {
public static void main(String[] args) {
File imgFile = new File("C:\\Documents and Settings\\rueca\\Desktop\\sampleImg.jpg");
Tesseract instance = Tesseract.getInstance(); // JNA Interface Mapping
// Tesseract1 instance = new Tesseract1(); // JNA Direct Mapping
try {
String result = instance.doOCR(imgFile);
System.out.println(result);
} catch (Exception e) {
System.err.println(e.getMessage());
}
}
}

In addition to adding the jars, you also need to add the natives. You can do so with Djava.library.path="C:\[absolute path to dir containing *.dll files and such]"
Note that you need to provide the directory, not the file itself.

Java: opening a resource (txt file) which is in a jar with OS standard application

i get the error "AWT-EventQueue-0 java.lang.IllegalArgumentException: URI is not hierarchical".
-I'm trying to use the java.awt.Desktop api to open a text file with the OS's default application.
-The application i'm running is launched from the autorunning jar.
I understand that getting a "file from a file" is not the correct way and that it's called resource. I still can't open it and can't figure out how to do this.
open(new File((this.getClass().getResource("prova.txt")).toURI()));
Is there a way to open the resource with the standard os application from my application?
Thx :)

You'd have to extract the file from the Jar to the temp folder and open that temporary file, much like you would do with files in a Zip-file (which a Jar basically is).

You do not have to extract file to /tmp folder. You can read it directly using `getClass().getResourceAsStream()'. But note that path depend on where your txt file is and what's your class' package. If your txt file is packaged in root of jar use '"/prova.txt"'. (pay attention on leading slash).

I don't think you can open it with external applications. As far as i know, all installers extract their compressed content to a temp location and delete them afterwards.
But you can do it inside your Java code with Class.getResource(String name)
http://download.oracle.com/javase/6/docs/api/java/lang/Class.html#getResource(java.lang.String)

Wrong
open(new File((this.getClass().getResource("prova.txt")).toURI()));
Right
/**
Do you accept the License Agreement of XYZ app.?
*/
import java.awt.Dimension;
import javax.swing.*;
import java.net.URL;
import java.io.File;
import java.io.IOException;
class ShowThyself {
public static void main(String[] args) throws Exception {
// get an URL to a document..
File file = new File("ShowThyself.java");
final URL url = file.toURI().toURL();
// ..then do this
SwingUtilities.invokeLater( new Runnable() {
public void run() {
JEditorPane license = new JEditorPane();
try {
license.setPage(url);
JScrollPane licenseScroll = new JScrollPane(license);
licenseScroll.setPreferredSize(new Dimension(305,90));
int result = JOptionPane.showConfirmDialog(
null,
licenseScroll,
"EULA",
JOptionPane.OK_CANCEL_OPTION);
if (result==JOptionPane.OK_OPTION) {
System.out.println("Install!");
} else {
System.out.println("Maybe later..");
}
} catch(IOException ioe) {
JOptionPane.showMessageDialog(
null,
"Could not read license!");
}
}
});
}
}

There is JarFile and JarEntry classes from JDK. This allows to load a file from JarFile.
JarFile jarFile = new JarFile("jar_file_Name");
JarEntry entry = jarFile.getJarEntry("resource_file_Name_inside_jar");
InputStream stream = jarFile.getInputStream(entry); // this input stream can be used for specific need

If what you're passing to can accept a java.net.URLthis will work:
this.getClass().getResource("prova.txt")).toURI().toURL()