Parse Json to String android studio - java

I have this JSON object:
{
"1":{
"id_module":"f83d6101cc",
"adresse_mac":"00:6A:8E:16:C6:26",
"mot_de_passe":"mp0001","name":"a"
},
"2":{
"id_module":"64eae5403b",
"adresse_mac":"00:6A:8E:16:C6:26",
"mot_de_passe":"mp0002",
"name":"a"
}
}
And I would like to parse and get to string id_module, adresse_mac, mot_de_passe and name for each thing the 1 and the 2.
So I made this but it's not working :
TextView txt1=(TextView) findViewById(R.id.textView);
String ajout1 = "http://";
JSONObject json = null;
String str = "1";
HttpResponse response;
HttpClient myClient = new DefaultHttpClient();
HttpPost myConnection = new HttpPost(ajout1);
try {
response = myClient.execute(myConnection);
str = EntityUtils.toString(response.getEntity(), "UTF-8");
} catch (ClientProtocolException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
try {
JSONObject jsonObject = new JSONObject(str);
String MAC = jsonObject.getString("id_module");
txt1.setText(MAC);
} catch (JSONException e) {
e.printStackTrace();
}

You should try this:
String str = "your json string";
JSONObject json = new JSONObject(str);
String module = json.getJSONObject("1").getString("id_module");
String address = json.getJSONObject("1").getString("adresse_mac");
String module2 = json.getJSONObject("2").getString("id_module"); //from 2nd object

Related

How to parse JSON api using JAVA?

I am new on JAVA, how to parse the countryname using this API: https://iplist.cc/api
Use JAVA to parse the JSON: https://iplist.cc/api
Get ONLY the "countryname" value.
For example,
If the country name is "countryname": "Germany",
The OUTPUT should be only:
Germany
I tried this but did not work :(
public class JSONParser {
static InputStream is = null;
static JSONObject jObj = null;
static String json = "";
// constructor
public JSONParser() {}
public JSONObject getJSONFromUrl(String url) {
// Making HTTP request
try {
// defaultHttpClient
DefaultHttpClient httpClient = new DefaultHttpClient();
HttpPost httpPost = new HttpPost(url);
HttpResponse httpResponse = httpClient.execute(httpPost);
HttpEntity httpEntity = httpResponse.getEntity();
is = httpEntity.getContent();
} catch (UnsupportedEncodingException e) {
e.printStackTrace();
} catch (ClientProtocolException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
try {
BufferedReader reader = new BufferedReader(new InputStreamReader(
is, "iso-8859-1"), 8);
StringBuilder sb = new StringBuilder();
String line = null;
while ((line = reader.readLine()) != null) {
sb.append(line + "\n");
}
is.close();
json = sb.toString();
} catch (Exception e) {
Log.e("Buffer Error", "Error converting result " + e.toString());
}
// try parse the string to a JSON object
try {
jObj = new JSONObject(json);
} catch (JSONException e) {
Log.e("JSON Parser", "Error parsing data " + e.toString());
}
// return JSON String
return jObj;
}
}
// url to make request
private static String url = "https://iplist.cc/api";
// JSON Node names
private static final String COUNTRY_NAME = "countryname";
// contacts JSONArray
JSONArray contacts = null;
// Creating JSON Parser instance
JSONParser jParser = new JSONParser();
// getting JSON string from URL
JSONObject json = jParser.getJSONFromUrl(url);
try {
country = json.getString(COUNTRY_NAME);
}
} catch (JSONException e) {
e.printStackTrace();
}
Thank You!
For such deserialization purpose, I would recommend you to use Gson (or another of this kind).
implementation 'com.google.code.gson:gson:2.8.6'
Prepare IP class for deserialization:
public class IP {
public final String ip;
public final String registry;
public final String countrycode;
public final String countryname;
public final String detail;
public final boolean spam;
public final boolean tor;
public IP(String ip, String registry,
String countrycode, String countryname,
String detail, boolean spam, boolean tor) {
this.ip = ip;
this.registry = registry;
this.countrycode = countrycode;
this.countryname = countryname;
this.detail = detail;
this.spam = spam;
this.tor = tor;
}
}
Deserialize from JSON String with Gson:
IP ip = new Gson().fromJson(json, IP.class);
System.out.println(ip.countryname);
First add org.json library to your project. this is for converting String to JSONObject.
public class HttpGet {
public static String readGetRequestData(String urlToRead) throws IOException {
// System.setProperty("https.proxyHost", "ip");
// System.setProperty("https.proxyPort", "port"); if you got some proxy set it
URL url = new URL(urlToRead);
HttpURLConnection connection = (HttpURLConnection) url.openConnection();
connection.setRequestMethod("GET");
return new String(connection.getInputStream().readAllBytes(), StandardCharsets.UTF_8);
}
public static void main(String[] args) throws Exception {
String data = readGetRequestData("https://iplist.cc/api");
try {
JSONObject jsonObject = new JSONObject(data);
System.out.println(jsonObject.get("countryname"));
} catch (JSONException err) {
err.printStackTrace();
}
}
}
result is: Germany

JSON object showing null pointer exception

I want to post data to the url and getting Null pointer exception
My JSON URL contains
{
"Details":
[
{
"Status":"NO UPDATES"
}
]
}
I'm getting the error the line:
String status = object.getString("Status").trim(); //error Line
Full code:
btnPost = (Button)findViewById(R.id.btnPost);
btnPost.setOnClickListener(this);
btnPost.setOnClickListener(new OnClickListener()
{
#SuppressWarnings("null")
#Override
public void onClick(View arg0)
{
try
{
String postReceiverUrl = "http://";
Log.v(TAG, "postURL: " + postReceiverUrl);
// HttpClient
#SuppressWarnings("resource")
HttpClient httpClient = new DefaultHttpClient();
// post header
HttpPost httpPost = new HttpPost(postReceiverUrl);
jsonobject.put("IDNo", IDNo.getText().toString());
jsonobject.put("Position", Position.getText().toString());
jsonobject.put("Data", Data.getText().toString());
HttpResponse response = httpClient.execute(httpPost);
String jsonResult = inputStreamToString(response.getEntity().getContent()).toString();
Log.v("jsonResult",jsonResult);
JSONObject object = new JSONObject(jsonResult);
String status = object.getString("Status").trim();
Toast.makeText(getBaseContext(), "Please wait...",100).show();
if(status.toString().equals("SUCCESS"))
{
Intent i = new Intent(LoginPage.this,MainActivity.class);
i.setFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP);
startActivity(i);
}
if(status.toString().equals("FAILED"))
{
Toast.makeText(getBaseContext(), "Wrong Credentials",100).show();
}
else
{
Toast.makeText(getBaseContext(), "Details Inserted",100).show();
}
}
catch(Exception e)
{
e.printStackTrace();
}
catch (JSONException e)
{
e.printStackTrace();
}
catch (ClientProtocolException e)
{
e.printStackTrace();
}
catch (IOException e)
{
e.printStackTrace();
}
}
});
Do proper parsing of the JSON as , you see yours response:-
{ "Details":[{"Status":"NO UPDATES"}]}
So Firstly try to make the object of the JSONObject than after the JSONArray , look at below example:-
JSONObject jsonObject = new JSONObject(jsonResult);
JSONArray detailsArray = jsonObject.getJSONArray("Details");
String status = dataArray.getJSONObject(0).getString("status");
Toast.makeText(getBaseContext(), "Please wait...",100+status).show();
your code should be like this
JSONObject object = new JSONObject(jsonResult);
JSONOArray details = object.getJSONArray("Details");
for (int i = 0; i < details.length(); i++) {
JSONObject c = details.getJSONObject(i);
String status = c.getString("Status");
}
Toast.makeText(getBaseContext(), "Please wait...",100).show();
Modift String status = object.getString("Status").trim(); to
String status = object.get("Details").getAsJsonArray()[0].getString("Status").trim();
You are using getString("Status") which may return null if key is not available in JSON. I'd suggest you to use optString("Status") it'll return blank String if key is not available.
JSONObject jsonObject = new JSONObject(stringJSON);
JSONArray jsonArray = jsonObject.optJSONArray("Details");
if(jsonArray != null){
for(int i = 0; i < jsonArray.length(); i++){
JSONObject jObject = jsonArray.optJSONObject(i);
if(jObject != null){
String strStatus = jObject.optString("Status");
}
}
}
Try this code
JSONObject object = new JSONObject(jsonResult);
JSONArray array=object.getJsonarray("Details");
for(int i=0;i<array.length();i++)
{
JSONObject innerObject=array.getJsonObject(i);
String s= innerObject.getString("Status");
}
If at any point in your code, org.json.JSONObject json_object becomes null and you wish to avoid NullPointerException (java.lang.NullPointerException), then simply check as following:
if(json_object == null) {
System.out.println("json_object is found as null");
}
else {
System.out.println("json_object is found as not null");
}

how to code json array without array name?

I'm new to JSON android java eclipse. I am doing a listview with images and parsing json array. I followed this tutorial: http://www.wingnity.com/blog/android-json-parsing-and-image-loading-tutorial/ . In that tutorial, their JSON array contains the array name.However, mine doesn't contain the array name. So my question is how to code JSON Array without the array name?
Below is my JSON code.
[
{ "event_id": "EV00000001",
"event_title": "Movie 1",
},
{
"event_id": "EV00000002",
"event_title": "Movie2",
}
]
Below is my JSON coding for parsing the JSON.
protected Boolean doInBackground(String... urls) {
try {
HttpGet httppost = new HttpGet(urls[0]);
HttpClient httpclient = new DefaultHttpClient();
HttpResponse response = httpclient.execute(httppost);
// StatusLine stat = response.getStatusLine();
int status = response.getStatusLine().getStatusCode();
if (status == 200) {
HttpEntity entity = response.getEntity();
String data = EntityUtils.toString(entity);
JSONObject jsono = new JSONObject(data);
JSONArray jarray = jsono.getJSONArray("actors");
for (int i = 0; i < jarray.length(); i++) {
JSONObject object = jarray.getJSONObject(i);
Events event = new Events();
event.setevent_title(object.getString("event_title"));
eventList.add(event);
}
return true;
}
//------------------>>
} catch (ParseException e1) {
e1.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
} catch (JSONException e) {
e.printStackTrace();
}
return false;
}
What am i suppose to do?
This problem is solved. Thus, i will be posting the correct code.
protected Boolean doInBackground(String... urls) {
try {
//------------------>>
HttpGet httppost = new HttpGet(urls[0]);
HttpClient httpclient = new DefaultHttpClient();
HttpResponse response = httpclient.execute(httppost);
// StatusLine stat = response.getStatusLine();
int status = response.getStatusLine().getStatusCode();
if (status == 200) {
HttpEntity entity = response.getEntity();
String data = EntityUtils.toString(entity);
JSONArray array = new JSONArray(data);
for (int i = 0; i < array.length(); i++) {
JSONObject obj = array.getJSONObject(i);
Events event = new Events();
event.setevent_title(obj.getString("event_title"));
eventList.add(event);
}
return true;
}
//------------------>>
} catch (ParseException e1) {
e1.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
} catch (JSONException e) {
e.printStackTrace();
}
return false;
}
Here is a little example:
JSONArray array = new JSONArray();
JSONObject obj1 = new JSONObject();
obj1.put("key", "value");
array.put(obj1);
JSONObject obj2 = new JSONObject();
obj2.put("key2", "value2");
array.put(obj2);
That would look like:
[
{
"key": "value"
},
{
"key2": "value2"
}
]
If you want to get information about your JSONObjects in your JSONArray just iterate over them:
for (int i = 0; i < array.length(); i++) {
JSONObject object = (JSONObject) array.get(i);
object.get("event_id");
object.get("event_title");
}
You can use GSON librery, it's very easy to use. Just create a class (model)
public class Event{
private String event_id;
private String event_title;
...
}
and in your main activity
Event ev = new Event ("EV00000001", "Movie 1")
Gson gson = new Gson();
gSon = gson.toJson(ev);
Log.i("gson", gSon);
and you will get JSON
[
{ "event_id": "EV00000001",
"event_title": "Movie 1",
}
]
What you have is an array of JSON Objects.
What the tutorial has is a JSON Object that has a property, which has an array of JSON objects.
When you look at these, here is a simple way to differentiate the two:
[] -> Array
{} -> Object
So in your code, instead of doing
JSONObject jsono = new JSONObject(data);
JSONArray jarray = jsono.getJSONArray("actors");
You might want to do:
JSONArray jarray = new JSONArray(data);

How to parse following json response in android app

I am working with webservice in an android app. I could not parse the following response in app. it always gives the
org.json.JSONException: Value
[{"METER_READING":"15","UTILITY_PLAN":"1","uname":"vinayak#triffort.com","kwh_usage":"3","meter_reading_date":"02-13-2014","ESID":"abc","METER_ID":"abc100"}]
at data of type java.lang.String cannot be converted to JSONArray.
Below is my code:
StringEntity entity = new StringEntity(jsonObject.toString(), HTTP.UTF_8);
httpPost.setEntity(entity);
HttpResponse response = httpClient.execute(httpPost);
BufferedReader reader =new BufferedReader(new InputStreamReader(response.getEntity().getContent(), "UTF-8"));
String jsonResultStr = reader.readLine();
JSONObject jObject = new JSONObject(jsonResultStr);
JSONArray jArray = jObject.optJSONArray("data");
I get following response from webservice
{"data":"[{\"METER_READING\":\"25\",\"UTILITY_PLAN\":\"1\",\"uname\":\"vinayak#triffort.com\",\"kwh_usage\":\"9\",\"meter_reading_date\":\"02-13-2014\",\"ESID\":\"abc\",\"METER_ID\":\"abc100\"}]"}
try using something like:
jsonResultStr = jsonResultStr.replace( "\\", "" ).replaceAll( "\"\\[", "[" ).replaceAll( "\\]\"", "]" );
JSONObject jObject = new JSONObject(jsonResultStr);
JSONArray jArray = jObject.optJSONArray("data");
I get following response
{
"data":"[{\"METER_READING\":\"25...}]"
}
The value of data is not an array; it is a string. That string is valid JSON which you could parse but why the service would do this is unclear.
So this should work:
JSONObject jObject = new JSONObject(jsonResultStr);
String parseMeAgain = jObject.optString("data");
try this simple code:
JSONObject o = new JSONObject(new JSONTokener(postResponse));
JSONArray ja = o.getJSONArray("data");
EDIT
Thanks #McDowell for observation
new JSONArray(new JSONTokener(jObject.optString("data")));
You can do this way :
JSONArray jsonArray = new JSONArray(result); // Pass your result here..
JSONObject jsonObject = jsonArray.getJSONObject(0);
String meterReading = jsonObject.getString("METER_READING");
String plan = jsonObject.getInt("UTILITY_PLAN");
String uname= jsonObject.getString("uname");
String meter_reading_date= jsonObject.getString("meter_reading_date");
String ESID= jsonObject.getString("ESID");
String METER_ID= jsonObject.getString("METER_ID");
Your json should be like this
{
"myarray": [
{
"METER_READING": "15",
"UTILITY_PLAN": "1",
"uname": "vinayak#triffort.com",
"kwh_usage": "3",
"meter_reading_date": "02-13-2014",
"ESID": "abc",
"METER_ID": "abc100"
}
]
}
for network call
public String initializeConnection(String url) {
String result = null;
JSONObject jObj;
try {
DefaultHttpClient client = new DefaultHttpClient();
HttpPost post = new HttpPost(url);
if(client==null){Log.i("Clinet **************** ", "Client is null");}
//post.setEntity(new UrlEncodedFormEntity(params));
HttpResponse res = client.execute(post);
result = inputStreamToString(res.getEntity().getContent()).toString();
Log.d("Result from server:", result);
jObj = new JSONObject(result.trim());
} catch (JSONException e1) {
Log.e("Json Exception", e1.toString());
} catch (ClientProtocolException e2) {
Log.e("Client Protocol", e2.toString());
} catch (IOException e3) {
Log.e("Io exception", e3.toString());
}
return result;
}
private StringBuilder inputStreamToString(InputStream is) throws UnsupportedEncodingException {
String rLine = "";
StringBuilder answer = new StringBuilder();
BufferedReader rd = new BufferedReader(new InputStreamReader(is, "iso-8859-1"),8);
try {
while ((rLine = rd.readLine()) != null) {
answer.append(rLine);
}
}
catch (IOException e) {
e.printStackTrace();
}
return answer;
}
to retrive from the json
ArrayList<String> params = new ArrayList<String>();
String result = networkCall.initializeConnection(url);
jObj = new JSONObject(result);
JSONArray jArray = jObj.optJSONArray("myarray");
params.add(jArray.optString(1));
params.add(jArray.optString(2));
params.add(jArray.optString(3));
params.add(jArray.optString(4));
params.add(jArray.optString(5));
params.add(jArray.optString(6));
now the data is stored in the params you can differentiate & store it as you want

Get a JSON object from a HTTP response

I want to get a JSON object from a Http get response:
Here is my current code for the Http get:
protected String doInBackground(String... params) {
HttpClient client = new DefaultHttpClient();
HttpGet request = new HttpGet(params[0]);
HttpResponse response;
String result = null;
try {
response = client.execute(request);
HttpEntity entity = response.getEntity();
if (entity != null) {
// A Simple JSON Response Read
InputStream instream = entity.getContent();
result = convertStreamToString(instream);
// now you have the string representation of the HTML request
System.out.println("RESPONSE: " + result);
instream.close();
if (response.getStatusLine().getStatusCode() == 200) {
netState.setLogginDone(true);
}
}
// Headers
org.apache.http.Header[] headers = response.getAllHeaders();
for (int i = 0; i < headers.length; i++) {
System.out.println(headers[i]);
}
} catch (ClientProtocolException e1) {
// TODO Auto-generated catch block
e1.printStackTrace();
} catch (IOException e1) {
// TODO Auto-generated catch block
e1.printStackTrace();
}
return result;
}
Here is the convertSteamToString function:
private static String convertStreamToString(InputStream is) {
BufferedReader reader = new BufferedReader(new InputStreamReader(is));
StringBuilder sb = new StringBuilder();
String line = null;
try {
while ((line = reader.readLine()) != null) {
sb.append(line + "\n");
}
} catch (IOException e) {
e.printStackTrace();
} finally {
try {
is.close();
} catch (IOException e) {
e.printStackTrace();
}
}
return sb.toString();
}
Right now I am just getting a string object. How can I get a JSON object back.
The string that you get is just the JSON Object.toString(). It means that you get the JSON object, but in a String format.
If you are supposed to get a JSON Object you can just put:
JSONObject myObject = new JSONObject(result);
Do this to get the JSON
String json = EntityUtils.toString(response.getEntity());
More details here : get json from HttpResponse
This is not the exact answer for your question, but this may help you
public class JsonParser {
private static DefaultHttpClient httpClient = ConnectionManager.getClient();
public static List<Club> getNearestClubs(double lat, double lon) {
// YOUR URL GOES HERE
String getUrl = Constants.BASE_URL + String.format("getClosestClubs?lat=%f&lon=%f", lat, lon);
List<Club> ret = new ArrayList<Club>();
HttpResponse response = null;
HttpGet getMethod = new HttpGet(getUrl);
try {
response = httpClient.execute(getMethod);
// CONVERT RESPONSE TO STRING
String result = EntityUtils.toString(response.getEntity());
// CONVERT RESPONSE STRING TO JSON ARRAY
JSONArray ja = new JSONArray(result);
// ITERATE THROUGH AND RETRIEVE CLUB FIELDS
int n = ja.length();
for (int i = 0; i < n; i++) {
// GET INDIVIDUAL JSON OBJECT FROM JSON ARRAY
JSONObject jo = ja.getJSONObject(i);
// RETRIEVE EACH JSON OBJECT'S FIELDS
long id = jo.getLong("id");
String name = jo.getString("name");
String address = jo.getString("address");
String country = jo.getString("country");
String zip = jo.getString("zip");
double clat = jo.getDouble("lat");
double clon = jo.getDouble("lon");
String url = jo.getString("url");
String number = jo.getString("number");
// CONVERT DATA FIELDS TO CLUB OBJECT
Club c = new Club(id, name, address, country, zip, clat, clon, url, number);
ret.add(c);
}
} catch (Exception e) {
e.printStackTrace();
}
// RETURN LIST OF CLUBS
return ret;
}
}
Again, it’s relatively straight forward, but the methods I’ll make special note of are:
JSONArray ja = new JSONArray(result);
JSONObject jo = ja.getJSONObject(i);
long id = jo.getLong("id");
String name = jo.getString("name");
double clat = jo.getDouble("lat");
Without a look at your exact JSON output, it's hard to give you some working code. This tutorial is very useful, but you could use something along the lines of:
JSONObject jsonObj = new JSONObject("yourJsonString");
Then you can retrieve from this json object using:
String value = jsonObj.getString("yourKey");
For the sake of a complete solution to this problem (yes, I know that this post died long ago...) :
If you want a JSONObject, then first get a String from the result:
String jsonString = EntityUtils.toString(response.getEntity());
Then you can get your JSONObject:
JSONObject jsonObject = new JSONObject(jsonString);
You need to use JSONObject like below:
String mJsonString = downloadFileFromInternet(urls[0]);
JSONObject jObject = null;
try {
jObject = new JSONObject(mJsonString);
}
catch (JSONException e) {
e.printStackTrace();
return false;
}
...
private String downloadFileFromInternet(String url)
{
if(url == null /*|| url.isEmpty() == true*/)
new IllegalArgumentException("url is empty/null");
StringBuilder sb = new StringBuilder();
InputStream inStream = null;
try
{
url = urlEncode(url);
URL link = new URL(url);
inStream = link.openStream();
int i;
int total = 0;
byte[] buffer = new byte[8 * 1024];
while((i=inStream.read(buffer)) != -1)
{
if(total >= (1024 * 1024))
{
return "";
}
total += i;
sb.append(new String(buffer,0,i));
}
}
catch(Exception e )
{
e.printStackTrace();
return null;
}catch(OutOfMemoryError e)
{
e.printStackTrace();
return null;
}
return sb.toString();
}
private String urlEncode(String url)
{
if(url == null /*|| url.isEmpty() == true*/)
return null;
url = url.replace("[","");
url = url.replace("]","");
url = url.replaceAll(" ","%20");
return url;
}
Hope this helps you..
There is a JSONObject constructor to turn a String into a JSONObject:
http://developer.android.com/reference/org/json/JSONObject.html#JSONObject(java.lang.String)
If your api is response is a java object, then the string that you got from Outputstream should be in json string format such as
{\"name\":\"xyz\", \"age\":21}
. This can be converted to JSON object in many ways, out of which one way is to use google GSON library.
GsonBuilder builder = new GsonBuilder().setPrettyPrinting(); Gson gson = builder.create(); <javaobject> = gson.fromJson(<outputString>, <Classofobject>.class);
One can do it without Gson also, using Jackson, which implements Json Tree Model.
ObjectMapper mapper = new ObjectMapper();
JsonNode jsonNode = mapper.readTree(responseString);
1)String jsonString = EntityUtils.toString(response.getEntity());
2)JSONObject jsonObject = new JSONObject(jsonString);

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