i have have a string looks :
mystring = "<EQHO state="degraded"...> at /NE[1]/EQHO[2]/#state to <EQHO state="working"...> at /NE[1]/EQHO[1]/#state"
and i want to get this value :
value="NE[1]/EQHO[1]"
how can i achieve that ?
thanks
Try this:
mystring.substring(mystring.lastIndexOf("at /")+4, mystring.lastIndexOf("/#"))
but you probably should use a more generic solution. To extract all the section that have this format you can use something like this:
String mystring = "<EQHO state=\"degraded\"...> at /NE[1]/EQHO[2]/#state to <EQHO state=\"working\"...> at /NE[1]/EQHO[1]/#state";
ArrayList<String> values = new ArrayList<String>();
while(mystring.indexOf("at /") < mystring.indexOf("/#")){
String val = mystring.substring(mystring.indexOf("at /") + 4, mystring.indexOf("/#"));
values.add(val);
mystring = mystring.substring(mystring.indexOf("/#")+2);
}
System.out.println(values);
You can change the value of a string like this
mystring = "NE[1]/EQHO[1]";
Remember to include the semicolon!
so, right now I have this String:
String csfo = "([csfo_num = 333015303][ csfo_minimum = 4044504600][ csfo_offering = 48526][csfo_add_ind A])";
I want to be able to get just this part of the the string but I'm at a loss as to how to do this.
Needed Output:
String[] requiredOutput;
requiredOutput[1] = 48526; // csfo_offering
requiredOutput[2] = csfo_add_ind A;
or
requiredOutput[2] = A; // csfo_add_ind
EDIT:
I have used some of your suggestions and am trying out subString but it seems like its a temp fix because if the length of the original string changes then it will throw a wrench in my calls. I will try regex next because it seems to go by pattern matching and I might be able to figure something out with that. Thanks everyone for all your help.
Suggestions are still appreciated!
Are the numbers always the same length? If so, use String.subString. If not use String.indexOf("csfo_add") to find the locations of the "csfo_add" parts and then find the relative locations of the required information.
Hi there you can also use split if you always have the same pattern for your string.
for example
String csfo = "([csfo_num = 333015303][ csfo_minimum = 4044504600][ csfo_offering = 48526][csfo_add_ind A])";
System.out.println(csfo.split("csfo_add_ind ")[1].split("\\]\\)")[0]);
Would get the requiredOutput[2] = A; // csfo_add_ind
and this would get the first one
String[] requiredOutput = new String[2];
String csfo = "([csfo_num = 333015303][ csfo_minimum = 4044504600][ csfo_offering = 48526][csfo_add_ind A])";
requiredOutput[0] = "csfo_add_ind " + csfo.split("csfo_add_ind ")[1].split("\\]\\)")[0];
requiredOutput[1] = csfo.split("\\]\\[csfo_add_ind ")[0].split("csfo_offering = ")[1];
//System.out.println(requiredOutput[0] + " et " + requiredOutput[1] );
I've got a really simple code snippet that I'm trying to move into two methods but for the life of me can't figure out what I'm doing wrong, here is the code currently:
if (chatLayer != null) {
Page checkPage = resource.resourceResolver.getResource(url).adaptTo(Page);
url = (checkPage) ? ".html" : "";
} else {
PageManager manager = resource.getResourceResolver().adaptTo(PageManager.class);
String currentPage = manager.getContainingPage(resource).getPath();
url = "&refer="+currentPage;
}
When I try to turn it into methods:
url = chatLayer ? chatOverlay() : chatURL()
private static String chatOverlay(Page checkPage, String url) {
Page checkPage = resource.resourceResolver.getResource(url).adaptTo(Page);
url = (checkPage) ? ".html" : "";
}
private static String chatURL(Page checkPage, String url) {
PageManager manager = resource.getResourceResolver().adaptTo(PageManager.class);
String currentPage = manager.getContainingPage(resource).getPath();
url = "&refer="+currentPage;
}
All I get as an error is a current scope already contains a variable of checkpage. Any help is greatly appreciated. I'm a newbie so modifications to my code or code snippets is greatly appreciated.
In your method chatOverlay you have a Page checkPage parameter and a Page checkPage local variable. Change the name of one of them. Additional: you're not returning anything from your methods (not sure if this is a typo).
private static String chatOverlay(Page checkPage, String url) {
//changed the name of the local variable
Page checkedPage = resource.resourceResolver.getResource(url).adaptTo(Page);
url = (checkedPage) ? ".html" : "";
return url;
}
private static String chatOverlay(Page checkPage, String url) {
Page checkPage = resource.resourceResolver.getResource(url).adaptTo(Page);
url = (checkPage) ? ".html" : "";
}
You already have a variable named checkPage as one of your method parameters. You can't have two variables named checkPage in your method -- how would the compiler know which variable you are referring to?
I am extracting a youtube video id from a youtube link. the list looks like this
http://www.youtube.com/watch?v=mmmc&feature=plcp
I want to get the mmmc only.
i used .replaceAll ?
Three ways:
Url parsing:
http://download.oracle.com/javase/6/docs/api/java/net/URL.html
URL url = new URL("http://www.youtube.com/watch?v=mmmc&feature=plcp");
url.getQuery(); // return query string.
Regular Expression
Examples here http://www.vogella.com/articles/JavaRegularExpressions/article.html
Tokenize
String s = "http://www.youtube.com/watch?v=mmmc&feature=plcp";
String arr[] = s.split("=");
String arr1[] = arr[1].split("&");
System.out.println(arr1[0]);
If you'd like to use regular expressions, this could be a solution:
Pattern p = Pattern
.compile("http://www.youtube.com/watch\\?v=([\\s\\S]*?)\\&feature=plcp");
Matcher m = p.matcher(youtubeLink);
if (m.find()) {
return m.group(1);
}
else{
throw new IllegalArgumentException("invalid youtube link");
}
Of course, this will only work if the feature will always be plcp, if not, you could simply remove that part or replace it with a wilcard as I did with mmmc
Edit: now i know what you are looking for i hope:
String url= "http://www.youtube.com/watch?v=mmmc&feature=plcp";
String search = "v=";
int index = url.indexOf(search);
int index2 = url.indexOf("&",index);
String found = url.substring(index+2,index2);
System.out.println(found);
Here's a generic solution (using Guava MapSplitter):
public final class UrlUtil {
/**
* Query string splitter.
*/
private static final MapSplitter PARAMS_SPLITTER = Splitter.on('&').withKeyValueSeparator("=");
/**
* Get param value in provided url for provided param.
*
* #param url Url to use
* #param param Param to use
* #return param value or null.
*/
public static String getParamVal(String url, String param)
{
if (url.contains("?")) {
final String query = url.substring(url.indexOf('?') + 1);
return PARAMS_SPLITTER.split(query).get(param);
}
return null;
}
public static void main(final String[] args)
{
final String url = "http://www.youtube.com/watch?v=mmmc&feature=plcp";
System.out.println(getParamVal(url, "v"));
System.out.println(getParamVal(url, "feature"));
}
}
Outputs:
mmmc
plcp
Given a URL, I want to extract domain name(It should not include 'www' part). Url can contain http/https. Here is the java code that I wrote. Though It seems to work fine, is there any better approach or are there some edge cases, that could fail.
public static String getDomainName(String url) throws MalformedURLException{
if(!url.startsWith("http") && !url.startsWith("https")){
url = "http://" + url;
}
URL netUrl = new URL(url);
String host = netUrl.getHost();
if(host.startsWith("www")){
host = host.substring("www".length()+1);
}
return host;
}
Input: http://google.com/blah
Output: google.com
If you want to parse a URL, use java.net.URI. java.net.URL has a bunch of problems -- its equals method does a DNS lookup which means code using it can be vulnerable to denial of service attacks when used with untrusted inputs.
"Mr. Gosling -- why did you make url equals suck?" explains one such problem. Just get in the habit of using java.net.URI instead.
public static String getDomainName(String url) throws URISyntaxException {
URI uri = new URI(url);
String domain = uri.getHost();
return domain.startsWith("www.") ? domain.substring(4) : domain;
}
should do what you want.
Though It seems to work fine, is there any better approach or are there some edge cases, that could fail.
Your code as written fails for the valid URLs:
httpfoo/bar -- relative URL with a path component that starts with http.
HTTP://example.com/ -- protocol is case-insensitive.
//example.com/ -- protocol relative URL with a host
www/foo -- a relative URL with a path component that starts with www
wwwexample.com -- domain name that does not starts with www. but starts with www.
Hierarchical URLs have a complex grammar. If you try to roll your own parser without carefully reading RFC 3986, you will probably get it wrong. Just use the one that's built into the core libraries.
If you really need to deal with messy inputs that java.net.URI rejects, see RFC 3986 Appendix B:
Appendix B. Parsing a URI Reference with a Regular Expression
As the "first-match-wins" algorithm is identical to the "greedy"
disambiguation method used by POSIX regular expressions, it is
natural and commonplace to use a regular expression for parsing the
potential five components of a URI reference.
The following line is the regular expression for breaking-down a
well-formed URI reference into its components.
^(([^:/?#]+):)?(//([^/?#]*))?([^?#]*)(\?([^#]*))?(#(.*))?
12 3 4 5 6 7 8 9
The numbers in the second line above are only to assist readability;
they indicate the reference points for each subexpression (i.e., each
paired parenthesis).
import java.net.*;
import java.io.*;
public class ParseURL {
public static void main(String[] args) throws Exception {
URL aURL = new URL("http://example.com:80/docs/books/tutorial"
+ "/index.html?name=networking#DOWNLOADING");
System.out.println("protocol = " + aURL.getProtocol()); //http
System.out.println("authority = " + aURL.getAuthority()); //example.com:80
System.out.println("host = " + aURL.getHost()); //example.com
System.out.println("port = " + aURL.getPort()); //80
System.out.println("path = " + aURL.getPath()); // /docs/books/tutorial/index.html
System.out.println("query = " + aURL.getQuery()); //name=networking
System.out.println("filename = " + aURL.getFile()); ///docs/books/tutorial/index.html?name=networking
System.out.println("ref = " + aURL.getRef()); //DOWNLOADING
}
}
Read more
Here is a short and simple line using InternetDomainName.topPrivateDomain() in Guava: InternetDomainName.from(new URL(url).getHost()).topPrivateDomain().toString()
Given http://www.google.com/blah, that will give you google.com. Or, given http://www.google.co.mx, it will give you google.co.mx.
As Sa Qada commented in another answer on this post, this question has been asked earlier: Extract main domain name from a given url. The best answer to that question is from Satya, who suggests Guava's InternetDomainName.topPrivateDomain()
public boolean isTopPrivateDomain()
Indicates whether this domain name is composed of exactly one
subdomain component followed by a public suffix. For example, returns
true for google.com and foo.co.uk, but not for www.google.com or
co.uk.
Warning: A true result from this method does not imply that the
domain is at the highest level which is addressable as a host, as many
public suffixes are also addressable hosts. For example, the domain
bar.uk.com has a public suffix of uk.com, so it would return true from
this method. But uk.com is itself an addressable host.
This method can be used to determine whether a domain is probably the
highest level for which cookies may be set, though even that depends
on individual browsers' implementations of cookie controls. See RFC
2109 for details.
Putting that together with URL.getHost(), which the original post already contains, gives you:
import com.google.common.net.InternetDomainName;
import java.net.URL;
public class DomainNameMain {
public static void main(final String... args) throws Exception {
final String urlString = "http://www.google.com/blah";
final URL url = new URL(urlString);
final String host = url.getHost();
final InternetDomainName name = InternetDomainName.from(host).topPrivateDomain();
System.out.println(urlString);
System.out.println(host);
System.out.println(name);
}
}
I wrote a method (see below) which extracts a url's domain name and which uses simple String matching. What it actually does is extract the bit between the first "://" (or index 0 if there's no "://" contained) and the first subsequent "/" (or index String.length() if there's no subsequent "/"). The remaining, preceding "www(_)*." bit is chopped off. I'm sure there'll be cases where this won't be good enough but it should be good enough in most cases!
Mike Samuel's post above says that the java.net.URI class could do this (and was preferred to the java.net.URL class) but I encountered problems with the URI class. Notably, URI.getHost() gives a null value if the url does not include the scheme, i.e. the "http(s)" bit.
/**
* Extracts the domain name from {#code url}
* by means of String manipulation
* rather than using the {#link URI} or {#link URL} class.
*
* #param url is non-null.
* #return the domain name within {#code url}.
*/
public String getUrlDomainName(String url) {
String domainName = new String(url);
int index = domainName.indexOf("://");
if (index != -1) {
// keep everything after the "://"
domainName = domainName.substring(index + 3);
}
index = domainName.indexOf('/');
if (index != -1) {
// keep everything before the '/'
domainName = domainName.substring(0, index);
}
// check for and remove a preceding 'www'
// followed by any sequence of characters (non-greedy)
// followed by a '.'
// from the beginning of the string
domainName = domainName.replaceFirst("^www.*?\\.", "");
return domainName;
}
I made a small treatment after the URI object creation
if (url.startsWith("http:/")) {
if (!url.contains("http://")) {
url = url.replaceAll("http:/", "http://");
}
} else {
url = "http://" + url;
}
URI uri = new URI(url);
String domain = uri.getHost();
return domain.startsWith("www.") ? domain.substring(4) : domain;
In my case i only needed the main domain and not the subdomain (no "www" or whatever the subdomain is) :
public static String getUrlDomain(String url) throws URISyntaxException {
URI uri = new URI(url);
String domain = uri.getHost();
String[] domainArray = domain.split("\\.");
if (domainArray.length == 1) {
return domainArray[0];
}
return domainArray[domainArray.length - 2] + "." + domainArray[domainArray.length - 1];
}
With this method the url "https://rest.webtoapp.io/llSlider?lg=en&t=8" will have for domain "webtoapp.io".
val host = url.split("/")[2]
All the above are good. This one seems really simple to me and easy to understand. Excuse the quotes. I wrote it for Groovy inside a class called DataCenter.
static String extractDomainName(String url) {
int start = url.indexOf('://')
if (start < 0) {
start = 0
} else {
start += 3
}
int end = url.indexOf('/', start)
if (end < 0) {
end = url.length()
}
String domainName = url.substring(start, end)
int port = domainName.indexOf(':')
if (port >= 0) {
domainName = domainName.substring(0, port)
}
domainName
}
And here are some junit4 tests:
#Test
void shouldFindDomainName() {
assert DataCenter.extractDomainName('http://example.com/path/') == 'example.com'
assert DataCenter.extractDomainName('http://subpart.example.com/path/') == 'subpart.example.com'
assert DataCenter.extractDomainName('http://example.com') == 'example.com'
assert DataCenter.extractDomainName('http://example.com:18445/path/') == 'example.com'
assert DataCenter.extractDomainName('example.com/path/') == 'example.com'
assert DataCenter.extractDomainName('example.com') == 'example.com'
}
try this one : java.net.URL;
JOptionPane.showMessageDialog(null, getDomainName(new URL("https://en.wikipedia.org/wiki/List_of_Internet_top-level_domains")));
public String getDomainName(URL url){
String strDomain;
String[] strhost = url.getHost().split(Pattern.quote("."));
String[] strTLD = {"com","org","net","int","edu","gov","mil","arpa"};
if(Arrays.asList(strTLD).indexOf(strhost[strhost.length-1])>=0)
strDomain = strhost[strhost.length-2]+"."+strhost[strhost.length-1];
else if(strhost.length>2)
strDomain = strhost[strhost.length-3]+"."+strhost[strhost.length-2]+"."+strhost[strhost.length-1];
else
strDomain = strhost[strhost.length-2]+"."+strhost[strhost.length-1];
return strDomain;}
There is a similar question Extract main domain name from a given url. If you take a look at this answer , you will see that it is very easy. You just need to use java.net.URL and String utility - Split
One of the way I did and worked for all of the cases is using Guava Library and regex in combination.
public static String getDomainNameWithGuava(String url) throws MalformedURLException,
URISyntaxException {
String host =new URL(url).getHost();
String domainName="";
try{
domainName = InternetDomainName.from(host).topPrivateDomain().toString();
}catch (IllegalStateException | IllegalArgumentException e){
domainName= getDomain(url,true);
}
return domainName;
}
getDomain() can be any common method with regex.
private static final String hostExtractorRegexString = "(?:https?://)?(?:www\\.)?(.+\\.)(com|au\\.uk|co\\.in|be|in|uk|org\\.in|org|net|edu|gov|mil)";
private static final Pattern hostExtractorRegexPattern = Pattern.compile(hostExtractorRegexString);
public static String getDomainName(String url){
if (url == null) return null;
url = url.trim();
Matcher m = hostExtractorRegexPattern.matcher(url);
if(m.find() && m.groupCount() == 2) {
return m.group(1) + m.group(2);
}
return null;
}
Explanation :
The regex has 4 groups. The first two are non-matching groups and the next two are matching groups.
The first non-matching group is "http" or "https" or ""
The second non-matching group is "www." or ""
The second matching group is the top level domain
The first matching group is anything after the non-matching groups and anything before the top level domain
The concatenation of the two matching groups will give us the domain/host name.
PS : Note that you can add any number of supported domains to the regex.
If the input url is user input. this method gives the most appropriate host name. if not found gives back the input url.
private String getHostName(String urlInput) {
urlInput = urlInput.toLowerCase();
String hostName=urlInput;
if(!urlInput.equals("")){
if(urlInput.startsWith("http") || urlInput.startsWith("https")){
try{
URL netUrl = new URL(urlInput);
String host= netUrl.getHost();
if(host.startsWith("www")){
hostName = host.substring("www".length()+1);
}else{
hostName=host;
}
}catch (MalformedURLException e){
hostName=urlInput;
}
}else if(urlInput.startsWith("www")){
hostName=urlInput.substring("www".length()+1);
}
return hostName;
}else{
return "";
}
}
To get the actual domain name, without the subdomain, I use:
private String getDomainName(String url) throws URISyntaxException {
String hostName = new URI(url).getHost();
if (!hostName.contains(".")) {
return hostName;
}
String[] host = hostName.split("\\.");
return host[host.length - 2];
}
Note that this won't work with second-level domains (like .co.uk).
// groovy
String hostname ={url -> url[(url.indexOf('://')+ 3)..-1].split('/')[0] }
hostname('http://hello.world.com/something') // return 'hello.world.com'
hostname('docker://quay.io/skopeo/stable') // return 'quay.io'
const val WWW = "www."
fun URL.domain(): String {
val domain: String = this.host
return if (domain.startsWith(ConstUtils.WWW)) {
domain.substring(ConstUtils.WWW.length)
} else {
domain
}
}
I use regex solution
public static String getDomainName(String url) {
return url.replaceAll("http(s)?://|www\\.|wap\\.|/.*", "");
}
It cleans url from "http/https/www./wap." and from all unnecessary things after / like "/questions" in "https://stackoverflow.com/questions" and we get just "stackoverflow.com"