Android Date format. from string to Date - java

I have a string like this: 2015-01-31 16:00:00 +0000 UTC, I want to parse this string to date object.
yyyy-MM-dd HH:mm:ss 'UTC'
but failed.

You can use the SimpleDateFormat for formatting the strings to date objects:
DateFormat originalFormat = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss+z", Locale.ENGLISH);
DateFormat targetFormat = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
Date date = null;
try {
date = originalFormat.parse("2015-01-31 16:00:00 +0000");
String formattedDate = targetFormat.format(date);
} catch (ParseException e) {
e.printStackTrace();
}

Related

How to print date in GMT format? [duplicate]

I have a string "2014-07-02T17:12:36.488-01:00" which shows the Mountain time zone. I parsed this into java.util.date format. Now I need to convert this to GMT format. Can anyone help me??
SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss");
Object dd = null;
try {
dd=sdf.parseObject("2014-07-02T17:12:36.488-01:00");
System.out.println(dd);
} catch (ParseException e) {
e.printStackTrace();`enter code here`
}
SimpleDateFormat gmtDateFormat = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
gmtDateFormat.setTimeZone(java.util.TimeZone.getTimeZone("GMT"));
System.out.println("Current Date and Time in GMT time zone:+ gmtDateFormat.format(dd));
There are a few problems in your code. For example, the format string doesn't match the actual format of the string you are parsing.
SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss.SSSX");
Object dd = null;
try {
dd = sdf.parse("2014-07-02T17:12:36.488-01:00");
System.out.println(dd);
} catch (ParseException e) {
e.printStackTrace();
}
SimpleDateFormat gmtDateFormat = new SimpleDateFormat("yyyy-MM-dd HH:mm:ssX");
gmtDateFormat.setTimeZone(java.util.TimeZone.getTimeZone("GMT"));
System.out.println("Current Date and Time in GMT time zone:" + gmtDateFormat.format(dd));
To print the current date in whatever timezone you like, set the timezone you want to use on the SimpleDateFormat object. For example:
// Create a Date object set to the current date and time
Date now = new Date();
DateFormat df = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss.SSSX");
df.setTimeZone(TimeZone.getTimeZone("GMT"));
System.out.println("Current date and time in GMT: " + df.format(now));
df.setTimeZone(TimeZone.getTimeZone("IST"));
System.out.println("Current date and time in IST: " + df.format(now));

Solving Parse Date Exception

i have a string "12/3/2014 12:00:00 AM" and i want to cast this string in date which have format like this "yyyy-MM-dd HH:mm:ss"
#DatabaseField(columnName="out_date",dataType=DataType.DATE_STRING,format="yyyy-MM-dd HH:mm:ss")
private Date out_date;
above is the object to get value from date string
SimpleDateFormat formater = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
outlet.setOut_date(formater.parse(json.getString("outletDate")));
after i using like the error occur java.text.ParseException: Unparseable date: ... (at offset 2) how to solve that problem thank in advance
Based on this answer, you need something like this. First convert your string in its present format to a date object, then reformat the date object.
String date = "12/3/2014 12:00:00 AM";
SimpleDateFormat sdf = new SimpleDateFormat("mm/dd/yyyy HH:MM:SS a");
Date testDate = null;
try {
testDate = sdf.parse(date);
}catch(Exception ex){
ex.printStackTrace();
}
SimpleDateFormat formatter = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
String newFormat = formatter.format(testDate);
System.out.println(".....Date..."+newFormat);
Conversion steps :
Create date object from your date format.
Target date format provide to SimpleDateFormat class constructor.
Parse date using SimpleDateFormat.
The code provided convert yyyy-MM-dd HH:mm:ss to dd/mm/yyyy HH:mm:ss format.
try {
SimpleDateFormat sdf1 = new SimpleDateFormat("dd/mm/yyyy HH:MM:SS a");
Date date = sdf1.parse("12/3/2014 12:00:00 AM");
String format = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss").format(date);
System.out.println(format);
}catch(Exception e){
e.printStackTrace();
}
Error : java.text.ParseException: Unparseable date: ... (at offset 2) indicates that you are using wrong date format to parse your sting.

i want to convert date fromat: "mm/dd/yyyy hh:mm" to "yyyy-mm-dd hh:mm:ss"

Response from jsp is coming in this format: "mm/dd/yyyy hh:mm", and I want to convert to db format "yyyy-mm-dd hh:mm:ss".
I tried this code :
public java.sql.Date getdateFormat(String datestring) throws ParseException {
String datestr = "";
try {
java.util.Date date = new SimpleDateFormat("mm/dd/yyyy hh:mm a",
Locale.ENGLISH).parse(datestring);
atestr = new SimpleDateFormat("yyyy-MM-dd hh:mm:ss").format(date);
} catch (Exception e) {
e.printStackTrace();
}
return getDateFromString(datestr);
}
public java.sql.Date getDateFromString(String string) {
SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd hh:mm:ss");
java.util.Date finalDate = null;
try {
finalDate = sdf.parse(string);
} catch (Exception e) {
e.printStackTrace();
}
return new java.sql.Date(finalDate.getTime());
}
A common mistake in using SimpleDateFormat is skip the documentation and assume that is knows when mm means months and when mm mean minutes. It doesn't. mm only means minutes. If you want months use MM Also only use a if you expect AM/PM and only use hh for 12 hour clocks. I would expect your format should read
MM/dd/yyyy HH:mm
and your output
yyyy-MM-dd HH:mm:ss
BTW You shouldn't need to convert to a String to use JDBC. Using a Date is faster and less error prone.
If all you want is the Date then you do not need to do
atestr=new SimpleDateFormat("yyyy-MM-dd hh:mm:ss").format(date);
simply return the date as this stage.
A date does not have any formatting, it is basically a number.
I would basically do it like this
String dateInString = "20140611";
SimpleDateFormat sdf = new SimpleDateFormat("yyyyMMdd");
Date toDate = sdf.parse(dateInString);
sdf = new SimpleDateFormat("yyyy-MM-dd");
String tmpStr = String.format(sdf.format(toDate));
System.out.println(tmpStr);
We can get the date in the following way
DateFormat dfm = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
Date parseDate = dfm.parse(datestring);
Now the parseDate is in the format "yyyy-MM-dd HH:mm:ss"

Parse Datetime to JAVA Date

im getting the SQL Server datetime (1 Jan 2013) form the SqlRowSet like
while (rs.next()) {
myBean.setDateProp(rs.getString(4));
}
the type of myBean DateProp is java.util.Date, is there a way to convert (1 Jan 2013) to java Date representation.
i have tried the following code
SimpleDateFormat sdf = new SimpleDateFormat("dd-MMM-yyyy HH:mm:ss.SSS");
Date date=new Date();
try {
date = sdf.parse("1 Jan 2013");
} catch (Exception e) {
e.printStackTrace();
}
and i get the ParseException
SEVERE: java.text.ParseException: Unparseable date: "1 Jan 2013"
any directions...
try this -
SimpleDateFormat sdf = new SimpleDateFormat("dd MMM yyyy");
Date date=new Date();
try {
date = sdf.parse("1 Jan 2013");
}catch (Exception e) {
e.printStackTrace();
}
Try
while (rs.next()) {
myBean.setDateProp(rs.getDate(4));
}
#Test
public void test() throws ParseException {
String dateString = "1 Jan 2013";
String dateString2 = "11 Jan 2013";
SimpleDateFormat sdf = new SimpleDateFormat("d MMM yyyy");
sdf.parse(dateString);
sdf.parse(dateString2);
}
You need to modify your Date formatter string to
SimpleDateFormat sdf = new SimpleDateFormat("dd MMM yyyy");
as your date string is in this format

Convert EST time to local Time in java

I'm unable to convert (12/19/2012 8:57am EST) to local Time (now Indian Time).
While converting I'm getting wrong time (Dec 19 2012 11:27). I'm using the following code:
private void convertEdtToLocalTime(String pubDate)
{
//pubDate = 12/19/2012 8:57am EST;
String localPubDate;
try
{
SimpleDateFormat sdf = new SimpleDateFormat(
"MM/dd/yyyy HH:mma z");
TimeZone timeZone = TimeZone.getDefault();
sdf.setTimeZone(timeZone);
if (pubDate != null)
{
Date date = sdf.parse(pubDate);
sdf = new SimpleDateFormat("MMM dd yyyy HH:mm");
localPubDate = sdf.format(date);
}
}
catch (ParseException e)
{
}
}
You dont need to set the timeZone as the the time zone is already specified in the pubDate string. When you want to format using different SDF, the default timezone will convert it into default timezone itself. For eg. if you are in india, IST time = Dec 19 2012 19:27
private static void convertEdtToLocalTime(String pubDate)
{
//pubDate = 12/19/2012 8:57am EST;
String localPubDate=null;
try
{
SimpleDateFormat sdf = new SimpleDateFormat(
"MM/dd/yyyy HH:mma z");
// TimeZone timeZone = TimeZone.getDefault(); // No need to do it
// sdf.setTimeZone(timeZone);
if (pubDate != null)
{
Date date = sdf.parse(pubDate);
sdf = new SimpleDateFormat("MMM dd yyyy HH:mm");
localPubDate = sdf.format(date);
}
}
catch (ParseException e)
{
}
System.out.println(localPubDate);
}

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