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cant find the element using classname in selenium java

I'am using selenium framework to test my own website. Im trying to click on specific icon which using anchor tag. I have java selenium code to click but couldn't click. Tried many xpath, css selectors, class name and names. but didn't worked. But can run the script and it is opening the chrome and navigating to entered domain but the clicking option is not working
above code I need to click nav-twitter class anchor option . which will create another tab in chrome to show my twitter page. but after running the app .it is only navigating to the page domain and nothing works.
So, This is my code where I have added. until the maximize everything works but not the anchor tag
This kind of error im getting when running the script in chrome. Please anyone let me know where I have been wrong here or is there are any way to make it happen. Thanks in advance.

Whenever you are initiating webdriver make sure to add implicit wait statement, so it can wait for sometime before looking for objects. Add below statement right after chromedriver initialization and your code should work without any issues.
driver.manage().timeouts().implicitlyWait(10, TimeUnit.SECONDS);

Your locator is slightly off. In your code you are looking for an element with tagName as twitter which doesn't exists. Instead you can use either of the following locator strategies:
Using cssSelector:
WebElement navTwitter = driver.findElement(By.cssSelector("a.nav-twitter[name='twitter']"));
navTwitter.click();
Using xpath:
WebElement navTwitter = driver.findElement(By.xpath("//a[#class='nav-twitter' and name='twitter']"));
navTwitter.click();

You have used wrong selector/locator here. "twitter" is not tag name, Tag name is the value from less than symbol to the first space or greater than symbol. Words like div, p, a, span are the tag names.
So here a is the tag name and name, class, href are attribute which you can use while forming xpath or css locators. So you can create multiple locators here:
By using class name attribute
By.className("nav-twitter");
By creating xpath using name attribute
By.xpath("//a[#name='twitter']");]
By creating xpath using class attribute
By.xpath("//a[#class='nav-twitter']");
By creating css locator using class attribute.
By.cssSelector("a[class*='nav-twitter']");
By using dot symbol in css selector with class name
By.cssSelector("a.nav-twitter");
Similarly you can create css selector with name too. Since there are multiple tags, so you can not use a tag directly and If you want to use By.tagName("a") then it will click on first tag present on the page
Note: We use dot with class name and Hash (#) with Id name while forming css selectors.

How to click a button where the class is the same for another options?

I am trying to click a button from a list but this button has the same class than others in the list because they have the same name (btn ban-red) so how can I click it if in the inspect I have this information:
<a class=“btn ban-red” data-track-event=“navigate” data-track=name=“Jobylon” - Quality Engineer” href=“https://emp.jobylon.com/jobs/16654-f/” target=“_blank”>View job/a>
The inspect is copying this xpath:
/html/body/div[1]/div[4]/div/div/div/div[3]/div/div/div/div[1]/section/div/div[2]/div[1]/div[1]/article[14]/a
But it is not working
I also created my own xpath this way:
wait.until(ExpectedConditions.elementToBeClickable(By.xpath("//a[#data-track-name=‘Jobylon - Quality Engineer’]"))).click();
But is not working either
I am using Selenium with java and I am in a Macbook, thank you for your help.

Absolute xpath not recommended. You can try using relative xpath.
Locate based on element text
driver.findElement(By.xpath("//a[contains(.,'View job')]")).click()
Locate using combination of element attribute if classes are not unique
driver.findElement(By.xpath("//a[#class='btn ban-red'][#data-track-event='navigate']")).click()
OR
driver.findElement(By.xpath("//a[#class="btn ban-red"][#href='https://emp.jobylon.com/jobs/16654-f/']")).click()
Better to use CSS selector as its faster then xpath. So you try like
driver.findElement(By.cssSelector("a[class='btn ban-red'][data-track-event='navigate']")).click()
OR
driver.findElement(By.cssSelector("a[class="btn ban-red"][href='https://emp.jobylon.com/jobs/16654-f/']")).click()
Still facing some issue like element not visible or no such element then try with explicit wait conditions until your element gets visible or clickable.

Selenium: find part of identifier

The next command does not work
wd.findElement(By.id("post_message_*"));
The goal is to find id's with post_message_3456346, post_message_01548 and so on. How to fix it?
Actulay there is only one id on page which starts with "post_message_".

Try to locate required element by XPath as below:
wd.findElement(By.xpath("//*[starts-with(#id, 'post_message_')]"));
or by CSS selector
wd.findElement(By.cssSelector("*[id^='post_message_']"));

Try using a css Selector
wd.findElement(By.cssSelector("[id^='post_message_']"));

How can I get text from element with Selenium webdriver and Java?

My code:
WebDriver driver = new SafariDriver();
driver.get("http://bet.hkjc.com/football/default.aspx");
WebElement matchs = driver.findElement(By.cssSelector("span.Head to Head"));
System.out.println(matchs);
driver.quit();
How can I crawl Manchester Utd and Celta Vigo?

WebElement matchs = driver.findElement(By.xpath("//a[#title='Head to Head']"));
System.out.println(matchs.getText());

Use firebug and firepath addons in firefox and inspect that element and get the xpath and put it here inside double quotes in this code :
System.out.println(driver.findElement(By.xpath("")).getText());
If you don't know how to use firebug and firepath refer this link

You can locate the element either by css selector or xpath selector
By using xpath
driver.findElement(By.xpath("//a[#title='Head to Head']"));
By using css Selector
driver.findElement(By.cssSelector("span > a[title='Head to Head']"));
OR Try somethings like this if not getting the match
driver.findElement(By.cssSelector("td.cteams.ttgR2>span>a[title='Head to Head']"));
Note : in your code you are trying like span.Head to Head in CSS selector . dot represents the class and according to your path you are locating span tag which have class name "Head to Head" which doesn't exist in your dom as this is the title of anchor tag.
Went through the Firebug and Firepath plugins of Firefox initially to get the Xpath or css path
Explore some blogs to get clear understanding, you will be able to create by yourself
Refer This link for the same

I assume all the above answers doesn't work for you and am providing another answer.
I can see both the texts are under "a" tag. So the idea is to navigate to the element and use getText() - which returns the visible text.
String word = driver.findElement(By.xpath("//span/a")).getText();
System.out.println(word);
Hope this works for you.

In all of my tests I'm using the getAttribute like this to get text and it is working fine for me on all drivers :
assertEquals(strCity, txtCity.getAttribute("value"));

How to deal with Dynamically changing class names in HTML source code while automating using Selenium WebDriver

How to deal with Dynamically changing "class names" or "ids" in HTML source code while automating using Selenium WebDriver
Example Application : GMAIL

if you know the cell index then using XPath or cssSelector will solve the issue. Here in the above screenshot it is clear that the text "Wordpress" is in 5th cell of each table row/so you can use below XPath to get the particular cell.
List<WebElement> cellValue = driver.findElements(By.xpath(".//table/descendant::tr/following-sibling::td[5]"));

The Selenium mechanism for locating elements (org.openqa.selenium.By) offers other methods of locating elements.
Example: name, partialLinkText, css selector, xpath selector, tagname, linkText.
This tutorial from Selenium Easy contains some easy to understand examples.

If you want to locate <span name="WordPress">WordPress</span> element, You can locate this element using By.name() as below :-
driver.findElement(By.name("WordPress"));