I am currently working on trying to deploy my java web application onto Openshift. My web application imports Gurobi library which requires a Gurobi License Environment to run my Linear Programming model. As such i've been going around trying everything i can to get the license installed to the openshift linux server etc
I've managed to get a few things going.
I've SSH into my application and registered the HostName of the openshift linux platform to the license.
I've managed to change the .bash_profile file which sets up the custom environments. below are the input i have placed into the file.
export GUROBI_HOME="/var/lib/openshift/54d4e281e0b8cd3a1400015c/jbossews/gurobi600/linux64"
export PATH="${PATH}:${GUROBI_HOME}/bin"
export LD_LIBRARY_PATH="${LD_LIBRARY_PATH}:${GUROBI_HOME}/lib"
export GRB_LICENSE_FILE="/var/lib/openshift/54d4e281e0b8cd3a1400015c/jbossews/gurobi.lic"
The problem with the input above is that I believe for PATH & LD_LIBRARY_PATH, openshift automatically reinstates them everytime I access my app through the shell.
I think this has resulted in my application being unable to instanciate a GRBENV object which is a Gurobi Environment object which checks the gurobi.lic file and use the LD_LIBRARY_FILE.
Has anyone did something similar to this before? Really need help in this.
Brandon
The way openshift instantiates your app and the ssh shell seems to be different. The correct place to set the environment variables are one of the start action_hooks. For instance, if you edit the .openshift/action_hooks/start file and add:
export PATH="${PATH}:${GUROBI_HOME}/bin"
this will work for the instance that runs your APP, but not for the SSH Shell. I did the following test:
echo $PATH > $OPENSHIFT_DATA_DIR/PATH
to confirm that the path running the APP can be set by the start hook.
I´m not sure if this solves your question (because you mention SSH shell, and I still don´t know how to set the PATH for that).
Related
Here's what I do in SpringBoot on Windows to read an environment variable (location of log folder).
In Windows Server, I set a System environment variable for "LOG_HOME" with the value with the directory that SpringBoot should use to write logs.
In SpringBoot's application.properties, I have:
logging.file.name= ${LOG_HOME}/ws.log
Works great!
But in Ubuntu Linux 20.04, the same approach doesn't work for me at all.
When the WAR file tries to deploy on Ubuntu 20.04 using this similar technique:
(in .bashrc): export LOG_HOME = /home/ubuntu/logs
reboot (to reload the environment for sure)
I get this error in the Tomcat log when trying to deploy the WAR file:
java.lang.IllegalArgumentException: Could not resolve placeholder 'LOG_HOME' in value "${LOG_HOME}/ws.log"
So, it seems that Spring doesn't see the environment variable set in Ubuntu.
I wrote a simple Java program just to check the value of the environment variables and they were all created as expected including the LOG_HOME as shown in Linux "printenv".
If possible, I need a technique that will work on Ubuntu without changing the working SpringBoot implementation on Windows Server.
Thanks in advance for suggestions.
Instead of exporting in shell session like
export LOG_HOME = /home/ubuntu/logs
try this as -D VM argument in your starup command
eg:
java -cp=xxx mainclass -DLOG_HOME=/home/ubuntu/log
if you are using tomcat then :
VM args can be added catalina.sh file under CATALINA_OPTS.
For tomcat, add your environment variables to $TOMCAT_HOME/bin/setenv.sh where $TOMCAT_HOME is the directory of your tomcat installation.
The solution for me posted by the extremely helpful satyesht above, was to edit the Catalina.sh file and add the "-D" name-value pair option under CATALINA_OPTS. Thanks to all who posted. :)
I have some question when using jenkins.
the scenario:
I have installed a tomcat on machine A,and config all necessary environment including JDK, and they work well.
I wrote a shell script named restart.sh to kill the tomcat process,and restart.
I execute the script and it works well.When I check the tomcat process using ps -ef，and it shows the exact JDK path as I already config.The JDK path is /usr/local/java/JDK7
When I execute the restart.sh script via jenkins,problem comes. I can see the tomcat process using the wrong JDK path,/usr/bin/java,not the path as i config. I use SSH Publishers plugin to run the remote script.see as the image below:
enter image description here
I don't know how this problem happen,please help,Thanks all
This might be the problem of path variables, just to cross verify , find JAVA_HOME on your server 1. By logging onto server manually 2. From Exec command of your ssh section of your jenkins job , most probably you will find the answer.
i'm assuming you're jenkins is configured to use jdk which is defined at its root level.
if this didn't solve , we need to look into this problem from another angle.
I have a java application, which has to run as windows service.
I am able to install the service using the following command.
"%EXECUTABLE%" //IS//%SERVICE_NAME% --StartClass %STARTER% --StopClass %STOPPER% %START_PARAMS% %STOP_PARAMS%
The service is installed successfully but when i try to run it it shows Failed to create java. path also it is not showing in the jkartha log file.
I have JAVA_HOME environment variable pointing to jdk1.5.
and even i copied msvcr71.dll to windows\system32 folder and restarted the PC.
I am running this on windows 2008 server.
I didn't install apache tomcat server. prunsrv.exe and procmgr.exe i just copied.
Please suggest me how i need to overcome this problem.
whether to run application as windows service, prunsrv.exe, prunmgr.exe are enough is it? I am able to successfully install but not able to start why???
You probably need to set your service to run as the user that installed Java, otherwise it won't find its environment variables.
If you must run in the default Local System account, then you can run a batch file that sets up the environment and then launches java.exe.
I am a newbie to Ubuntu 12.10 and moved to it from Windows.
In Windows I have configured the environment variable to include servlet-api.jar in the CLASSPATH variable so I do not have to type -cp <path to servlet-api.jar> every time I compile.
For normal Java programs, I have set the JAVA_HOME using:
export JAVA_HOME="/usr/lib/jvm/java-7-openjdk-i386" >> ~/.bashrc
With that solved, I need to set the CLASSPATH but do not know how to.
Please help on that!
Also I read on some forums that I should change the CLASSPATH manually each time I compile because changing the CLASSPATH may upset other applications.
Next, I tried this command to start Tomcat
service tomcat7 start but I got an error :
You need root privileges to run this script I do not know why. Help me solve that!
And if within the scope, please tell me how the directory structure of tomcat in Windows differs from that in Ubuntu.
Misc
I used sudo apt-get install tomcat7 to get Tomcat 7.
You don't say whether you're using an Ubuntu Tomcat package or a standalone Tomcat installation.
For a standalone Tomcat, you will be starting and stopping it using the scripts in its bin directory: startup.sh and shutdown.sh. In that case, Tomcat will use the environment variable values set at the time of invocation.
When doing this, you can set the environment variables prior to running these commands.
The same is true for the Tomcat 6 or Tomcat 7 that Ubuntu distributes as packages.
These neatly separate the $CATALINA_HOME directory (where the Tomcat 7 distribution is supposed to be) from the $CATALINA_BASE directory (where all of the changes and additions for a particular Tomcat instance are supposed to be. For the tomcat7 package, the first directory is /usr/share/tomcat7, while the second is /var/lib/tomcat7.
You can find startup.sh and shutdown.sh in /usr/share/tomcat7/bin and of course you can use them.
However, if you use the Tomcat provided with Ubuntu, you're probably going to want to run it just like any other standard system service, and the packages support this: e.g. in the case of tomcat7, you can just use
sudo service tomcat7 status
sudo service tomcat7 start
sudo service tomcat7 stop
sudo service tomcat7 restart
just like you can for any system service, and it uses the same mechanism as other system services do:
the shell script /etc/init.d/tomcat7 is used to start and stop Tomcat 7
/etc/default/tomcat7 is its configuration file, allowing a few parameters to be set
Using this method, you cannot specify additional environment variables for Tomcat to use by setting them in your shell or in /etc/default/tomcat7; they will not be passed to Tomcat.
However, there is a second method to set environment variables: if you set them in the shell script /var/lib/tomcat7/bin/setenv.sh (or, if you must, /usr/share/tomcat7/bin/setenv.sh), they will be picked up and passed to Tomcat. This method always works.
Finally, Tomcat offers finer control than just using a $CLASSPATH when it comes to specifying additional classes or JARs to be loaded on startup: in its conf/catalina.properties configuration file, you can set the common.loader, server.loader and shared.loader to a list of directories and/or JAR files to be loaded in additional to the standard ones.
All it means is that you should do that as a superuser - which translates to administrator in windows so you should try something like sudo service tomcat7 start
Try export CLASSPATH=/usr/share/tomcat7/lib/servlet-api.jar:/usr/share/tomcat7/lib/jsp-api.jar - This will depend on where your tomcat installation in located.
You can get more here
Cheers
There are numerous places on the Internet, suggesting that it is easily achieved by any (or all) of the following methods:
through CATALINA_OPTS
through JAVA_OPTS
through TOMCAT_OPTS
by placing the set statements in the setenv.bat file inside the tomcat's bin folder
My problem, is that I have tried all of the above and my web application still does not see my system property!
Here is what I am doing:
Stop tomcat7 service
set CATALINA_OPTS=-Dabc.def=true in the system environment
set JAVA_OPTS=-Dabc.def=true in the system environment
set TOMCAT_OPTS=-Dabc.def=true in the system environment
put all of the above into c:\Program Files\Apache Software Foundation\Tomcat 7.0\bin\setenv.bat (seems totally redundant, but just in case)
Start tomcat7 service
Inspect the environment of the tomcat7 process using the Process Explorer tool - the environment is correct, I do see both CATALINA_OPTS and JAVA_OPTS and TOMCAT_OPTS equal to -Dabc.def=true
run my web app, which is a simple servlet dumping all the system properties to the response stream - abc.def is not amongst them
Please, put me out of my misery and tell me how to do it.
For the Tomcat service, startup settings are stored in the registry under Options key at:
HKEY_LOCAL_MACHINE\SOFTWARE\Apache Software Foundation\Procrun 2.0\Tomcat<X>\Parameters\Java
(substitute appropriate Tomcat version where needed).
Edit:
On 64-bit Windows, the registry key is:
HKEY_LOCAL_MACHINE\SOFTWARE\Wow6432Node\Apache Software Foundation\Procrun 2.0\Tomcat<X>\Parameters\Java
even if Tomcat is running under a 64-bit JVM.
I know this post is almost 9 years old but thought someone might find this useful.
Although #prunge and #mark answers were very accurate and following their logic I was able to add system properties to my tomcat 7 instance running on Windows, there is an easier way.
In the installation directory of Tomcat there is an exe you can run called
%INSTALL_DIRECTORY%\bin\tomcat7w.exe
This opens up a Tomcat properties windows where you can control the service i.e. start and stop tomcat and there is a tab (Java) that allows you to set the Java properties as well
Scroll to the end of that panel under "Java Options" and add your system properties
-Dpropertyname=value
Then navigate back to the General tab and restart tomcat
I have tested this and my grails app now can see my properties. I use the following Groovy code to get the property out
System.properties.getProperty("propertyname")
Adding the system properties in the Windows registry showed up in this window as well so its one and the same thing, just this application seems to me to be slightly more convenient.
Hope this helps someone else