I have an ArrayList with several objects per index. I want to sort this list alphanumerically by one object in particular. The object is "my_id" and the values for this object can look similar to: 1A, 10B, 11B, 2C, 205Z, etc.
I need to sort these to come out: 1A, 2C, 10B, 11B, 205Z. Where the numeric part is sorted first, then the alpha- part is sorted secondary. 1,2,3,4,5,... A,B,C,D,E,...
I checked out some alphanumeric string sorting that worked really well:
http://sanjaal.com/java/206/java-data-structure/alphanumeric-string-sorting-in-java-implementation/
Unfortunately I can only get that object to sort and I lose the other objects in my ArrayList as a consequence. I really need a sorting algorithm that can rearrange the ArrayList index's by the object of my choosing and not lose the other objects!
Is there a method to do this already out there? I've been unable to find one. I think it's useful to add that all the objects in my ArrayList are mapped strings: ArrayList<HashMap<String, String>>
[edit]
I have my array:
ArrayList<HashMap<String, String>> al
I then store the object:
String[] alphaNumericStringArray = new String[al.size()];
for(int i = 0; i < al.size(); i++)
{
alphaNumericStringArray[i] = al.get(i).get("my_id");
}
I now sort the string array:
// Sort the array now.
Arrays.sort(alphaNumericStringArray, new AlphanumericSorting());
I then put the object back:
for(int i = 0; i < al.size(); i++)
{
HashMap<String, String> map = new HashMap<String, String>();
map.put("my_id", alphaNumericStringArray[i]);
// TODO, need to append the rest of the objects.
al.set(i, map);
}
I know what you're thinking, I'm not adding all the objects BACK when I re-map it. This is what I have currently, but what I want is a way to sort the whole list not just the one object "my_id". I want to rearrange the indexes so I don't have to re-map everything at the end.
Running the main method:
import java.util.Arrays;
import java.util.Collections;
import java.util.Comparator;
import java.util.List;
public class Sorter {
public static void main(String[] args) {
List<String> unsorted = Arrays.asList("1A", "10B", "B", "753c", "Z", "M7", "32x", "11B", "2C", "205Z");
Collections.sort(unsorted, new Comparator<String>() {
#Override
public int compare(String o1, String o2) {
if (o1.isEmpty())
return -1;
if (o2.isEmpty())
return 1;
String o1number = extractNumberPrefix(o1);
String o2number = extractNumberPrefix(o2);
if (o1number.isEmpty())
if (o2number.isEmpty())
return o1.compareTo(o2);
else return 1;
if (o2number.isEmpty())
return -1;
if (o1number.equals(o2number))
return o1.compareTo(o2);
return Integer.parseInt(o1number) - Integer.parseInt(o2number);
}
private String extractNumberPrefix(String o1) {
String result = "";
for (int i = 0; i < o1.length(); i++) {
try {
Integer.parseInt(o1.substring(i, i + 1));
result += o1.substring(i, i + 1);
} catch (Exception e) {
break;
}
}
return result;
}
});
System.out.println("sorted = " + unsorted);
}
}
returns:
sorted = [1A, 2C, 10B, 11B, 32x, 205Z, 753c, B, M7, Z]
After careful reconstruction of the Comparator and all the comments I finally figured out how to do this.
Question:
To reiterate what my goal is, as well as the solution. I have an ArrayList<HashMap<String, String>>. I want to sort the ArrayList by one object in the HashMap. My HashMap has more than 1 object in it so I want to retain the entire index of the Array. I also want to sort alphanumerically where numeric values are the first to be sorted, than I sort alphabetically. i.e., 1,2,3,4,... A,B,C,D,...
References:
http://sanjaal.com/java/206/java-data-structure/alphanumeric-string-sorting-in-java-implementation/
TL;DR Solution:
In my custom Comparator function public int compare(object firstObj, Object secondObj) I needed to change the String values to HashMap object references/values. Here the KEY_ID is the object that I wanted to sort by. Once I did this I used Collections.sort to sort by the HashMap comparator rather than the Arrays.sort (Collections handles ArrayList/HashMaps).
Code Solution:
import java.util.ArrayList;
import java.util.Collections;
import java.util.Comparator;
import java.util.HashMap;
/**
* DOCUMENTATION:
* http://sanjaal.com/java/206/java-data-structure/alphanumeric-string-sorting-in-java-implementation/
**/
#SuppressWarnings({"rawtypes", "unchecked"})
public class AlphanumericSorting implements Comparator
{
public int compare(Object firstObjToCompare, Object secondObjToCompare)
{
String firstString = ((HashMap<String,String>) firstObjToCompare).get("KEY_ID");
String secondString = ((HashMap<String,String>) secondObjToCompare).get("KEY_ID");
//String firstString = firstObjToCompare.toString();
//String secondString = secondObjToCompare.toString();
if (secondString == null || firstString == null)
{
return 0;
}
int lengthFirstStr = firstString.length();
int lengthSecondStr = secondString.length();
int index1 = 0;
int index2 = 0;
while(index1 < lengthFirstStr && index2 < lengthSecondStr)
{
char ch1 = firstString.charAt(index1);
char ch2 = secondString.charAt(index2);
char[] space1 = new char[lengthFirstStr];
char[] space2 = new char[lengthSecondStr];
int loc1 = 0;
int loc2 = 0;
do
{
space1[loc1++] = ch1;
index1++;
if (index1 < lengthFirstStr)
{
ch1 = firstString.charAt(index1);
}
else
{
break;
}
}
while (Character.isDigit(ch1) == Character.isDigit(space1[0]));
do
{
space2[loc2++] = ch2;
index2++;
if (index2 < lengthSecondStr)
{
ch2 = secondString.charAt(index2);
} else
{
break;
}
}
while (Character.isDigit(ch2) == Character.isDigit(space2[0]));
String str1 = new String(space1);
String str2 = new String(space2);
int result;
if (Character.isDigit(space1[0]) && Character.isDigit(space2[0]))
{
Integer firstNumberToCompare = new Integer(Integer.parseInt(str1.trim()));
Integer secondNumberToCompare = new Integer(Integer.parseInt(str2.trim()));
result = firstNumberToCompare.compareTo(secondNumberToCompare);
}
else
{
result = str1.compareTo(str2);
}
if (result != 0)
{
return result;
}
}
return lengthFirstStr - lengthSecondStr;
}
/**
* ALPHANUMERIC SORTING
*/
public static ArrayList<HashMap<String, String>> sortArrayList(ArrayList<HashMap<String, String>> al)
{
Collections.sort(al, new AlphanumericSorting());
return al;
}
}
To return the sorted ArrayList:
myArrayList = AlphanumericSorting.sortArrayList(myArrayList);
Where,
ArrayList<HashMap<String, String>> myArrayList;
Related
I need to compare the roman letters and get the correct integer out of it.
If I'm correct, there should be a way to compare the hashmap key with the arraylist element and if they match, get the associated value from the key.
The return 2020 is there just for test purposes, since I wrote a JUnit test in a different class. It can be ignored for now.
I hope someone could give me a hint, since I wouldn't like to use the solutions from the web, because I need to get better with algorithms.
package com.company;
import java.util.*;
public class Main {
static HashMap<String, Integer> romanNumbers = new HashMap<String, Integer>();
static {
romanNumbers.put("I", 1);
romanNumbers.put("V", 5);
romanNumbers.put("X", 10);
romanNumbers.put("L", 50);
romanNumbers.put("C", 100);
romanNumbers.put("D", 500);
romanNumbers.put("M", 1000);
}
public static void main(String[] args) {
romanToArabic("MMXX");
}
static int romanToArabic(String roman) {
ArrayList romanLetters = new ArrayList();
roman = roman.toUpperCase();
for (int i = 0; i < roman.length(); i++) {
char c = roman.charAt(i);
romanLetters.add(c);
}
// [M, M, X, X]
System.out.println(romanLetters);
// iterates over the romanLetters
for (int i = 0; i < romanLetters.size(); i++) {
System.out.println(romanLetters.get(i));
}
// retrive keys and values
for (Map.Entry romanNumbersKey : romanNumbers.entrySet()) {
String key = (String) romanNumbersKey.getKey();
Object value = romanNumbersKey.getValue();
System.out.println(key + " " + value);
}
return 2020;
}
}
You could just Map.get each array element.
package com.company;
import java.util.ArrayList;
import java.util.HashMap;
public class Main {
static HashMap<String, Integer> romanNumbers = new HashMap<String, Integer>();
static {
romanNumbers.put("I", 1);
romanNumbers.put("V", 5);
romanNumbers.put("X", 10);
romanNumbers.put("L", 50);
romanNumbers.put("C", 100);
romanNumbers.put("D", 500);
romanNumbers.put("M", 1000);
}
public static void main(String[] args) {
System.out.println(romanToArabic("MMXX"));
}
static int romanToArabic(String roman) {
ArrayList romanLetters = new ArrayList();
roman = roman.toUpperCase();
for (int i = 0; i < roman.length(); i++) {
char c = roman.charAt(i);
romanLetters.add(c);
}
// [M, M, X, X]
System.out.println(romanLetters);
// iterates over the romanLetters
int sum = 0;
for (int i = 0; i < romanLetters.size(); i++) {
String key = String.valueOf(romanLetters.get(i));
if (romanNumbers.containsKey(key)) {
sum += romanNumbers.get(key);
}
}
return sum;
}
}
As stated in the comments, this just answers your question of how to get values from an hashmap where keys are the array elements. It is not a solution to calculate the numeric value out of a roman number. For that, you will have to look at the next letter, and join if it is larger, before consulting the map for the final value to sum.
I'd like to suggest a completly different approach using an enum.
public enum RomanNumber {
I(1), V(5), X(10), L(50), C(100), D(500), M(1000);
private final int arabic;
RomanNumber(int arabic) {
this.arabic = arabic;
}
public int getArabicNumber() {
return arabic;
}
// This is obviously broken. IV wouldn't work for example.
public static int toArabic(String romanLetters) {
romanLetters = romanLetters.toUpperCase();
int arabicResult = 0;
for (int i = 0; i < romanLetters.length(); i++) {
char romanNumber = romanLetters.charAt(i);
// valueOf(String) returns the enum based on its name. So a String of "I" returns the RomanNumber I enum.
int arabicNumber = valueOf(String.valueOf(romanNumber)).getArabicNumber();
arabicResult = arabicResult + arabicNumber;
}
return arabicResult;
}
}
Can be used like this:
String romanNumber = "MMXX";
System.out.println(RomanNumber.toArabic(romanNumber));
Btw. every enum has an ordinal() method which returns the declaration position inside the enum. (I.ordinal() == 1 or V.ordinal() == 2) I think this could help you with the IV problem aswell. :)
I'm taking a binary String like this:
010010010000110100001010
as a String, converting it to Integer Array like this:
int[] DD = new DD[binString.length()];
char temp = binString.charAt(i);
int binData = Character.getNumericValue(temp);
DD[i] = binData;
and I'm tying to save these Integer values in to HashMap(I have to store into a HashMap as per instructions given to me) like this:
Map<String, Integer> toMemory = new HashMap<String, Integer>();
for(int i=0;i<binString.length();i++) {
char temp = binString.charAt(i);
int binData = Character.getNumericValue(temp);
DD[i] = binData;
if((DD[i] & (DD[i]-1) ) == 0) {
toMemory.put(new String("ON"), new Integer(DD[i]));
} else {
toMemory.put(new String("ON"), new Integer(DD[i]));
}
}
for(String s: toMemory.keySet()) {
if(s.startsWith("ON")) {
System.out.println(toMemory.get(s));
}
}
The issue I'm facing here is that, only one entry is being stored in the HashMap, say {"ON",0}. And no other values are being stored. My expected output is this:
{"ON" , 1 , "OFF" , 0, "ON" , 1 .........}
Is there any better way to store the values to get my expected output? Any help will be much appreciated.
P.S: Please ignore the recurring code, and I'm relatively new to programming.
Your usage of a Map is flawed. Maps take a unique key and return a value.
You are trying to use duplicate keys. Instead, look at using a List with a wrapper class:
class ClassName {
public String status;
public int value;
public ClassName(String status, int value){
this.status = status;
this.value = value;
}
}
List<ClassName> list = new ArrayList();
To add to the list, create a new instance of your class and call List#add:
list.add(new ClassName("ON", 1));
as Infuzed Guy said, you are using the Map the wrong way. It's a unique "key to value mapping".
As long as you are using several times the same key and want to store all the dada, you need to use a List.
Here is what I could come up with the little you gave us: test it here
import java.util.LinkedList;
import java.util.List;
class Main {
public static void main(String[] args) {
class Tuple<X, Y> { //The wrapper object
public final X x;
public final Y y;
public Tuple(X x, Y y) { //Object constructor
this.x = x;
this.y = y;
}
public String toString() //Here for printing purpose
{
return "\"" + this.x + "\", " + this.y;
}
}
//Note here te use of List
List<Tuple> toMemory = new LinkedList<>();
String binString = "10100100101100101011";
int[] DD = new int[binString.length()];
for(int i=0; i < binString.length(); ++i)
{
//Here I use the char value
//to get the by subtraction
DD[i] = binString.charAt(i) - '0';
if(DD[i] == 1) //Simple check with the int value
{
toMemory.add(new Tuple<>("ON", DD[i]));
}
else
{
toMemory.add(new Tuple<>("OFF", DD[i]));
}
}
//Print the List
System.out.print("{ ");
for(Tuple s: toMemory) {
System.out.print(s +", ");
}
System.out.println("}");
}
}
I am trying to rearrange an ArrayList based on the name of the items to be on specific index.
My list currently is this:
"SL"
"TA"
"VP"
"SP"
"PR"
and i want to rearrange them to:
"SL"
"SP"
"TA"
"PR"
"VP"
but based on the name and not in the index.
I have tried this:
for (int i=0; i< list.size(); i++){
if (list.get(i).getCategoryName().equals("SL")){
orderedDummyJSONModelList.add(list.get(i));
}
}
for (int i=0; i< list.size(); i++){
if (list.get(i).getCategoryName().equals("SP")){
orderedDummyJSONModelList.add(list.get(i));
}
}
for (int i=0; i< list.size(); i++){
if (list.get(i).getCategoryName().equals("TA")){
orderedDummyJSONModelList.add(list.get(i));
}
}
for (int i=0; i< list.size(); i++){
if (list.get(i).getCategoryName().equals("PR")){
orderedDummyJSONModelList.add(list.get(i));
}
}
for (int i=0; i< list.size(); i++){
if (list.get(i).getCategoryName().equals("VP")){
orderedDummyJSONModelList.add(list.get(i));
}
}
and it works fine, but i want to know if there is a more efficient way to do in 1 for loop or maybe a function. I do not wish to do it like this:
orderedDummyJSONModelList.add(list.get(0));
orderedDummyJSONModelList.add(list.get(3));
orderedDummyJSONModelList.add(list.get(1));
orderedDummyJSONModelList.add(list.get(4));
orderedDummyJSONModelList.add(list.get(2));
Which also works. Any ideas?
You can use Collection.Sort method as Collection.Sort(list) since list is a List<String> you will be fine. But if you want to implement a new comparator:
Collections.sort(list, new NameComparator());
class NameComparator implements Comparator<String> { //You can use classes
#Override
public int compare(String a, String b) { //You can use classes
return a.compareTo(b);
}
}
EDIT:
You can define a class comparator for your needs:
class ClassComparator implements Comparator<YourClass> { //You can use classes
#Override
public int compare(YourClass a, YourClass b) { //You can use classes
return a.name.compareTo(b.name);
}
}
The key thing here is: you need to get clear on your requirements.
In other words: of course one can shuffle around objects stored within a list. But: probably you want to do that programmatically.
In other words: the correct approach is to use the built-in Collection sorting mechanisms, but with providing a custom Comparator.
Meaning: you better find an algorithm that defines how to come from
"SL"
"TA"
"VP"
"SP"
"PR"
to
"SL"
"SP"
"TA"
"PR"
"VP"
That algorithm should go into your comparator implementation!
The point is: you have some List<X> in the first place. And X objects provide some sort of method to retrieve those strings you are showing here. Thus you have to create a Comparator<X> that works on X values; and uses some mean to get to those string values; and based on that you decide if X1 is <, = or > than some X2 object!
hereĀ“s an answer just specific for your problem working just for the given output. If the List contains anything else this might break your ordering, as there is no rule given on how to order it and the PR just randomly appears in the end.
public static void main(String[] args) {
List<String> justSomeNoRuleOrderingWithARandomPRInside = new ArrayList<String>();
justSomeNoRuleOrderingWithARandomPRInside.add("SL");
justSomeNoRuleOrderingWithARandomPRInside.add("TA");
justSomeNoRuleOrderingWithARandomPRInside.add("VP");
justSomeNoRuleOrderingWithARandomPRInside.add("SP");
justSomeNoRuleOrderingWithARandomPRInside.add("PR");
java.util.Collections.sort(justSomeNoRuleOrderingWithARandomPRInside, new NameComparator());
for(String s : justSomeNoRuleOrderingWithARandomPRInside) {
System.out.println(s);
}
}
static class NameComparator implements Comparator<String> { //You can use classes
#Override
public int compare(String a, String b) { //You can use classes
// Lets just add a T in front to make the VP appear at the end
// after TA, because why not
if (a.equals("PR")) {
a = "T"+a;
} else if(b.equals("PR")) {
b = "T"+b;
}
return a.compareTo(b);
}
}
O/P
SL
SP
TA
PR
VP
But honestly, this solution is crap, and without any clear rule on how to order these this will be doomed to fail as soon as you change anything as #GhostCat tried to explain.
How about this
// define the order
List<String> ORDER = Arrays.asList("SL", "SP", "TA", "PR", "VP");
List<MyObject> list = ...
list.sort((a, b) -> {
// lamba syntax for a Comparator<MyObject>
return Integer.compare(ORDER.indexOf(a.getString()), ORDER.indexOf(b.getString());
});
Note that this will put any strings that aren't defined in the ORDER list at the start of the sorted list. This may or may not be acceptable - it may be worth checking that only valid strings (i.e. members of ORDER) appear as the result of MyObject.getString().
Use a hashmap to store the weight of all strings (Higher the value of the hashmap means the later this string should come in the final list).
Using a Hashmap, so you can expand it later for other strings as well. It'll be easier to enhance in future.
Finally, Use a custom Comparator to do it.
Required Setup:
List<String> listOfStrings = Arrays.asList("SL", "TA", "VP", "SP", "PR");
HashMap<String, Integer> sortOrder = new HashMap<>();
sortOrder.put("SL", 0);
sortOrder.put("TA", 1);
sortOrder.put("VP", 2);
sortOrder.put("SP", 3);
sortOrder.put("PR", 4);
Streams:
List<String> sortedList = listOfStrings.stream().sorted((a, b) -> {
return Integer.compare(sortOrder.get(a), sortOrder.get(b));
}).collect(Collectors.toList());
System.out.println(sortedList);
Non-Stream:
Collections.sort(listOfStrings, (a, b) -> {
return Integer.compare(sortOrder.get(a), sortOrder.get(b));
});
OR
listOfStrings.sort((a, b) -> {
return Integer.compare(sortOrder.get(a), sortOrder.get(b));
});
System.out.println(listOfStrings);
Output:
[SL, TA, VP, SP, PR]
You can build an index map using a LinkedHashMap. This will be used to lookup the order which to sort using the category names of your items.
ItemSorting
import java.util.ArrayList;
import java.util.Collections;
import java.util.List;
public class ItemSorting {
public static void main(String[] args) {
List<Item> list = new ArrayList<Item>();
IndexMap indexMap = new IndexMap("SL", "SP", "TA", "PR", "VP");
ItemComparator itemComparator = new ItemComparator(indexMap);
list.add(new Item("SL"));
list.add(new Item("TA"));
list.add(new Item("VP"));
list.add(new Item("SP"));
list.add(new Item("PR"));
Collections.sort(list, itemComparator);
for (Item item : list) {
System.out.println(item);
}
}
}
ItemComparator
import java.util.Comparator;
public class ItemComparator implements Comparator<Item> {
private IndexMap indexMap;
public IndexMap getIndexMap() {
return indexMap;
}
public void setIndexMap(IndexMap indexMap) {
this.indexMap = indexMap;
}
public ItemComparator(IndexMap indexMap) {
this.indexMap = indexMap;
}
#Override
public int compare(Item itemA, Item itemB) {
if (itemB == null) return -1;
if (itemA == null) return 1;
if (itemA.equals(itemB)) return 0;
Integer valA = indexMap.get(itemA.getCategoryName());
Integer valB = indexMap.get(itemB.getCategoryName());
if (valB == null) return -1;
if (valA == null) return 1;
return valA.compareTo(valB);
}
}
IndexMap
import java.util.LinkedHashMap;
public class IndexMap extends LinkedHashMap<String, Integer> {
private static final long serialVersionUID = 7891095847767899453L;
public IndexMap(String... indicies) {
super();
if (indicies != null) {
for (int i = 0; i < indicies.length; i++) {
this.put(indicies[i], new Integer(i));
}
}
}
}
Item
public class Item {
private String categoryName;
public Item(String categoryName) {
super();
this.categoryName = categoryName;
}
public String getCategoryName() {
return categoryName;
}
public void setCategoryName(String categoryName) {
this.categoryName = categoryName;
}
#Override
public int hashCode() {
final int prime = 31;
int result = 1;
result = prime * result + ((categoryName == null) ? 0 : categoryName.hashCode());
return result;
}
#Override
public boolean equals(Object obj) {
if (this == obj) return true;
if (obj == null) return false;
if (getClass() != obj.getClass()) return false;
Item other = (Item) obj;
if (categoryName == null) {
if (other.categoryName != null) return false;
} else if (!categoryName.equals(other.categoryName)) return false;
return true;
}
#Override
public String toString() {
return String.format("Item { \"categoryName\" : \"%s\" }", categoryName);
}
}
Result
Item { "categoryName" : "SL" }
Item { "categoryName" : "SP" }
Item { "categoryName" : "TA" }
Item { "categoryName" : "PR" }
Item { "categoryName" : "VP" }
You coud define a helper method like this one:
public static int get(String name) {
switch (name) {
case "SL":
return 1;
case "SP":
return 2;
case "TA":
return 3;
case "PR":
return 4;
case "VP":
return 5;
default:
return 6;
}
}
and write in your main method something like:
ArrayList<String> al = new ArrayList<>();
al.add("SL");
al.add("TA");
al.add("VP");
al.add("SP");
al.add("PR");
Collections.sort(al, (o1, o2) -> return get(o1) - get(o2); );
al.forEach((s) -> System.out.println(s));
You can create a Map that maintains the position. When you iterate through the unordered list just get the position of that string value and insert into new array(not arraylist), then later if required you can convert that array to ArrayList.
Example code:
Map<String,Integer> map = new HashMap<>(); //you can may be loop through and make this map
map.put("SL", 0);
map.put("SP", 1);
map.put("TA",2);
map.put("PR",3);
map.put("VP",3);
List<String> list1 // your unordered list with values in random order
String[] newArr = new String[list1.size()];
for(String strName: list1){
int position = map.get(strName);
arr[position] = strName;
}
//newArr has ordered result.
With the help of the community i managed to get this problem solved: How to convert String to the name of the Array?
But now i get 'nullPointerExceptions'. Here is the code i use:
public class IroncladsAdder
{
public static String weaponId = null;
public static String ship = null;
public static String wing = null;
//map code
private static Map<String, List<Integer>> arrays = new HashMap<String, List<Integer>>();
public void Holder(String... names) {
for (String name : names) {
arrays.put(name, new ArrayList<Integer>());
}
}
//adds weapons to fleets and stations
public static void AddWeapons(CargoAPI cargo, String fac, int count, int type) {
String arrayName = null;
int quantity = (int) (Math.random()*5f + count/2) + 1;
if (count == 1) {quantity = 1;}
if (type == 0) {arrayName = fac+"_mil_weps";}
else if (type == 1) {arrayName = fac+"_civ_weps";}
else {arrayName = fac+"_tech_weps";}
List<Integer> array = arrays.get(arrayName);
for (int j = 0; j <= count; j++)
{
weaponId = valueOf(arrays.get(arrayName).get((int) (Math.random() * arrays.get(arrayName).size())));
cargo.addWeapons(weaponId, quantity);
}
}
Here is an example of the array:
//high-tech UIN weapons
private static String [] uin_tech_weps =
{
"med-en-uin-partpulse",
"lrg-en-uin-partacc",
"med-bal-uin-driver",
"lrg-bal-uin-terminator",
"lrg-bal-uin-hvydriver",
"lrg-bal-uin-shotgundriver",
"lrg-en-uin-empbeam",
};
Error indicates that something is wrong with this construction:
weaponId = valueOf(arrays.get(arrayName).get((int) (Math.random() * arrays.get(arrayName).size())));
NOTE: i`m using Intellij IDEA and Java 6. Application most of the time has advices/fixes for some errors and in this case shows that everything is ok.
What i need is to get a String out of the specific array (that is using a code-generated name) and assign it to 'weaponId'.
When your application start the map with the arrays is empty, then when you try to get the array with name X you get back a null value.
First solution: at startup/construction time fill the map with empty arrays/List for all the arrays names.
Second solution: use this method in order to obtain the array.
protected List<Integer> getArray(String arrayName) {
List<Integer> array = map.get(arrayName);
if (array == null) {
array = new ArrayList<Integer>();
map.put(arrayName, array);
}
return array;
}
P.s.
You can change this code:
weaponId = valueOf(arrays.get(arrayName).get((int) (Math.random() * arrays.get(arrayName).size())));
into
weaponId = valueOf(array.get((int) (Math.random() * array.size())));
Ok. Now there is a different error - 'java.lang.IndexOutOfBoundsException: Index: 0, Size: 0'
Made the code look like this:
private static Map <String, List<Integer>> arrays = new HashMap<String, List<Integer>>();
public static List<Integer> getArray(String arrayName) {
List<Integer> array = arrays.get(arrayName);
if (array == null) {
array = new ArrayList<Integer>();
arrays.put("rsf_civ_weps", array);
arrays.put("rsf_mil_weps", array);
arrays.put("rsf_tech_weps", array);
arrays.put("isa_civ_weps", array);
arrays.put("isa_mil_weps", array);
arrays.put("isa_tech_weps", array);
arrays.put("uin_mil_weps", array);
arrays.put("uin_tech_weps", array);
arrays.put("uin_civ_weps", array);
arrays.put("xle_civ_weps", array);
arrays.put("xle_mil_weps", array);
arrays.put("xle_tech_weps", array);
}
return array;
}
This is how i now call the array and weaponId:
List<Integer> array = arrays.get(arrayName);
for (int j = 0; j <= count; j++)
{
weaponId = valueOf(array.get((int) (Math.random() * array.size())));
cargo.addWeapons(weaponId, quantity);
}
What`s wrong?
private List<String> subList;
private List<List<String>> records = new ArrayList<List<String>>();
for(....){
subList = new ArrayList<String>();
...populate..
records.add(subList);
}
For example, subList has three Strings - a, b, and c.
I want to sort the records by the value of b in subList.
records at 0 has a list of "10", "20", "30"
records at 1 has a list of "10", "05", "30"
records at 2 has a list of "10", "35", "30"
After the sort, the order of records should be -
records at 0 = records at 1 above
records at 1 = records at 0 above
records at 2 = records at 2 above
What could be a good algorithm for that?
Something like:
Collections.sort(records, new Comparator<List<String>>()
{
public int compare(List<String> o1, List<String> o2)
{
//Simple string comparison here, add more sophisticated logic if needed.
return o1.get(1).compareTo(o2.get(1));
}
})
Though I find hard-coding the positions a little dubious in practice, your opinion may differ.
This is just like sorting a string of characters: given two strings, start at the beginning and compare each character; if there's a difference, the string with the lower value comes first, otherwise, look at the next characters from each string. If the strings are of different lengths, treat the shorter string as if it had a suffix of zeroes.
In this case, the "characters" are integer values, obtained by calling Integer.parseInt(). Additionally, implementing a Comparator for a List<String> would be helpful here. Then the Collections.sort() method can be used.
The comparator might look something like this:
final class MyComparator implements Comparator<List<String>> {
public int compare(List<String> a, List<String> b) {
/* Assume all strings are parseable to values
* in range [0,Integer.MAX_VALUE] */
int len = Math.min(a.size(), b.size());
for (int idx = 0; idx < len; ++idx) {
int va = Integer.parseInt(a.get(idx)), vb = Integer.parseInt(b.get(idx));
if (va != vb)
return va - vb;
}
return va.size() - vb.size();
}
#Override
public boolean equals(Object o) {
return o instanceof MyComparator;
}
#Override
public int hashCode() {
return MyComparator.class.hashCode();
}
}
import java.util.ArrayList;
import java.util.Collections;
import java.util.Comparator;
import java.util.List;
public class MyList
{
private List<List<Long>> myList;
public MyList()
{
myList = new ArrayList<List<Long>>();
ArrayList arrayList = null;
for(int i=0;i<3;i++)
{
arrayList = new ArrayList<Long>();
for(int x=0;x<3;x++)
{
arrayList.add((Long)Math.round(Math.random()*10));
}
myList.add(arrayList);
}
}
public static void main(String[] args)
{
MyList newList = new MyList();
newList.printList();
Collections.sort(newList.getMyList(),new Comparator<List<Long>>(){
public int compare(List<Long> o1, List<Long> o2) {
if(o1 != null && o2 !=null)
{
Long var1 = o1.get(0);
Long var2 = o2.get(0);
return var1.compareTo(var2);
}
return 0;
}
});
newList.printList();
}
private void printList() {
for(List<Long> subString : myList)
{
System.out.println("List");
for(Long elements : subString)
{
System.out.println(elements);
}
}
}
public List<List<Long>> getMyList() {
return myList;
}
public void setMyList(List<List<Long>> myList) {
this.myList = myList;
}
}
The Column Comparator allows your to sort on any column within the List. The sort is done using the natural sort order of the data in the column.