Java - getting error on Hashmap.put [duplicate] - java

This question already has answers here:
What is a NullPointerException, and how do I fix it?
(12 answers)
Closed 7 years ago.
I wrote a simple program in JAVA having 4 classes:
Main - > CarFaxApp
GUI / Logic - > CarFaxFrame
Object -> Car
Validator -> CarFaxValidator
Once the program is running and I start to enter the necessary data in the textbox's for the car (String vin, String make, String model, int year). Everything works fine, but when I hit buttonADD(), I get a error.
private HashMap<String,Car>hmCar; //Hashmap to hold Cars, the key pair value consists of (Vin, Car Object)
The error happens on hmCar.put(car.getVin(), car); which I dont understand why, I tried debugging up to the point and car does hold the correct values.
Here a screen shot of the error:

the error is NullPointException, are you sure you do this
hmCar = new HashMap<String, Car>();
before you put the entry in.

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I have a record for Employees:
public record Employee(
String name,
String id,
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I'm frankly confused by documentation, and I've been getting errors not knowing how stream this properly. This is as close as I got:
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Hope this makes sense.

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This post was edited and submitted for review 12 months ago and failed to reopen the post:
Original close reason(s) were not resolved
-When I use toString to print: System.out.println(animal);
I get this : Animal{name='Shark', weight=30, speed=40}
What I want is : Animal {name = 'Shark',
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Needs details or clarity Add details and clarify the problem by editing this post.
In the following loop how may I create a new List<>(), but I have a problem in the moment I try to set a value:
ListlistOfString = new ArrayList()<>;
listOfString.set(index, value);
Can anyone explain me how does it work?
Unlike arrays, you cannot do array[i] = val. You should use ArrayList.set:
// this must be set
announcementDTO.set(j, new ArrayList<>());
// this can still be get
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I'm beginner in Java environment, accustomed to PHP.
And in Php we can create an array like the code below :
$array['params1'] = 'the first param';
$array['params2'] = 'the second param';
And when i will output $array['params1'] it will be 'the first param'.
But i do not find any similar solutions in Java, do you know something similar ?
Thanks in advance
As #mrblewog said, you might want to readup on data structures and the syntax in Java as it is quite different than php.
To give you an Example:
// Key Value
HashMap<String, String> map = new HashMap<>();
map.insert("key1", "value1");
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If you want to store other objects than Strings you will need to change the generic types (written in the <X, Y>).

Variable is setting itself to value of another variable [duplicate]

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PS: This question is different than others because I need to know exactly what code to write in order to prevent the variable from changing.
I have this example of code to demonstrate my problem:
float[][] one = {{0}};
float[][] two = one;
System.out.println(two[0][0]);
one[0][0] ++;
System.out.println(two[0][0]);
int three = 0;
int four = three;
System.out.println(four);
three ++;
System.out.println(four);
The output is:
0.0
1.0
0
0
For some reason, when I change float[][] 'one', 'two' automatically changes as well.
However, when I performed the same task but for a different data type int, then the code works as intended.
What is causing this variable to drag the other one with it?
Why doesn't it happen for the int type?
How do I fix it?

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