Develop Reference

Unusual Java implementation of red/black tree node insertion

I'm writing a program for class in Java regarding red/black trees. I've got a good understanding of how they usually work, and am supposed to use a recursive insertion method. What I would typically use is below, to match my professor's Node class. In regards to color, a 0 is black, a 1 is red. The Node class given to us does not deal with keys at all.
private static void put(int val, int col)
{ root = put(root, val, col); }
private static Node put(Node n, Integer val, int col)
{
if (n == null){
Node t=new Node(val);
t.setColor(1);
return t;
}
int cmp = val.compareTo(n.getValue());
if (cmp < 0) n.setLeft(put(n.getLeft(), val, col));
else if (cmp > 0) n.setRight(put(n.getRight(), val, col));
else n.setColor(col);
if (isRed(n.getRight()) && !isRed(n.getLeft())) n = rotateLeft(n);
if (isRed(n.getLeft()) && isRed(n.getLeft().getLeft())) n = rotateRight(n);
if (isRed(n.getLeft()) && isRed(n.getRight())) flipColors(n);
return n;
}
However, the catch is that we are supposed to return a boolean value--if the user inserts a duplicate value as is already on the tree, we return false and don't attach the node. Otherwise, we attach them and return true; the code given to us for this is below, but is not recursive (part of the project requirements). And while I hadn't implemented a way of balancing or rotating properly, the returned boolean part works.
public boolean insertNode(Node node) {
//Here is just an example of setting colors for a node. So far, it is in green color. But you need to modify the code to dynamically adjust the color to
//either RED or BLACK according to the red-black logic
Node current_node;
// if the root exists
if (root == null) {
root = node; // let the root point to the current node
root.setColor(Node.BLACK);
return true;
} else {
current_node = root;
node.setColor(1);
while (current_node != null) {
int value = current_node.getValue();
if (node.getValue() < value){ // go to the left sub-tree
if (current_node.getLeft() != null) // if the left node is not empty
current_node = current_node.getLeft();
else{ // put node as the left child of current_node
current_node.setLeft(node);
node.setParent(current_node);
current_node = null; }
//System.out.println("Left:"+current_node);
}
else if (node.getValue() > value){ // go to the right
if (current_node.getRight() != null) // if the right node is not empty
current_node = current_node.getRight();
else{ // put node as the right child of current_node
current_node.setRight(node);
node.setParent(current_node);
current_node = null; }
//System.out.println("Right: "+current_node);
}
else{
//System.out.println("Else: "+current_node);
return false; }
//if(current_node!=null&&current_node.getLeft()!=null&&current_node.getRight()!=null&&current_node.getLeft().isRed()&&current_node.getRight().isRed())
// flipColors(node);
}
}
if(node.getParent()!=null){
node=node.getParent();
System.out.println("Case: node has parent, val="+node.getValue());
}
if(node.getLeft()!=null&&node.getRight()!=null){
if((node.getRight().isRed())&&!node.getLeft().isRed())
node=rotateLeft(node);
if((node.getLeft().isRed())&&(node.getParent()!=null)&&(node.getParent().getLeft().getLeft()!=null)&&(node.getParent().getLeft().getLeft().isRed()))
node=rotateRight(node);
if((node.getLeft().isRed()) && (node.getRight().isRed()))
flipColors(node);
}
return true;
}
I wasn't able to find any comparable implementations online, and it seems that the boolean is necessary for the program's gui to work properly. If someone has a good suggestion for where to start, I would appreciate it!

For the recursive insertNode, I would suggest you the following: Create a function insertNode(Node node, Node current_node) which returns a boolean value. The idea is to always call the function insertNode for the currently investigated node, starting from the root node. If the node cannot be immediately added to current_node, the responsible node is called recursively to handle the node. I have provided you a short example based on your code (with some comments what the basic idea is, there is obviously some stuff missing). I hope, I got your question correctly and this helps you with your understanding.
public boolean insertNode(Node node) {
if (root == null) {
root = node;
root.setColor(Node.BLACK);
return true;
} else {
boolean result = insertNode(node, root);
if (result) {
//Some other important stuff to do...
}
return result;
}
}
public boolean insertNode(Node node, Node current_node) {
int value = current_node.getValue();
if (node.getValue() < value) {
if (current_node.getLeft() != null) {
// Investigate left
return insertNode(node, current_node.getLeft());
} else {
// Insert node left
return true;
}
} else if (node.getValue() > value) {
if (current_node.getRight() != null) {
// Investigate right
return insertNode(node, current_node.getRight());
} else {
// Insert node right
return true;
}
} else {
return false;
}
}

I now have the working functions, as below:
public boolean insertNode(Node node) {
if(root==null){
root=node;
root.setColor(Node.BLACK);
return true;
}
else
node.setColor(Node.RED);
return insertNode(node, root);
}
public boolean insertNode(Node node, Node cur){
if(node.getValue()<cur.getValue()){
if(cur.getLeft()!=null)
return insertNode(node, cur.getLeft());
else{
cur.setLeft(node);
node.setParent(cur);
handleInsertion(node);
return true; } }
else if(node.getValue()>cur.getValue()){
if(cur.getRight()!=null)
return insertNode(node, cur.getRight());
else{
cur.setRight(node);
node.setParent(cur);
handleInsertion(node);
return true; } }
else
return false;
}

Delete method for Binary Search Trees? [duplicate]

This question already has answers here:
What is a NullPointerException, and how do I fix it?
(12 answers)
Closed 5 years ago.
Ok, so I wanted to write a delete method that works for any "delete-case" for Binary Search Trees and this is my attempt:
public void delete(int key) {
if (root.value == key) {
root = root.right;
root.left = root.right.left;
return;
}
else {
deleteRecursive(key, root); ***LINE 58***
}
}
public void deleteRecursive(int key, BinaryNode node) {
if (node == null) {
System.out.println("ERROR");
return;
}
else {
if (key < node.value) {
// continue search on left
if (node.left.value == key) {
if (node.left.left == null && node.left.right == null) {
node.left = null;
}
else if (node.left.left == null){
node.left = node.left.right;
}
else if (node.left.right == null){
node.left = node.left.left;
}
else{
node.left = node.left.right;
node.left.left = node.left.right.left; ***LINE 83***
}
}
else {
deleteRecursive (key, node.left);
}
}
else if (key > node.value){
// continue search on right
if (node.right.value == key) {
if (node.right.left == null && node.right.right == null) {
node.right = null;
}
else if (node.right.left == null){
node.right = node.right.right;
}
else if (node.right.right == null){
}
else if (node.left.left != null && node.left.right != null){
node.right = node.right.right;
node.right.left = node.right.right.left;
}
}
else {
deleteRecursive (key, node.right);
}
}
}
}
But when I actually use the delete method in Main its gives out a NullPointerException.
The error-message reads :
Exception in thread "main" java.lang.NullPointerException
at BinaryTree.deleteRecursive(BinaryTree.java:83)
at BinaryTree.delete(BinaryTree.java:58)
at Main.main(Main.java:14)
So I assume that it is in line 83 and 58 (marked in code).
I've been sitting here for the last hour trying to figure it out and can't seem to get it.
I'm not the best in Java so I thought i could look for some help here! :)
Here are all the files to run the program (everything except for the delete method was already given) : https://www.dropbox.com/sh/r1bt2880hnn6tjm/AADsRsOOzuiNKHp-ZC-IrvVta?dl=0

Since you are trying to remove from Binary Search Tree, better make it totally recursive rather than partially.
private BinaryNode deleteRecursive( int data,BinaryNode node) {
if(node==null){
return null;
}
if(data==node.value)
{
if(node.left!=null && node.right!=null){
BinaryNode minNode = getHighestNodeFromRight(node.right);
node.value = minNode.value;
node.right = deleteRecursive(minNode.value, node.right);
//System.out.println(minNode);
}
else if(node.left==null){
return node.right;
}
else{
return node.left;
}
}
else if(data>node.value){
node.right = deleteRecursive( data,node.right);
}
else{
node.left = deleteRecursive(data, node.left);
}
return node;
}
public BinaryNode getHighestNodeFromRight(BinaryNode node){
if(node.left==null){
return node;
}
else{
BinaryNode n = getHighestNodeFromRight(node.left);
return n;
}
}

Java pass by value with recursion

The following is a simple implementation of Binary search tree using java. However, the code always outputs "BST empty!!" despite inserting elements. Where am I going wrong? I suspect I'm going wrong with recursion. Any help is greatly appreciated.
public class BinarySearchTree {
NODE root;
BinarySearchTree(){
root = null;
}
void insert(NODE nodeptr,int key){
if(root == null){
nodeptr = new NODE(key);
return;
}
if(nodeptr == null){
nodeptr = new NODE(key);
return;
}
if(key <= nodeptr.data){
insert(nodeptr.left,key);
}
else{
insert(nodeptr.right,key);
}
}
void inorder(NODE nodeptr){
if(nodeptr == null){
System.out.println("BST empty!!");
return;
}
inorder(nodeptr.left);
System.out.println(nodeptr.data + " ");
inorder(nodeptr.right);
}
/*driver program*/
public static void main(String args[]){
int[] a = {20,30,40,24,39};
BinarySearchTree bst = new BinarySearchTree();
for (int i: a){
bst.insert(bst.root,i);
}
bst.inorder(bst.root);
}
}
class NODE{
int data;
NODE left,right;
NODE(int data){
this.data = data;
left = null;
right = null;
}
}

Your insert method never assigns value to the root, so it remains null.
If I understand your code, your insert should look like this :
void insert(NODE nodeptr,int key){
if(root == null){
root = new NODE(key);
return;
}
if(nodeptr == null){
insert (root, key);
return;
}
if(key <= nodeptr.data){
if (nodeptr.left != null)
insert(nodeptr.left,key);
else
nodeptr.left = new NODE(key);
}
else{
if (nodeptr.right != null)
insert(nodeptr.right,key);
else
nodeptr.right = new NODE(key);
}
}
If the root is null, ignore the passed nodeptr and put key at the root of the tree.
If nodeptr is null, try to insert the new key starting at the root of the tree.
otherwise, once you find a null nodeptr.left or nodeptr.right, you must put the new key there, because if you make another recursive call, you would be passing a null Node to it, and the recursion would never end.

Expanding from Erans answer you could change it to:
public void insert(int key){
if(root == null){
root = new NODE(key);
return;
}
insert(root,key)
}
private void insert(NODE nodeptr,int key){
if(key <= nodeptr.data){
if(nodeptr.left == null){
nodeptr.left = new NODE(key)
}
else {
insert(nodeptr.left,key);
}
}
else{
if(nodeptr.right == null){
nodeptr.right = new NODE(key)
}
else {
insert(nodeptr.right,key);
}
}
}
Edit: As he has added his own code now its just a matter of what style you like better. A single method or two methods from which the public one has only one parameter.

I wanted my insert method something like this. Got it to working finally. Thank you all for your precious time.
NODE insert(NODE nodeptr,int key){
if(nodeptr == null){
nodeptr = new NODE(key);
}
else if(key <= nodeptr.data){
nodeptr.left = insert(nodeptr.left,key);
}
else{
nodeptr.right = insert(nodeptr.right,key);
}
return nodeptr;
}
I would call insert method from main something like this:
bst.root = bst.insert(bst.root,i);

binary search tree deletion method [duplicate]

I am trying to implement a remove method for the BST structure that I have been working on. Here is the code with find, insert, and remove methods:
public class BST {
BSTNode root = new BSTNode("root");
public void insert(BSTNode root, String title){
if(root.title!=null){
if(title==root.title){
//return already in the catalog
}
else if(title.compareTo(root.title)<0){
if(root.leftChild==null){
root.leftChild = new BSTNode(title);
}
else{
insert(root.leftChild,title);
}
}
else if(title.compareTo(root.title)>0){
if(root.rightChild==null){
root.rightChild = new BSTNode(title);
}
else{
insert(root.rightChild,title);
}
}
}
}
public void find(BSTNode root, String title){
if(root!= null){
if(title==root.title){
//return(true);
}
else if(title.compareTo(root.title)<0){
find(root.leftChild, title);
}
else{
find(root.rightChild, title);
}
}
else{
//return false;
}
}
public void remove(BSTNode root, String title){
if(root==null){
return false;
}
if(title==root.title){
if(root.leftChild==null){
root = root.rightChild;
}
else if(root.rightChild==null){
root = root.leftChild;
}
else{
//code if 2 chlidren remove
}
}
else if(title.compareTo(root.title)<0){
remove(root.leftChild, title);
}
else{
remove(root.rightChild, title);
}
}
}
I was told that I could use the insert method to help me with the remove method, but I am just not seeing how I can grab the smallest/largest element, and then replace the one I am deleting with that value, then recursively delete the node that I took the replacement value, while still maintaining O(logn) complexity. Anyone have any ideas or blatant holes I missed, or anything else helpful as I bang my head about this issue?
EDIT:
I used the answers ideas to come up with this, which I believe will work but I'm getting an error that my methods (not just the remove) must return Strings, here is what the code looks like, I thought that's the return statements??
public String remove(BSTNode root, String title){
if(root==null){
return("empty root");
}
if(title==root.title){
if(root.leftChild==null){
if(root.rightChild==null){
root.title = null;
return(title+ "was removed");
}
else{
root = root.rightChild;
return(title+ "was removed");
}
}
else if(root.rightChild==null){
root = root.leftChild;
return(title+ "was removed");
}
else{
String minTitle = minTitle(root);
root.title = minTitle;
remove(root.leftChild,minTitle);
return(title+ "was removed");
}
}
else if(title.compareTo(root.title)<0){
remove(root.leftChild, title);
}
else{
remove(root.rightChild, title);
}
}

public void remove (String key, BSTNode pos)
{
if (pos == null) return;
if (key.compareTo(pos.key)<0)
remove (key, pos.leftChild);
else if (key.compareTo(pos.key)>0)
remove (key, pos.rightChild);
else {
if (pos.leftChild != null && pos.rightChild != null)
{
/* pos has two children */
BSTNode maxFromLeft = findMax (pos.leftChild); //need to make a findMax helper
//"Replacing " pos.key " with " maxFromLeft.key
pos.key = maxFromLeft.key;
remove (maxFromLeft.key, pos.leftChild);
}
else if(pos.leftChild != null) {
/* node pointed by pos has at most one child */
BSTNode trash = pos;
//"Promoting " pos.leftChild.key " to replace " pos.key
pos = pos.leftChild;
trash = null;
}
else if(pos.rightChild != null) {
/* node pointed by pos has at most one child */
BSTNode trash = pos;
/* "Promoting " pos.rightChild.key" to replace " pos.key */
pos = pos.rightChild;
trash = null;
}
else {
pos = null;
}
}
}
This is the remove for an unbalanced tree. I had the code in C++ so I have quickly translated. There may be some minor mistakes though. Does the tree you are coding have to be balanced? I also have the balanced remove if need be. I wasn't quite sure based on the wording of your question. Also make sure you add a private helper function for findMax()

void deleteTreeNode(int data){
root = deleteTreeNode(root ,data);
}
private TreeNode deleteTreeNode(TreeNode root, int data) {
TreeNode cur = root;
if(cur == null){
return cur;
}
if(cur.data > data){
cur.left = deleteTreeNode(cur.left, data);
}else if(cur.data < data){
cur.right = deleteTreeNode(cur.right, data);
}else{
if(cur.left == null && cur.right == null){
cur = null;
}else if(cur.right == null){
cur = cur.left;
}else if(cur.left == null){
cur = cur.right;
}else{
TreeNode temp = findMinFromRight(cur.right);
cur.data = temp.data;
cur.right = deleteTreeNode(cur.right, temp.data);
}
}
return cur;
}
private TreeNode findMinFromRight(TreeNode node) {
while(node.left != null){
node = node.left;
}
return node;
}

To compare objects in java use .equals() method instead of "==" operator
if(title==root.title)
^______see here
you need to use like this
if(title.equals(root.title))
or if you are interesed to ignore the case follow below code
if(title.equalsIgnoreCase(root.title))

private void deleteNode(Node temp, int n) {
if (temp == null)
return;
if (temp.number == n) {
if (temp.left == null || temp.right == null) {
Node current = temp.left == null ? temp.right : temp.left;
if (getParent(temp.number, root).left == temp)
getParent(temp.number, root).left = current;
else
getParent(temp.number, root).right = current;
} else {
Node successor = findMax(temp.left);
int data = successor.number;
deleteNode(temp.left, data);
temp.number = data;
}
} else if (temp.number > n) {
deleteNode(temp.left, n);
} else {
deleteNode(temp.right, n);
}
}

I know this is a very old question but anyways... The accepted answer's implementation is taken from c++, so the idea of pointers still exists which should be changed as there are no pointers in Java. So every time when you change the node to null or something else, that instance of the node is changed but not the original one This implementation is taken from one of the coursera course on algorithms.
public TreeNode deleteBSTNode(int value,TreeNode node)
{
if(node==null)
{
System.out.println("the value " + value + " is not found");
return null;
}
//delete
if(node.data>value) node.left = deleteBSTNode(value,node.left);
else if(node.data<value) node.right = deleteBSTNode(value,node.right);
else{
if(node.isLeaf())
return null;
if(node.right==null)
return node.left;
if(node.left==null)
return node.right;
TreeNode successor = findMax(node.left);
int data = successor.data;
deleteBSTNode(data, node.left);
node.data = data;
}
return node;
}
All the links between the nodes are pertained using the return value from the recursion.

For the Depth First Post-Order traversal and removal, use:
/*
*
* Remove uses
* depth-first Post-order traversal.
*
* The Depth First Post-order traversal follows:
* Left_Child -> Right-Child -> Node convention
*
* Partial Logic was implemented from this source:
* https://stackoverflow.com/questions/19870680/remove-method-binary-search-tree
* by: sanjay
*/
#SuppressWarnings("unchecked")
public BinarySearchTreeVertex<E> remove(BinarySearchTreeVertex<E> rootParameter, E eParameter) {
BinarySearchTreeVertex<E> deleteNode = rootParameter;
if ( deleteNode == null ) {
return deleteNode; }
if ( deleteNode.compareTo(eParameter) == 1 ) {
deleteNode.left_child = remove(deleteNode.left_child, eParameter); }
else if ( deleteNode.compareTo(eParameter) == -1 ) {
deleteNode.right_child = remove(deleteNode.right_child, eParameter); }
else {
if ( deleteNode.left_child == null && deleteNode.right_child == null ) {
deleteNode = null;
}
else if ( deleteNode.right_child == null ) {
deleteNode = deleteNode.left_child; }
else if ( deleteNode.left_child == null ) {
deleteNode = deleteNode.right_child; }
else {
BinarySearchTreeVertex<E> interNode = findMaxLeftBranch( deleteNode.left_child );
deleteNode.e = interNode.e;
deleteNode.left_child = remove(deleteNode.left_child, interNode.e);
}
} return deleteNode; } // End of remove(E e)
/*
* Checking right branch for the swap value
*/
#SuppressWarnings("rawtypes")
public BinarySearchTreeVertex findMaxLeftBranch( BinarySearchTreeVertex vertexParameter ) {
while (vertexParameter.right_child != null ) {
vertexParameter = vertexParameter.right_child; }
return vertexParameter; } // End of findMinRightBranch

Java binary search tree - incorrectly working insert method

I've a binary search tree homework in Java where I was given complete Tree and Node classes and a SearchTree class in which I'm to complete the search and insert methods. The search is supposed to return the value of the node corresponding the searched key.
Here is the Tree class and here the Node class. My search and insert methods are below.
It seems I'm getting close, but test insert of key 0 and value 2 into Tree[Node[0,1,null,null]] results in Tree[Node[0,1,null,null] rather than the correct Tree[Node[0,2,null,null]]. What am I not understanding here?
public static Object search(Tree tree, int key) {
Node x = tree.getRoot();
while (x != null) {
if (key == x.getKey()) {
return x.getValue();
}
if (key < x.getKey()) {
x = x.getLeft();
} else {
x = x.getRight();
}
}
return null;
}
public static void insert(Tree tree, int key, Object value) {
if (tree.getRoot() == null) {
tree.setRoot(new Node(key, value));
}
Node juuri = tree.getRoot();
while (juuri != null) {
if (key == juuri.getKey()) {
return;
} else if (key < juuri.getKey()) {
if (juuri.getLeft() == null) {
juuri.setLeft(new Node(key, value));
return;
} else {
juuri = juuri.getLeft();
}
} else {
if (juuri.getRight() == null) {
juuri.setRight(new Node(key, value));
return;
} else {
juuri = juuri.getRight();
}
}
}
}

Well the issue I am seeing is that key values in your tree are unique. In this if statement you leave your insert method without adding a node if you see that the key is already in the tree.
if (key == juuri.getKey()) {
return;
}
In your example (if I understand it right) 0 is already in the tree so nothing changes when inserting 0 again. Based on your example, I am assuming you want to do an update on a node if the key is the same. So this code would do it.
if (key == juuri.getKey()) {
juuri.setValue(value);
return;
}