How convert Gregorian to Chinese Lunar Calendar? - java

I want to build an android app using Greogorian Calendar to Chinese Lunar Calendar.
I don't know how to convert from Gregorian to Chinese Calendar. How can I do this?

You can try:
http://www.docjar.com/html/api/com/ibm/icu/util/ChineseCalendar.java.html
There is a contructor:
public ChineseCalendar(Date date) ...
Links:
Doc: http://icu-project.org/apiref/icu4j/com/ibm/icu/util/ChineseCalendar.html
Source: http://site.icu-project.org/download

Conversion from gregorian to chinese
I just released a new version of Time4J (v4.35, but use Time4A-v3.40-2018b on Android) which supports the Chinese calendar. The conversion from gregorian to chinese lunisolar calendar can be done in a straight forward way:
PlainDate gregorian = PlainDate.nowInSystemTime(); // 2018-03-07
ChineseCalendar cc = gregorian.transform(ChineseCalendar.axis());
System.out.println(cc); // chinese[wu-xu(2018)-1-21]
The documentation of the Chinese calendar also contains examples how to format or parse it in many localized ways.
Special design requirements for the display on Android
Keep also in mind that the Chinese calendar contains elements which don't exist in gregorian calendar, for example cyclic years, leap months or solar terms (a generalization of our astronomical seasons). Time4J/A can format it, but it is specific for the calendar. This is relevant if you have thought about a generic calendar display which shall be universally applicable for all calendars. It is probably better to make a specific display for the Chinese calendar on Android so other important informations like cyclic years in text form or solar terms can still be displayed, too.
Comparison to ICU4J
Main differences:
API-style: ICU4J has adopted the old world of java.util.Calendar while Time4J/A follows a domain-driven approach
immutability feature (ICU4J-calendar-class is NOT immutable in contrast to Time4J/A)
solar terms (ICU4J does not seem to have any support for this feature)
accuracy (ICU4J uses an astronomy module based on the book of Peter Duffet/Smith, while Time4J/A is mainly based on the work of Jean Meeus)
While some people still like the old-fashioned-style of ICU4J, I am most worried about the accuracy of ICU4J. As reference, you can watch the data published by Hongkong observatory for the year 2018. ICU4J deviates from Hongkong data already on 2018-11-07 (for a whole month, the date is wrong by one day!). Proof using the following code:
DateFormat df =
DateFormat.getDateInstance(
DateFormat.FULL,
ULocale.forLanguageTag("en-u-ca-chinese"));
SimpleDateFormat sf = new SimpleDateFormat("yyyy-MM-dd");
sf.setTimeZone(TimeZone.getTimeZone("Asia/Shanghai"));
ChineseCalendar cc = new ChineseCalendar(78, 35, 0, 0, 1);
System.out.println(df.format(cc.getTime())); // Friday, First Month 1, 2018(wu-xu)
for (int i = 0; i < 13; i++) {
cc.add(Calendar.MONTH, 1);
System.out.print(df.format(cc.getTime()));
System.out.println("=>" + sf.format(cc.getTime()));
}
Output (pay attention to line in November):
Saturday, Second Month 1, 2018(wu-xu)=>2018-03-17
Monday, Third Month 1, 2018(wu-xu)=>2018-04-16
Tuesday, Fourth Month 1, 2018(wu-xu)=>2018-05-15
Thursday, Fifth Month 1, 2018(wu-xu)=>2018-06-14
Friday, Sixth Month 1, 2018(wu-xu)=>2018-07-13
Saturday, Seventh Month 1, 2018(wu-xu)=>2018-08-11
Monday, Eighth Month 1, 2018(wu-xu)=>2018-09-10
Tuesday, Ninth Month 1, 2018(wu-xu)=>2018-10-09
Wednesday, Tenth Month 1, 2018(wu-xu)=>2018-11-07
Friday, Eleventh Month 1, 2018(wu-xu)=>2018-12-07
Sunday, Twelfth Month 1, 2018(wu-xu)=>2019-01-06
Tuesday, First Month 1, 2019(ji-hai)=>2019-02-05
Thursday, Second Month 1, 2019(ji-hai)=>2019-03-07
See also the old unsolved issue on the bug-tracker of ICU4J, many more dates in the future are wrong. Sure, astronomical calculations cannot be predicted in a strict way for the future, but the first date where Time4J/A deviates from Hongkong data is the year 2057 (calculated as only 37 seconds after local midnight) and not already the present year 2018 like in ICU4J. So I would advise against ICU4J as long as they have not corrected their astronomy module and cannot even be correct for the actual year.
To be realistic in far future, we don't know who is right for the year 2057, and even the Hongkong observatory is explicitly uncertain at this date:
If the time of new moon (first day of the lunar month) or solar term
is close to midnight, the dates of the relevant lunar month or solar
term in the "Conversion Table" may have a discrepancy of one day. Such
situation will occur on the new moons on 28 September 2057 [...]

Related

Is there a way to correctly count number of days in 1582

How would one calculate a number of days in 1582. Yes, that is the year of introduction of the Georgian Calendar (in some countries). I assume October 1582 should not have 31 days as some of the dates never existed.
Yet when I tried Joda Time (Java/Groovy) it says 30 days:
LocalDate start = new LocalDate("1582-10-01");
LocalDate end = new LocalDate("1582-10-31");
println Days.daysBetween(start, end).getDays();
Same for SQL
-- PostgreSQL
SELECT DATE_PART('day', '1582-10-31'::date - '1582-10-01'::timestamp);
-- MSSQL
SELECT DATEDIFF(dd, '1582-10-31', '1582-10-01');
So is there some agreement/specification to actually treat 1582-10-14 as if it would actually exist? Or is there some easy way to calculate correct diff for year 1582 and earlier?
I have not used Java in many years, but I am familiar with dealing with several calendars in other languages. From the "Key Concepts" subtab of the "Documentation" tab of the Joda Time website we find the "Chronology" page which states
The default chronology in Joda-Time is ISO. This calendar system is
the same as that used by business in the majority of the world today.
The ISO system is unsuitable for historical work before 1583 as it
applies the leap year rules from today back in time (it is a proleptic
calendar). As a result, users requiring a more historically accurate
calendar system are forced to think about their actual requirements,
which we believe is a Good Thing.
Proleptic means that from a known day and date that virtually everyone agrees about, such as the Meter Convention having been signed in Paris on 20 May 1875, the rules of the calendar are applied backward to find any date desired, even if it is before the calendar was created.
As for computing the interval in one calendar, such as the Julian calendar, to a date in a different calendar, such as the Gregorian calendar, a common approach is to convert them both to a count-of-days from a chosen epoch, such as the modified julian date, which counts from midnight universal time at the beginning of November 17, 1858. Then one simply subtracts one day count from the other to find the number of days between them. A quick glance at the Joda Time documentation did not show any facility for computing a day count.
I am currently not set up to program in Java. Ole V.V. comment about using the Gregorian-Julian chronology of Joda-Time seems useful, but I have not tried it:
LocalDate first = new LocalDate(1582, 10, 1, GJChronology.getInstance());
LocalDate last = new LocalDate(1582, 10, 31, GJChronology.getInstance());
int countOfDaysDiff = Days.daysBetween(first, last).getDays();
System.out.println(countOfDaysDiff);
Output according to Ole V.V.:
20
I think I will go ahead and close with that both answers are probably correct. October 1582 did and didn't have 31 days. I mean that 14th October didn't exist (as in no one was born on that day in Gregorian Calendar) and for the purpose of accounting all debts were pushed by ten days. So I guess the only way is to manually count days and don't use any libraries for that.
When establishing Gregorian Calendar it was said that:
we direct and ordain:
that ten days shall be removed from the month of October of the year 1582
But also:
But in order that nobody suffers prejudice by this our subtraction of ten days, in connection with any annual or monthly payments, the judges in any controversies that may arise over this, shall by reason of the said subtraction add ten days to the due date for any such payment.
Source: https://en.wikisource.org/wiki/Translation:Inter_gravissimas

Calling getTime changes Calendar value

I'm trying to get the sunday of the same week as a given date.
During this I ran into this problem:
Calendar calendar = Calendar.getInstance(Locale.GERMANY);
calendar.set(2017, 11, 11);
calendar.set(Calendar.DAY_OF_WEEK, Calendar.SUNDAY);
System.out.println(calendar.getTime().toString());
results in "Sun Jan 07 11:18:42 CET 2018"
but
Calendar calendar2 = Calendar.getInstance(Locale.GERMANY);
calendar2.set(2017, 11, 11);
calendar2.getTime();
calendar2.set(Calendar.DAY_OF_WEEK, Calendar.SUNDAY);
System.out.println(calendar2.getTime().toString());
gives me the correct Date "Sun Dec 17 11:18:42 CET 2017"
Can someone explain why the first exmple is behaving this way? Is this really intended?
Thanks
Basically, the Calendar API is horrible, and should be avoided. It's not documented terribly clearly, but I think I see where it's going, and it's behaving as intended in this situation. By that I mean it's following the intention of the API authors, not the intention of you or anyone reading your code...
From the documentation:
The calendar field values can be set by calling the set methods. Any field values set in a Calendar will not be interpreted until it needs to calculate its time value (milliseconds from the Epoch) or values of the calendar fields. Calling the get, getTimeInMillis, getTime, add and roll involves such calculation.
And then:
When computing a date and time from the calendar fields, there may be insufficient information for the computation (such as only year and month with no day of month), or there may be inconsistent information (such as Tuesday, July 15, 1996 (Gregorian) -- July 15, 1996 is actually a Monday). Calendar will resolve calendar field values to determine the date and time in the following way.
If there is any conflict in calendar field values, Calendar gives priorities to calendar fields that have been set more recently. The following are the default combinations of the calendar fields. The most recent combination, as determined by the most recently set single field, will be used.
For the date fields:
YEAR + MONTH + DAY_OF_MONTH
YEAR + MONTH + WEEK_OF_MONTH + DAY_OF_WEEK
YEAR + MONTH + DAY_OF_WEEK_IN_MONTH + DAY_OF_WEEK
YEAR + DAY_OF_YEAR
YEAR + DAY_OF_WEEK + WEEK_OF_YEAR
In the first example, the fact that the last field set was "day of week" means it will then use the YEAR + MONTH + WEEK_OF_MONTH + DAY_OF_WEEK calculation (I think). The year and month have been set to December 2017, but the week-of-month is the current week-of-month, which is the week 5 of January 2018... so when you then say to set the day of week to Sunday, it's finding the Sunday in the "week 5" of December 2017. December only had 4 weeks, so it's effectively rolling it forward... I think. It's all messy and you shouldn't have to think about that, basically.
In the second example, calling getTime() "locks in" the year/month/day you've specified, and computes the other fields. When you set the day of week, that's then adjusting it within the existing computed fields.
Basically, avoid this API as far as you possibly can. Use java.time, which is a far cleaner date/time API.
As Jon Skeet said, avoid Calendar. For your case it is truly horrible, and it’s poorly designed in general. Instead do
WeekFields weekFieldsForLocale = WeekFields.of(Locale.GERMANY);
// To find out which number Sunday has in the locale,
// grab any Sunday and get its weekFieldsForLocale.dayOfWeek()
int dayNumberOfSundayInLocale = LocalDate.now()
.with(TemporalAdjusters.nextOrSame(DayOfWeek.SUNDAY))
.get(weekFieldsForLocale.dayOfWeek());
LocalDate date = LocalDate.of(2017, Month.DECEMBER, 11);
LocalDate sunday
= date.with(weekFieldsForLocale.dayOfWeek(), dayNumberOfSundayInLocale);
System.out.println(sunday);
This prints the expected date
2017-12-17
As others have already mentioned, the solution is to use java.time, the modern Java date and time API. Also generally it is so much nicer to work with. One nice feature is the LocalDate class that I am using. It is a date without time of day, which seems to match your requirements more precisely that Calendar did.
If the above looks complicated, it’s because, as I think you are aware, “Sunday of the same week” means different things in different locales. In the international standard that Germany follows, weeks begin on Monday, so Sunday is the last day of the week. In the American standard, for example, Sunday os the first day of the week. WeekFields.dayOfWeek() numbers the days of the week from 1 to 7, so when we want to set the day to Sunday, we first need to find out which number Sunday has got in this numbering (7 in Germany, 1 in the US). So for any Sunday, get its weekFieldsForLocale.dayOfWeek() value and later use this for setting the day of week to Sunday. The reason why this is necessary is that the with() method is so general and therefore has been designed to accept only numeric values; we can’t just pass it a DayOfWeek object.
If I substitute Locale.US into the code, I get 2017-12-10, which is the correct Sunday for a calendar where Sunday is the first day of the week. If you are sure your only want your code to work for Germany, you may of course just hardcode a 7 (please make it a constant with a very explanatory name).
Link: Oracle Tutorial Date Time explaining how to use java.time. There are other resources on the net (just avoid the outdated placed that suggest java.util.Calendar :-)

Setting October 14 ,1582 fails in java.sql.Date

If I try to set java.sql.Date as
new java.sql.Date(1582-1900,09,14)
It returns me
1582-10-24
So there is a difference of 10 days. How to solve this problem?
Are you sure that date exists?
Wikipedia says the Gregorian Calender (which is what you are probably using) started on October 15, 1582.
When the new calendar was put in use, the error accumulated in the 13 centuries since the Council of Nicaea was corrected by a deletion of 10 days. The Julian calendar day Thursday, 4 October 1582 was followed by the first day of the Gregorian calendar, Friday, 15 October 1582 (the cycle of weekdays was not affected).
If you need to deal with days before that, you probably have to write some more involved code.
This is due to the calendar being switched from Julian to Gregorian in that year. (The latter has the 100 and 400 leap year corrections that the Julian calendar lacks. This accounts for the 10 day difference that had accumulated.)
Note that some countries - in particular England - did not adopt that calendar until 1752. And Russia, for example, didn't adopt it until well into the 20th century!
As a rule of thumb, if you're working with dates before 1752 then you ought to consult an historian.

Why does converting Java Dates before 1582 to LocalDate with Instant give a different date?

Consider this code:
Date date = new SimpleDateFormat("MMddyyyy").parse("01011500");
LocalDate localDateRight = LocalDate.parse(formatter.format(date), dateFormatter);
LocalDate localDateWrong = LocalDateTime.ofInstant(date.toInstant(), ZoneId.systemDefault()).toLocalDate();
System.out.println(date); // Wed Jan 01 00:00:00 EST 1500
System.out.println(localDateRight); // 1500-01-01
System.out.println(localDateWrong); // 1500-01-10
I know that 1582 is the cutoff between the Julian and Gregorian calendars. What I don't know is why this happens, or how to adjust for it.
Here's what I've figured out so far:
The date Object has a BaseCalender set to JulianCalendar
date.toInstant() just returns Instant.ofEpochMilli(getTime())
date.getTime() returns -14830974000000
-14830974000000 is Wed, 10 Jan 1500 05:00:00 GMT Gregorian
So it seems like either the millis returned by getTime() is wrong (unlikely) or just different than I expect and I need to account for the difference.
LocalDate handles the proleptic gregorian calendar only. From its javadoc:
The ISO-8601 calendar system is the modern civil calendar system used
today in most of the world. It is equivalent to the proleptic
Gregorian calendar system, in which today's rules for leap years are
applied for all time. For most applications written today, the
ISO-8601 rules are entirely suitable. However, any application that
makes use of historical dates, and requires them to be accurate will
find the ISO-8601 approach unsuitable.
In contrast, the old java.util.GregorianCalendar class (which is indirectly also used in toString()-output of java.util.Date) uses a configurable gregorian cut-off defaulting to 1582-10-15 as separation date between julian and gregorian calendar rules.
So LocalDate is not useable for any kind of historical dates.
But bear in mind that even java.util.GregorianCalendar often fails even when configured with correct region-dependent cut-off date. For example UK started the year on March 25th before 1752. And there are many more historical deviations in many countries. Outside of Europe even the julian calendar is not useable before introduction of gregorian calendar (or best useable only from a colonialist perspective).
UPDATE due to questions in comment:
To explain the value -14830974000000 let's consider following code and its output:
SimpleDateFormat format = new SimpleDateFormat("MMddyyyy", Locale.US);
format.setTimeZone(TimeZone.getTimeZone("America/New_York"));
Date d = format.parse("01011500");
long t1500 = d.getTime();
long tCutOver = format.parse("10151582").getTime();
System.out.println(t1500); // -14830974000000
System.out.println(tCutOver); // default gregorian cut off day in "epoch millis"
System.out.println((tCutOver - t1500) / 1000); // output: 2611699200 = 30228 * 86400
It should be noted that the value -12219292800000L mentioned in your earlier comment is different by 5 hours from tCutOver due to timezone offset difference between America/New_York and UTC. So in timezone EST (America/New_York) we have exactly 30228 days difference. For the timespan in question we apply the rules of julian calendar that is every fourth year is a leap year.
Between 1500 and 1582 we have 82 * 365 days + 21 leap days. Then we have also to add 273 days between 1582-01-01 and 1582-10-01, finally 4 days until cut-over (remember 4th of Oct is followed by 15th of Oct). At total: 82 * 365 + 21 + 273 + 4 = 30228 (what was to be proved).
Please explain to me why you have expected a value different from -14830974000000 ms. It looks correct for me since it handles the timezone offset of your system, the julian calendar rules before 1582 and the jump from 4th of Oct 1582 to cut-over date 1582-10-15. So for me your question "how do I tell the date object to return the ms to the correct Gregorian date?" is already answered - no correction needed. Keep in mind that this complex stuff is a pretty long time in production use and can be expected to work correctly after so many years.
If you really want to use JSR-310 for that stuff I repeat that there is no support for gregorian cut-over date. The best thing is that you might do your own work-around.
For example you might consider the external library Threeten-Extra which contains a proleptic julian calendar since release 0.9. But it will still be your effort to handle the cut-over between old julian calendar and new gregorian calendar. (And don't expect such libraries to be capable of handling REAL historic dates due to many other reasons like new year start etc.)
Update in year 2017: Another more powerful option would be using HistoricCalendar of my library Time4J which handles much more than just julian/gregorian-cutover.

Year 0000 in java

When I parse a date with the year 0000 it appears to be stored as the year 0001.
See below for code:
String dateStr = "00000102";
System.out.println(dateStr);
DateFormat dateFormat = new SimpleDateFormat("yyyyMMdd");
Date date = dateFormat.parse("00000102");
String convertedStr = dateFormat.format(date);
System.out.println(convertedStr);
The output is as per below:
00000102
00010102
Is there a way to represent the year 0000 in Java using the standard Java API?
I don't believe it's possible, since java.util.Date is based on UTC, which is based on the Gregorian calendar, and the Gregorian calendar has no year zero.
...the traditional proleptic Gregorian calendar (like the Julian calendar) does not have a year 0 and instead uses the ordinal numbers 1, 2, … both for years AD and BC. Thus the traditional time line is 2 BC, 1 BC, AD 1, and AD 2.
(Source: The Wikipedia article on the Gregorian calendar)
I don't think the calendar is zero-based. Before 1 AD there was 1 BC. No 0.
Also: what kind of application are you building that needs to handle dates from that era? And if you need to cover that area, consider this: "Dates obtained using GregorianCalendar are historically accurate only from March 1, 4 AD onward, when modern Julian calendar rules were adopted. Before this date, leap year rules were applied irregularly, and before 45 BC the Julian calendar did not even exist."
Year 0 does not exist in the Gregorian calendar. From Year 0 at Wikipedia:
"Year zero" does not exist in the widely used Gregorian calendar or in its predecessor, the Julian calendar. Under those systems, the year 1 BC is followed by AD 1.
...
The absence of a year 0 leads to some confusion concerning the boundaries of longer decimal intervals, such as decades and centuries. For example, the third millennium of the Gregorian calendar began on Monday, 1 January, 2001, rather than the widely celebrated Saturday, 1 January, 2000. Likewise, the 20th century began on 1 January 1901.
...
java.time
I recommend that you use java.time, the modern Java date and time API, for your date work.
As others have said, the Julian/Gregorian calendar that the old Date and SimpleDateFormat classes used does not have a year zero. Before year one in the current era (CE also known as AD) came year 1 before the current era (BCE also known as BC).
A side effect of using java.time is that you do get a year zero! That’s right. java.time uses the proleptic Gregorian calendar, a modern inventions that not only extends the rules of the Gregorian back into times before the Gregorian calendar was invented, but also includes a year 0 before year 1, and a year -1 (minus one) before that. You may say that year 0 corresponds to 1 BCE and -1 to 2 BCE, etc.
So parsing your string is no problem. There’s even a built-in formatter for it.
String dateStr = "00000102";
LocalDate date = LocalDate.parse(dateStr, DateTimeFormatter.BASIC_ISO_DATE);
System.out.println("Parsed date is " + date);
String convertedStr = date.format(DateTimeFormatter.BASIC_ISO_DATE);
System.out.println(convertedStr);
Output:
Parsed date is 0000-01-02
00000102
We see that in both output lines year 0000 is printed back as expected.
What went wrong in your code?
When we all agree that there was no year 0, we should have expected your parsing to fail with an exception because of the invalid year. Why didn’t it? It’s one of the many problems with the old SimpleDateFormat class: with default settings it just extrapolates and takes year 0000 to mean the year before year 0001, so year 1 BCE. And falsely pretends that all is well. This explains why year 0001 was printed back: it meant year 1 BCE, but since you didn’t print the era too, this was really hard to tell.
Links
Oracle tutorial: Date Time explaining how to use java.time.
Proleptic Gregorian calendar on Wikipedia.

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