Develop Reference

Date.compareTo(Date) not working

I am writing an app scenario, where need to match between two date if there are same or not and that I am trying to achieve using Date.compareTo(). But it never return 0 as API said for equal date.
I am getting these dates from Caledar.getTime() but it never
I checked with print to both date object and even they are returning same string.
Sat Nov 15 14:17:41 GMT+05:30 2014, Sat Nov 15 14:17:41 GMT+05:30 2014
Any suggestion, how to check date object if they are equal or not.

I think you forgot to check if the dates milliseconds are the same.
This is the source code of the compareTo method.
public int compareTo(Date anotherDate) {
long thisTime = getMillisOf(this);
long anotherTime = getMillisOf(anotherDate);
return (thisTime<anotherTime ? -1 : (thisTime==anotherTime ? 0 : 1));
}
As you can see this method compares two dates using milliseconds as "time step".
Code for old API:
This code checks if two days are the same. (Without hours, minutes, seconds and milliseconds)
Date date1; //Your initial date
Date date2; //Your initial second date
//Remove hours, minutes, seconds and milliseconds by creating new "clean" Date objects
Date compare1 = new Date(date1.getYear(), date1.getMonth(), date1.getDay());
Date compare2 = new Date(date2.getYear(), date2.getMonth(), date2.getDay());
if(compare1.compareTo(compare2) == 0){
}
But I suggest you don't use Date for this task. Because the getYear, getMonth etc. methods are deprecated I suggest you take a look at newer API's like GregorianCalendar and Calendar
Code for new API
This code checks if two days are the same including hours and minutes. But without seconds and milliseconds.
Date date1;
Date date2;
Calendar compareCalendar1 = Calendar.getInstance();
Calendar compareCalendar2 = Calendar.getInstance();
compareCalendar1.setTime(date1);
compareCalendar2.setTime(date2);
//Set for both calendars the seconds and milliseconds to 0
compareCalendar1.set(Calendar.MILLISECOND, 0);
compareCalendar1.set(Calendar.SECOND, 0);
compareCalendar2.set(Calendar.MILLISECOND, 0);
compareCalendar2.set(Calendar.SECOND, 0);
if(compareCalendar1.compareTo(compareCalendar2) == 0){
}

Try to understand compare scenario :
Date date1 = Calendar.getInstance().getTime();
Date date2 = Calendar.getInstance().getTime();
date1.compareTo(date2) >> -1
AND
Date date3 = Calendar.getInstance().getTime();
Date date4 = date3;
date3.compareTo(date4) >> 0

Unable to find difference between two dates w.r.t time,seconds,months and years?

This is my java class
public class dateparse {
public static void main(String args[]) throws ParseException
{
Date dd=new Date();
int year = Calendar.getInstance().get(Calendar.YEAR);
int month=0;
int calc_days=0;
String d1 = dd.getDate()+"/"+dd.getMonth()+"/"+year;
String d2 = "19/1/2014";
SimpleDateFormat s1 = new SimpleDateFormat("dd/mm/yyyy");
SimpleDateFormat s2 = new SimpleDateFormat("dd/mm/yyyy");
Date dateOne = new SimpleDateFormat("dd/mm/yyyy").parse(d1);
Date dateTwo = s2.parse(d2);
long diff = dateOne.getTime() - dateTwo.getTime();
calc_days= (int) (diff / 1000 / 60 / 60 / 24 / 1);
}
}
I am trying to find the difference between current date and the date specified with respect to seconds,minutes,hours,days,months and years.Here my input date is 19th Feb 2014.I want to show the difference in no of days(e.g. 10 days) or months+days(e.g.1 month and 2 days) or year+month+days(e.g. 1 year and 2 months and 4 days).But when I run this code it returns difference as -10 days.

Your error is your parsing. Lowercase m means minutes, not month:
SimpleDateFormat s2 = new SimpleDateFormat("dd/mm/yyyy");
should be:
SimpleDateFormat s2 = new SimpleDateFormat("dd/MM/yyyy");
Here's a simplified example:
String d1 = "21/1/2014";
String d2 = "19/1/2014";
SimpleDateFormat sdf = new SimpleDateFormat("dd/MM/yyyy");
Date dateOne = sdf.parse(d1);
Date dateTwo = sdf.parse(d2);
long diff = dateOne.getTime() - dateTwo.getTime();
int differenceInDays = (int) (diff / 1000 / 60 / 60 / 24 / 1);
System.out.println(differenceInDays);
Prints: 2

This is a classic error caused by the horrible API that Java has provided:
date.getMonth() returns 0 for January, 1 for february... and 11 for December. If you can, try to avoid java.util.Date and Calendar :P

Attention - Accepted answer is wrong! Prove:
Use as input the dates 2014-03-19 and 2014-04-01 in my timezone "Europe/Berlin". The true answer is 13 days as everyone can easily veryify using standard calendars, but the accepted code of #Duncan produces 12 days because in my timezone there was a dst-jump which breaks the basis of calculation formular (1 day = 24 hours). On 30th of March the day was only 23 hours long.
The JDK pre 8 does not offer a built-in generic solution for this problem. Please also note that your input is just a pair of two plain dates with no time. Therefore it is silly to ask for the difference in seconds, etc. Only asking for the difference in days, months, weeks or years is sensible. In Java 8 you can do following:
// only days
LocalDate start = LocalDate.of(2014, 3, 19); // start in March
LocalDate end = LocalDate.of(2014, 4, 1);
int days = ChronoUnit.DAYS.between(start, end); // 13
// period in years, months and days
LocalDate start = LocalDate.of(2014, 2, 19); // start in February
LocalDate end = LocalDate.of(2014, 4, 1);
Period period = Period.between(start, end); // P1M13D = 1 month + 13 days
Unfortunately you are not free to choose in which calendar units you like to get the difference expressed. JodaTime (and my library) has a more flexible approach using PeriodType.

How to get date of last Friday from specified date? [duplicate]

This question already has answers here:
Time: How to get the next friday?
(9 answers)
Closed 6 years ago.
How can I find out the date of last (previous) "Friday" or any other day from a specified date?
public getDateOnDay(Date date, String dayName) {
// ?
}

I won't give an answer (try it yourself first!), but, maybe these tips can help you out.
You first need to figure out the current day of the week you are on. You may want to take a look at Java's Calendar class to get an idea of how to do that.
Once you get the date you are on, think about the modulus operator and how you can use that to move backwards to pick up the previous day that you are looking for from the day you are currently at. (Remember, a week is 7 days and each day of the week takes up a "slot" in those 7 days.)
Once you have the number of days in between, you'll want to subtract. Of course, there are classes that can add and subtract days for you in the Java framework...
I hope that helps. Again, I encourage you to always try the problem for yourself, first. You learn far much more that way and be a better developer in the long run for it.

Here is a brute force idea. Check if current date is friday. If not, subtract 1 day from today. Check if new date is friday. If not, subtract 1 day from new date..... so on.. you get the idea.

Try this one:
/**
* Return last day of week before specified date.
* #param date - reference date.
* #param day - DoW field from Calendar class.
* #return
*/
public static Date getDateOnDay(Date date, int day) {
Calendar cal = Calendar.getInstance();
cal.setTime(date);
cal.add(Calendar.WEEK_OF_YEAR, -1);
cal.set(Calendar.DAY_OF_WEEK, day);
return cal.getTime();
}
Good luck.

I'm using this:
private Date getDateOnDay(Date date, int day) {
Calendar cal = Calendar.getInstance();
cal.setTime(date);
cal.setFirstDayOfWeek(day);
cal.set(Calendar.DAY_OF_WEEK, day);
return cal.getTime();
}

Get the day of week for the date. Look at Calendar javadoc. Once you have the day of the week you can calculate an offset to apply to the date.

To get any latest date based on weekday:
private String getWeekDayDate(String weekday){
DateFormat formatter = new SimpleDateFormat("yyyy-MM-dd");
Calendar start = Calendar.getInstance();
Date now = new Date();
start.setTime(now);
Calendar end = Calendar.getInstance();
end.add(Calendar.DATE, -7);
while (start.after(end))
{
try {
Date temp = start.getTime();
String day = new SimpleDateFormat("EEEE").format(temp);
if(day.equalsIgnoreCase(weekday))
return formatter.format(temp);
}catch(Exception e) {
e.printStackTrace();
}
start.add(Calendar.DAY_OF_YEAR, -1);
}
return null;
}
To get latest Friday date, give weekday as "Friday"

//gets the last four Fridays from today's date if you want pass in a any date
//just need to tweak the code, the other method just basically formats the date in dd/MM/YYYY format.
function GetLastFourFridays() {
today = new Date();
LastFridayDate = new Date();
LastFridayDate.setDate(LastFridayDate.getDate() - 1);
while (LastFridayDate.getDay() != 5) {
LastFridayDate.setDate(LastFridayDate.getDate() - 1);
}
var lfd = LastFridayDate
lfd = convertDate(lfd)
document.getElementById("first_week_th").innerHTML = lfd
LastFridayDate.setDate(LastFridayDate.getDate() - 1);
var friLastWeek = LastFridayDate
while (friLastWeek.getDay() != 5) {
friLastWeek.setDate(friLastWeek.getDate() - 1);
}
var flw = friLastWeek
flw = convertDate(flw)
document.getElementById("second_week_th").innerHTML = flw
friLastWeek.setDate(friLastWeek.getDate() - 1);
var friTwoWeeks = friLastWeek
while (friTwoWeeks.getDay() != 5) {
friTwoWeeks.setDate(friTwoWeeks.getDate() - 1);
}
var ftw = friTwoWeeks
ftw = convertDate(ftw)
document.getElementById("third_week_th").innerHTML = ftw
friTwoWeeks.setDate(friTwoWeeks.getDate() - 1);
var friThreeWeeks = friTwoWeeks
while (friThreeWeeks.getDay() != 5) {
friThreeWeeks.setDate(friThreeWeeks.getDate() - 1);
}
var ftww = friThreeWeeks
ftww = convertDate(ftww)
document.getElementById("fourth_week_th").innerHTML = ftww
}
//convets the date 00//00//0000
function convertDate(inputFormat) {
function pad(s) { return (s < 10) ? '0' + s : s; }
var d = new Date(inputFormat);
return [pad(d.getDate()), pad(d.getMonth()+1), d.getFullYear()].join('/');}

How to get the past Sunday and the coming Sunday in Java? [duplicate]

This question already has answers here:
Is there a good way to get the date of the coming Wednesday?
(6 answers)
Closed 3 years ago.
I asked How to detect if a date is within this or next week in Java? but the answers were confusing, so now I think if I can find the past Sunday and the coming Sunday, any day in between is this week, and any day between the coming Sunday and the Sunday after that is next week, am I correct ?
So my new question is : How to get the past Sunday and the coming Sunday in Java ?

java.time
Briefly:
LocalDate.now().with( next( SUNDAY ) )
See this code run live at IdeOne.com.
Details
I thought I'd add a Java 8 solution for posterity. Using LocalDate, DayOfWeek, and TemporalAdjuster implementation found in the TemporalAdjusters class.
final LocalDate today = LocalDate.of(2015, 11, 20);
final LocalDate nextSunday = today.with(next(SUNDAY));
final LocalDate thisPastSunday = today.with(previous(SUNDAY));
This approach also works for other temporal classes like ZonedDateTime.
import
As written, it assumes the following static imports:
import java.time.LocalDate;
import static java.time.DayOfWeek.SUNDAY;
import static java.time.temporal.TemporalAdjusters.next;
import static java.time.temporal.TemporalAdjusters.previous;

How about this :
Calendar c=Calendar.getInstance();
c.set(Calendar.DAY_OF_WEEK,Calendar.SUNDAY);
c.set(Calendar.HOUR_OF_DAY,0);
c.set(Calendar.MINUTE,0);
c.set(Calendar.SECOND,0);
DateFormat df=new SimpleDateFormat("EEE yyyy/MM/dd HH:mm:ss");
System.out.println(df.format(c.getTime())); // This past Sunday [ May include today ]
c.add(Calendar.DATE,7);
System.out.println(df.format(c.getTime())); // Next Sunday
c.add(Calendar.DATE,7);
System.out.println(df.format(c.getTime())); // Sunday after next
The result :
Sun 2010/12/26 00:00:00
Sun 2011/01/02 00:00:00
Sun 2011/01/09 00:00:00
Any day between the first two is this week, anything between the last two is next week.

Without using a better time/date package...
DateFormat df = DateFormat.getDateTimeInstance(DateFormat.FULL, DateFormat.FULL);
Calendar now = new GregorianCalendar();
Calendar start = new GregorianCalendar(now.get(Calendar.YEAR),
now.get(Calendar.MONTH), now.get(Calendar.DAY_OF_MONTH) );
while (start.get(Calendar.DAY_OF_WEEK) != Calendar.SUNDAY) {
start.add(Calendar.DAY_OF_WEEK, -1);
}
Calendar end = (Calendar) start.clone();
end.add(Calendar.DAY_OF_MONTH, 7);
System.out.println(df.format(now.getTime()) );
System.out.println(df.format(start.getTime()) );
System.out.println(df.format(end.getTime()) );
If today is Sunday, it is considered the start of the time period. If you want a period of this week and next week (as it sounds from your question), you can substitute 14 instead of 7 in the end.add(...) line. The times are set to midnight for comparison of another object falling between start and end.

First, don't use the Date/Time package from Java. There is a much better utility package called Joda-Time - download that and use it.
To determine if your time is in this week, last week, or any week at all, do this:
Create two Interval objects - one for last week and one for this week
Use the contains( long ) method to determine which interval holds the date you are looking for.
There are several cool ways you can create two back to back weeks. You could set up a Duration of one week, find the start time for the first week, and just create two Intervals based on that start time. Feel free to find any other way that works for you - the package has numerous ways to get to what you want.
EDIT:
Joda-Time can be downloaded here, and here is an example of how Joda would do this:
// Get the date today, and then select midnight of the first day of the week
// Joda uses ISO weeks, so all weeks start on Monday.
// If you want to change the time zone, pass a DateTimeZone to the method toDateTimeAtStartOfDay()
DateTime midnightToday = new LocalDate().toDateTimeAtStartOfDay();
DateTime midnightMonday = midnightToday.withDayOfWeek( DateTimeConstants.MONDAY );
// If your week starts on Sunday, you need to subtract one. Adjust accordingly.
DateTime midnightSunday = midnightMonday.plusDays( -1 );
DateTime midnightNextSunday = midnightSunday.plusDays( 7 );
DateTime midnightSundayAfter = midnightNextSunday.plusDays( 7 );
Interval thisWeek = new Interval( midnightSunday, midnightNextSunday );
Interval nextWeek = new Interval( midnightNextSunday, midnightSundayAfter );
if ( thisWeek.contains( someDate.getTime() )) System.out.println("This week");
if ( nextWeek.contains( someDate.getTime() )) System.out.println("Next week");

Given bellow next Sunday code and you can easily figure out how to find past Sunday.
private static void nextSunday() throws ParseException
{
SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd");
Calendar calendar = Calendar.getInstance();
calendar.setTime(new Date());
int weekday = calendar.get(Calendar.DAY_OF_WEEK);
int days = Calendar.SUNDAY - weekday;
if (days < 0)
{
days += 7;
}
calendar.add(Calendar.DAY_OF_YEAR, days);
System.out.println(sdf.format(calendar.getTime()));
}

I recently developed Lamma Date which is designed to solve this use case:
Date today = new Date(2014, 7, 1); // assume today is 2014-07-01
Date previousSunday = today.previousOrSame(DayOfWeek.SUNDAY); // 2014-06-29
Date nextSunday = today.next(DayOfWeek.SUNDAY); // 2014-07-06

http://download.oracle.com/javase/1.4.2/docs/api/java/util/Date.html
I recommend Calendar.get(Calendar.DAY_OF_WEEK)

You could try to work with the Calendar.WEEK_OF_YEAR field, which gives you the numeric representation of the week within the current year.
#Test
public void testThisAndNextWeek() throws Exception {
GregorianCalendar lastWeekCal = new GregorianCalendar(2010,
Calendar.DECEMBER, 26);
int lastWeek = lastWeekCal.get(Calendar.WEEK_OF_YEAR);
GregorianCalendar nextWeekCal = new GregorianCalendar(2011,
Calendar.JANUARY, 4);
int nextWeek = nextWeekCal.get(Calendar.WEEK_OF_YEAR);
GregorianCalendar todayCal = new GregorianCalendar(2010,
Calendar.DECEMBER, 27);
int currentWeek = todayCal.get(Calendar.WEEK_OF_YEAR);
assertTrue(lastWeekCal.before(todayCal));
assertTrue(nextWeekCal.after(todayCal));
assertEquals(51, lastWeek);
assertEquals(52, currentWeek);
// New Year.. so it's 1
assertEquals(1, nextWeek);
}

My Solution:
LocalDate date = ...;
LocalDate newWeekDate = date.plusDays(1);
while (newWeekDate.getDayOfWeek() != DayOfWeek.SATURDAY &&
newWeekDate.getDayOfWeek() != DayOfWeek.SUNDAY) {
newWeekDate = date.plusDays(1);
}

I need a cycle which iterates through dates interval

I have the start date and the end date. I need to iterate through every day between these 2 dates.
What's the best way to do this?
I can suggest only something like:
Date currentDate = new Date (startDate.getTime ());
while (true) {
if (currentDate.getTime () >= endDate.getTime ())
break;
doSmth ();
currentDate = new Date (currentDate.getTime () + MILLIS_PER_DAY);
}

ready to run ;-)
public static void main(String[] args) throws ParseException {
GregorianCalendar gcal = new GregorianCalendar();
SimpleDateFormat sdf = new SimpleDateFormat("yyyy.MM.dd");
Date start = sdf.parse("2010.01.01");
Date end = sdf.parse("2010.01.14");
gcal.setTime(start);
while (gcal.getTime().before(end)) {
gcal.add(Calendar.DAY_OF_YEAR, 1);
System.out.println( gcal.getTime().toString());
}
}

Ditto on those saying to use a Calendar object.
You can get into surprising trouble if you try to use a Date object and add 24 hours to it.
Here's a riddle for you: What is the longest month of the year? You might think that there is no answer to that question. Seven months have 31 days each, so they are all the same length, right? Well, in the United States that would be almost right, but in Europe it would be wrong! In Europe, October is the longest month. It has 31 days and 1 hour, because Europeans set their clocks back 1 hour for Daylight Saving Time in October, making one day in October last 25 hours. (Americans now begin DST in November, which has 30 days, so November is still shorter than October or December. Thus making that riddle not as amusing for Americans.)
I once ran into trouble by doing exactly what you're trying to do: I used a Date object and added 24 hours to it in a loop. It worked as long as I didn't cross Daylight Saving Time boundaries. But when I did, suddenly I skipped a day or hit the same day twice, because Midnight March 8, 2009 + 24 hours = 1:00 AM March 10. Drop off the time, as I was doing, and March 9 was mysteriously skipped. Likewise midnight Nov 1, 2009 + 24 hours = 11:00 PM Nov 1, and we hit Nov 1 twice.

Use a Calendar object if you want to manipulate dates.
Calendar c = Calendar.getInstance();
// ... set the calendar time ...
Date endDate = new Date();
// ... set the endDate value ...
while (c.getTime().before(endDate) {
// do something
c.add(Calendar.DAY_OF_WEEK, 1);
}
Or use Joda Time

I highly recommend using Joda time:
Java Joda Time - Implement a Date range iterator