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in Java I get an error, that says close parenthesis is expected [closed]

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Closed 2 years ago.
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my Main class look like the following:
public class Main {
public static void main(String[] args)
{
Account account=new Account();
account.deposit(amount:10);
System.out.println(account.getBalance());
}
}
and Account class as below:
public class Account {
private float balance;
public void deposit(float amount){
if(amount>0)
balance+=amount;
}
}
I get an java ) expected error, which refers to the line "account.deposit(amount:10);" in Main class and hints, that amounts can not be resolved, but i dont understand why, could you give me some hint.

Change
account.deposit(amount:10);
to
account.deposit(10);
or
account.deposit(10.0f);
You can't label parameters that way at the caller's site. Also, don't forget to implement getBalance(). And use brackets ({}) even when they're optional.

Class or Interface excepted [closed]

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Closed 4 years ago.
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Here is the code:
public class Tuna {
public void eat() {
System.out.println("I am a tuna fish"); // Here it says class or interface excepted
}
}
I have a Tuna class above that has a eat method. In that eat method, it says class or interface expected at the print line. Even though it is running smoothly, when I hover over the print line in the eat method it says class or interface expected. I already checked other questions related to it but I couldn't solve it. Any help is appreciated.

How do I cast Stream.empty() in Java 8? [closed]

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Closed 7 years ago.
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All the examples I've found use other type information to infer the type of Stream.empty(). It seems like there should be syntax to allow me to cast it directly. This example works:
import java.util.*;
import java.util.stream.*;
class OptionalBasics {
static void test(Optional<String> optString) {
if(optString.isPresent())
System.out.println(optString.get());
else
System.out.println("Nothing inside!");
}
public static void main(String[] args) {
Stream<String> s = Stream.empty();
test(s.findFirst());
test(Stream.of("Epithets").findFirst());
}
}
/* Output:
Nothing inside!
Epithets
*/
But notice that I have to create s separately in order to provide type information for Stream.empty(). I'd like to just create it in the call to
test(), something like this (which doesn't work):
test(Stream<String>.empty().findFirst());
Is there a syntax for setting the type on the call to Stream.empty()?

You just have the brackets in the wrong spot. Try Stream.<String> empty().findFirst())

Java Interfaces , Declaring an Interface [closed]

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Why eclipse throws an error message while giving public modifier to interface
publid interface one // throws an error
{
}
Public type one must be defined in its own file error i am getting
please give your clarifications regarding this

Create a new file called 'one.java'. Place the declaration of your interface in there.
Every public class, interface etc. needs to be in its own file.

Because your Java file containing one most probably is not named "one.java".

Any public class or interface must be declared in a separate file, having the name of that interface or class.
If you have multiple top level classes/interfaces in the same file, only one of them can be public.

no arg method compiler error not generated [closed]

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Closed 8 years ago.
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Here is my code:
public class XYZ {
public static void overLoaded(Object a) {
System.out.println("IN OBJECT");
}
public static void main(String[] args) {
overLoaded();
}
}
I expected compile time error as there is no arg method but instead the output is coming out to be IN OBJECT.
Please explain the output.

I just tried your code and am getting:
method overLoaded in class XYZ cannot be applied to given types;
overLoaded();
^
required: Object
found: no arguments
reason: actual and formal argument lists differ in length
1 error
So, if you are getting the behaviour you describe, either your compiler is seriously broken or the code you've given us is not the code you have.