Develop Reference

How to get full URL in JSP

How would I get the full URL of a JSP page.
For example the URL might be http://www.example.com/news.do/?language=nl&country=NL
If I do things like the following I always get news.jsp and not .do
out.print(request.getServletPath());
out.print(request.getRequestURI());
out.print(request.getRequest());
out.print(request.getContextPath());

You need to call request.getRequestURL():
Reconstructs the URL the client used to make the request. The returned URL contains a protocol, server name, port number, and server path, but it does not include query string parameters.

Given URL = http:/localhost:8080/sample/url.jsp?id1=something&id2=something&id3=something
request.getQueryString();
it returns id1=something&id2=something&id3=something
See This

I found a solution. It may not be perfect solution. But it working solution.
String qs = request.getQueryString();
String foo = request.getRequestURL().toString()+"?"+qs;

Java - Getting cookie value without escape characters

I guess this is duplicate. But could not found what I am loking for.
I have one Java Spring MVC web application runniong as server. I have another angularJS application running as client. In AngularJS I am setting some cookies, But the string values are encoded with special characters. It looks like this
id=20; name=%22myname%22
In my Controller I am getting the cookie value id properly, but not name.
Cookie[] cookies=request.getCookies();
String name=cookies[1].getValue();
System.out.println(name);
And it prints
%22myname%22
How to get rid of this encoded characters?

You can decode your string in your controller as follows:
URLDecoder.decode(name, "utf8")

String value = URLDecode.decode(cookie.getValue(), "UTF-8");

How to get request query string from the URL

I am trying to extract the query string from the static URL from the browser using Java.
But when I use the getQueryString() method, it is returning the query string for the particular portlet.
For example: my static url looks like this /owner/?search&name= and the portlet URL is /home/create which can't be seen in the browser URL.
Is there any way to extract the query string from Static URL?

James,
You may try to use PortletRequest.getParameterMap(), returning a java.util.Map of java.lang.String,java.lang.String[] - as in the official JSR-286 spec
Check the link, there are some other methods to extract URL parameters and values.
Hope this helps,
Philippe

Hide sending parameters from url

I should use link. And it means that method GET and all parameters I can see in url. How I can hide parametrs from url like that
http://localhost:8080/MyApp/action.do?method=delete&id=0
And how after that I can get parametrs in java class.

You can't hide GET parameters from a URL. GET name value pairs have to be part of a request. However one thing you can certainly try is to encrypt your querystring into a string which only your code can decode on your host, for example
http://localhost:8080/MyApp/action.do?method=delete&id=0
could be
http://localhost:8080/MyApp/action.do?param=[ENCRYPTED/OBFUSCATED STRING]
then your application at the above url can decode that and convert back into name value pairs

That's the idea of GET method - to path parameters through URL, probably you should use POST.

JBoss application complete path

Is there any way I can get url address of an application from java code, I mean complete address not only value from getContextPath(). Something like http://localhost:8080/etc

Try with getRequestUrl().
I hope it helps you

In a servlet or JSP, you can call javax.servlet.http.HttpUtils.getRequestURL(request)
It returns a StringBuffer containing the entire URL up to the servlet
From the javadoc
Reconstructs the URL the client used to make the request, using information in the HttpServletRequest object. The returned URL contains a protocol, server name, port number, and server path, but it does not include query string parameters.
If you only want up to the context path, you'll have to remove your servlet path

There is no method that returns the entire URL including the query parameters. You need to use something like:
req.getRequestURL()+"?"+req.getQueryString();
Or if you don't have query parameters you can use getRequestURL
It is pretty confusing, but here is a graphic that helps sort it out: