The common implementation is here, Java's built-in implementation is here. I have two questions regarding these two implementations:
1) The first implementation use synchronized key word on put() and take() methods, which means only one thread can access one method. Let's say if thread A call put() and found the queue is full, so it's waiting, then no one can ever call take() method since the lock is not released yet, how can the implementation be used?
2) Java's built-in uses two locks: takeLock and putLock, and used in put() and take() respectively. I saw that the interval queue is a linked list, which is not thread-safe, how can that be done?
As already mentioned in some of the comments the first implementation just uses traditional wait()/notify() mechanism where one thread waits (and of course releasing lock) for being notified by other threads.
The second one uses different locks each for put and take operations. So the individual operations (simultaneous put() or take()) are synchronous. But they need to communicate with each other when queue is full or empty. So they interact with each other through condition. Checkout the two private methods-
/**
* Signals a waiting take. Called only from put/offer (which do not
* otherwise ordinarily lock takeLock.)
*/
private void signalNotEmpty() {
final ReentrantLock takeLock = this.takeLock;
takeLock.lock();
try {
notEmpty.signal();
} finally {
takeLock.unlock();
}
}
/**
* Signals a waiting put. Called only from take/poll.
*/
private void signalNotFull() {
final ReentrantLock putLock = this.putLock;
putLock.lock();
try {
notFull.signal();
} finally {
putLock.unlock();
}
}
put method signals other threads trying to take/poll from empty queue and take method signals other threads trying to put elements into full queue.
Related
For an ArrayBlockingQueue in Java, does queue.add(element) ever lock up the thread it is in? I have an application with dozens of threads running that will all put information into one ArrayBlockingQueue. The threads cannot afford to be locked up for any short amount of time. If they are all putting objects into the queue, will the add method instantly move on and let the queue put the object into itself in the future or will it wait until it actually is put inside the queue?
ArrayBlockingQueue is implementation of Queue which additionally supports operations that wait for the queue to become non-empty when retrieving an element, and wait for space to become available in the queue when storing an element.
add method inserts the specified element at the tail of this queue if it is possible to do so immediately without exceeding the queue's capacity, returning true upon success and throwing an IllegalStateException if this queue is full.
Attempts to put an element into a full queue will result in the operation blocking; attempts to take an element from an empty queue will similarly block.
Once created, the capacity cannot be changed.
Yes when you call add method in ArrayBlockingQueue it will take lock to do the operation or else how it will make threadsafe. How you will put your object to any shared variable in multi-threaded environment.You need synchronization.You can check some non-blocking collection (can create own linked list).Where you will add your value then a single daemon thread will read one by one and put in queue.
JAVA Implementation
add method internally call offer.If you don't want to wait more than a given time you can use public boolean tryLock(long timeout, TimeUnit unit)
public boolean offer(E e) {
checkNotNull(e);
final ReentrantLock lock = this.lock;
lock.lock();
try {
if (count == items.length)
return false;
else {
enqueue(e);
return true;
}
} finally {
lock.unlock();
}
}
In ArrayBlockingQueue concurrent operations guarded with java.util.concurrent.locks.ReentrantLock. And operations are synchronous. When you add an item to the queue add operation returns after enqueue operation completed.
I know that the documentation says that the object is thread safe but does that mean that all access to it from all methods are thread safe? So if I call put() on it from many threads at once and take() on it at the same instance, will nothing bad happen?
I ask because this answer is making me second guess:
https://stackoverflow.com/a/22006181/4164238
The quick answer is yes, they are thread safe. But lets not leave it there ...
Firstly a little house keeping, BlockingQueue is an interface, and any implementation that is not thread safe will be breaking the documented contract. The link that you included was referring to LinkedBlockingQueue, which has some cleverness to it.
The link that you included makes an interesting observation, yes there are two locks within LinkedBlockingQueue. However it fails to understand that the edge case that a 'simple' implementation would have fallen foul of was in-fact being handled, which is why the take and put methods are more complicated than one would at first expect.
LinkedBlockingQueue is optimized to avoid using the same lock on both reading and writing, this reduces contention however for correct behavior it relies on the queue not being empty. When the queue has elements within it, then the push and the pop points are not at the same region of memory and contention can be avoided. However when the queue is empty then the contention cannot be avoided, and so extra code is required to handle this common 'edge' case. This is a common trade off between code complexity and performance/scalability.
The question then follows, how does LinkedBlockingQueue know when the queue is empty/not empty and thus handle the threading then? The answer is that it uses an AtomicInteger and a Condition as two extra concurrent data structures. The AtomicInteger is used to check whether the length of the queue is zero and the Condition is used to wait for a signal to notify a waiting thread when the queue is probably in the desired state. This extra coordination does have an overhead, however in measurements it has been shown that when ramping up the number of concurrent threads that the overheads of this technique are lower than the contention that is introduced by using a single lock.
Below I have copied the code from LinkedBlockingQueue and added comments explaining how they work. At a high level, take() first locks out all other calls to take() and then signals put() as necessary. put() works in a similar way, first it blocks out all other calls to put() and then signals take() if necessary.
From the put() method:
// putLock coordinates the calls to put() only; further coordination
// between put() and take() follows below
putLock.lockInterruptibly();
try {
// block while the queue is full; count is shared between put() and take()
// and is safely visible between cores but prone to change between calls
// a while loop is used because state can change between signals, which is
// why signals get rechecked and resent.. read on to see more of that
while (count.get() == capacity) {
notFull.await();
}
// we know that the queue is not full so add
enqueue(e);
c = count.getAndIncrement();
// if the queue is not full, send a signal to wake up
// any thread that is possibly waiting for the queue to be a little
// emptier -- note that this is logically part of 'take()' but it
// has to be here because take() blocks itself
if (c + 1 < capacity)
notFull.signal();
} finally {
putLock.unlock();
}
if (c == 0)
signalNotEmpty();
From take()
takeLock.lockInterruptibly();
try {
// wait for the queue to stop being empty
while (count.get() == 0) {
notEmpty.await();
}
// remove element
x = dequeue();
// decrement shared count
c = count.getAndDecrement();
// send signal that the queue is not empty
// note that this is logically part of put(), but
// for thread coordination reasons is here
if (c > 1)
notEmpty.signal();
} finally {
takeLock.unlock();
}
if (c == capacity)
signalNotFull();
Yes, all implementations of BlockingQueue are thread safe for put and take and all actions.
The link just goes halfway...and is not covering the full details. It is thread safe.
That answer is a little strange - for a start, BlockingQueue is an interface so it doesn't have any locks. Implementations such as ArrayBlockingQueue use the same lock for add() and take() so would be fine. Generally, if any implementation is not thread safe then it is a buggy implementation.
I think #Chris K has missed some points. "When the queue has elements within it, then the push and the pop points are not at the same region of memory and contention can be avoided. ", notice that when the queue has one element, head.next and tail points to the same node and put() and take() can both get locks and execute.
I think empty and full condition can be solved by synchronized put() and take(). However when it comes to one element, the lb queue has a null dummy head node, which may has something to do with the thread safety.
I tried this implementation on Leetcode
import java.util.concurrent.BlockingQueue;
import java.util.concurrent.LinkedBlockingDeque;
class FooBar {
private final BlockingQueue<Object> line = new LinkedBlockingDeque<>(1);
private static final Object PRESENT = new Object();
private int n;
public FooBar(int n) {
this.n = n;
}
public void foo(Runnable printFoo) throws InterruptedException {
for (int i = 0; i < n; i++) {
line.put(PRESENT);
// printFoo.run() outputs "foo". Do not change or remove this line.
printFoo.run();
}
}
public void bar(Runnable printBar) throws InterruptedException {
for (int i = 0; i < n; i++) {
line.take();
// printBar.run() outputs "bar". Do not change or remove this line.
printBar.run();
}
}
}
With n = 3, mosttimes I get a correct response of foobarfoobarfoorbar but sometimes I get barbarfoofoofoobar which is quite surprising.
I resolved to use using ReentrantLock and Condition, #chris-k can you shed more light
i need to write a java program but i need some advice before starting on my own.
The program i will be writing is to do the following:
Simulate a shop takes advanced order for donuts
The shop would not take further orders, once 5000 donuts have been ordered
Ok i am kind of stuck thinking if i should be writing the java-class to act as a Monitor or should i use Java-Semaphore class instead?
Please advice me. Thanks for the help.
Any java object can work as a monitor via the wait/notify methods inherited from Object:
Object monitor = new Object();
// thread 1
synchronized(monitor) {
monitor.wait();
}
// thread 2
synchronized(monitor) {
monitor.notify();
}
Just make sure to hold the lock on the monitor object when calling these methods (don't worry about the wait, the lock is released automatically to allow other threads to acquire it). This way, you have a convenient mechanism for signalling among threads.
It seems to me like you are implementing a bounded producer-consumer queue. In this case:
The producer will keep putting items in a shared queue.
If the queue size reaches 5000, it will call wait on a shared monitor and go to sleep.
When it puts an item, it will call notify on the monitor to wake up the consumer if it's waiting.
The consumer will keep taking items from the queue.
When it takes an item, it will call notify on the monitor to wake up the producer.
If the queue size reaches 0 the consumer calls wait and goes to sleep.
For an even more simplified approach, have a loop at the various implementation of BlockingQueue, which provides the above features out of the box!
It seems to me that the core of this exercise is updating a counter (number of orders taken), in a thread-safe and atomic fashion. If implemented incorrectly, your shop could end up taking more than 5000 pre-orders due to missed updates and possibly different threads seeing stale values of the counter.
The simplest way to update a counter atomically is to use synchronized methods to get and increment it:
class DonutShop {
private int ordersTaken = 0;
public synchronized int getOrdersTaken() {
return ordersTaken;
}
public synchronized void increaseOrdersBy(int n) {
ordersTaken += n;
}
// Other methods here
}
The synchronized methods mean that only one thread can be calling either method at any time (and they also provide a memory barrier to ensure that different threads see the same value rather than locally cached ones which may be outdated). This ensures a consistent view of the counter across all threads in your application.
(Note that I didn't have a "set" method but an "increment" method. The problem with "set" is that if client has to call shop.set(shop.get() + 1);, another thread could have incremented the value between the calls to get and set, so this update would be lost. By making the whole increment operation atomic - because it's in the synchronized block - this situation cannot occur.
In practice I would probably use an AtomicInteger instead, which is basically a wrapper around an int to allow for atomic queries and updates, just like the DonutShop class above. It also has the advantage that it's more efficient in terms of minimising exclusive blocking, and it's part of the standard library so will be more immediately familiar to other developers than a class you've written yourself.
In terms of correctness, either will suffice.
Like Tudor wrote, you can use any object as monitor for general purpose locking and synchronization.
However, if you got the requirement that only x orders (x=5000 for your case) can be processed at any one time, you could use the java.util.concurrent.Semaphore class. It is made specifically for use cases where you can only have fixed number of jobs running - it is called permits in the terminology of Semaphore
If you do the processing immediately, you can go with
private Semaphore semaphore = new Semaphore(5000);
public void process(Order order)
{
if (semaphore.tryAcquire())
{
try
{
//do your processing here
}
finally
{
semaphore.release();
}
}
else
{
throw new IllegalStateException("can't take more orders");
}
}
If if takes more than that (human input required, starting another thread/process, etc.), you need to add callback for when the processing is over, like:
private Semaphore semaphore = new Semaphore(5000);
public void process(Order order)
{
if (semaphore.tryAcquire())
{
//start a new job to process order
}
else
{
throw new IllegalStateException("can't take more orders");
}
}
//call this from the job you started, once it is finished
public void processingFinished(Order order)
{
semaphore.release();
//any other post-processing for that order
}
I'm trying to implement a simple blocking queue in Java ME. In JavaME API, the concurrency utilities of Java SE are not available, so I have to use wait-notify like in the old times.
This is my provisional implementation. I'm using notify instead of notifyAll because in my project there are multiple producers but only a single consumer. I used an object for wait-notify on purpose to improve readability, despite it wastes a reference:
import java.util.Vector;
public class BlockingQueue {
private Vector queue = new Vector();
private Object queueLock = new Object();
public void put(Object o){
synchronized(queueLock){
queue.addElement(o);
queueLock.notify();
}
}
public Object take(){
Object ret = null;
synchronized (queueLock) {
while (queue.isEmpty()){
try {
queueLock.wait();
} catch (InterruptedException e) {}
}
ret = queue.elementAt(0);
queue.removeElementAt(0);
}
return ret;
}
}
My main question is about the put method. Could I put the queue.addElement line out of the synchronized block? Will performance improve if so?
Also, the same applies to take: could I take the two operations on queue out of the synchronized block?
Any other possible optimization?
EDIT:
As #Raam correctly pointed out, the consumer thread can starve when being awakened in wait. So what are the alternatives to prevent this? (Note: In JavaME I don't have all these nice classes from Java SE. Think of it as the old Java v1.2)
The Vector class makes no guarantees to be thread safe, and you should synchronize access to it, like you have done. Unless you have evidence that your current solution has performance problems, I wouldn't worry about it.
On a side note, I see no harm in using notifyAll rather than notify to support multiple consumers.
synchronized is used to protect access to shared state and ensure atomicity.
Note that methods of Vector are already synchronized, therefore Vector protects it own shared state itself. So, your synchronization blocks are only needed to ensure atomicity of your operations.
You certainly cannot move operations on queue from the synchronized block in your take() method, because atomicity is crucial for correctness of that method. But, as far as I understand, you can move queue operation from the synchronized block in the put() method (I cannot imagine a situation when it can go wrong).
However, the reasoning above is purely theoretical, because in all cases you have double synchronization: your synchronize on queueLock and methods of Vector implicitly synchronize on queue. Therefore proposed optimization doesn't make sense, its correctness depends on presence of that double synchronization.
To avoid double synchronization you need to synchronize on queue as well:
synchronized (queue) { ... }
Another option would be to use non-synchronized collection (such as ArrayList) instead of Vector, but JavaME doesn't support it. In this case you won't be able to use proposed optimization as well because synchronized blocks also protect shared state of the non-synchronized collection.
Unless you have performance issues specifically due to garbage collection, I would rather use a linked list than a Vector to implement a queue (first in,first out).
I would also write code that would be reused when your project (or another) gets multiple consumers. Although in that case, you need to be aware that the Java language specifications do not impose a way to implement monitors. In practice, that means that you don't control which consumer thread gets notified (half of the existing Java Virtual Machines implement monitors using a FIFO model and the other half implement monitors using a LIFO model)
I also think that whoever is using the blocking class is also supposed to deal with the InterruptedException. After all, the client code would have to deal with a null Object return otherwise.
So, something like this:
/*package*/ class LinkedObject {
private Object iCurrentObject = null;
private LinkedObject iNextLinkedObject = null;
LinkedObject(Object aNewObject, LinkedObject aNextLinkedObject) {
iCurrentObject = aNewObject;
iNextLinkedObject = aNextLinkedObject;
}
Object getCurrentObject() {
return iCurrentObject;
}
LinkedObject getNextLinkedObject() {
return iNextLinkedObject;
}
}
public class BlockingQueue {
private LinkedObject iLinkedListContainer = null;
private Object iQueueLock = new Object();
private int iBlockedThreadCount = 0;
public void appendObject(Object aNewObject) {
synchronized(iQueueLock) {
iLinkedListContainer = new iLinkedListContainer(aNewObject, iLinkedListContainer);
if(iBlockedThreadCount > 0) {
iQueueLock.notify();//one at a time because we only appended one object
}
} //synchonized(iQueueLock)
}
public Object getFirstObject() throws InterruptedException {
Object result = null;
synchronized(iQueueLock) {
if(null == iLinkedListContainer) {
++iBlockedThreadCount;
try {
iQueueLock.wait();
--iBlockedThreadCount; // instead of having a "finally" statement
} catch (InterruptedException iex) {
--iBlockedThreadCount;
throw iex;
}
}
result = iLinkedListcontainer.getCurrentObject();
iLinkedListContainer = iLinkedListContainer.getNextLinkedObject();
if((iBlockedThreadCount > 0) && (null != iLinkedListContainer )) {
iQueueLock.notify();
}
}//synchronized(iQueueLock)
return result;
}
}
I think that if you try to put less code in the synchronized blocks, the class will not be correct anymore.
There seem to be some issues with this approach. You can have scenarios where the consumer can miss notifications and wait on the queue even when there are elements in the queue.
Consider the following sequence in chronological order
T1 - Consumer acquires the queueLock and then calls wait. Wait will release the lock and cause the thread to wait for a notification
T2 - One producer acquires the queueLock and adds an element to the queue and calls notify
T3 - The Consumer thread is notified and attempts to acquire queueLock BUT fails as another producer comes at the same time. (from the notify java doc - The awakened thread will compete in the usual manner with any other threads that might be actively competing to synchronize on this object; for example, the awakened thread enjoys no reliable privilege or disadvantage in being the next thread to lock this object.)
T4 - The second producer now adds another element and calls notify. This notify is lost as the consumer is waiting on queueLock.
So theoretically its possible for the consumer to starve (forever stuck trying to get the queueLock) also you can run into a memory issue with multiple producers adding elements to the queue which are not being read and removed from the queue.
Some changes that I would suggest is as follows -
Keep an upper bound to the number of items that can be added to the queue.
Ensure that the consumer always read all the elements. Here is a program which shows how the producer - consumer problem can be coded.
I am writing a multi-threaded application that mimics a movie theater. Each person involved is its own thread and concurrency must be done completely by semaphores. The only issue I am having is how to basically link threads so that they can communicate (via a pipe for instance).
For instance:
Customer[1] which is a thread, acquires a semaphore that lets it walk up to the Box Office. Now Customer[1] must tell the Box Office Agent that they want to see movie "X". Then BoxOfficeAgent[1] also a thread, must check to make sure the movie isn't full and either sell a ticket or tell Customer[1] to pick another movie.
How do I pass that data back and forth while still maintaining concurrency with the semaphores?
Also, the only class I can use from java.util.concurrent is the Semaphore class.
One easy way to pass data back and forth between threads is to use the implementations of the interface BlockingQueue<E>, located in the package java.util.concurrent.
This interfaces has methods to add elements to the collection with different behaviors:
add(E): adds if possible, otherwise throws exception
boolean offer(E): returns true if the element has been added, false otherwise
boolean offer(E, long, TimeUnit): tries to add the element, waiting the specified amount of time
put(E): blocks the calling thread until the element has been added
It also defines methods for element retrieval with similar behaviors:
take(): blocks until there's an element available
poll(long, TimeUnit): retrieves an element or returns null
The implementations I use most frequently are: ArrayBlockingQueue, LinkedBlockingQueue and SynchronousQueue.
The first one, ArrayBlockingQueue, has a fixed size, defined by a parameter passed to its constructor.
The second, LinkedBlockingQueue, has illimited size. It will always accept any elements, that is, offer will return true immediately, add will never throw an exception.
The third, and to me the most interesting one, SynchronousQueue, is exactly a pipe. You can think of it as a queue with size 0. It will never keep an element: this queue will only accept elements if there's some other thread trying to retrieve elements from it. Conversely, a retrieval operation will only return an element if there's another thread trying to push it.
To fulfill the homework requirement of synchronization done exclusively with semaphores, you could get inspired by the description I gave you about the SynchronousQueue, and write something quite similar:
class Pipe<E> {
private E e;
private final Semaphore read = new Semaphore(0);
private final Semaphore write = new Semaphore(1);
public final void put(final E e) {
write.acquire();
this.e = e;
read.release();
}
public final E take() {
read.acquire();
E e = this.e;
write.release();
return e;
}
}
Notice that this class presents similar behavior to what I described about the SynchronousQueue.
Once the methods put(E) gets called it acquires the write semaphore, which will be left empty, so that another call to the same method would block at its first line. This method then stores a reference to the object being passed, and releases the read semaphore. This release will make it possible for any thread calling the take() method to proceed.
The first step of the take() method is then, naturally, to acquire the read semaphore, in order to disallow any other thread to retrieve the element concurrently. After the element has been retrieved and kept in a local variable (exercise: what would happen if that line, E e = this.e, were removed?), the method releases the write semaphore, so that the method put(E) may be called again by any thread, and returns what has been saved in the local variable.
As an important remark, observe that the reference to the object being passed is kept in a private field, and the methods take() and put(E) are both final. This is of utmost importance, and often missed. If these methods were not final (or worse, the field not private), an inheriting class would be able to alter the behavior of take() and put(E) breaking the contract.
Finally, you could avoid the need to declare a local variable in the take() method by using try {} finally {} as follows:
class Pipe<E> {
// ...
public final E take() {
try {
read.acquire();
return e;
} finally {
write.release();
}
}
}
Here, the point of this example if just to show an use of try/finally that goes unnoticed among inexperienced developers. Obviously, in this case, there's no real gain.
Oh damn, I've mostly finished your homework for you. In retribution -- and for you to test your knowledge about Semaphores --, why don't you implement some of the other methods defined by the BlockingQueue contract? For example, you could implement an offer(E) method and a take(E, long, TimeUnit)!
Good luck.
Think it in terms of shared memory with read/write lock.
Create a buffer to put the message.
The access to the buffer should be controlled by using a lock/semaphore.
Use this buffer for inter thread communication purpose.
Regards
PKV