As depicted in above image java home is set and is being echoed but when i check for version it gives me latest version.
Already restarted the command prompt after setting env variable.
OS is Windows 7
Update:
Following is the Path.
..ProgramData\Oracle\Java\javapath;%SystemRoot%\system32;%SystemRoot%;%SystemRoot%\System32\Wbem;%SYSTEMROOT%\System32\WindowsPowerShell\v1.0\;;%JAVA_HOME%/bin;
I had the same trouble and I solved it with the following steps:
You need the correct environment variables.
To be exactly correct, you only need to set the Path variable.
You need to find where you add %JAVA_HOME%\bin to the path.
Put it at first place in the Path variable:
%JAVA_HOME%\bin;...
where ... represents all other values of Path.
I assume that JAVA_HOME is defined as a variable and had the correct value.
After this reopen console and check:
java -version
JAVA_HOME is environment variable that various application reads in their launcher script
when you invoke java it looks up for all paths specified in your env variable named PATH and wherever the first match is it gets picked up
so if you like command prompt to refer to jdk 6's Java append the path to PATH
You need to add the path to jJAVA_HOME%/bin directory in the path variable too. java command is located in %JAVA_HOME%/bin
Check your PATH environment variable also. Your system is referring to latest Java installation through PATH variable.
I think in your path variable you have hardcoded the path to bin folder. it should always be %JAVA_HOME%/bin.
So that it can pick path from JAVA_HOME variable and you don't need to change both the variables every time.
Related
After setting JAVA_HOME to C:\Program Files\Java\jdk1.8.0_171 and adding %JAVA_HOME%\bin to my path, I am still getting this error. I have checked that the path is correct multiple times and every solution online just says to add these two variables. Is there any other step to fix this?
I'm getting this error when trying to run "java -jar start.jar" for solr.
You have not added Java Location as the Path variable in your system. The Command Prompt or Powershell can only take you to the path/paths you have already specified.
Add "C:\Program Files\Java\jdk1.8.0_171\bin\" to the Path variable in your Advanced System Settings->Enviroment Variables->Path.
Make sure you run the command in a new DOS shell. If you are using the same one you ran the java command in before setting the path, it won't have the path update.
Don't type path manualy - choose path by [Browse directory] button.
Path looks the same but can be different (maybe encoding of signs)
I have installed Java 8 and set my JAVA_HOME and JRE_HOME paths and added %JAVA_HOME% to the start of the path variable.
When I try to run simple java program I get error as
"The system cannot find the file C:\spl\java\bin\bin\java.exe".
The above path contains extra bin.
Where as environment variable and JAVA_HOME has C:\spl\java\bin\ this path.
I cannot understand from where this extra bin directory is coming.
Please help.
From where does system is taking C:\spl\java\bin\bin\ this path?
Your JAVA_HOME should point to the ...\Java\jdk1.8.. directory.
In Your path you should have %JAVA_HOME%\bin.
Some applications refer to JAVA_HOME and add \bin on their own, so you must not add \bin to your JAVA_HOME. Otherwise, you'll receive correct error saying, that C:\spl\java\bin\bin\ doesn't contain Java.exe
Solution:
Remove \bin from your JAVA_HOME
It is quite clear from your example: the system is taking %JAVA_HOME% as the "home" of your java installation, not its bin directory. So when you try to start java.exe, it looks in %JAVA_HOME%\bin. Just remove the bin part of your JAVA_HOME.
At my work I have user access with no admin privileges. My environment variable points to an old JDK at the current path: C:\ProgramData\Oracle\Java\javapath
From what I read on different posts such as this which states that all user variables override the environment variable except the PATH variable in which it concatenates the environment variable and user variable together. I have followed many different tutorials and currently have my variables set up like this in my user PATH variable.
JAVA_HOME = C:\Program Files\Java\jdk1.7.0_79
JRE_HOME = C:\Users\316830207\jre7
PATH = C:\Users\316830207\AppData\Roaming\npm;C:\Users\316830207\AppData\Roaming\jdk1.7.0_79\bin
TMP = %USERPROFILE%\AppData\Local\Temp
If you notice my PATH variable for the user has npm path as well as jdk. The npm path was added so I could bower from the command line. That works! However the path for the JDK is never used. No matter what when I type java -v I get
The system cannot find the file C:\ProgramData\Oracle\Java\javapath\java.exe
Since the path variable contacts the only thing I can think of is it skips my JDK path or overwrites. I have tried using command line using setx as I cannot use setx /M as I do not have admin access. I have searched for a few days now and the only conclusion is I am doing this wrong or security from my work is stopping me to overwrite JDKpath.
So my question is am I setting the JDK path incorrectly? Is there a different way I can set it? Why will it only use my environment path and not my user JDK path?
JAVA_HOME contains the installation path of JAVA.
Set environment variable JAVA_HOME to installation path C:\Program Files\java\ jdk-1_7_0_08 using following steps for windows user
1. Right Click on My Computer->Properties-> Advanced->Environment Variables ->User Variables -> New
2. Set JAVA_HOME to value C:\Program Files\java\ jdk-1_7_0_08
-Djava.library.path="path to a dll"
This replace the environment path variable in the current session. I want to append this path to the already existing path.
Kindly let me know how to do it. I'm calling a jar from command prompt using
java -Djava.library.path="path to a dll" -jar myjar.jar
On Windows: Add the path to the library to the PATH environment variable.
On Linux: Add the path to the library to the LD_LIBRARY_PATH environment variable.
On Mac: Add the path to the library to the DYLD_LIBRARY_PATH environment variable.
java.library.path is initilized with the values of the variables above on its corresponding platform.
You can test if the value is what you expect by calling java -XshowSettings:properties
You can try -Djava.library.path="%PATH%;path to a dll" or if it does't work
you need to get existing PATH variable value and add you path to it.
I have installed java on windows-64bit OS. but when I execute javac, it is failing with the
error message no such command is available". I have created following environmental variable
CLASSPATH C:\Program Files (x86)\Java\jdk1.6.0_05\lib
Add the appropriate javac path to your PATH variable. java.exe will be found under the bin directory of your JDK. E.g.
SET PATH=%PATH%;C:\Program Files (x86)\Java\jdk1.6.0_05\bin
Before answering your question, just wann ans this simple question : Why we need PATH and CLASSPATH?
Answer:
1) PATH: You need to set PATH to compile Java source code, create JAVA CLASS FILES and Operating System to load classes at runtime.
2) CLASSPATH: This is used by JVM and not by OS.
Answer to your question :
Just make sure you have Modified PATH variable (Windows System Environmental Variable) so that it points to bin dir which contains all exe for example: java,javac and etc. In my case it is like this : ;C:\Program Files\Java\jre7\bin.
So, it doesn't matter your system is 32 bit/64 bit until and unless you specify/Modify the PATH variable correctly.
Actually, the most conventional way of getting it done on Windows is
Go to Control Panel
Click System
Open Advanced settings
Click Environment Variables...
Path is one of the variables under "System Variables".
This is where the system will search when you try to execute a command.
just append the full path to the Bin folder under your Java
installation path. You can copy it using Windows Explorer to avoid typing it manually
click OK to close the dialogs.
To verify, open the command window aka console window (for example, WindowsKey-R cmd.exe ) and run:
javac -version
If the java bin folder is in the path, the system will find and execute the javac.exe file located there, and you will see your Java version. Something like:
c:\>javac -version
javac 1.7.0_65
Very Simple:
You need to set the two environment variables only; PATH and java
=>Right Click on My computer
=>Properties
=>Click on left hand side bar menu "Advanced system settings"
=> Click on "Environment Variables" button refer below fig.
=>Follow the below steps to Set User variable and System variable.
To Set User variable named as "PATH"
Click on "New" button in user variables section.
Set the variable name as "PATH" and variable value as per your java
installed version.(Shown in below fig.)
To Set System variable named as "java"
Click on "New" button in System variable tab.
Set the variable name as "java" and variable value as per your java
installed version.(Shown in below fig.)
Refer below images for the reference.
For me, the 'JAVA_HOME' variable should be set as a System Variable, instead of User Variable.
When the 'JAVA_HOME' was changed to be a System Variable, the command 'javac' works.
Also, the PATH and CLASSPATH are System Variable.