Develop Reference

sshpass command not found when I run it in java

I am trying to run a command to read a string from a file inside a remote address (and I'm sure the file is there), this command works when I run it on the bash but it doesn't work when I run it in my java code.
Runtime rt = Runtime.getRuntime();
String[] command;
String line;
try {
command = new String[] {"sh", "-c", "\"sshpass " + "-p " + password + " ssh " + user + "#" + ip + " 'cat " + file.getAbsolutePath() + "'\"" };
Process mountProcess = rt.exec(command);
mountProcess.waitFor();
bufferedReader = new BufferedReader(new InputStreamReader(mountProcess.getInputStream()));
while ((line = bufferedReader.readLine()) != null) {
user_list.put(user, line);
}
bufferedReader.close();
bufferedReader = new BufferedReader(new InputStreamReader(mountProcess.getErrorStream()));
while ((line = bufferedReader.readLine()) != null) {
LOGGER.debug("Stderr: " + line);
}
bufferedReader.close();
} catch ...
No line is added to my user_list (so the line from getInputStream is null) and I get the following error from the logger in the code:
Stderr: sh: 1: sshpass: not found
If I use the exact same command on the bash it works and it prints the string I need.
sshpass -p password ssh remote#192.168.1.10 'cat /home/ID/ID'
Anyone knows why this is happening? thanks!

I'd suggest you don't need to use sh to wrap your command. Try
command = new String[] {"sshpass", "-p", password, "ssh", user + "#" + ip, "cat " + file.getAbsolutePath() };
If you need to use sh, then remove the escaped double quotes from the command string: you are sending those as literal characters:
command = new String[] {
"sh",
"-c",
String.format("sshpass -p %s ssh %s#%s 'cat %s'", password, user, ip, file.getAbsolutionPath())
};
If you're still getting "command not found", then you need to either specify the full path to sshpass, or ensure that its directory is in your PATH.

When doing this command with java the user is tomcat8 instead of root (when used in the bash terminal)
The solution that worked for me included some flags:
String.format("/usr/local/bin/sshpass -p %s /usr/bin/ssh -q -o UserKnownHostsFile=/dev/null -o StrictHostKeyChecking=no %s#%s 'cat %s'", password, user, ip, file.getAbsolutePath());

Run bat file from different disk with java

Im trying to run a bat from C:/abc/def/coolBat.bat but my java workspace is in D:/
I've tried with :
String cmd = "cmd /c /start C:/abc/def/coolBat.bat";
Runtime.getRuntime().exec(cmd);
But didn't work, so I tried this
String[] command = { "cmd.exe", "/C", "C:/abc/def/coolBat.bat" };
Runtime.getRuntime().exec(cmd);
didnt work either. Tried this too
Executor exec = new DefaultExecutor();
exec.setWorkingDirectory(new File("C:/abc/def"));
CommandLine cl = new CommandLine("coolBat.bat");
int exitvalue = exec.execute(cl);
Says it cant find the file.
Tried something like this too:
Runtime.getRuntime().exec("cmd cd /d C:/abc/def/ && coolBat.bat");
And nothing. The weird thing is that this command:
cd /d C:/abc/def/ && coolBat.bat
Works when i do it in cmd. Its worth saying that the bat file copies some files to another directory, all inside C:/
EDITED N°1
CD C:\abc\def\MN
copy almn + ctmn + bamn C:\abc\def\mn_sf.txt
CD C:\abc\def\ME
copy alme + ctme + bame C:\abc\def\me_sf.txt
CD C:\abc\def\
if exist MN.txt del MN.txt
if exist ME.txt del ME.txt
if exist JUZ.txt del JUZ.txt
if exist FUNC.txt del FUNC.txt
if exist AHO.txt del AHO.txt
CD C:\

Allow MS Windows to use the associated application to run your batch file (or any other application):
Required Imports:
import java.awt.Desktop;
Here is code you can try:
String filePath = "C:/abc/def/coolBat.bat";
if (Desktop.isDesktopSupported()) {
try {
File myFile = new File(filePath);
Desktop.getDesktop().open(myFile);
}
catch (IOException | IllegalArgumentException ex) {
System.err.println("Either there is no application found "
+ "which is associatd with\nthe file you want to work with or the "
+ "file doesn't exist!\n\n" + filePath);
}
}

Well I finally got it to work, just had to change my workspace to C:/
Apparently the problem was that it couldn't change from D:/ to C:/ to execute. I ran the same commands I tried before and there was no problem.
Guess the question remains, why it couldn't change from D:/ to C:/ when running commands from Java.
Thanks to everyone for the help

The Java version could work as:
String[] command = {"cmd.exe", "/C", "Start", "/D", "c:\\abc\\def", "c:\\abc\\def\\coolBat.bat"};
Process process = Runtime.getRuntime().exec(command);
BufferedReader input = new BufferedReader(new InputStreamReader(process.getInputStream()));
while ((line = input.readLine()) != null) {
System.out.println(line);
}
input.close();
BufferedReader errReader = new BufferedReader(new InputStreamReader(process.getErrorStream()));
while ((line = errReader.readLine()) != null) {
System.out.println(line);
}
System.out.flush();
int retCode = process.waitFor();
System.out.println("Return code: " + retCode);

Try this:
String[] command = { "cmd.exe", "/C", "C: && C:/abc/def/coolBat.bat" };

Runtime.getRuntime().exec not finding file in java environment

I started a project in Processing and then found that I needed more functionality. I had the following function that worked fine in Processing but now in the java environment I am getting an error.
Function:
void camSummary() {
System.out.format("Cam summary");
String commandToRun = "./camSummary.sh";
File workingDir = new File(main.path);
try {
Process p = Runtime.getRuntime().exec(commandToRun, null, workingDir);
int i = p.waitFor();
if (i==0) {
BufferedReader stdInput = new BufferedReader(new InputStreamReader(p.getInputStream()));
while ( (returnedValues = stdInput.readLine ()) != null) {
System.out.format(returnedValues);
}
}
}
catch(Throwable t) {
System.out.format("error: " + t + "\n");
}
}
Error:
Cannot run program "camSummary.sh" (in directory
"/Users/lorenzimmer/Documents/RC/CamSoft/ "): error=2, No such file or
directory
I've found that there have been some very slight differences from processing to java. I'm wondering if this function just needs to be tweaked slightly to run properly.
Any help would be greatly appreciated.
Loren

Runtime.exec does not invoke a shell, so you have to explicitly invoke one (bash, sh, etc)
Try this:
Change String commandToRun = "./camSummary.sh";
to
String[] commandToRun = {"bash", "-c", "/path/to/camSummary.sh"};
or
String[] commandToRun = {"sh", "/path/to/camSummary.sh"};
Then change
Process p = Runtime.getRuntime().exec(commandToRun, null, workingDir);
to
Process p = Runtime.getRuntime().exec(commandToRun);
In one line: Process p = Runtime.getRuntime().exec(new String[] {"bash", "-c", "/path/to/script"});

Running mysqldump from java in linux

** The following command works fine when run directly on terminal
mysqldump -uabc -pabc1234 --compact --no-create-info -w \"fieldname != 'A'\" dbname tablename -hhostaddress --result-file=/tmp/myfile.txt
** But when it is executed using Runtime() method then it does not produce the output in the destination file.
String s="mysqldump -uabc -pabc1234 --compact --no-create-info -w \"fieldname != 'A'\" dbname tablename -hhostaddress --result-file=/tmp/myfile.txt";
Runtime.getRuntime().exec(s);
(** say abc is the username and abc1234 the password)
The same problem occurs if redirection to the destination file ( > ) is usedinstead of --result-file option.
What shall i do to execute it from within a java program ?

for unachiveing file I used
final Runtime r = Runtime.getRuntime();
final Process p = r.exec("/bin/tar -xvf " + zipFile, null, fileDir);
where zipFile - target filename,
fileDir - current dir path (where need to put files)
Also I used "/bin/tar" because direct "tar" was hidden from Runtime.exec environment. Try to use direct path too (just for test).
for logs just add next at the end
final int returnCode = p.waitFor();
if (logger.isDebugEnabled()) {
final BufferedReader is = new BufferedReader(new InputStreamReader(p.getInputStream()));
String line;
while ((line = is.readLine()) != null) {
logger.debug(line);
}
final BufferedReader is2 = new BufferedReader(new InputStreamReader(p.getErrorStream()));
while ((line = is2.readLine()) != null) {
logger.debug(line);
}
}

Use ProcessBuilder api which handles whitespaces better. Output will be in result file.
new ProcessBuilder( "mysqldump" , "-uabc", "-pabc1234", ... ).start();
'>' is Shell indirection- It works if your program is shell.
new ProcessBuilder( "bash", -"c "mysqldump" , "-uabc", "-pabc1234", ..., "> fileresult" ).start();

Java - Exec console

I want to create a full cross-plateform console in Java.
The problem I have is when I use the cd command, the path is reset. For example, if I do cd bin, then cd ../, I will execute the first one from the directory of my app and the second one exactly from the same directory.
If I want to go to a specific folder and execute a program I have to do something like that:
cd C:\mydir & cd bin & start.exe
What I want to do is to split this cmd in different parts:
cd C:\mydir then cd bin then start.exe
How can I do that? Is there a way to store the current cd path and use it then?
Here is the code I use:
String[] cmd_exec = new String[] {"cmd", "/c", cmd};
Process child = Runtime.getRuntime().exec(cmd_exec);
BufferedReader in = new BufferedReader(new InputStreamReader(child.getInputStream()));
StringBuffer buffer = new StringBuffer();
buffer.append("> " + cmd + "\n");
String line;
while ((line = in.readLine()) != null)
{
buffer.append(line + "\n");
}
in.close();
child.destroy();
return buffer.toString();
It executes the command, then return the content of the console. (This is for windows for the moment).

If you want to run a command from a specific directory, use ProcessBuilder instead of Runtime.exec. You can set the working directory using the directory method before you start the process. Don't try to use the cd command - you're not running a shell, so it doesn't make sense.

If you do cd you don't want to execute it. You just want to check if the relative path exists and then change a
File currentDir
to that directory. So I would propose you split your commands up in three: cd, dir/ls and other stuff. cd changes the dir, as I mentioned, by using a File currentDir, dir should just get folders and files of currentDir and list them and then the rest you should just execute as you do know.
Remember you can split a command string by "".split("&"); this way you can do "cd C:\mydir & cd bin & start.exe".split("&"); => {"cd C:\mydir", "cd bin", "start.exe"} and then you can execute them in order.
Good luck.

Thanks to Mads, I was able to do the trick:
Here is the code I used:
if (cmd.indexOf("cd ") >= 0)
{
String req_cmd = cmd.substring(0, 3);
String req_path = cmd.substring(3);
if (req_path.startsWith(File.separator) || req_path.substring(1, 2).equals(":"))
path = req_path;
else
if (new File(path + cmd.substring(3)).exists())
path += cmd.substring(3);
else return "[Error] Directory doesn't exist.\n";
if (!path.endsWith(File.separator)) path += File.separator;
cmd = req_cmd + path;
}
else cmd = "cd " + path + " & " + cmd;
Then you can execute the command calling:
Runtime.getRuntime().exec(new String[] {"cmd", "/c", cmd});
Don't forget to add this attribute in your class:
private static String path = System.getProperty("user.dir") + File.separator;