How to add number of months to a specific date - java

I want to add a number of months to a specific date based on what that user selected. for instance adding 3 months to 15/05/2015.
I tried something but its showing me the same date.
Code below:
Calendar aed = Calendar.getInstance();
int monthsToAdd = 0;
if (advertPostedDate.equals(1)) {
monthsToAdd = 1;
}
if (advertPostedDate.equals(2)) {
monthsToAdd = 2;
}
if (advertPostedDate.equals(3)) {
monthsToAdd = 3;
}
aed.add(Calendar.MONTH, monthsToAdd);
Date advertED = aed.getTime();
DateFormat df = new SimpleDateFormat("dd-MM-yyyy");
String advertExpiryDate = df.format(advertED);

Your code looks fine, with exception that I would use an if/else if structure instead of just the if structure. Are you sure advertPostedDate has a value of 1, 2, or 3? Because if it doesn't then 0 is being added to months.
public static void main(String[] args) {
Integer advertPostedDate = 2;
Calendar aed = Calendar.getInstance(); // 15-5-2015
int monthsToAdd = 0;
if (advertPostedDate.equals(1)) {
monthsToAdd = 1;
} else if (advertPostedDate.equals(2)) {
monthsToAdd = 2;
} else if (advertPostedDate.equals(3)) {
monthsToAdd = 3;
}
aed.add(Calendar.MONTH, monthsToAdd);
Date advertED = aed.getTime();
DateFormat df = new SimpleDateFormat("dd-MM-yyyy");
String advertExpiryDate = df.format(advertED);
System.out.println(advertExpiryDate);
}
Results:
15-07-2015

I suggest that you use Joda-Time
DateTime dt = new DateTime(2015, 5, 15, 12, 0, 0, 0);
DateTime plusPeriod = dt.plusMonths(3);

Related

Split a date into equal intervals based on a given frequency

I'm trying to break a range of dates into equal intervals. Here is the code that I'm using. (Dates are in YYYY-MM-dd format)
Integer frequency= 4;
Date startDate = '2020-02-27';
Date endDate = '2022-02-26';
String[] startD = string.valueOf(behadelPlan.Start_datum__c).split('-');
String[] endD = string.valueOf(behadelPlan.Einddatum__c).split('-');
//String[] dates;
Integer x = 0;
Integer startYear = Integer.valueof(startD[0]);
Integer endYear = Integer.valueof(endD[0]);
//while (x < 4) {
for (Integer i = startYear; i <= endYear; i++) {
Integer endMonth = i != endYear ? 11 : Integer.valueof(endD[1]) - 1;
Integer startMon = i == startYear ? Integer.valueof(startD[1]) - 1 : 0;
for (Integer j = startMon; j <= endMonth && x < frequency; j = j + 1) {
Integer month = j + 1;
String displayMonth;
if (month < 10) {
displayMonth = '0' + month;
} else {
displayMonth = String.valueOf(month);
}
List<string> slist = new string[]{string.valueOf(i), displayMonth, '01'};
string allstring = string.join(sList,'-');
System.debug(slist);
x+=1;
}
}
when I run this I get the output as
2020-02-01
2020-03-01
2020-04-01
2020-05-01
Here In my case, I want to generate the dates at equal(monthly with the day being start dates day) intervals. In the above example, I should be getting the resultant dates as 4 equal intervals (as I've given my frequency in a number of months).
Please let me know on how can I achieve this.
Here is a simple example.
startdate = '2020-01-01'
endDate = '2020-12-01'
frequency = 4
output should be
2020-01-01
2020-03-01
2020-06-01
2020-09-01
Here is how I would do it. I will us class Calendar for this.
public class FrequencyTransform {
public static void main (String[] args) {
System.out.println("Split a date into equal intervals based on a given frequency");
Integer frequency= 4;
try {
Date startDate = new SimpleDateFormat("yyyy-mm-dd").parse("2020-02-27");
Date endDate = new SimpleDateFormat("yyyy-mm-dd").parse("2021-02-26");
Calendar startCalendar = Calendar.getInstance();
startCalendar.clear();
startCalendar.setTime(startDate);
Calendar endCalendar = Calendar.getInstance();
endCalendar.clear();
endCalendar.setTime(endDate);
// id you want the interval to be months
int monthsElapsed = elapsed(startCalendar, endCalendar, Calendar.MONTH);
System.out.println("Number of months between dates:" + monthsElapsed);
int interval = monthsElapsed % frequency;
System.out.println("For the frequency 4 the interval is: " + interval);
while (!startCalendar.after(endCalendar)){
startCalendar.add(Calendar.MONTH,interval);
Date auxDate= startCalendar.getTime();
System.out.println(auxDate);
}
}
catch (ParseException ex) {
ex.printStackTrace();
}
}
private static int elapsed(Calendar before, Calendar after, int field) {
Calendar clone = (Calendar) before.clone(); // Otherwise changes are been reflected.
int elapsed = -1;
while (!clone.after(after)) {
clone.add(field, 1);
elapsed++;
}
return elapsed;
}
}
This is just a quick example. You can take it from here. The thing is Calendar allow you to use different time units. Instead of Calendar.MONTH you can use Calendar.DATE for days, Calendar.YEAR for year. Wasn't very sure how you wanted to do the split.
Sample code ,
import java.text.DateFormat;
import java.text.ParseException;
import java.text.SimpleDateFormat;
import java.util.Date;
public class SOTest {
static DateFormat dateFormat = new SimpleDateFormat("yyy-MM-dd");
public static void main(String[] args) {
try {
String startDateString = "2020-01-01";
String endDateString = "2020-12-01";
int frequency = 4;
Date startDate = (Date)dateFormat.parse(startDateString);
Date endDate = (Date)dateFormat.parse(endDateString);
Long intervalSize = (endDate.getTime()-startDate.getTime())/frequency;
for(int i=0; i<= frequency && intervalSize > 0; i++) {
Date date = new Date(startDate.getTime()+intervalSize*i);
System.out.println("Date :: "+dateFormat.format(date));
}
} catch (ParseException e) {
e.printStackTrace();
}
}
}
output for above ::
Date :: 2020-01-01
Date :: 2020-03-24
Date :: 2020-06-16
Date :: 2020-09-08
Date :: 2020-12-01
For input :: startDate = '2020-02-27' , endDate = '2022-02-26', interval = 4
Date :: 2020-02-27
Date :: 2020-08-27
Date :: 2021-02-26
Date :: 2021-08-27
Date :: 2022-02-26

Implement Java method for test data [duplicate]

I'm trying to generate a random date of birth for people in my database using a Java program. How would I do this?
import java.util.GregorianCalendar;
public class RandomDateOfBirth {
public static void main(String[] args) {
GregorianCalendar gc = new GregorianCalendar();
int year = randBetween(1900, 2010);
gc.set(gc.YEAR, year);
int dayOfYear = randBetween(1, gc.getActualMaximum(gc.DAY_OF_YEAR));
gc.set(gc.DAY_OF_YEAR, dayOfYear);
System.out.println(gc.get(gc.YEAR) + "-" + (gc.get(gc.MONTH) + 1) + "-" + gc.get(gc.DAY_OF_MONTH));
}
public static int randBetween(int start, int end) {
return start + (int)Math.round(Math.random() * (end - start));
}
}
java.util.Date has a constructor that accepts milliseconds since The Epoch, and java.util.Random has a method that can give you a random number of milliseconds. You'll want to set a range for the random value depending on the range of DOBs that you want, but those should do it.
Very roughly:
Random rnd;
Date dt;
long ms;
// Get a new random instance, seeded from the clock
rnd = new Random();
// Get an Epoch value roughly between 1940 and 2010
// -946771200000L = January 1, 1940
// Add up to 70 years to it (using modulus on the next long)
ms = -946771200000L + (Math.abs(rnd.nextLong()) % (70L * 365 * 24 * 60 * 60 * 1000));
// Construct a date
dt = new Date(ms);
Snippet for a Java 8 based solution:
Random random = new Random();
int minDay = (int) LocalDate.of(1900, 1, 1).toEpochDay();
int maxDay = (int) LocalDate.of(2015, 1, 1).toEpochDay();
long randomDay = minDay + random.nextInt(maxDay - minDay);
LocalDate randomBirthDate = LocalDate.ofEpochDay(randomDay);
System.out.println(randomBirthDate);
Note: This generates a random date between 1Jan1900 (inclusive) and 1Jan2015 (exclusive).
Note: It is based on epoch days, i.e. days relative to 1Jan1970 (EPOCH) - positive meaning after EPOCH, negative meaning before EPOCH
You can also create a small utility class:
public class RandomDate {
private final LocalDate minDate;
private final LocalDate maxDate;
private final Random random;
public RandomDate(LocalDate minDate, LocalDate maxDate) {
this.minDate = minDate;
this.maxDate = maxDate;
this.random = new Random();
}
public LocalDate nextDate() {
int minDay = (int) minDate.toEpochDay();
int maxDay = (int) maxDate.toEpochDay();
long randomDay = minDay + random.nextInt(maxDay - minDay);
return LocalDate.ofEpochDay(randomDay);
}
#Override
public String toString() {
return "RandomDate{" +
"maxDate=" + maxDate +
", minDate=" + minDate +
'}';
}
}
and use it like this:
RandomDate rd = new RandomDate(LocalDate.of(1900, 1, 1), LocalDate.of(2010, 1, 1));
System.out.println(rd.nextDate());
System.out.println(rd.nextDate()); // birthdays ad infinitum
You need to define a random date, right?
A simple way of doing that is to generate a new Date object, using a long (time in milliseconds since 1st January, 1970) and substract a random long:
new Date(Math.abs(System.currentTimeMillis() - RandomUtils.nextLong()));
(RandomUtils is taken from Apache Commons Lang).
Of course, this is far to be a real random date (for example you will not get date before 1970), but I think it will be enough for your needs.
Otherwise, you can create your own date by using Calendar class:
int year = // generate a year between 1900 and 2010;
int dayOfYear = // generate a number between 1 and 365 (or 366 if you need to handle leap year);
Calendar calendar = Calendar.getInstance();
calendar.set(Calendar.YEAR, randomYear);
calendar.set(Calendar.DAY_OF_YEAR, dayOfYear);
Date randomDoB = calendar.getTime();
For Java8 -> Assumming the data of birth must be before current day:
import java.time.LocalDate;
import java.time.LocalTime;
import java.time.Period;
import java.time.temporal.ChronoUnit;
import java.util.Random;
public class RandomDate {
public static LocalDate randomBirthday() {
return LocalDate.now().minus(Period.ofDays((new Random().nextInt(365 * 70))));
}
public static void main(String[] args) {
System.out.println("randomDate: " + randomBirthday());
}
}
If you don't mind adding a new library to your code you can use MockNeat (disclaimer: I am one of the authors).
MockNeat mock = MockNeat.threadLocal();
// Generates a random date between [1970-1-1, NOW)
LocalDate localDate = mock.localDates().val();
System.out.println(localDate);
// Generates a random date in the past
// but beore 1987-1-30
LocalDate min = LocalDate.of(1987, 1, 30);
LocalDate past = mock.localDates().past(min).val();
System.out.println(past);
LocalDate max = LocalDate.of(2020, 1, 1);
LocalDate future = mock.localDates().future(max).val();
System.out.println(future);
// Generates a random date between 1989-1-1 and 1993-1-1
LocalDate start = LocalDate.of(1989, 1, 1);
LocalDate stop = LocalDate.of(1993, 1, 1);
LocalDate between = mock.localDates().between(start, stop).val();
System.out.println(between);
Generating random Date of Births:
import java.util.Calendar;
public class Main {
public static void main(String[] args) {
for (int i = 0; i < 100; i++) {
System.out.println(randomDOB());
}
}
public static String randomDOB() {
int yyyy = random(1900, 2013);
int mm = random(1, 12);
int dd = 0; // will set it later depending on year and month
switch(mm) {
case 2:
if (isLeapYear(yyyy)) {
dd = random(1, 29);
} else {
dd = random(1, 28);
}
break;
case 1:
case 3:
case 5:
case 7:
case 8:
case 10:
case 12:
dd = random(1, 31);
break;
default:
dd = random(1, 30);
break;
}
String year = Integer.toString(yyyy);
String month = Integer.toString(mm);
String day = Integer.toString(dd);
if (mm < 10) {
month = "0" + mm;
}
if (dd < 10) {
day = "0" + dd;
}
return day + '/' + month + '/' + year;
}
public static int random(int lowerBound, int upperBound) {
return (lowerBound + (int) Math.round(Math.random()
* (upperBound - lowerBound)));
}
public static boolean isLeapYear(int year) {
Calendar calendar = Calendar.getInstance();
calendar.set(Calendar.YEAR, year);
int noOfDays = calendar.getActualMaximum(Calendar.DAY_OF_YEAR);
if (noOfDays > 365) {
return true;
}
return false;
}
}
You can checkout randomizer for random data generation.This library helps to create random data from given Model class.Checkout below example code.
public class Person {
#DateValue( from = "01 Jan 1990",to = "31 Dec 2002" , customFormat = "dd MMM yyyy")
String dateOfBirth;
}
//Generate random 100 Person(Model Class) object
Generator<Person> generator = new Generator<>(Person.class);
List<Person> persons = generator.generate(100);
As there are many built in data generator is accessible using annotation,You also can build custom data generator.I suggest you to go through documentation provided on library page.
Look this method:
public static Date dateRandom(int initialYear, int lastYear) {
if (initialYear > lastYear) {
int year = lastYear;
lastYear = initialYear;
initialYear = year;
}
Calendar cInitialYear = Calendar.getInstance();
cInitialYear.set(Calendar.YEAR, 2015);
long offset = cInitialYear.getTimeInMillis();
Calendar cLastYear = Calendar.getInstance();
cLastYear.set(Calendar.YEAR, 2016);
long end = cLastYear.getTimeInMillis();
long diff = end - offset + 1;
Timestamp timestamp = new Timestamp(offset + (long) (Math.random() * diff));
return new Date(timestamp.getTime());
}
I think this will do the trick:
public static void main(String[] args) {
Date now = new Date();
long sixMonthsAgo = (now.getTime() - 15552000000l);
long today = now.getTime();
for(int i=0; i<10; i++) {
long ms = ThreadLocalRandom.current().nextLong(sixMonthsAgo, today);
Date date = new Date(ms);
System.out.println(date.toString());
}
}
If you don't mind a 3rd party library, the Utils library has a RandomDateUtils that generates random java.util.Dates and all the dates, times, instants, and durations from Java 8's date and time API
LocalDate birthDate = RandomDateUtils.randomPastLocalDate();
LocalDate today = LocalDate.now();
LocalDate under18YearsOld = RandomDateUtils.randomLocalDate(today.minus(18, YEARS), today);
LocalDate over18YearsOld = RandomDateUtils.randomLocalDateBefore(today.minus(18, YEARS));
It is in the Maven Central Repository at:
<dependency>
<groupId>com.github.rkumsher</groupId>
<artifactId>utils</artifactId>
<version>1.3</version>
</dependency>
simplest method:
public static LocalDate randomDateOfBirth() {
final int maxAge = 100 * 12 * 31;
return LocalDate.now().minusDays(new Random().nextInt(maxAge));
}
Using the original answer and adapting it to the new java.time.* api and adding ways to generate n random dates -- the function will return a List.
// RandomBirthday.java
import java.util.ArrayList;
import java.util.List;
import java.util.concurrent.ThreadLocalRandom;
import java.time.LocalDate;
import java.time.format.DateTimeFormatter;
public class RandomBirthday {
public static List<String> getRandomBirthday(int groupSize, int minYear, int maxYear) {
/** Given a group size, this method will return `n` random birthday
* between 1922-2022 where `n=groupSize`.
*
* #param groupSize the number of random birthday to return
* #param minYear the min year [lower bound]
* #param maxYear the max year [upper bound]
* #return a list of random birthday with format YYYY-MM-DD
*/
ArrayList<String> birthdays = new ArrayList<>();
DateTimeFormatter dateFormat = DateTimeFormatter.ofPattern("yyyy-MM-dd");
for (int i = 0; i < groupSize; i++) {
LocalDate baseDate = LocalDate.now();
LocalDate baseYear = baseDate.withYear(ThreadLocalRandom.current().nextInt(minYear, maxYear));
int dayOfYear = ThreadLocalRandom.current().nextInt(1, baseYear.lengthOfYear());
LocalDate baseRandBirthday = baseYear.withDayOfYear(dayOfYear);
LocalDate randDate = LocalDate.of(
baseRandBirthday.getYear(),
baseRandBirthday.getMonth(),
baseRandBirthday.getDayOfMonth()
);
String formattedDate = dateFormat.format(randDate);
birthdays.add(formattedDate);
}
return birthdays;
}
public static void main(String[] args) {
// main method
List<String> bDay = getRandomBirthday(40, 1960, 2022);
System.out.println(bDay);
}
}
I am studying Scala and ended up Googling Java solutions for choosing a random date between range. I found this post super helpful and this is my final solution. Hope it can help future Scala and Java programmers.
import java.sql.Timestamp
def date_rand(ts_start_str:String = "2012-01-01 00:00:00", ts_end_str:String = "2015-01-01 00:00:00"): String = {
val ts_start = Timestamp.valueOf(ts_start_str).getTime()
val ts_end = Timestamp.valueOf(ts_end_str).getTime()
val diff = ts_end - ts_start
println(diff)
val ts_rand = new Timestamp(ts_start + (Random.nextFloat() * diff).toLong)
return ts_rand.toString
} //> date_rand: (ts_start_str: String, ts_end_str: String)String
println(date_rand()) //> 94694400000
//| 2012-10-28 18:21:13.216
println(date_rand("2001-01-01 00:00:00", "2001-01-01 00:00:00"))
//> 0
//| 2001-01-01 00:00:00.0
println(date_rand("2001-01-01 00:00:00", "2010-01-01 00:00:00"))
//> 283996800000
//| 2008-02-16 23:15:48.864 //> 2013-12-21 08:32:16.384
int num = 0;
char[] a={'a','b','c','d','e','f'};
String error = null;
try {
num = Integer.parseInt(request.getParameter("num"));
Random r = new Random();
long currentDate = new Date().getTime();
ArrayList<Student> list = new ArrayList<>();
for (int i = 0; i < num; i++) {
String name = "";
for (int j = 0; j < 6; j++) {
name += a[r.nextInt(5)];
}
list.add(new Student(i + 1, name, r.nextBoolean(), new Date(Math.abs(r.nextLong() % currentDate))));
}
request.setAttribute("list", list);
request.setAttribute("num", num);
request.getRequestDispatcher("student.jsp").forward(request, response);
} catch (NumberFormatException e) {
error = "Please enter interger number";
request.setAttribute("error", error);
request.getRequestDispatcher("student.jsp").forward(request, response);
}

Show time with the different hour

public static void main(String[] args) throws ParseException {
String myTime = "08:00";
int diffHour = 2;
SimpleDateFormat df = new SimpleDateFormat("HH:mm");
Date d = df.parse(myTime);
Calendar cal = Calendar.getInstance();
cal.setTime(d);
for (int i=0; i<=diffHour; i++) {
cal.add(Calendar.HOUR, i);
String newTime = df.format(cal.getTime());
System.out.println(newTime);
}
}
The output is:
08:00
09:00
11:00
I want it to be:
08:00
09:00
10:00
because in the different two hours only until 10:00 if we started with 08:00.
Why did the output jump from 10:00 to 11:00?
The answer by Draken is correct. You are adding i where you should be adding a number one 1.
java.time
You are also using old troublesome classes now outmoded by the java.time classes.
LocalTime
The LocalTime class represents a time-of-day-only value without date and without time zone.
LocalTime start = LocalTime.parse( "08:00" );
int hours = 2;
LocalTime time = start;
for ( int i = 0 ; i <= hours ; i++ ) {
String output = time.toString();
// Set up next loop.
time = time.plusHours( 1 );
}
cal.add(Calendar.HOUR, 1);
You're adding i, which will increase by one on each loop, so for the first it will add zero, then one, and then two. Instead, since you want to add by a concrete number, try instead to add just 1.
Though that does mean you would need to start at 07:00, the other choice is to put some logic in, but that depends on what you are expecting. Something like this could work:
for (int i=0; i<=diffHour; i++) {
if (i <= 1) {
cal.add(Calendar.HOUR, i);
} else {
cal.add(Calendar.HOUR, 1);
}
String newTime = df.format(cal.getTime());
System.out.println(newTime);
}
Here's a fiddle of it working
Try something like this:
package org.app.temputil;
import java.text.ParseException;
import java.text.SimpleDateFormat;
import java.util.Calendar;
import java.util.Date;
public class Test {
public static void main(String[] args) throws ParseException {
String myTime = "08:00";
int diffHour = 2;
SimpleDateFormat df = new SimpleDateFormat("HH:mm");
Date d = df.parse(myTime);
Calendar cal = Calendar.getInstance();
cal.setTime(d);
for (int i = 0; i <= diffHour; i++) {
cal.add(Calendar.HOUR, i == 0 ? 0 : 1);
String newTime = df.format(cal.getTime());
System.out.println("i=[" + i + "], time=" + newTime);
}
}
}
Here is the description of your code -
for (int i=0; i<=diffHour; i++) {
cal.add(Calendar.HOUR, i);
String newTime = df.format(cal.getTime());
System.out.println(newTime);
}
Here the loop is running for i = 0, 1, 2.
For i = 0, 0 is added to calendar so that value remains same as it was earlier 8.
For i = 1, 1 is added to calendar so the value becomes 8 (earlier value) + 1 = 9
For i = 2, 2 is added to calendar so the value becomes 9 (earlier value) + 2 = 11.
To make it work,
Remove the line - cal.add(Calendar.HOUR, i);
Add this line -
if (i == 0) {
cal.add(Calendar.HOUR, 0);
} else {
cal.add(Calendar.HOUR, 1);
}
change your loop to this
for (int i=0; i<=diffHour; i++) {
String newTime = df.format(cal.getTime());
System.out.println(newTime);
cal.add(Calendar.HOUR, 1);
}

Java overlapping date

I have this programming exercise which looks for overlapping date ranges.
So far this is what I've done:
private static final SimpleDateFormat dateFormat = new SimpleDateFormat("MMM dd, yyyy");
private static final Date invalidDate = new Date(0);
private static final Date fromString( String spec ) {
try {
return dateFormat.parse( spec );
} catch( ParseException dfe ) {
return invalidDate;
}
}
public static void main(String[] args) {
Date [] randomDates = {
fromString("Aug 28, 2014"),
fromString("Sep 1, 2014"),
fromString("Aug 30, 2014"),
fromString("Sep 3, 2014"),
fromString("Sep 5, 2014"),
fromString("Sep 7, 2014")
};
for( Date date: randomDates ) {
print( date );
}
}
private static final void print( Date date ) {
if( date == invalidDate ) {
System.out.println("Invalid date");
} else {
System.out.println( dateFormat.format( date ) );
}
}
But I can't seem to figure out the overlapping of dates. Or I don't still get how to find the overlapping dates. Any ideas? Your help will be truly appreciated.
For checking overlapping date ranges you can use JodaTime
DateTime currentdate1 = DateTime.now(); //first Date range
DateTime endDate1 = now.plusHours(10);
DateTime currentdate2 = now.plusDays(5); //second Date range
DateTime endDate2 = now.plusDays(6);
Interval interval1 = new Interval( currentdate1, endDate1 );
Interval interval2 = new Interval( currentdate2, endDate2 );
System.out.println( interval1.overlaps( interval2 ) );
Edit:-
Since you do not want to use external library, you can use .compareTo() of Date and try to implement the following condition:-
( currentdate1 <= endDate2 and currentdate2 <= endDate1 )
Example:-
if( (currentdate1.compareTo(endDate2)<=0) && (currentdate2.compareTo(endDate1)<=0) ){
//ranges overlap
}
Since you want to compare a single date and check if it is present in the range specified you can do something like this:-
| Daterange start------Your Date------ DateRange ends|
Hence:-
for(Date date:randomDates){
//check if the date in in the range
if( (DateRangeStart.compareTo(date)<=0) && (date.compareTo(DateRangeEnd)<=0)){
//date overlaps
System.out.println(dateFormat.format(date));
}
}
Edit:- Updating answer to include solution to the problem as discussed in chat
outerloop: for (int i = 0; i < (dates.length - 1); i = i + 2) {
Date currentdate1 = dates[i];
Date endDate1 = dates[i + 1];
for (int j = i + 2; j < dates.length - 1; j = j + 2) {
Date currentdate2 = dates[j];
Date endDate2 = dates[j + 1];
if ((currentdate1.compareTo(endDate2) <= 0)
&& (currentdate2.compareTo(endDate1) <= 0)) {
System.out.println("Overlapping found:-");
print(currentdate2);
print(endDate2);
break outerloop;
}
}
}

Does anyone know how to convert a datefield to a string in java j2me?

I need to get the data from a datefield calender and be able to display it in a string and later store it in a recordstore. I tried the toString() method but i had an error once run.
StartDate = new DateField("Start Date ", DateField.DATE);
StartDate.setDate(Calendar.getInstance().getTime());
I now have this code
public static String dateToString (long date)
{
Calendar c = Calendar.getInstance() ;
c.setTime(new Date(date));
int y = c.get(Calendar.YEAR);
int m = c.get(Calendar.MONTH) + 1;
int d = c.get(Calendar.DATE);
String t = (y<10? "0": "")+y+"-"+(m<10? "0": "")+m+"-"+(d<10?
"0": "")+d;
return t;
}
How can I change this in order for this to get the date from Startdate and make that t.?
If anyone could help!
There are some sample implementations that may help you get started, since it appears your runtime doesn't provide a useful toString implementation.
Does this solve your problem?
...
date = new Date();
currentDate = new DateField("", DateField.DATE_TIME);
currentDate.setDate(date);
dateinstring = date.toString();
System.out.println("Date And Time Is In String Format: "+dateinstring);
...
Try to use something like this
...
Calendar c = Calendar.getInstance() ;
c.setTime(new Date(date));
int y = c.get(Calendar.YEAR);
int m = c.get(Calendar.MONTH) + 1;
int d = c.get(Calendar.DATE);
Date t = c.getTime();
String str = t.format("YY-MM-dd");
...
First you need to change the parameter type of dateToString to Date:
Public static String dateToString(Date date)
Then after
StartDate.setDate(Calendar.getInstance().getTime();
add this line:
String dateString = dateToString(StartDate.getDate());
Well, at least that works in my MIDlet.
Hopefully this helps.
Regards,
wahyu a
you might wanna use this:
public String getDateFormat(Date inDate){
String stDate = null;
String dd = null;
String mm = null;
String yyyy = null;
Calendar cd = Calendar.getInstance();
cd.setTime(inputDT);
int iD = cd.get( Calendar.DAY_OF_MONTH );
if (iD < 10){ dd = "0" + String.valueOf(iD); }
else { dd = String.valueOf(iD); }
int iM = cd.get( Calendar.MONTH )+1;
if (iM < 10){ mm = "0" + String.valueOf(iM); }
else { mm = String.valueOf(iM); }
int iY = cd.get( Calendar.YEAR );
yyyy = String.valueOf(iY);
stDate = yyyy+"-"+mm+"-"+dd;
return stDate;
}
to get the 'long' variable become 'Date' use the Date(long date) from java.util.Date}

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