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(Spring Boot, JpaRepository, Postgresql) Why is repository interface is not instanced during runtime?

I'm making a small program using Spring, Maven and Hibernate. The current goal is to use JpaRepository to interact with a Postgresql database. However, when I try to call for it to list all entries in a table within the database, it spits out a NullPointerException. Online resources vary in their implementation, so it's been hard for me to understand what goes wrong.
My application can be summarized as follows:
Javatest3Application.java (Outermost layer, handles communication)
#SpringBootApplication
#EnableAutoConfiguration
#EnableJpaRepositories
#RestController
public class Javatest3Application {
//---VARIABLES---
private JavatestService service_handler = new JavatestService();
//---PUBLIC---
public static void main(String[] args) {
SpringApplication.run(Javatest3Application.class, args);
}
#PostMapping("/login")
public ResponseEntity<String> Login(#RequestBody Map<String, String> json_map) {
//>>Read json_map for account_name and account_pwd
//Ask Service layer to log user in
Long session_id = this.service_handler.OpenSession(account_name, account_pwd);
//>>Construct response, blah blah...
}
}
JavatestService.java (Middle layer, manages repository interaction)
#Service
public class JavatestService {
//---VARIABLES---
#Autowired
private JavatestRepository repo;
//---PUBLIC---
public JavatestService() {}
public Long OpenSession(String in_name, String in_pwd) {
//Call database for credentials
List<JavatestUser> user_listings = this.repo.findAll(); //<- THIS FAILS
//>>Go though list, blah blah...
}
}
JavatestRepository.java (Bottom layer, interface extention)
#Repository
public interface JavatestRepository extends JpaRepository<JavatestUser, Long> {
//List<JavatestUser> findAll(); <- Don't think I need to add this. I believe its already in JpaRepository
}
JavatestUser.java (Bottommost layer, DTO class for database entry)
#Entity
#Table(name = "javatest_table", schema = "javatest_schema")
public class JavatestUser {
#Id
#GeneratedValue(strategy = GenerationType.AUTO)
private Long account_id;
private String account_name;
private String account_pwd;
public JavatestUser(){
}
//>>Getter and Setter functions, blah blah...
}
So, as far as I have understood it, we cannot instance objects of an interface. However, when using Spring, the program itself creates classes that implement the interface, and then hands such a derived class back to us via the #Autowired keyword.
Thus when we call the findAll() function, we use that derived class to fetch objects of the associated #Entity class.
From my research I've come to believe I might use the #Service keyword wrong, and that it perhaps should be a #Controller. However, as far as I can see, the are implementations of both alternatives, so my understanding of what differentiates them is somewhat lacking. Regardless of which I am using, the #Autowired doesn't seem to provide any JavatestRepository-derived object for me to call findAll() upon.
EDITS
Added #EnableJpaRepositories in accordance with Eugene Botyanovsky's suggestion.

You are probably missing annotation, which enables all your repositories:
#EnableJpaRepositories
It's similar to #EnableAutoConfiguration you used, but exactly for JPA repositories.

Spring mvc - which layer should convert entities to dtos (and vice versa)

In which layer should DTO/Entity conversion take place.
Having following structure in a Spring Mvc application:
Controller
Service
Repository
The approach I'm using now, where service layer is #Transactional.
#RestController
public class ExampleController {
#Autowired
private ExampleService exampleService;
#Autowired
private ExampleMapper exampleMapper;
#GetMapping("/examples")
public ResponseEntity<List<ExamleDto>> getAll() {
var examples = exampleService.getAll();
return ResponseEntity.ok(exampleMapper.examplesToExampleDtos(examples));
}
#PostMapping("/examples")
public ResponseEntity<Void> create(#RequestBody #Valid ExampleCreateDto createDto) {
var example = exampleService.create(createDto)
return ResponseEntity.created(URI.create("examples/" + example.getId()).build();
}
// PUT, DELETE, ...
}
#Service
#Transactional
public class ExampleService {
#Autowired
private ExampleRepository exampleRepository;
#Autowired
private ExampleMapper exampleMapper;
public List<Examle> getAll() {
var examples = exampleRepository.findAll();
return examples;
}
public void create(ExampleDto exampleDto) {
var example = exampleMapper.asExample(exampleDto);
return exampleRepository.save(example);
}
}
public interface ExampleRepository extends JpaRepository<Example, Long> {
Why I choose this aproach:
The service layer is transactional, so whenever we get back to the controller, all changes will be flushed (version field for example) will all be set.
It makes you think about your entitygraph, lets say you have a Person entity which has a list of Deparments. Lets say the PersonDto contains also the list of DeparmentDtos, it forces you to fetch all deparments before hand or you will run into a LazyInitializationException in the controller layer.
Which in my opinion is a good thing, because if you would perform the mapping in the service you would be doing N + 1 queries (N being the number of deparments) without realizing it.
Services who need each other to perform there business tasks, work on the entity model instead of the DTO model, which might have some validation (#NotNull, #Size, ...) which only supposed to be valided when it comes from the outside, but internally not all validations should be applied.
Business rules will still be checked in the service layer as part of the service method.
The only thing here is that for update/creates service still communicate by passing dtos iso of entities.
I googled this topic a lot, but couldn't find a definitive answer.

Decide which of multiple implementations to use in Spring Boot app

Given two (or more) implementations of a particular service API, what's the best way to pick which one to use at runtime in my app based on an application property?
Example API:
public interface Greeting {
String sayHello(String username);
}
Implementations:
public class FriendlyGreeting implements Greeting {
public String sayHello(String username) {
return "Hello, " + username;
}
}
public class HostileGreeting implements Greeting {
public String sayHello(String username) {
return "Go away, " + username;
}
}
I've got a separate service class with an #Autowired constructor that takes an instance of Greeting. What I want, is based upon a configuration property, to decide which greeting implementation gets injected and used. I came up with using a configuration class to make that decision:
#Configuration
public class GreetingConfiguration {
private String selection;
#Autowired
public GreetingConfiguration(#Value("${greeting.type}") String type) {
this.selection = type;
}
#Bean
public Greeting provideGreeting() {
if ("friendly".equals(selection)) {
return new FriendlyGreeting();
} else {
return new HostileGreeting();
}
}
}
Is this the right way to do what I want? I went down the road of using #Qualifier on the implementations, and ended up with a mess where Spring saw 3 instances of my Greeting API, and I needed a configuration anyway to pick which implementation to use and return it with a unique qualifier name on it, and that feels worse than what I settled on.

You can mark both Greeting as #Service and select the chosen one with #Qualifier("yourServiceHere") like this:
#Autowired
#Qualifier("friendlyGreeting")
private Greeting greeting;
Another way you can do it is with profile. You can mark your FriendlyGreeting service with #Service and #Profile("friendly") and the HostileGreeting service with #Service and #Profile("hostileGreeting") and just put in the application.properties the following:
spring.profiles.active=friendly

Answering my own question.
#Compass and #user268396 were correct - using Profiles got this working as expected.
I created both implementations, annotated with #Service and #Profile("friendly") or #Profile("hostile"), and could change the property spring.profiles.active to dev,friendly for example, and get what I wanted.

You can use #Conditional annotations described at https://docs.spring.io/spring-framework/docs/current/javadoc-api/org/springframework/context/annotation/Conditional.html and https://reflectoring.io/spring-boot-conditionals/
#Profile annotations mentioned above are based upon #Conditional(from Spring Framework); see also Spring Boot: org.springframework.boot.autoconfigure.condition

Here is a full solution using ideas mentioned by David and Vitor above with #Profile and #Qualifer annotations.
Two beans with same name but Only one is activated based on which profile is defined.
#Profile("profile1")
#Bean("greeting")
public class FriendlyGreeting implements Greeting {
---
#Profile("profile2")
#Bean("greeting")
public class HostileGreeting implements Greeting {
---
#Configuration
public class GreetingConfiguration {
private Greeting greeting;
#Autowired
public GreetingConfiguration(#Qualifier("greeting") Greeting greeting) {
this.greeting = greeting;
}
}
Notes:
you can remove the intermediate class GreetingConfiguration and stick the "greeting" bean wherever you need
i prefer the #Autowired on the constructor instead of the class member to make it easier for unit testing.

When and how to instantiate a Spring Bean in my Rest Api

First of all, I'm a relative noob to Spring Boot, so keep that in mind.
I've got a REST api in which I'm trying to minimize database calls for the same object and I've determined that using a Spring Bean scoped to the Request is what I want. Assuming that is correct, here is what I'm trying to do:
1) Controller takes in a validated PhotoImportCommandDto command
PhotoCommandController
#RequestMapping(method = RequestMethod.POST)
public ResponseEntity<?> importPhoto(#Valid #RequestBody PhotoImportCommandDto command){
...
}
2) PhotoImportCommandDto is validated. Note the custom #UserExistsConstraint which validates that the user exists in the database by calling a service method.
PhotoImportCommandDto
#Component
public class PhotoImportCommandDto extends BaseCommand {
#NotNull(message = "userId must not be null!")
#UserExistsConstraint
private Long userId;
...
}
What I would like to do is somehow set a Spring Bean of the user that is validated in the #UserExistsConstraint and reference it in various methods that might be called throughout a Http request, but I'm not really sure how to do that. Since I've never really created my own Spring Beans, I don't know how to proceed. I've read various guides like this, but am still lost in how to implement it in my code.
Any help/examples would be much appreciated.

You can use the #Bean annotation.
#Configuration
public class MyConfiguration {
#Bean({"validUser"})
public User validUser() {
User user;
//instantiate user either from DB or anywhere else
return user;
}
then you can obtain the validUser.
#Component
public class PhotoImportCommandDto extends BaseCommand {
#Autowired
#Qualifier("validUser")
private User validUser;
...
}

I don't really know how to make annotations in Java. Anyway, in Spring, checking where the User exists in the DataBase or not is one line of code:
userRepository.findOne(user) == null
That is accomplished by the Spring Data JPA project:
Create a JPA Entity User.
Set the spring.datasource.url and login/password in the
resources/application.properties.
Create this interface:
import org.springframework.data.repository.CrudRepository;
import org.springframework.stereotype.Repository;
#Repository
public interface UserRepository extends CrudRepository<User, Long> {
}
Note, Spring implements it behind the scences.
Inject this interface into your RestController (or any other Spring bean):
private UserRepository userRepository ;
**constructor**(UserRepository ur){
userRepository = ur;
}
Note, a Spring Bean is any class annotated #Component (this includes stereotype annotations like Controller, Repository - just look up the contents of an annotation, it may use #Component internally) or returned from a method which is annotated #Bean (can only be on the Component or Configuration class). A Component is injected by searching the classpath, Bean is injected more naturally.
Also note, injecting is specifying #Autowired annotation on field or constructor, on a factory method, or on a setter. The documentation recommends that you inject required dependencies into constructor and non-required into the setter.
Also note, if you're injecting into a constructor and it is clean by the arguments, you may omit #Autowired annotation, Spring will figure it out.
Call its method findOne.
So, you can do one of the following:
Inject the userRepository into the #RestController constructor (as shown above). I would do that.
Inject the userRepository into the #Service (internally #Component) class that will do this sorts of thing for you. Maybe you can play with it to create an annotation.
p.s. Use #PostMapping instead of #RequestMapping(method = RequestMethod.POST)
p.p.s. If ever in doubt, go to the official documentation page and just press CTRL-F: http://docs.spring.io/spring/docs/current/spring-framework-reference/htmlsingle/ Note the current word, that will always take you to the latest version.
p.p.p.s Each Spring project has its own .io webpage as well as quick Get Started Guides where you can quickly see the sample project with explanations expecting you to know nothing.
Hope that helps! :)
Don't forget to mark the answer as accepted if you wish

Using Jose's input, I took a bit of a different route.
Here's what I did:
I created a ValidatedUser class:
#RequestScope
#Component
public class ValidatedUser {
private UserEntity user;
public UserEntity getUser() {
return user;
}
public void setUser(UserEntity user) {
this.user = user;
}
}
and I also created a wrapper class HttpRequestScopeConfig to capture all variables to use over the course of an Http Request to the api.
#Component
public class HttpRequestScopeConfig {
#Autowired
private ValidatedUser validatedUser;
...
public UserEntity getValidatedUser() {
return validatedUser.getUser();
}
public void setValidatedUser(UserEntity validatedUser) {
this.validatedUser.setUser(validatedUser);
}
...
}
In my UserExistsConstraintValidator (which is the impl of #UserExistsConstraint, I set the validatedUser in the httpRequestScopeConfig:
public class UserExistsConstraintValidator implements ConstraintValidator<UserExistsConstraint, Long> {
//private Log log = LogFactory.getLog(EmailExistsConstraintValidator.class);
#Autowired
private UserCommandService svc;
#Autowired
private HttpRequestScopeConfig httpRequestScope;
#Override
public void initialize(UserExistsConstraint userId) {
}
#Override
public boolean isValid(Long userIdField, ConstraintValidatorContext context) {
try {
UserEntity user = svc.findUserOfAnyStatus((Long) userIdField);
if (user != null) {
httpRequestScope.setValidatedUser(user);
return true;
}
} catch (Exception e) {
//log.error(e);
}
return false;
}
}
Now, I can access these variables throughout the rest of my service layers by autowiring HttpRequestScopeConfig where necessary.

Partially implemented repository with Spring data Neo4j 4

I'm trying to partially implement a repository using the following structure:
public interface ExampleCustomRepository {
Iterable<Example> findExamplesByUserId(Long id);
}
#Repository
#Transactional
public class ExampleCustomRepositoryImpl implements ExampleCustomRepository {
#Autowired
private Neo4jTemplate template;
#Override
public Iterable<Example> findExamplesByUserId(final Long id) {
// implementation
}
}
public interface ExampleRepository extends GraphRepository<Example>, ExampleCustomRepository {
}
For some reason the RepositoryFactory wants to create a DerivedGraphRepositoryQuery for this implemented method, and fails:
org.springframework.data.mapping.PropertyReferenceException: No property userId found for type Example!
Is it even possible to partially implement a repository with SDN4? If it is, what am I doing wrong?

I overlooked the naming convention, which was explained here.
I had too rename ExampleCustomRepositoryImpl to ExampleRepositoryImpl.