I am using the below code to create a Zip file. I would like to return the created Zip as a File object in the method createZipFromFiles in order to use elsewhere. Can this be done from the FileOutputStream or ZipOutputStream?
public File createZipFromFiles(String zipName, List<File> files) {
try {
FileOutputStream fos = new FileOutputStream(zipName);
ZipOutputStream zos = new ZipOutputStream(fos);
for (File file : files) {
addToZipFile(file.getName(), zos);
}
return null;
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
return null;
}
public static void addToZipFile(String fileName, ZipOutputStream zos) throws FileNotFoundException, IOException {
System.out.println("Writing '" + fileName + "' to zip file");
File file = new File(fileName);
FileInputStream fis = new FileInputStream(file);
ZipEntry zipEntry = new ZipEntry(fileName);
zos.putNextEntry(zipEntry);
byte[] bytes = new byte[1024];
int length;
while ((length = fis.read(bytes)) >= 0) {
zos.write(bytes, 0, length);
}
zos.closeEntry();
fis.close();
}
Just return
new File(zipName);
since you already have the zip file name
I have a project called "MyApp". MyApp will use a java library I am creating called "MyLibrary". I am writing a function in "MyLibrary" to unzip a zip file in "MyApp"(or whatever app is using "MyLibrary") "resources" dir.
Reading https://community.oracle.com/blogs/kohsuke/2007/04/25/how-convert-javaneturl-javaiofile I cannot create a File via a path because it is not a "physical file". I was using zip4j, but its constructor takes a File or String rather than an InputStream. So I cannot do this:
ZipFile zipfile = new
ZipFile("src/main/resources/compressed.zip");
downloadedZipfile.extractAll("src/main/resources");
java.io.File javadoc and http://www.mkyong.com/java/how-to-convert-inputstream-to-file-in-java/ indicate there isn't a way to convert an InputStream to a File.
Is there another way to access the zip file in the project that is using my library? Thank you in advance.
UPDATE:
The zipIn lacks entries, so the while loop won't extract the file out.
InputStream in = getInputStream("", JSON_FILENAME);
ZipInputStream zipIn = new ZipInputStream(in);
ZipEntry entry;
try {
while ((entry = zipIn.getNextEntry()) != null) {
String filepath = entry.getName();
if(!entry.isDirectory()) {
extractFile(zipIn, filepath);
}
else {
File dir = new File(filepath);
dir.mkdir();
}
zipIn.closeEntry();
}
zipIn.close();
} catch (IOException e) {
e.printStackTrace();
}
private void extractFile(ZipInputStream zipIn, String filepath) {
BufferedOutputStream bos = null;
try {
bos = new BufferedOutputStream(new FileOutputStream(filepath));
} catch (FileNotFoundException e) {
e.printStackTrace();
}
byte[] bytesIn = new byte[BUFFER_SIZE];
int read = 0;
try {
while ((read = zipIn.read(bytesIn)) != -1) {
bos.write(bytesIn, 0, read);
}
bos.close();
} catch (IOException e) {
e.printStackTrace();
}
}
Will the file be extracted into the home directory of "MyApp" when using this code that belongs to "MyLibrary"?
If you have a InputStream to your virtual ZIP file you can use java.util.zip.ZipInputStream to read the ZIP entries:
InputStream in = ...
ZipInputStream zipIn = new ZipInputStream(in);
ZipEntry entry;
while ((entry = zipIn.getNextEntry()) != null) {
// handle the entry
}
Here i have Bookfolder in that few more folders(english,hindi,japanese).Converting english,hindi,japanese to english.zip,hindi.zip and japanese.zip.Everything is working fine and i'm keeping zip files and folders inside Bookfolder,this thing i'm doing using with java.But when i'm unzipping manually the zip file ex:english.zip ,right click on that extract here then showing error as UNEXPECTED END OF ARCHIVE.This is my code.
public void foldertToZip(File zipDeleteFile) {
//System.out.println(zipDeleteFile);
File directoryToZip = zipDeleteFile;
List<File> fileList = new ArrayList<>();
//System.out.println("---Getting references to all files in: " + directoryToZip.getCanonicalPath());
getAllFiles(directoryToZip, fileList);
//System.out.println("---Creating zip file");
writeZipFile(directoryToZip, fileList);
//System.out.println("---Done");
}
public static void getAllFiles(File dir, List<File> fileList) {
try {
File[] files = dir.listFiles();
for (File file : files) {
fileList.add(file);
if (file.isDirectory()) {
System.out.println("directory:" + file.getCanonicalPath());
getAllFiles(file, fileList);
} else {
System.out.println("file:" + file.getCanonicalPath());
}
}
} catch (IOException e) {
}
}
public static void writeZipFile(File directoryToZip, List<File> fileList) {
try {
//try (FileOutputStream fos = new FileOutputStream(directoryToZip.getName() + ".zip"); ZipOutputStream zos = new ZipOutputStream(fos)) {
File path = directoryToZip.getParentFile();
File zipFile = new File(path, directoryToZip.getName() + ".zip");
try (FileOutputStream fos = new FileOutputStream(zipFile)) {
ZipOutputStream zos = new ZipOutputStream(fos);
for (File file : fileList) {
if (!file.isDirectory()) { // we only zip files, not directories
addToZip(directoryToZip, file,zos);
}
}
}
} catch (FileNotFoundException e) {
} catch (IOException e) {
}
}
public static void addToZip(File directoryToZip, File file, ZipOutputStream zos) throws FileNotFoundException,
IOException {
try (FileInputStream fis = new FileInputStream(file)) {
String zipFilePath = file.getCanonicalPath().substring(directoryToZip.getCanonicalPath().length() + 1,
file.getCanonicalPath().length());
System.out.println("Writing '" + zipFilePath + "' to zip file");
ZipEntry zipEntry = new ZipEntry(zipFilePath);
zos.putNextEntry(zipEntry);
byte[] bytes = new byte[1024];
int length;
while ((length = fis.read(bytes)) >= 0) {
zos.write(bytes, 0, length);
}
zos.closeEntry();
}
}`
while i'm extracting new zip file(eg:english.zip) it showing error as unexpected end of archieve (i think not zipping exactly)'
You need to close ZipOutputStream in writeZipFile() method;
for (File file : fileList) {
if (!file.isDirectory()) { // we only zip files, not directories
addToZip(directoryToZip, file,zos);
}
}
//here close zos
zos.close();
I was missing media type on ResponseEntity object and therefore I got this error information during extracting zip archive.
That means when calling rest api to download zip archive with files then needed information needs to be passed within ResponseEntity (media type application/zip, header info, cache info, etc.).
Another observation
is that I was missing correct return response type from angular side. There must be responseType as blob and not as text. That caused me the main issue.
Angular side:
getZIPData(id: number) {
const path = resolveBase() + 'rest-api-path' + id
return this._http.get(path, { observe: 'response', responseType: 'blob' });
}
It might help somebody.
I have read a lot of threads on this site regarding my issue, and the code I have is based off some of them. The problem I have currently is that unzipping an ePub results in only the mimetype file being extracted with LogCat getting errors in creating a folder from what I understand.
Following is what I use to decompress any zip file, I got it from Problem when Unzipping:
/**
* #author jon
*/
public class Decompress {
private String _zipFile;
private String _location;
ZipEntry ze = null;
public Decompress(String zipFile, String location) {
_zipFile = zipFile;
_location = location;
_dirChecker("");
}
public void unzip() {
try {
FileInputStream fin = new FileInputStream(_zipFile);
ZipInputStream zin = new ZipInputStream(fin);
while ((ze = zin.getNextEntry()) != null) {
Log.v("Decompress", "Unzipping " + ze.getName());
if (ze.isDirectory()) {
_dirChecker(ze.getName());
} else {
FileOutputStream fout = new FileOutputStream(_location
+ ze.getName());
for (int c = zin.read(); c != -1; c = zin.read()) {
fout.write(c);
}
zin.closeEntry();
fout.close();
}
}
zin.close();
} catch (Exception e) {
Log.e("Decompress", "unzip", e);
}
}
private void _dirChecker(String dir) {
File f = new File(_location + dir);
Log.d("Decompress", f.getAbsolutePath().toString());
if (!f.isDirectory()) {
f.mkdirs();
}
}
}
Other articles I have referred to:
Unzip a zipped file on sd card in Android application
Why my decompress class don't make directories?
Uzip folders recursively -android
Render epub files in android
Android EPUBLIB read/load content
Here is the LogCat Error I receive on the second file(/folder) after the mimetype file.
03-24 10:38:13.991: E/Decompress(23190): java.io.FileNotFoundException: /storage/emulated/0/unzipped/yamani/CDS-suggestions.docx: open failed: ENOENT (No such file or directory)
I'm currently using a regular zip file to test out my code.
Thanks for the help.
Was able to solve my problem by using another snippet found on this site.
Source:
public class unpackZip {
public boolean unzip(String zipname, String path) {
InputStream is;
ZipInputStream zis;
try {
String filename;
is = new FileInputStream(zipname);
zis = new ZipInputStream(new BufferedInputStream(is));
ZipEntry ze;
byte[] buffer = new byte[1024];
int count;
while ((ze = zis.getNextEntry()) != null) {
// zapis do souboru
filename = ze.getName();
// Need to create directories if not exists, or
// it will generate an Exception...
if (ze.isDirectory()) {
File fmd = new File(path, filename);
fmd.mkdirs();
continue;
} else {
// Make this part of the code more efficient .code-revise
File fmd = new File(path, filename);
Log.d("Unzipping", fmd.getParentFile().getPath());
String parent = fmd.getParentFile().getPath();
File fmd_1 = new File(parent);
fmd_1.mkdirs();
// end of .code-revise
}
FileOutputStream fout = new FileOutputStream(path + filename);
// cteni zipu a zapis
while ((count = zis.read(buffer)) != -1) {
fout.write(buffer, 0, count);
}
fout.close();
zis.closeEntry();
}
zis.close();
} catch (IOException e) {
e.printStackTrace();
return false;
}
return true;
}
}
I have a dynamic text file that picks content from a database according to the user's query. I have to write this content into a text file and zip it in a folder in a servlet. How should I do this?
Look at this example:
StringBuilder sb = new StringBuilder();
sb.append("Test String");
File f = new File("d:\\test.zip");
ZipOutputStream out = new ZipOutputStream(new FileOutputStream(f));
ZipEntry e = new ZipEntry("mytext.txt");
out.putNextEntry(e);
byte[] data = sb.toString().getBytes();
out.write(data, 0, data.length);
out.closeEntry();
out.close();
This will create a zip in the root of D: named test.zip which will contain one single file called mytext.txt. Of course you can add more zip entries and also specify a subdirectory like this:
ZipEntry e = new ZipEntry("folderName/mytext.txt");
You can find more information about compression with Java here.
Java 7 has ZipFileSystem built in, that can be used to create, write and read file from zip file.
Java Doc: ZipFileSystem Provider
Map<String, String> env = new HashMap<>();
// Create the zip file if it doesn't exist
env.put("create", "true");
URI uri = URI.create("jar:file:/codeSamples/zipfs/zipfstest.zip");
try (FileSystem zipfs = FileSystems.newFileSystem(uri, env)) {
Path externalTxtFile = Paths.get("/codeSamples/zipfs/SomeTextFile.txt");
Path pathInZipfile = zipfs.getPath("/SomeTextFile.txt");
// Copy a file into the zip file
Files.copy(externalTxtFile, pathInZipfile, StandardCopyOption.REPLACE_EXISTING);
}
To write a ZIP file, you use a ZipOutputStream. For each entry that you want to place into the ZIP file, you create a ZipEntry object. You pass the file name to the ZipEntry constructor; it sets the other parameters such as file date and decompression method. You can override these settings if you like. Then, you call the putNextEntry method of the ZipOutputStream to begin writing a new file. Send the file data to the ZIP stream. When you are done, call closeEntry. Repeat for all the files you want to store. Here is a code skeleton:
FileOutputStream fout = new FileOutputStream("test.zip");
ZipOutputStream zout = new ZipOutputStream(fout);
for all files
{
ZipEntry ze = new ZipEntry(filename);
zout.putNextEntry(ze);
send data to zout;
zout.closeEntry();
}
zout.close();
Here is an example code to compress a Whole Directory(including sub files and sub directories), it's using the walk file tree feature of Java NIO.
import java.io.FileOutputStream;
import java.io.IOException;
import java.nio.file.*;
import java.nio.file.attribute.BasicFileAttributes;
import java.util.zip.ZipEntry;
import java.util.zip.ZipOutputStream;
public class ZipCompress {
public static void compress(String dirPath) {
final Path sourceDir = Paths.get(dirPath);
String zipFileName = dirPath.concat(".zip");
try {
final ZipOutputStream outputStream = new ZipOutputStream(new FileOutputStream(zipFileName));
Files.walkFileTree(sourceDir, new SimpleFileVisitor<Path>() {
#Override
public FileVisitResult visitFile(Path file, BasicFileAttributes attributes) {
try {
Path targetFile = sourceDir.relativize(file);
outputStream.putNextEntry(new ZipEntry(targetFile.toString()));
byte[] bytes = Files.readAllBytes(file);
outputStream.write(bytes, 0, bytes.length);
outputStream.closeEntry();
} catch (IOException e) {
e.printStackTrace();
}
return FileVisitResult.CONTINUE;
}
});
outputStream.close();
} catch (IOException e) {
e.printStackTrace();
}
}
}
To use this, just call
ZipCompress.compress("target/directoryToCompress");
and you'll get a zip file directoryToCompress.zip
Single file:
String filePath = "/absolute/path/file1.txt";
String zipPath = "/absolute/path/output.zip";
try (ZipOutputStream zipOut = new ZipOutputStream(new FileOutputStream(zipPath))) {
File fileToZip = new File(filePath);
zipOut.putNextEntry(new ZipEntry(fileToZip.getName()));
Files.copy(fileToZip.toPath(), zipOut);
}
Multiple files:
List<String> filePaths = Arrays.asList("/absolute/path/file1.txt", "/absolute/path/file2.txt");
String zipPath = "/absolute/path/output.zip";
try (ZipOutputStream zipOut = new ZipOutputStream(new FileOutputStream(zipPath))) {
for (String filePath : filePaths) {
File fileToZip = new File(filePath);
zipOut.putNextEntry(new ZipEntry(fileToZip.getName()));
Files.copy(fileToZip.toPath(), zipOut);
}
}
Spring boot controller, zip the files in a directory, and can be downloaded.
#RequestMapping(value = "/files.zip")
#ResponseBody
byte[] filesZip() throws IOException {
File dir = new File("./");
File[] filesArray = dir.listFiles();
if (filesArray == null || filesArray.length == 0)
System.out.println(dir.getAbsolutePath() + " have no file!");
ByteArrayOutputStream bo = new ByteArrayOutputStream();
ZipOutputStream zipOut= new ZipOutputStream(bo);
for(File xlsFile:filesArray){
if(!xlsFile.isFile())continue;
ZipEntry zipEntry = new ZipEntry(xlsFile.getName());
zipOut.putNextEntry(zipEntry);
zipOut.write(IOUtils.toByteArray(new FileInputStream(xlsFile)));
zipOut.closeEntry();
}
zipOut.close();
return bo.toByteArray();
}
This is how you create a zip file from a source file:
String srcFilename = "C:/myfile.txt";
String zipFile = "C:/myfile.zip";
try {
byte[] buffer = new byte[1024];
FileOutputStream fos = new FileOutputStream(zipFile);
ZipOutputStream zos = new ZipOutputStream(fos);
File srcFile = new File(srcFilename);
FileInputStream fis = new FileInputStream(srcFile);
zos.putNextEntry(new ZipEntry(srcFile.getName()));
int length;
while ((length = fis.read(buffer)) > 0) {
zos.write(buffer, 0, length);
}
zos.closeEntry();
fis.close();
zos.close();
}
catch (IOException ioe) {
System.out.println("Error creating zip file" + ioe);
}
public static void main(String args[])
{
omtZip("res/", "omt.zip");
}
public static void omtZip(String path,String outputFile)
{
final int BUFFER = 2048;
boolean isEntry = false;
ArrayList<String> directoryList = new ArrayList<String>();
File f = new File(path);
if(f.exists())
{
try {
FileOutputStream fos = new FileOutputStream(outputFile);
ZipOutputStream zos = new ZipOutputStream(new BufferedOutputStream(fos));
byte data[] = new byte[BUFFER];
if(f.isDirectory())
{
//This is Directory
do{
String directoryName = "";
if(directoryList.size() > 0)
{
directoryName = directoryList.get(0);
System.out.println("Directory Name At 0 :"+directoryName);
}
String fullPath = path+directoryName;
File fileList = null;
if(directoryList.size() == 0)
{
//Main path (Root Directory)
fileList = f;
}else
{
//Child Directory
fileList = new File(fullPath);
}
String[] filesName = fileList.list();
int totalFiles = filesName.length;
for(int i = 0 ; i < totalFiles ; i++)
{
String name = filesName[i];
File filesOrDir = new File(fullPath+name);
if(filesOrDir.isDirectory())
{
System.out.println("New Directory Entry :"+directoryName+name+"/");
ZipEntry entry = new ZipEntry(directoryName+name+"/");
zos.putNextEntry(entry);
isEntry = true;
directoryList.add(directoryName+name+"/");
}else
{
System.out.println("New File Entry :"+directoryName+name);
ZipEntry entry = new ZipEntry(directoryName+name);
zos.putNextEntry(entry);
isEntry = true;
FileInputStream fileInputStream = new FileInputStream(filesOrDir);
BufferedInputStream bufferedInputStream = new BufferedInputStream(fileInputStream, BUFFER);
int size = -1;
while( (size = bufferedInputStream.read(data, 0, BUFFER)) != -1 )
{
zos.write(data, 0, size);
}
bufferedInputStream.close();
}
}
if(directoryList.size() > 0 && directoryName.trim().length() > 0)
{
System.out.println("Directory removed :"+directoryName);
directoryList.remove(0);
}
}while(directoryList.size() > 0);
}else
{
//This is File
//Zip this file
System.out.println("Zip this file :"+f.getPath());
FileInputStream fis = new FileInputStream(f);
BufferedInputStream bis = new BufferedInputStream(fis,BUFFER);
ZipEntry entry = new ZipEntry(f.getName());
zos.putNextEntry(entry);
isEntry = true;
int size = -1 ;
while(( size = bis.read(data,0,BUFFER)) != -1)
{
zos.write(data, 0, size);
}
}
//CHECK IS THERE ANY ENTRY IN ZIP ? ----START
if(isEntry)
{
zos.close();
}else
{
zos = null;
System.out.println("No Entry Found in Zip");
}
//CHECK IS THERE ANY ENTRY IN ZIP ? ----START
}catch(Exception e)
{
e.printStackTrace();
}
}else
{
System.out.println("File or Directory not found");
}
}
}
Given exportPath and queryResults as String variables, the following block creates a results.zip file under exportPath and writes the content of queryResults to a results.txt file inside the zip.
URI uri = URI.create("jar:file:" + exportPath + "/results.zip");
Map<String, String> env = Collections.singletonMap("create", "true");
try (FileSystem zipfs = FileSystems.newFileSystem(uri, env)) {
Path filePath = zipfs.getPath("/results.txt");
byte[] fileContent = queryResults.getBytes();
Files.write(filePath, fileContent, StandardOpenOption.CREATE);
}
You have mainly to create two functions. First is writeToZipFile() and second is createZipfileForOutPut .... and then call the createZipfileForOutPut('file name of .zip')` …
public static void writeToZipFile(String path, ZipOutputStream zipStream)
throws FileNotFoundException, IOException {
System.out.println("Writing file : '" + path + "' to zip file");
File aFile = new File(path);
FileInputStream fis = new FileInputStream(aFile);
ZipEntry zipEntry = new ZipEntry(path);
zipStream.putNextEntry(zipEntry);
byte[] bytes = new byte[1024];
int length;
while ((length = fis.read(bytes)) >= 0) {
zipStream.write(bytes, 0, length);
}
zipStream.closeEntry();
fis.close();
}
public static void createZipfileForOutPut(String filename) {
String home = System.getProperty("user.home");
// File directory = new File(home + "/Documents/" + "AutomationReport");
File directory = new File("AutomationReport");
if (!directory.exists()) {
directory.mkdir();
}
try {
FileOutputStream fos = new FileOutputStream("Path to your destination" + filename + ".zip");
ZipOutputStream zos = new ZipOutputStream(fos);
writeToZipFile("Path to file which you want to compress / zip", zos);
zos.close();
fos.close();
} catch (FileNotFoundException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
}
There is another option by using zip4j at https://github.com/srikanth-lingala/zip4j
Creating a zip file with single file in it / Adding single file to an existing zip
new ZipFile("filename.zip").addFile("filename.ext");
Or
new ZipFile("filename.zip").addFile(new File("filename.ext"));
Creating a zip file with multiple files / Adding multiple files to an existing zip
new ZipFile("filename.zip").addFiles(Arrays.asList(new File("first_file"), new File("second_file")));
Creating a zip file by adding a folder to it / Adding a folder to an existing zip
new ZipFile("filename.zip").addFolder(new File("/user/myuser/folder_to_add"));
Creating a zip file from stream / Adding a stream to an existing zip
new ZipFile("filename.zip").addStream(inputStream, new ZipParameters());
I know this question is answered but if you have a list of strings and you want to create a separate file for each string in the archive, you can use the snippet below.
public void zipFileTest() throws IOException {
Map<String, String> map = Map.ofEntries(
new AbstractMap.SimpleEntry<String, String>("File1.txt", "File1 Content"),
new AbstractMap.SimpleEntry<String, String>("File2.txt", "File2 Content"),
new AbstractMap.SimpleEntry<String, String>("File3.txt", "File3 Content")
);
createZipFileFromStringContents(map, "archive.zip");
}
public void createZipFileFromStringContents(Map<String, String> map, String zipfilePath) throws IOException {
FileOutputStream fout = new FileOutputStream(zipfilePath);
ZipOutputStream zout = new ZipOutputStream(fout);
for (Map.Entry<String, String> entry : map.entrySet()) {
String fileName = entry.getKey();
ZipEntry zipFile = new ZipEntry(fileName);
zout.putNextEntry(zipFile);
String fileContent = entry.getValue();
zout.write(fileContent.getBytes(), 0, fileContent.getBytes().length);
zout.closeEntry();
}
zout.close();
}
It will create a zip file with the structure as in the below image:
Here is my working solution:
public static byte[] createZipFile(Map<String, FileData> files) throws IOException {
try(ByteArrayOutputStream tZipFile = new ByteArrayOutputStream()) {
try (ZipOutputStream tZipFileOut = new ZipOutputStream(tZipFile)) {
for (Map.Entry<String, FileData> file : files.entrySet()) {
ZipEntry zipEntry = new ZipEntry(file.getValue().getFileName());
tZipFileOut.putNextEntry(zipEntry);
tZipFileOut.write(file.getValue().getBytes());
}
}
return tZipFile.toByteArray();
}
}
public class FileData {
private String fileName;
private byte[] bytes;
public String getFileName() {
return this.fileName;
}
public byte[] getBytes() {
return this.bytes;
}
}
This will create byte[] of ZIP file which contains one or more compressed files. I've used this method inside controller method and write bytes[] of ZIP file into response to download ZIP file(s) from server.
Since it took me a while to figure it out, I thought it would be helpful to post my solution using Java 7+ ZipFileSystem
openZip(runFile);
addToZip(filepath); //loop construct;
zipfs.close();
private void openZip(File runFile) throws IOException {
Map<String, String> env = new HashMap<>();
env.put("create", "true");
env.put("encoding", "UTF-8");
Files.deleteIfExists(runFile.toPath());
zipfs = FileSystems.newFileSystem(URI.create("jar:" + runFile.toURI().toString()), env);
}
private void addToZip(String filename) throws IOException {
Path externalTxtFile = Paths.get(filename).toAbsolutePath();
Path pathInZipfile = zipfs.getPath(filename.substring(filename.lastIndexOf("results"))); //all files to be stored have a common base folder, results/ in my case
if (Files.isDirectory(externalTxtFile)) {
Files.createDirectories(pathInZipfile);
try (DirectoryStream<Path> ds = Files.newDirectoryStream(externalTxtFile)) {
for (Path child : ds) {
addToZip(child.normalize().toString()); //recursive call
}
}
} else {
// copy file to zip file
Files.copy(externalTxtFile, pathInZipfile, StandardCopyOption.REPLACE_EXISTING);
}
}
public static void zipFromTxt(String zipFilePath, String txtFilePath) {
Assert.notNull(zipFilePath, "Zip file path is required");
Assert.notNull(txtFilePath, "Txt file path is required");
zipFromTxt(new File(zipFilePath), new File(txtFilePath));
}
public static void zipFromTxt(File zipFile, File txtFile) {
ZipOutputStream out = null;
FileInputStream in = null;
try {
Assert.notNull(zipFile, "Zip file is required");
Assert.notNull(txtFile, "Txt file is required");
out = new ZipOutputStream(new FileOutputStream(zipFile));
in = new FileInputStream(txtFile);
out.putNextEntry(new ZipEntry(txtFile.getName()));
int len;
byte[] buffer = new byte[1024];
while ((len = in.read(buffer)) > 0) {
out.write(buffer, 0, len);
out.flush();
}
} catch (Exception e) {
log.info("Zip from txt occur error,Detail message:{}", e.toString());
} finally {
try {
if (in != null) in.close();
if (out != null) {
out.closeEntry();
out.close();
}
} catch (Exception e) {
log.info("Zip from txt close error,Detail message:{}", e.toString());
}
}
}
Using Jeka https://jeka.dev JkPathTree, it's quite straightforward.
Path wholeDirToZip = Paths.get("dir/to/zip");
Path zipFile = Paths.get("file.zip");
JkPathTree.of(wholeDirToZip).zipTo(zipFile);
If you want decompress without software better use this code. Other code with pdf files sends error on manually decompress
byte[] buffer = new byte[1024];
try {
FileOutputStream fos = new FileOutputStream("123.zip");
ZipOutputStream zos = new ZipOutputStream(fos);
ZipEntry ze= new ZipEntry("file.pdf");
zos.putNextEntry(ze);
FileInputStream in = new FileInputStream("file.pdf");
int len;
while ((len = in.read(buffer)) > 0) {
zos.write(buffer, 0, len);
}
in.close();
zos.closeEntry();
zos.close();
} catch(IOException ex) {
ex.printStackTrace();
}