Assume I have following DTO:
class C {
String a;
String b;
}
And I have the JSON:
{
"c" : {
"a" : "aaa",
"b" : "bbb"
}
}
What I want to do is, accomplish following test:
C expected = new C("aaa","bbb");
mockMvc.perform(get("url"))
.andExpect(jsonPath("$.c", is(expected)));
It fails. If I first serialize expected to JSON and then try to match, it again fails because it's a string. Is this possible?
Always remember: There is no such thing as a "JSON object". JSON is a serialization format for objects. JSON is always a string. You can convert from object to JSON and back (and hence from object to string and back). But
{ "a": "b" }
is a JavaScript object, not JSON (even if it looks very similar).
This in fact is the answer to your question: When you serialize expected, you get JSON (the transport format, i.e. the string). This isn't what jsonPath() checks. jsonPath() validates against JavaScript types.
This blog post suggests that you need to check each field individually:
.andExpect(jsonPath("$.c.a", is(expected.a)))
.andExpect(jsonPath("$.c.b", is(expected.b)));
which is tedious. What you need is
a) to configure your JSON framework to use a mapping system that sorts keys and
b) you need to figure out what type jsonPath("$.c", ...) returns - it's probably the type which your JSON framework uses to represent generic JavaScript objects.
The check then looks like this:
C c = new C("aaa","bbb");
String serialized = JSON.serialize(c); // to string
JSObject expected = JSON.parse(serialized); // to generic JavaScript object
mockMvc.perform(get("url"))
.andExpect(jsonPath("$.c", is(expected)));
Note that this only works if JSObject has a proper implementation for equals().
If you can afford to modify your "C" class to add it an "equals" operator and to modify slightly your JSON file, I would suggest you to transform your JSON string into an instance of "C". This can be done with a good JSON-ifier (Jackson or GSON). Then you just have to compare the 2 instances.
Some examples with GSON:
class C {
String a;
String b;
public boolean equals(C obj) { return a.equals(obj.a) && b.equals(obj.b); }
}
// Your JSON file should look like that
{
"a" : "aaa",
"b" : "bbb"
}
// So the test is simple
C expected = new C("aaa","bbb");
C json = gson.fromJson(jsonString, C.class);
if (expected.equals(json)) {
// Do whatever you want here
}
If you cannot afford to change the JSON file, just create another class to contains your main class, like this:
class Wrapper {
C c;
}
Wrapper jsonW = gson.fromJson(jsonString, Wrapper.class);
C json = jsonW.c;
...
If you cannot afford the addition of the equals operator, I suggest to create JSON string based on the 2 "C" instance objects and compare the strings. Your jsonString becomes a real "C" object (json) before ending into a new string (jsonStr).
String expectedStr = gson.toJson(expected);
String jsonStr = gson.toJSON(json);
if (expectedStr.equals(jsonStr)) {
// Do whatever you want here
}
Related
I am quite new to Java and trying to understand the effect of using toString() while accessing the individual string elements of JSON object in Java.
Below are the steps followed:
Parse the JSON data. Let's assume only string elements are there in parsed JSON data.
JSONParser parser = new JSONParser();
JSONObject jsonObj = (JSONObject) parser.parse(json_data);
{
"firstname" : "new",
"lastname" : "human",
"id" : "some_id"
}
Try to access the individual elements.
Access without toString():
Public static String firstname = jsonObj.get("firstname");
Access with toString():
Public static String firstname = jsonObj.get("firstname").toString();
I do not see a difference when I try to print the data.
However I would like to know the difference between the above 2 methods, and also will there be any issues if I use without toString() in this particular case.
Appreciate your help.
Thank you
When you have some Int or other type of data type variables in your model class and you want to parse it into a string so for that we use toString(), it will convert int or any other data variable into a string, in your case here you already have string so no need to change again and again and JSON uses string variables when it comes from backend so that the purpose.
toString() returns string representation of property/object on which this method is called.
Whenever we print an object reference, it invokes the toString() method internally as a result , it is not making difference.
Because you are using Json, there is no difference.
You can use the Option, you like more
This is what my class looks like -
public class A {
private Map<String, Object> objects = null;
....
}
My json would be like -
{
"f1" : {
"name" : "some name",
"val" : 3
},
"f2" : {
"arg": {
some field/value pairs
}
}
}
What I want is to specify in the JSON itself the type to which it can be deserialized to. So the value for f1 would be converted to an object of class B and f2 would get converted to object of C.
My code will look like this -
Object o = objects.get("f1");
if (o instanceof B) {
...
} else if (o instanceof C) {
...
}
Is there a way to do this? I want the json to control the deserialization.
Yes, Jackson can use a type identifier if JSON document has it. This is usually done by using annotation #JsonTypeInfo.
There are multiple ways to add/use type identifier, both regarding how it is included in JSON document, and as to what kind of id is being used (type name or Java class name?).
The easiest way to see how things match is to actually start with a POJO, add #JsonTypeInfo annotation, and serialize it to see kind of JSON produced. And once you understood how inclusion works you can modify, if necessary, structure of JSON and/or Java class definition.
I tried converting my json string to java object by using Gson but somehow it was not successful and I haven't figured out why..
My Json string
{
"JS":{
"JS0":{
"Name":"ABC",
"ID":"5"
},
"JS1":{
"Location":"UK",
"Town":"LD"
},
"JS2":{
"Usable":"true",
"Port":"ABC"
}
}
}
In java code I have 4 classes, JS, JS0, JS1 and JS2
JS class contains JS0, JS1 and JS2 variables
JS0, JS1 and JS2 classes contain fields as in Json string example, e.g. JS0 contains 02 fields, String Name and String ID
In all classes I have getter/setter for variables, 02 constructors (01 with empty parameters and another one with all variables in the parameter field)
And for using Gson:
Gson gson = new Gson();
jsObject = gson.fromJson(sb.toString(), JS.class);
When I access JS0, JS1 and JS2 objects from jsObject, they are null...
Can someone show me what did I do wrong?
Thank you very much,
The problem here is, you are trying to convert
{
"JS" : {
/* rest of JSON */
}
}
to JS object, but the above JSON is a representation of Java class like this
class Foo {
JS JS;
}
So, you need to get the value of JS from the JSON string first, then call fromJSON to deserialize it with the JS.class passed as the second parameter.
OR
Create a simple class containing only JS as a variable, then call fromJSON with that class passed as the second parameter of fromJSON like this:
Java
class Foo {
JS JS;
}
jsObject = gson.fromJson(sb.toString(), Foo.class);
I want to use Jackson to convert the Json payload of a HTTP request to a Java object.
However, I care only about some fields in that object.
e.g.
Obj
{
String a,
String b,
C c {
int d,
long e
}
}
I want Jackson to parse Json to a semi-populated Java object
e.g.
Obj
{
String a,
String b,
String c // as string: { int d,long e} }
}
Is this possible?
Looks like you are either looking for a propriety way of serializing and de-serializing property c from your example. For this purpose Jackson supplies the JsonSerialize and JsonDeserialize annotations. You can find more informations here.
Alternatively, you might want to ignore certain properties of your Java object during Jackson serialization. For this Jackson comes with a couple of options.
I have a model object which is initialized with default values. To refresh the content of object I call an web service and get the response and get the content from json object.
I want to check If json response contains the object or not. If it does then call the setter and set the data and if it doesn't then leave then don't set it. I have approx 300 fields in my object. How I can do it with less code. I am listing my current approach.
My Model object is like
public class MyObject {
private String str1 = "Initial Value1";
private String str2 = "Initial Value2";
public void setStr1(String str1)
{
this.str1 = str1;
}
public void setStr2(String str2)
{
this.str2 = str2;
}
public String getStr1(){
return str1;
}
public String getStr2(){
return str2;
}
}
my json response be like
{
"val_one":"New Value1",
"val_two":"New_value2"
}
Now at run time I need to set the value from json response
MyObject myObject = new MyObject();
if(jsonObject.has("val_one"));
myObject.setStr1(jsonObject.get("val_one"));
if(jsonObject.has("val_two"));
myObject.setStr2(jsonObject.get("val_two"));
Now how to do it in a better and efficient
If both sides are using JAVA then why not just use json-io. You can create an object as normal. ie
Animal a = new Aminmal() andimal.setName("bob");
Then use json-io to make it into json -- stream to where ever it needs to be... use json io to change back to object
This can be done using
JsonWriter.objectToJson(Object o);
JsonReader.jsonToJava(String json);
https://code.google.com/p/json-io/
json-io is also extremely light weight and quicker than most if not all other third party json library's that I have used.
That being said if you want to have more control on the output ie.. date conversions etc.. then look at GSON.
https://code.google.com/p/google-gson/
Another option, in addition to the other suggestions is gson. Here the link for gson information.
Essentially the idea with gson being that you define an object to represent the JSON structure that you are receiving. So somewhat like what you have now, you'd just need to change the object attributes to match the names of the JSON fields, ie 'val_one' and 'val_two'.
Then you just need to use gson to create the object from the JSON text, eg:
Gson gson = new GsonBuilder().create();
MyObject json = gson.fromJson(jsonStr, MyObject.class);
Why do you want to take of the object model mapping yourself? If you take spring then you can use the jackson mapper and have it all done for you.
If you don't want to use spring then you still can use jackson2 and let it handle the parsing:
http://wiki.fasterxml.com/JacksonRelease20